Area = πr². 154 = (22/7)r². Solving gives r² = 154 * 7 / 22 = 49, so r = 7 units.

Area = base × height. Thus, 120 = 15 × height, giving height = 120/15 = 8 meters.

Area = base × height. Thus, 120 = 15 × height, giving height = 120/15 = 8 units.

If the height of a parallelogram is halved, the area is also halved, as area = base × height.

This formula applies to a kite, where the diagonals intersect at an angle.

In the formula for the area of a quadrilateral, d1 and d2 represent the lengths of the diagonals.

Area = (d1 × d2) / 2. 72 = (12 × d2) / 2, so d2 = 12 cm.

Area = (1/2) × d1 × d2. Thus, 72 = (1/2) × 12 × d2, giving d2 = 12 cm.

Area of a sector = (θ/360) × πr². Thus, 25π = (θ/360) × π(10)². Solving gives θ = 90 degrees.

Area of a sector = (θ/360) × πr². Thus, 25π = (θ/360) × π(5)². Solving gives θ = 90°.

Area of a sector = (θ/360) × πr². Thus, 30 = (θ/360) × π × 25. Solving gives θ = (30 × 360)/(25π) ≈ 72°.

Area of a square = side². Therefore, side = √64 = 8 cm.

Area = side². Thus, 64 = side², giving side = √64 = 8 meters.

Area = side². Thus, side = √64 = 8 units.

Area = (1/2) × (a + b) × height. 60 = (1/2) × (10 + 14) × height. Solving gives height = 5 cm.

Area = (1/2) × (base1 + base2) × height. Thus, 60 = (1/2) × (10 + 20) × height, giving height = 60 / 15 = 4 units.

Area = (1/2) × (base1 + base2) × height. Thus, 60 = (1/2) × (10 + 20) × height, giving height = 60 / 15 = 4 units.

Area = 1/2 * base * height. Therefore, 24 = 1/2 * 8 * height, which gives height = 6 cm.

The area of a triangle is given by the formula Area = 1/2 * base * height. Thus, 24 = 1/2 * 8 * height, which gives height = 6 cm.

Area of a triangle = (1/2) × base × height. Thus, 50 = (1/2) × 10 × height. Solving gives height = 10 cm.

Area of a triangle = (1/2) × base × height. Thus, 50 = (1/2) × 10 × height. Solving gives height = 10 units.

Substituting the values into the area formula: A = 1/2 * 10 * 5 = 25 cm².

Circumference = 2πr. Therefore, r = circumference / (2π) = 31.4 / (2 * 3.14) = 5 cm.

Using the formula C = 2πr, we find r = C/(2π) = 31.4/(2*3.14) = 5 cm.

Solving the equations x + y = 10 and x - y = 2 simultaneously gives x = 6 and y = 4.

Setting y = 0 in the equation -3x + 6 = 0 gives x = 2.

The slope m is calculated as (y2 - y1) / (x2 - x1) = (7 - 3) / (4 - 2) = 4/2 = 2.

The diagonal d of a square is related to the side length s by the formula d = s√2. Therefore, s = d/√2 = 10√2/√2 = 10 cm. The area is s² = 10² = 100 cm².

If the diagonals of a quadrilateral are equal and bisect each other, it can be classified as a rectangle.

If the diagonals of a quadrilateral bisect each other at right angles, it indicates that the quadrilateral is a rhombus.