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Q. A 10 kg object is moving with a velocity of 5 m/s. What is its momentum?

A. 10 kg·m/s
B. 25 kg·m/s
C. 50 kg·m/s
D. 75 kg·m/s

Solution

Momentum p = mv = 10 kg * 5 m/s = 50 kg·m/s.

Correct Answer: C — 50 kg·m/s

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Q. A 10 kg object is pushed with a force of 30 N. If the frictional force is 10 N, what is the net force?

A. 10 N
B. 20 N
C. 30 N
D. 40 N

Solution

Net force = applied force - friction = 30 N - 10 N = 20 N.

Correct Answer: B — 20 N

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Q. A 10 kg object is subjected to a net force of 30 N. What is its acceleration? (2022)

A. 2 m/s²
B. 3 m/s²
C. 4 m/s²
D. 5 m/s²

Solution

Using F = ma, acceleration a = F/m = 30 N / 10 kg = 3 m/s².

Correct Answer: B — 3 m/s²

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Q. A 10 kg object is subjected to a net force of 30 N. What is the object's acceleration? (2019)

A. 1 m/s²
B. 2 m/s²
C. 3 m/s²
D. 4 m/s²

Solution

Using F = ma, a = F/m = 30 N / 10 kg = 3 m/s².

Correct Answer: C — 3 m/s²

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Q. A 10 kg object is thrown upwards with a speed of 15 m/s. What is the maximum height it reaches? (g = 9.8 m/s²)

A. 11.5 m
B. 22.5 m
C. 15.3 m
D. 10.0 m

Solution

Using conservation of energy, KE at the bottom = PE at the top. 0.5mv² = mgh. Solving gives h = v²/(2g) = (15)²/(2*9.8) = 11.5 m.

Correct Answer: A — 11.5 m

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Q. A 10 kg object is thrown upwards with a velocity of 15 m/s. What is the maximum height it reaches? (g = 9.8 m/s²)

A. 11.5 m
B. 22.5 m
C. 15.0 m
D. 7.5 m

Solution

Using energy conservation: KE_initial = PE_max; 0.5 * m * v² = mgh; h = v² / (2g) = (15 m/s)² / (2 * 9.8 m/s²) = 11.5 m.

Correct Answer: A — 11.5 m

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Q. A 10 kg object is thrown vertically upward with a speed of 20 m/s. What is the maximum height reached by the object? (g = 10 m/s²) (2020)

A. 20 m
B. 30 m
C. 40 m
D. 50 m

Solution

Using the formula h = v² / (2g), h = (20 m/s)² / (2 * 10 m/s²) = 20 m.

Correct Answer: B — 30 m

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Q. A 10 kg object is thrown vertically upwards with a speed of 15 m/s. What is the maximum height it reaches? (g = 10 m/s²)

A. 11.25 m
B. 22.5 m
C. 15 m
D. 7.5 m

Solution

Using energy conservation: KE_initial = PE_max; 1/2 * m * v^2 = m * g * h; h = v^2 / (2g) = (15^2) / (2 * 10) = 11.25 m

Correct Answer: A — 11.25 m

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Q. A 10 kg object is thrown vertically upwards with a velocity of 20 m/s. What is the maximum height it reaches? (g = 10 m/s²) (2023)

A. 20 m
B. 40 m
C. 30 m
D. 10 m

Solution

Using the formula h = (v²)/(2g) = (20 m/s)² / (2 × 10 m/s²) = 20 m.

Correct Answer: B — 40 m

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Q. A 10 N force is applied at an angle of 60° to the horizontal while moving an object 4 m. What is the work done?

A. 20 J
B. 40 J
C. 30 J
D. 10 J

Solution

Work done (W) = F × d × cos(θ) = 10 N × 4 m × cos(60°) = 10 × 4 × 0.5 = 20 J.

Correct Answer: C — 30 J

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Q. A 10 N force is applied to move an object 3 m. What is the work done if the force is applied at an angle of 60 degrees to the direction of motion?

A. 15 J
B. 30 J
C. 25 J
D. 20 J

Solution

Work done = Force × Distance × cos(θ) = 10 N × 3 m × cos(60°) = 10 N × 3 m × 0.5 = 15 J

Correct Answer: A — 15 J

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Q. A 10 Ω resistor and a 20 Ω resistor are connected in series. What is the total resistance?

A. 10 Ω
B. 20 Ω
C. 30 Ω
D. 5 Ω

Solution

In series, the total resistance R = R1 + R2 = 10 Ω + 20 Ω = 30 Ω.

Correct Answer: C — 30 Ω

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Q. A 10 Ω resistor is connected to a 20 V battery. What is the current flowing through the resistor?

A. 2 A
B. 0.5 A
C. 5 A
D. 10 A

Solution

Using Ohm's law, V = IR, where V = 20 V and R = 10 Ω. Therefore, I = V/R = 20/10 = 2 A.

Correct Answer: A — 2 A

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Q. A 10-ohm resistor and a 20-ohm resistor are connected in series. What is the total resistance?

A. 10 ohms
B. 20 ohms
C. 30 ohms
D. 5 ohms

Solution

In series, the total resistance R = R1 + R2 = 10 + 20 = 30 ohms.

Correct Answer: C — 30 ohms

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Q. A 10-ohm resistor has a voltage of 20 volts across it. What is the current flowing through the resistor?

A. 1 A
B. 2 A
C. 3 A
D. 4 A

Solution

Using Ohm's Law, I = V / R = 20 V / 10 Ω = 2 A.

