The angle for the first minimum in single-slit diffraction is given by a sin θ = λ, hence θ = λ/a.

The angle of the first minimum in single-slit diffraction is given by sin(θ) = λ/a, where a is the width of the slit.

Work done = mgh = 2 kg * 9.8 m/s² * 5 m = 98 J.

Using Newton's second law, F = ma. Here, F = 10 N and m = 2 kg. Therefore, a = F/m = 10/2 = 5 m/s².

Using conservation of energy, potential energy at the top = kinetic energy at the bottom. mgh = 0.5mv². Thus, v = sqrt(2gh) = sqrt(2 * 9.8 * 10) = 14 m/s.

Using conservation of energy, potential energy at the top = kinetic energy at the bottom. mgh = 0.5mv². Thus, v = sqrt(2gh) = sqrt(2 * 9.81 * 5) = 10 m/s.

Using conservation of energy, potential energy at the top (mgh) converts to kinetic energy at the bottom (1/2 mv²). Thus, v = sqrt(2gh) = sqrt(2 * 9.8 * 5) ≈ 10 m/s.

Net force = Applied force - Frictional force = 20 N - 5 N = 15 N. Using F = ma, a = F/m = 15 N / 5 kg = 3 m/s².

Using Newton's second law, F = ma, acceleration (a) = F/m = 10 N / 5 kg = 2 m/s².

Acceleration a = F/m = 15 N / 5 kg = 3 m/s². Velocity after 3 seconds = a × t = 3 m/s² × 3 s = 9 m/s.

Using F = ma, acceleration a = F/m = 15 N / 5 kg = 3 m/s².

Acceleration a = g sin(θ) = 9.8 m/s² × sin(30°) = 4.9 m/s².

Total balls = 4 + 6 = 10. Probability of black ball = 6/10 = 3/5.

Total balls = 4 + 6 = 10. Probability of black ball = 6/10 = 3/5.

Total balls = 5 + 3 = 8. Probability of black ball = 3/8.

Total balls = 5 + 3 = 8. Probability of black ball = 3/8.

Capacitive reactance XC = 1/(2πfC) = 1/(2π*50*10e-6) ≈ 318.3Ω.

Capacitive reactance Xc = 1/(ωC) where ω = 2πf. Calculate Xc.

The capacitive reactance is given by XC = 1/(2πfC).

Using the equation of motion: s = ut + (1/2)at². Here, u = 0, a = 2 m/s², t = 5 s. So, s = 0 + (1/2)(2)(5²) = 25 m.

Using the formula v = u + at, where u = 0, a = 2 m/s², and t = 5 s, we get v = 0 + 2 * 5 = 10 m/s.

Acceleration is calculated using the formula a = (final velocity - initial velocity) / time. Here, a = (20 m/s - 0 m/s) / 5 s = 4 m/s².

Kinetic Energy (KE) = 0.5 × m × v² = 0.5 × 1000 kg × (20 m/s)² = 0.5 × 1000 × 400 = 200000 J.

Kinetic Energy (KE) = 0.5 × m × v² = 0.5 × 1000 kg × (20 m/s)² = 0.5 × 1000 × 400 = 200,000 J.

Kinetic Energy (KE) = 0.5 × m × v² = 0.5 × 1000 kg × (20 m/s)² = 0.5 × 1000 × 400 = 200000 J.

Acceleration (a) = (final velocity - initial velocity) / time = (30 m/s - 0) / 10 s = 3 m/s².

Average Force = Work done / Distance = 5000 J / 100 m = 50 N

Using the formula: distance = initial velocity * time + 0.5 * acceleration * time^2. Here, acceleration = (0 - 30) / 6 = -5 m/s². Distance = 30 * 6 + 0.5 * (-5) * 6^2 = 180 - 90 = 90 m.

Kinetic Energy = 0.5 * m * v² = 0.5 * 1000 kg * (20 m/s)² = 200,000 J.

Number of hearts = 13. Probability = 13/52 = 1/4.