Major Competitive Exams MCQ & Objective Questions
Major Competitive Exams play a crucial role in shaping the academic and professional futures of students in India. These exams not only assess knowledge but also test problem-solving skills and time management. Practicing MCQs and objective questions is essential for scoring better, as they help in familiarizing students with the exam format and identifying important questions that frequently appear in tests.
What You Will Practise Here
Key concepts and theories related to major subjects
Important formulas and their applications
Definitions of critical terms and terminologies
Diagrams and illustrations to enhance understanding
Practice questions that mirror actual exam patterns
Strategies for solving objective questions efficiently
Time management techniques for competitive exams
Exam Relevance
The topics covered under Major Competitive Exams are integral to various examinations such as CBSE, State Boards, NEET, and JEE. Students can expect to encounter a mix of conceptual and application-based questions that require a solid understanding of the subjects. Common question patterns include multiple-choice questions that test both knowledge and analytical skills, making it essential to be well-prepared with practice MCQs.
Common Mistakes Students Make
Rushing through questions without reading them carefully
Overlooking the negative marking scheme in MCQs
Confusing similar concepts or terms
Neglecting to review previous years’ question papers
Failing to manage time effectively during the exam
FAQs
Question: How can I improve my performance in Major Competitive Exams?Answer: Regular practice of MCQs and understanding key concepts will significantly enhance your performance.
Question: What types of questions should I focus on for these exams?Answer: Concentrate on important Major Competitive Exams questions that frequently appear in past papers and mock tests.
Question: Are there specific strategies for tackling objective questions?Answer: Yes, practicing under timed conditions and reviewing mistakes can help develop effective strategies.
Start your journey towards success by solving practice MCQs today! Test your understanding and build confidence for your upcoming exams. Remember, consistent practice is the key to mastering Major Competitive Exams!
Q. If the resistances in a Wheatstone bridge are equal, what is the potential difference across the galvanometer?
A.
Zero
B.
Equal to the supply voltage
C.
Half of the supply voltage
D.
Depends on the resistances
Show solution
Solution
If the resistances are equal, the potential difference across the galvanometer is zero.
Correct Answer:
A
— Zero
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Q. If the resistances in a Wheatstone bridge are P = 10Ω, Q = 15Ω, R = 5Ω, and S = xΩ, what is the value of x for the bridge to be balanced?
A.
7.5Ω
B.
10Ω
C.
12.5Ω
D.
15Ω
Show solution
Solution
For balance, P/Q = R/S => 10/15 = 5/x => x = 7.5Ω.
Correct Answer:
C
— 12.5Ω
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Q. If the resistances in a Wheatstone bridge are P = 3Ω, Q = 6Ω, R = 1.5Ω, and S = 3Ω, is the bridge balanced?
A.
Yes
B.
No
C.
Cannot be determined
D.
Only if P = R
Show solution
Solution
The bridge is not balanced because P/Q ≠ R/S.
Correct Answer:
B
— No
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Q. If the resistances in a Wheatstone bridge are R1 = 10Ω, R2 = 15Ω, R3 = 5Ω, and R4 = xΩ, what value of x will balance the bridge?
A.
7.5Ω
B.
10Ω
C.
12.5Ω
D.
15Ω
Show solution
Solution
Using the balance condition R1/R2 = R3/R4, we have 10/15 = 5/x, solving gives x = 7.5Ω.
Correct Answer:
A
— 7.5Ω
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Q. If the resistances in a Wheatstone bridge are R1 = 10Ω, R2 = 15Ω, R3 = 5Ω, and R4 = 7.5Ω, is the bridge balanced?
A.
Yes
B.
No
C.
Depends on the voltage
D.
Not enough information
Show solution
Solution
The bridge is balanced if R1/R2 = R3/R4. Here, 10/15 = 5/7.5, which simplifies to 2/3 = 2/3, confirming the bridge is balanced.
Correct Answer:
A
— Yes
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Q. If the resistances in a Wheatstone bridge are R1 = 10Ω, R2 = 15Ω, R3 = 5Ω, what is the value of R4 for the bridge to be balanced?
A.
7.5Ω
B.
10Ω
C.
12.5Ω
D.
15Ω
Show solution
Solution
Using the balance condition R1/R2 = R3/R4, we have 10/15 = 5/R4. Solving gives R4 = 7.5Ω.
Correct Answer:
C
— 12.5Ω
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Q. If the resistances in a Wheatstone bridge are R1 = 10Ω, R2 = 15Ω, R3 = 5Ω, what should R4 be for the bridge to be balanced?
A.
7.5Ω
B.
10Ω
C.
