The constant term occurs when x^0, which is the term with k = 4: C(4, 4)(-2)^4 = 16, thus the constant term is -16.

The number of terms in the expansion of (a + b)^n is n + 1, so for n = 7, there will be 8 terms.

The term containing x^0 occurs when k = 3, which gives 6C3 * 1^3 * (1/x)^3 = 20.

C(n,k) represents the number of ways to choose k items from n, which corresponds to the coefficient of x^k.

In the expansion of (x + y)^5, the term x^3y^2 corresponds to the 4th term, calculated using the formula C(5, 2)x^3y^2.

In the term x^4y^2, the sum of the exponents (4 + 2) must equal n, hence n = 6.

The sum of the exponents in the term x^4y^3 is 4 + 3 = 7, hence n must be 7.

The number of terms n can be calculated using the formula: n = (last - first) / difference + 1. Here, n = (50 - 10) / 5 + 1 = 9.

The nth term of an arithmetic sequence is given by a + (n-1)d. Here, a = 5, d = 3, n = 10. So, 5 + (10-1)3 = 32.

Substituting n = 7 into the formula gives a_7 = 5*7 - 3 = 35 - 3 = 32.

The 4th term is 4^2 + 4 = 16 + 4 = 20.

The probability of failing is 1 - P(passing) = 1 - 0.75 = 0.25.

The probability of either A or B occurring is P(A) + P(B) - P(A and B) = 0.2 + 0.5 - (0.2 * 0.5) = 0.7.

For independent events, P(A and B) = P(A) * P(B) = 0.4 * 0.5 = 0.2.

For mutually exclusive events, P(C or D) = P(C) + P(D) = 0.2 + 0.3 = 0.5.

The probability that it will not rain is 1 - 0.7 = 0.3.

A constant ratio of consecutive terms indicates that the series is exponential.

The constant ratio of consecutive terms in a geometric series is called the common ratio.

The constant ratio of consecutive terms in a geometric series is called the common ratio.

If all squares are rectangles, it implies that there are rectangles that are not squares, thus some rectangles are not squares.

A triangle with one angle measuring 90 degrees is classified as a right triangle, as it adheres to the property of having one angle equal to 90 degrees.

A triangle with one angle measuring 90 degrees is defined as a right triangle.

Using the formula for the sum of a geometric series, S_n = a(1 - r^n) / (1 - r), we can solve for r. Here, S_5 = 1(1 - r^5) / (1 - r) = 31, leading to r = 3.

The common difference can be found by calculating S_n - S_(n-1). Here, S_n = 3n^2 + 2n and S_(n-1) = 3(n-1)^2 + 2(n-1). The difference simplifies to 4.

The 4th term can be found using T_n = S_n - S_(n-1). Here, S_4 = 5(4) + 3 = 23 and S_3 = 5(3) + 3 = 18. Thus, T_4 = 23 - 18 = 5.

The common difference can be found by calculating S_n - S_(n-1). This gives the common difference as 5.

The 10th term can be found using T_n = S_n - S_(n-1). Here, S_10 = 5(10) + 3 = 53 and S_9 = 5(9) + 3 = 48. Thus, T_10 = 53 - 48 = 5.

'd' represents the common difference in an arithmetic series.

'a' represents the first term of the arithmetic series.

The complement of A in U is the set of elements in U that are not in A, which is {1, 3, 5, 7, 9, 10}.