Physics Study Resources for Competitive Exam Success

Physics

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Q. A vehicle travels 100 km in 2 hours and then 50 km in 1 hour. What is its average speed for the entire trip? (2019)

A. 50 km/h
B. 60 km/h
C. 70 km/h
D. 75 km/h

Solution

Total distance = 100 km + 50 km = 150 km; Total time = 2 h + 1 h = 3 h. Average speed = Total distance / Total time = 150 km / 3 h = 50 km/h.

Correct Answer: C — 70 km/h

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Q. An object is dropped from a height of 20 m. How long will it take to reach the ground? (Take g = 10 m/s²)

A. 2 s
B. 4 s
C. 3 s
D. 5 s

Solution

Using the formula h = (1/2)gt², we have 20 = (1/2)(10)t², thus t² = 4, t = 2 s.

Correct Answer: B — 4 s

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Q. An object is in free fall. What is its acceleration?

A. 0 m/s²
B. 9.8 m/s²
C. 10 m/s²
D. 5 m/s²

Solution

In free fall, the only force acting on the object is gravity, so its acceleration is approximately 9.8 m/s².

Correct Answer: B — 9.8 m/s²

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Q. An object is moving with a velocity of 10 m/s. What is its kinetic energy if its mass is 2 kg? (2022)

A. 10 J
B. 20 J
C. 30 J
D. 40 J

Solution

Kinetic Energy = (1/2)mv² = (1/2) × 2 kg × (10 m/s)² = 100 J

Correct Answer: B — 20 J

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Q. An object is placed 10 cm from a convex lens with a focal length of 5 cm. What is the nature of the image formed? (2022)

A. Real and inverted
B. Virtual and erect
C. Real and erect
D. Virtual and inverted

Solution

Since the object distance is less than the focal length, the image formed is virtual and erect.

Correct Answer: B — Virtual and erect

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Q. An object is placed 15 cm in front of a convex lens of focal length 10 cm. What is the position of the image formed? (2020)

A. 5 cm
B. 10 cm
C. 30 cm
D. 15 cm

Solution

Using the lens formula: 1/f = 1/v - 1/u, where f = 10 cm and u = -15 cm, we find v = 30 cm.

Correct Answer: C — 30 cm

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Q. An object is placed 30 cm in front of a convex lens of focal length 15 cm. What is the image distance?

A. 10 cm
B. 15 cm
C. 20 cm
D. 25 cm

Solution

Using the lens formula 1/f = 1/v - 1/u, where u = -30 cm and f = 15 cm, we find v = 10 cm.

Correct Answer: A — 10 cm

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Q. An object is placed 30 cm in front of a convex lens of focal length 15 cm. What is the position of the image formed? (2020)

A. 10 cm
B. 15 cm
C. 20 cm
D. 25 cm

Solution

Using the lens formula 1/f = 1/v - 1/u, where u = -30 cm and f = 15 cm, we find v = 10 cm.

Correct Answer: D — 25 cm

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Q. An object is thrown horizontally from a height of 45 m. How long will it take to hit the ground? (Take g = 10 m/s²) (2022)

A. 3 s
B. 4 s
C. 5 s
D. 6 s

Solution

Using h = (1/2)gt², 45 = (1/2)(10)t². Solving gives t² = 9, so t = 3 s.

Correct Answer: B — 4 s

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Q. An object is thrown vertically upwards with a speed of 20 m/s. How high will it rise before coming to rest? (Take g = 10 m/s²) (2020)

A. 20 m
B. 40 m
C. 50 m
D. 80 m

Solution

Using the formula h = (u²)/(2g) = (20²)/(2 × 10) = 20 m.

Correct Answer: B — 40 m

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Q. An object moves in a straight line with a uniform speed of 10 m/s. How far will it travel in 15 seconds? (2023)

A. 100 m
B. 120 m
C. 150 m
D. 200 m

Solution

Distance = Speed × Time = 10 m/s × 15 s = 150 m.

Correct Answer: C — 150 m

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Q. An object moves in a straight line with a uniform speed of 30 m/s. How far will it travel in 15 seconds? (2022)

A. 300 m
B. 450 m
C. 600 m
D. 750 m

Solution

Distance = Speed × Time = 30 m/s × 15 s = 450 m.

Correct Answer: C — 600 m

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Q. An object moves with a uniform speed of 15 m/s. How far will it travel in 10 seconds? (2022)

A. 100 m
B. 150 m
C. 200 m
D. 250 m

Solution

Distance = Speed × Time = 15 m/s × 10 s = 150 m.

Correct Answer: B — 150 m

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Q. An object of mass 10 kg is moving with a velocity of 3 m/s. What is its kinetic energy? (2022)

A. 45 J
B. 30 J
C. 60 J
D. 15 J

Solution

Kinetic Energy (KE) = 0.5 × m × v² = 0.5 × 10 kg × (3 m/s)² = 45 J.

Correct Answer: B — 30 J

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Q. An object of mass 4 kg is moving with a velocity of 3 m/s. What is its kinetic energy? (2022)

A. 18 J
B. 24 J
C. 36 J
D. 12 J

Solution

Kinetic Energy (KE) = 1/2 mv² = 1/2 × 4 kg × (3 m/s)² = 18 J.