Correct Answer: B — 2 A

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Q. A 10-ohm resistor has a voltage of 50 volts across it. What is the current flowing through the resistor?

A. 5 A
B. 10 A
C. 15 A
D. 20 A

Solution

Using Ohm's Law, I = V / R = 50 V / 10 Ω = 5 A.

Correct Answer: B — 10 A

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Q. A 10-ohm resistor is connected to a 20-volt battery. What is the power consumed by the resistor? (2021)

A. 20 W
B. 40 W
C. 10 W
D. 2 W

Solution

Power (P) can be calculated using the formula P = V^2 / R. Here, P = 20^2 / 10 = 400 / 10 = 40 W.

Correct Answer: B — 40 W

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Q. A 10-ohm resistor is connected to a 20-volt battery. What is the power dissipated by the resistor?

A. 40 W
B. 20 W
C. 10 W
D. 2 W

Solution

Power (P) can be calculated using P = V^2 / R = 20^2 / 10 = 400 / 10 = 40 W.

Correct Answer: A — 40 W

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Q. A 100 g piece of metal at 100°C is placed in 200 g of water at 20°C. What will be the final temperature of the system? (Specific heat of water = 4.2 J/g°C, specific heat of metal = 0.5 J/g°C) (2023)

A. 30°C
B. 40°C
C. 50°C
D. 60°C

Solution

Using the heat transfer equation, we can find the final temperature to be 50°C.

Correct Answer: C — 50°C

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Q. A 100 g piece of metal at 150°C is placed in 200 g of water at 25°C. What is the final temperature of the system assuming no heat loss? (2019)

A. 30°C
B. 40°C
C. 50°C
D. 60°C

Solution

Using the principle of conservation of energy, we can calculate the final temperature to be 50°C.

Correct Answer: C — 50°C

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Q. A 100 W bulb is connected to a 220 V supply. What is the current flowing through the bulb?

A. 0.45 A
B. 1.0 A
C. 2.2 A
D. 2.5 A

Solution

Using the formula P = VI, where P = 100 W and V = 220 V, the current I = P/V = 100/220 ≈ 0.45 A.

Correct Answer: A — 0.45 A

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Q. A 100 W bulb is used for 5 hours. How much energy does it consume? (2016)

A. 500 Wh
B. 1000 Wh
C. 200 Wh
D. 250 Wh

Solution

Energy consumed = Power × Time = 100 W × 5 h = 500 Wh.

Correct Answer: A — 500 Wh

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Q. A 1000 kg car accelerates from rest to a speed of 20 m/s in 10 seconds. What is the average power exerted by the engine?

A. 2000 W
B. 4000 W
C. 5000 W
D. 6000 W

Solution

First, calculate the work done: W = (1/2)mv^2 = (1/2)(1000 kg)(20 m/s)^2 = 200000 J. Then, power is P = W/t = 200000 J / 10 s = 20000 W.

Correct Answer: C — 5000 W

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Q. A 1000 kg car is moving at a speed of 15 m/s. What is its kinetic energy?

A. 112,500 J
B. 75,000 J
C. 50,000 J
D. 25,000 J

Solution

Kinetic Energy = 0.5 * m * v² = 0.5 * 1000 kg * (15 m/s)² = 112,500 J.

Correct Answer: A — 112,500 J

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Q. A 1000 kg car is moving at a speed of 20 m/s. What is its momentum? (2000)

A. 2000 kg m/s
B. 10000 kg m/s
C. 5000 kg m/s
D. 4000 kg m/s

Solution

Momentum (p) is calculated using the formula p = m * v. Here, p = 1000 kg * 20 m/s = 20000 kg m/s.

Correct Answer: B — 10000 kg m/s

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Q. A 1000 kg car is moving at a speed of 36 km/h. What is its kinetic energy? (1 km/h = 1/3.6 m/s) (2000)

A. 500 J
B. 1000 J
C. 2000 J
D. 5000 J

Solution

First convert speed: 36 km/h = 10 m/s. KE = 0.5 × m × v² = 0.5 × 1000 kg × (10 m/s)² = 0.5 × 1000 × 100 = 50000 J.

Correct Answer: C — 2000 J

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Q. A 1000 W electric motor runs for 2 hours. How much work does it do? (2023)

A. 720,000 J
B. 1,000,000 J
C. 2,000,000 J
D. 1,440,000 J

Solution

Work = Power × Time = 1000 W × (2 × 3600 s) = 7,200,000 J.

Correct Answer: D — 1,440,000 J

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Q. A 1000 W heater is used to heat water. How much heat is supplied in 10 minutes? (2020)

A. 600 kJ
B. 300 kJ
C. 100 kJ
D. 150 kJ

Solution

Heat (Q) = Power (P) * Time (t) = 1000 W * 600 s = 600 kJ.

Correct Answer: A — 600 kJ

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Q. A 1000 W heater operates for 1 hour. How much energy does it consume?

A. 3600 J
B. 1000 J
C. 3600000 J
D. 100000 J

Solution

Energy consumed is E = P * t. Here, P = 1000 W and t = 1 hour = 3600 seconds. Thus, E = 1000 W * 3600 s = 3600000 J.

Correct Answer: C — 3600000 J

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Q. A 1000 W heater operates for 2 hours. How much energy does it consume?

A. 7200000 J
B. 2000000 J
C. 3600000 J
D. 1000000 J

Solution

Energy consumed can be calculated using E = P * t. Here, P = 1000 W and t = 2 hours = 7200 seconds. Thus, E = 1000 W * 7200 s = 7200000 J.

Correct Answer: C — 3600000 J

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Major Competitive Exams

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