Physics (School & Undergraduate) MCQ & Objective Questions
Physics is a fundamental subject that plays a crucial role in school and undergraduate exams. Mastering Physics concepts not only enhances your understanding of the universe but also significantly boosts your exam scores. Practicing MCQs and objective questions helps you identify important topics and improves your problem-solving skills, making it an essential part of your exam preparation.
What You Will Practise Here
Newton's Laws of Motion and their applications
Work, Energy, and Power concepts and formulas
Waves and Sound: Properties and equations
Optics: Reflection, refraction, and lens formulas
Thermodynamics: Laws and key definitions
Electromagnetism: Basics of electric fields and circuits
Modern Physics: Introduction to quantum mechanics and relativity
Exam Relevance
Physics is a significant part of the curriculum for CBSE, State Boards, NEET, and JEE exams. Questions often focus on conceptual understanding and application of formulas. Common patterns include numerical problems, theoretical questions, and diagram-based queries. Familiarizing yourself with these patterns through practice is vital for success in these competitive exams.
Common Mistakes Students Make
Misunderstanding the application of Newton's Laws in different scenarios
Confusing work done with energy concepts
Overlooking the importance of units and dimensions in calculations
Neglecting to draw diagrams for problems related to optics and mechanics
Failing to relate theoretical concepts to practical examples
FAQs
Question: What are some effective ways to prepare for Physics MCQs?Answer: Regular practice of MCQs, understanding key concepts, and revising important formulas are effective strategies for preparation.
Question: How can I improve my problem-solving speed in Physics exams?Answer: Practice timed quizzes and focus on solving a variety of problems to enhance your speed and accuracy.
Don't wait any longer! Start solving practice MCQs today to test your understanding and boost your confidence in Physics. Remember, consistent practice is the key to mastering important Physics (School & Undergraduate) questions for exams.
Q. If a capacitor is connected to an AC source, what happens to the current through the capacitor?
A.
It is constant
B.
It leads the voltage
C.
It lags the voltage
D.
It is zero
Show solution
Solution
In an AC circuit, the current through a capacitor leads the voltage by 90 degrees.
Correct Answer:
B
— It leads the voltage
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Q. If a capacitor of 10 µF is charged to 20 V, what is the energy stored in the capacitor?
A.
0.02 J
B.
0.1 J
C.
0.5 J
D.
0.1 mJ
Show solution
Solution
Energy stored, U = 0.5 * C * V^2 = 0.5 * 10 x 10^-6 F * (20 V)^2 = 0.02 J.
Correct Answer:
B
— 0.1 J
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Q. If a capacitor of 10 µF is charged to a voltage of 5V, what is the stored energy?
A.
0.125 mJ
B.
0.25 mJ
C.
0.5 mJ
D.
0.75 mJ
Show solution
Solution
Energy stored U = 0.5 * C * V^2 = 0.5 * 10 x 10^-6 F * (5V)^2 = 0.125 mJ.
Correct Answer:
B
— 0.25 mJ
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Q. If a capacitor of 10 µF is connected in series with a 20 µF capacitor, what is the total capacitance?
A.
6.67 µF
B.
30 µF
C.
15 µF
D.
8 µF
Show solution
Solution
1/C_total = 1/C1 + 1/C2 = 1/10 + 1/20 = 3/20, thus C_total = 20/3 µF = 6.67 µF.
Correct Answer:
A
— 6.67 µF
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Q. If a capacitor of 5 microfarads is charged to 20 volts, what is the energy stored in the capacitor?
A.
0.01 J
B.
0.02 J
C.
0.05 J
D.
0.1 J
Show solution
Solution
The energy (U) stored in a capacitor is given by U = 0.5 * C * V^2. Here, U = 0.5 * 5 x 10^-6 F * (20^2) = 0.02 J.
Correct Answer:
B
— 0.02 J
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Q. If a capacitor of 5 µF is charged to 12 V, what is the energy stored in the capacitor?
A.
0.36 mJ
B.
0.72 mJ
C.
1.44 mJ
D.
2.88 mJ
Show solution
Solution
Energy stored U = 0.5 * C * V^2 = 0.5 * 5 x 10^-6 F * (12 V)^2 = 0.36 mJ.
Correct Answer:
A
— 0.36 mJ
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Q. If a capacitor of 5 µF is charged to a voltage of 10 V, what is the charge stored in the capacitor?