12.5Ω
D.
15Ω
Show solution
Solution
Using the balance condition R1/R2 = R3/R4, we find R4 = (R2 * R3) / R1 = (15 * 5) / 10 = 7.5Ω.
Correct Answer:
C
— 12.5Ω
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Q. If the resistances in a Wheatstone bridge are R1 = 10Ω, R2 = 20Ω, R3 = 15Ω, what is the value of R4 for the bridge to be balanced?
A.
30Ω
B.
20Ω
C.
15Ω
D.
10Ω
Show solution
Solution
Using the balance condition R1/R2 = R3/R4, we find R4 = (R2 * R3) / R1 = (20 * 15) / 10 = 30Ω.
Correct Answer:
B
— 20Ω
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Q. If the resistances in a Wheatstone bridge are R1 = 10Ω, R2 = 20Ω, R3 = 15Ω, what should R4 be for the bridge to be balanced?
A.
30Ω
B.
15Ω
C.
20Ω
D.
10Ω
Show solution
Solution
Using the balance condition R1/R2 = R3/R4, we find R4 = (R2 * R3) / R1 = (20 * 15) / 10 = 30Ω.
Correct Answer:
B
— 15Ω
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Q. If the resistances in a Wheatstone bridge are R1 = 20Ω, R2 = 30Ω, and R3 = 10Ω, what is the value of R4 for the bridge to be balanced?
A.
15Ω
B.
20Ω
C.
25Ω
D.
30Ω
Show solution
Solution
Using the balance condition R1/R2 = R3/R4, we have 20/30 = 10/x, solving gives x = 20Ω.
Correct Answer:
B
— 20Ω
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Q. If the resistances in a Wheatstone bridge are R1, R2, R3, and R4, what is the condition for balance?
A.
R1/R2 = R3/R4
B.
R1 + R2 = R3 + R4
C.
R1 * R4 = R2 * R3
D.
R1 - R2 = R3 - R4
Show solution
Solution
The condition for balance in a Wheatstone bridge is R1/R2 = R3/R4.
Correct Answer:
A
— R1/R2 = R3/R4
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Q. If the resistivity of a material is 1.5 x 10^-8 Ω·m, what is the resistance of a 3 m long wire with a cross-sectional area of 0.5 mm²?
A.
0.09 Ω
B.
0.18 Ω
C.
0.27 Ω
D.
0.36 Ω
Show solution
Solution
Resistance R = ρ(L/A) = (1.5 x 10^-8)(3)/(0.5 x 10^-6) = 0.09 Ω.
Correct Answer:
B
— 0.18 Ω
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Q. If the resistivity of a material is 2 x 10^-8 Ω·m and the wire has a length of 3 m and a cross-sectional area of 0.5 mm², what is the resistance?
A.
0.12 Ω
B.
0.15 Ω
C.
0.18 Ω
D.
0.20 Ω
Show solution
Solution
Resistance R = ρ * (L / A) = 2 x 10^-8 * (3 / 0.5 x 10^-6) = 0.12 Ω.
Correct Answer:
A
— 0.12 Ω
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Q. If the resistivity of a material is doubled, what happens to the resistance of a wire of constant length and cross-sectional area?
A.
It doubles
B.
It halves
C.
It remains the same
D.
It quadruples
Show solution
Solution
Resistance R is directly proportional to resistivity ρ, so if ρ is doubled, R also doubles.
Correct Answer:
A
— It doubles
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Q. If the resistivity of a material is doubled, what happens to the resistance of a wire of fixed length and cross-sectional area?
A.
It doubles
B.
It halves
C.
It remains the same
D.
It quadruples
Show solution
Solution
Resistance R is directly proportional to resistivity; if resistivity doubles, resistance also doubles.
Correct Answer:
A
— It doubles
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Q. If the resistivity of a material is halved, what happens to the resistance of a wire of fixed length and cross-sectional area?
A.
Halved
B.
Doubled
C.
Remains the same
D.
Quadrupled
Show solution
Solution
Resistance is directly proportional to resistivity; halving resistivity halves the resistance.
Correct Answer:
A
— Halved
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Q. If the resistivity of a material is halved, what happens to the resistance of a uniform wire of that material?
A.
Halved
B.
Doubled
C.
Remains the same
D.
Quadrupled
Show solution
Solution
Resistance is directly proportional to resistivity; halving resistivity halves the resistance.
Correct Answer:
A
— Halved
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Q. If the resistivity of a material is halved, what will happen to the resistance of a wire of fixed length and cross-sectional area?
A.
Halved
B.
Doubled
C.
Remains the same
D.
