The phase velocity v is given by v = ω/k.

In the wave equation y(x, t) = A sin(kx - ωt), A represents the amplitude of the wave, which is the maximum displacement from the equilibrium position.

The amplitude of the wave is given directly by A in the wave equation. Here, A = 2 m.

'A' represents the amplitude of the wave, which is the maximum displacement from the equilibrium position.

Wavelength λ is given by λ = v/f. Here, v = 300 m/s and f = 150 Hz. Thus, λ = 300/150 = 2.0 m.

The wavelength λ can be calculated using the formula v = fλ. Thus, λ = v/f = 300 m/s / 150 Hz = 2 m.

The speed of a wave is given by the formula v = fλ, where f is the frequency and λ is the wavelength. Here, v = 500 Hz * 2 m = 1000 m/s.

Wavelength λ = v/f = 300/150 = 2 m.

The wavelength λ can be calculated using the formula v = fλ. Thus, λ = v/f = 300 m/s / 150 Hz = 2 m.

Wavelength (λ) can be calculated using the formula λ = v/f. Here, λ = 300 m/s / 150 Hz = 2 m.

The speed of the wave is given by v = fλ. Here, v = 500 Hz * 2 m = 1000 m/s.

Wavelength (λ) can be calculated using the formula λ = v/f. Here, λ = 300 m/s / 150 Hz = 2 m.

The damped frequency is less than the natural frequency due to the effect of damping.

A damping ratio (ζ) < 1 indicates underdamped motion.

Natural frequency (ω_n) = √(k/m) = √(20/5) = √4 = 2 Hz.

At frequencies much lower than the natural frequency, the amplitude of the forced oscillator increases significantly.

Time period (T) is the reciprocal of frequency (f). T = 1/f = 1/1 = 1 s.

The amplitude of a simple harmonic oscillator is defined as the maximum displacement from the equilibrium position, which is 5 cm in this case.

The total energy E is conserved. When the displacement is half the amplitude, the potential energy is (1/2)E, so the kinetic energy is E - (1/2)E = (1/2)E.

The period (T) is the inverse of frequency (f); T = 1/f = 1/440 ≈ 0.00227 s.

Using the formula A(t) = A_0 e^(-ζω_nt), we find ζ = 0.2.

Maximum velocity V_max = Aω. If A is doubled, V_max also doubles.

The total energy E in SHM is given by E = (1/2)kA². If A is doubled, E becomes (1/2)k(2A)² = 4(1/2)kA², which is quadrupled.

Maximum velocity V_max = ωA. If A is halved, V_max is also halved.

The total energy in simple harmonic motion is proportional to the square of the amplitude. If amplitude is doubled, energy increases by a factor of 2^2 = 4.

The total energy of a simple harmonic oscillator is proportional to the square of the amplitude. If the amplitude is doubled, the energy increases by a factor of 2^2 = 4.

The total energy in SHM is proportional to the square of the amplitude. If amplitude is halved, energy is reduced to (1/2)^2 = 1/4, which is halved.

The energy of a wave is proportional to the square of the amplitude. If the amplitude is doubled, the energy increases by a factor of 2^2 = 4.

The energy of a wave is proportional to the square of its amplitude. Therefore, if the amplitude is doubled, the energy increases by a factor of four.

Energy is proportional to the square of the amplitude, so if amplitude is tripled, energy increases by a factor of 3^2 = 9.