A.
50 µC
B.
100 µC
C.
25 µC
D.
75 µC
Show solution
Solution
Charge (Q) = C * V = 5 µF * 10 V = 50 µC.
Correct Answer:
A
— 50 µC
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Q. If a capacitor of 5 µF is charged to a voltage of 10V, what is the energy stored in the capacitor?
A.
0.25 mJ
B.
0.5 mJ
C.
0.75 mJ
D.
1.0 mJ
Show solution
Solution
Energy stored, U = 0.5 * C * V² = 0.5 * 5 x 10^-6 F * (10V)² = 0.25 mJ.
Correct Answer:
B
— 0.5 mJ
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Q. If a capacitor of 5 µF is charged to a voltage of 10V, what is the stored energy?
A.
0.25 mJ
B.
0.5 mJ
C.
0.75 mJ
D.
1 mJ
Show solution
Solution
Energy stored, U = 0.5 * C * V² = 0.5 * 5 x 10^-6 F * (10V)² = 0.25 mJ.
Correct Answer:
B
— 0.5 mJ
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Q. If a car accelerates from rest to 20 m/s in 5 seconds, what is its average acceleration?
A.
2 m/s²
B.
4 m/s²
C.
5 m/s²
D.
1 m/s²
Show solution
Solution
Average acceleration (a) = (final velocity - initial velocity) / time = (20 m/s - 0 m/s) / 5 s = 4 m/s².
Correct Answer:
A
— 2 m/s²
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Q. If a car accelerates from rest to 20 m/s in 5 seconds, what is the average power output if the car has a mass of 1000 kg?
A.
4000 W
B.
8000 W
C.
16000 W
D.
20000 W
Show solution
Solution
Work done = Change in Kinetic Energy = 0.5 × 1000 kg × (20 m/s)² = 200000 J. Power = Work / Time = 200000 J / 5 s = 40000 W.
Correct Answer:
C
— 16000 W
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Q. If a car accelerates from rest to a speed of 20 m/s in 10 seconds, what is the average power output if the car has a mass of 1000 kg?
A.
2000 W
B.
4000 W
C.
6000 W
D.
8000 W
Show solution
Solution
Work done = Change in Kinetic Energy = 0.5 × 1000 kg × (20 m/s)² = 200000 J. Power = Work / Time = 200000 J / 10 s = 20000 W.
Correct Answer:
C
— 6000 W
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Q. If a car accelerates from rest to a speed of 20 m/s in 5 seconds, what is its acceleration?
A.
2 m/s²
B.
4 m/s²
C.
5 m/s²
D.
10 m/s²
Show solution
Solution
Acceleration is calculated using the formula a = (v - u)/t. Here, a = (20 m/s - 0)/5 s = 4 m/s².
Correct Answer:
A
— 2 m/s²
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Q. If a car is moving at 80 km/h and a cyclist is moving at 20 km/h in the opposite direction, what is the speed of the cyclist relative to the car?
A.
60 km/h
B.
100 km/h
C.
80 km/h
D.
20 km/h
Show solution
Solution
The speed of the cyclist relative to the car is the sum of their speeds since they are moving in opposite directions: 80 km/h + 20 km/h = 100 km/h.
Correct Answer:
B
— 100 km/h
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Q. If a car is moving at a constant speed of 60 km/h, how far will it travel in 2 hours?
A.
60 km
B.
120 km
C.
180 km
D.
240 km
Show solution
Solution
Distance = speed × time = 60 km/h × 2 h = 120 km.
Correct Answer:
B
— 120 km
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Q. If a car traveling at 20 m/s comes to a stop in 5 seconds, what is its deceleration?
A.
2 m/s²
B.
4 m/s²
C.
5 m/s²
D.
10 m/s²
Show solution
Solution
Deceleration a = (final velocity - initial velocity) / time = (0 - 20 m/s) / 5 s = -4 m/s².
Correct Answer:
B
— 4 m/s²
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Q. If a car travels 100 m in 5 seconds, what is its average speed?
A.
20 m/s
B.
25 m/s
C.
15 m/s
D.
30 m/s
Show solution
Solution
Average speed is calculated as speed = distance/time, so speed = 100 m / 5 s = 20 m/s.