Correct Answer: B — 24 J

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Q. If 200 g of water at 80°C is mixed with 300 g of water at 20°C, what will be the final temperature of the mixture? (2019)

A. 30°C
B. 40°C
C. 50°C
D. 60°C

Solution

Using the formula m1c1T1 + m2c2T2 = (m1 + m2)cT, we find T = (200*80 + 300*20) / (200 + 300) = 40°C.

Correct Answer: B — 40°C

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Q. If a 10 kg object is lifted to a height of 5 m, what is the work done against gravity? (Use g = 9.8 m/s²) (2021)

A. 49 J
B. 98 J
C. 490 J
D. 245 J

Solution

Work done = mgh = 10 kg × 9.8 m/s² × 5 m = 490 J.

Correct Answer: C — 490 J

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Q. If a 10 ohm resistor is connected to a 5V battery, what is the current flowing through the resistor? (2020)

A. 0.5 A
B. 1 A
C. 2 A
D. 5 A

Solution

Using Ohm's law, I = V/R = 5V / 10Ω = 0.5 A.

Correct Answer: B — 1 A

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Q. If a 12 V battery is connected to a resistor of 4 ohms, what is the current flowing through the circuit?

A. 3 A
B. 4 A
C. 12 A
D. 0.33 A

Solution

Using Ohm's Law (I = V/R), I = 12 V / 4 Ω = 3 A.

Correct Answer: A — 3 A

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Q. If a 2 kg object is lifted to a height of 3 m, what is the potential energy gained? (Use g = 9.8 m/s²) (2020)

A. 58.8 J
B. 19.6 J
C. 29.4 J
D. 39.2 J

Solution

Potential Energy = mass × g × height = 2 kg × 9.8 m/s² × 3 m = 58.8 J

Correct Answer: A — 58.8 J

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Q. If a 2 kg object is lifted to a height of 3 m, what is the potential energy gained by the object? (Use g = 9.8 m/s²)

A. 58.8 J
B. 19.6 J
C. 29.4 J
D. 39.2 J

Solution

Potential Energy (PE) = mgh = 2 kg × 9.8 m/s² × 3 m = 58.8 J.

Correct Answer: A — 58.8 J

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Q. If a 2 kg object is lifted to a height of 3 m, what is the potential energy gained by the object? (Take g = 9.8 m/s²) (2020)

A. 58.8 J
B. 19.6 J
C. 29.4 J
D. 39.2 J

Solution

Potential Energy (PE) = mgh = 2 kg × 9.8 m/s² × 3 m = 58.8 J.

Correct Answer: A — 58.8 J

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Q. If a 2 kg object is lifted to a height of 3 m, what is the work done against gravity? (Use g = 9.8 m/s²) (2023)

A. 58.8 J
B. 39.2 J
C. 19.6 J
D. 29.4 J

Solution

Work done = mgh = 2 kg × 9.8 m/s² × 3 m = 58.8 J.

Correct Answer: A — 58.8 J

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Q. If a 5 kg object is lifted to a height of 2 m, what is the potential energy gained by the object? (Use g = 9.8 m/s²) (2020)

A. 49 J
B. 98 J
C. 19.6 J
D. 39.2 J

Solution

Potential Energy = mgh = 5 kg × 9.8 m/s² × 2 m = 98 J

Correct Answer: B — 98 J

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Q. If a body is moving with a uniform acceleration of 2 m/s², what will be its velocity after 5 seconds if it starts from rest? (2023)

A. 5 m/s
B. 10 m/s
C. 15 m/s
D. 20 m/s

Solution

Using the formula v = u + at, where u = 0, a = 2 m/s², t = 5 s. v = 0 + (2 × 5) = 10 m/s.

Correct Answer: B — 10 m/s

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Q. If a car accelerates from rest at a rate of 2 m/s², what will be its speed after 5 seconds? (2023)

A. 5 m/s
B. 10 m/s
C. 15 m/s
D. 20 m/s

Solution

Speed = Initial speed + (Acceleration × Time) = 0 + (2 m/s² × 5 s) = 10 m/s.

Correct Answer: B — 10 m/s

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Q. If a car accelerates uniformly from rest to a speed of 25 m/s in 10 seconds, what is the distance covered during this time? (2023)

A. 125 m
B. 150 m
C. 200 m
D. 250 m

Solution

Distance = ut + (1/2)at². Here, u = 0, a = (25-0)/10 = 2.5 m/s². Distance = 0 + (1/2)(2.5)(10²) = 125 m.

Correct Answer: A — 125 m

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Q. If a car accelerates uniformly from rest to a speed of 72 km/h in 10 seconds, what is its acceleration? (2023)

A. 2 m/s²
B. 3 m/s²
C. 4 m/s²
D. 5 m/s²

Solution

Acceleration = (Final Speed - Initial Speed) / Time = (20 m/s - 0) / 10 s = 2 m/s².

Correct Answer: A — 2 m/s²

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Q. If a car does 2000 J of work in moving a distance of 50 m, what is the average force exerted? (2023)

A. 40 N
B. 50 N
C. 60 N
D. 30 N

Solution

Average Force = Work / Distance = 2000 J / 50 m = 40 N

Correct Answer: A — 40 N

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Q. If a car does 2000 J of work in moving a distance of 50 m, what is the average force exerted by the car? (2000)

A. 40 N
B. 50 N
C. 60 N
D. 30 N

Solution

Average Force (F) = Work done (W) / Distance (d) = 2000 J / 50 m = 40 N.

Correct Answer: A — 40 N

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Physics

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