Correct Answer:
B
— 25 m/s
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Q. If a circuit has a total current of 5 A and a total resistance of 10 Ω, what is the total voltage?
A.
50 V
B.
25 V
C.
10 V
D.
5 V
Show solution
Solution
Using Ohm's Law, V = I * R = 5 A * 10 Ω = 50 V.
Correct Answer:
A
— 50 V
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Q. If a circuit has a total resistance of 10 Ω and a current of 2 A, what is the voltage across the circuit?
A.
5 V
B.
10 V
C.
20 V
D.
15 V
Show solution
Solution
Using Ohm's Law: V = I * R = 2 A * 10 Ω = 20 V.
Correct Answer:
C
— 20 V
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Q. If a circuit has a total resistance of 10Ω and a current of 5A, what is the voltage across the circuit?
A.
10V
B.
15V
C.
50V
D.
5V
Show solution
Solution
Using Ohm's Law, V = I * R = 5A * 10Ω = 50V.
Correct Answer:
C
— 50V
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Q. If a circuit has a total resistance of 10Ω and a total current of 2A, what is the total voltage supplied by the battery?
A.
5V
B.
10V
C.
15V
D.
20V
Show solution
Solution
Using Ohm's Law, V = I * R = 2A * 10Ω = 20V.
Correct Answer:
B
— 10V
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Q. If a circuit has a total resistance of 12Ω and a total current of 2A, what is the total voltage supplied by the battery?
A.
12 V
B.
24 V
C.
36 V
D.
48 V
Show solution
Solution
Using Ohm's law, V = I * R = 2A * 12Ω = 24 V.
Correct Answer:
B
— 24 V
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Q. If a circuit has a total resistance of 12Ω and a total voltage of 24V, what is the power consumed by the circuit?
A.
48 W
B.
24 W
C.
12 W
D.
36 W
Show solution
Solution
Power P = V^2 / R = (24V)^2 / 12Ω = 48 W.
Correct Answer:
A
— 48 W
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Q. If a circuit has a total resistance of 12Ω and a total voltage of 48V, what is the total current in the circuit?
A.
2 A
B.
3 A
C.
4 A
D.
6 A
Show solution
Solution
Using Ohm's law, I = V/R = 48V / 12Ω = 4 A.
Correct Answer:
C
— 4 A
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Q. If a circuit has a total resistance of 12Ω and a voltage of 24V, what is the power consumed by the circuit?
A.
48 W
B.
24 W
C.
12 W
D.
36 W
Show solution
Solution
Power P = V²/R = 24² / 12 = 48 W.
Correct Answer:
A
— 48 W
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Q. If a circuit has a total voltage of 24 V and a total resistance of 6 Ω, what is the current flowing through the circuit?
A.
2 A
B.
3 A
C.
4 A
D.
5 A
Show solution
Solution
Using Ohm's law, I = V/R = 24 V / 6 Ω = 4 A.
Correct Answer:
B
— 3 A
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Q. If a circuit has a total voltage of 24V and a total resistance of 8Ω, what is the power consumed?
A.
72 W
B.
48 W
C.
36 W
D.
24 W
Show solution
Solution
Power P = V^2 / R = 24V^2 / 8Ω = 72 W.
Correct Answer:
A
— 72 W
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Q. If a circuit has a voltage of 12 V and a resistance of 4 Ω, what is the current flowing through the circuit?
A.
3 A
B.
4 A
C.
2 A
D.
6 A
Show solution
Solution
Using Ohm's Law, I = V/R = 12 V / 4 Ω = 3 A.
Correct Answer:
A
— 3 A
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Q. If a conductor moves perpendicular to a magnetic field, what is the induced emf proportional to?
A.
Speed of the conductor
B.
Angle of movement
C.
Length of the conductor
D.
Both speed and length
Show solution
Solution
The induced emf is proportional to both the speed of the conductor and the length of the conductor when moving perpendicular to the magnetic field.
Correct Answer:
D
— Both speed and length
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Q. If a dielectric material with a dielectric constant of 4 is inserted into a capacitor, how does the capacitance change?
A.
It doubles
B.
It quadruples
C.
It halves
D.
It remains the same
Show solution
Solution
The capacitance increases by a factor equal to the dielectric constant. Thus, it quadruples.
Correct Answer:
B
— It quadruples
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