Quadrupled
Show solution
Solution
Resistance is directly proportional to resistivity; halving resistivity halves the resistance.
Correct Answer:
A
— Halved
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Q. If the resistivity of a superconductor is zero, what can be said about its resistance?
A.
Infinite
B.
Zero
C.
Depends on temperature
D.
Undefined
Show solution
Solution
A superconductor has zero resistivity, which means it has zero resistance.
Correct Answer:
B
— Zero
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Q. If the resistivity of copper is 1.68 x 10^-8 Ω·m, what is the resistance of a copper wire of length 100 m and diameter 1 mm?
A.
0.168 Ω
B.
0.168 kΩ
C.
1.68 Ω
D.
1.68 kΩ
Show solution
Solution
Resistance R = ρ * (L / A) = 1.68 x 10^-8 * (100 / (π * (0.5 x 10^-3)²)) = 0.168 Ω.
Correct Answer:
A
— 0.168 Ω
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Q. If the revenue function is R(x) = 100x - 2x^2, find the number of units that maximizes revenue. (2021)
Show solution
Solution
Max revenue occurs at x = -b/(2a) = 100/(2*2) = 25.
Correct Answer:
B
— 50
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Q. If the revenue function is R(x) = 20x - 0.5x^2, find the quantity that maximizes revenue. (2021)
Show solution
Solution
R'(x) = 20 - x = 0 gives x = 20. This maximizes revenue.
Correct Answer:
B
— 20
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Q. If the revenue function is R(x) = 50x - 0.5x^2, find the number of units that maximizes revenue. (2023)
Show solution
Solution
Max revenue occurs at x = -b/(2a) = -50/(2*-0.5) = 50.
Correct Answer:
A
— 25
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Q. If the RMS speed of a gas is 250 m/s, what is the temperature if the molar mass is 0.028 kg/mol?
A.
100 K
B.
200 K
C.
300 K
D.
400 K
Show solution
Solution
Using v_rms = sqrt(3RT/M), we can rearrange to find T = (v_rms^2 * M) / (3R) = 300 K.
Correct Answer:
C
— 300 K
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Q. If the RMS speed of a gas is 300 m/s and its molar mass is 28 g/mol, what is the temperature of the gas?
A.
300 K
B.
600 K
C.
900 K
D.
1200 K
Show solution
Solution
Using the formula v_rms = sqrt((3RT)/M), we can rearrange to find T = (v_rms^2 * M)/(3R). Plugging in the values gives T = 600 K.
Correct Answer:
B
— 600 K
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Q. If the RMS speed of a gas is 300 m/s at 300 K, what will be its RMS speed at 600 K?
A.
300 m/s
B.
600 m/s
C.
300√2 m/s
D.
600√2 m/s
Show solution
Solution
The RMS speed is proportional to the square root of the temperature. Therefore, at 600 K, the RMS speed will be 300 * sqrt(2) m/s.
Correct Answer:
C
— 300√2 m/s
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Q. If the RMS speed of a gas is 300 m/s at 400 K, what will be the RMS speed at 200 K?
A.
150 m/s
B.
300 m/s
C.
600 m/s
D.
100 m/s
Show solution
Solution
The RMS speed is proportional to the square root of the temperature. Therefore, at 200 K, the RMS speed will be 300 * sqrt(200/400) = 150 m/s.
Correct Answer:
A
— 150 m/s
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Q. If the RMS speed of a gas is 300 m/s at 400 K, what will be the RMS speed at 800 K?
A.
300 m/s
B.
600 m/s
C.
424 m/s
D.
848 m/s
Show solution
Solution
RMS speed is proportional to the square root of temperature. v_rms at 800 K = 300 * sqrt(800/400) = 300 * sqrt(2) = 600 m/s.
Correct Answer:
B
— 600 m/s
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Q. If the RMS speed of a gas is 300 m/s, what is the kinetic energy per molecule?
A.
0.5 * m * (300)^2
B.
0.5 * m * (150)^2
C.
0.5 * m * (600)^2
D.
0.5 * m * (100)^2
Show solution
Solution
The kinetic energy per molecule is given by KE = 0.5 * m * v^2. Substituting v = 300 m/s gives the correct expression.
Correct Answer:
A
— 0.5 * m * (300)^2
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Q. If the RMS speed of a gas is 300 m/s, what is the RMS speed of the same gas at double the temperature?
A.
300 m/s
B.
600 m/s
C.
300√2 m/s
D.
600√2 m/s
Show solution
Solution
The RMS speed is proportional to the square root of the temperature. If the temperature is doubled, the RMS speed increases by a factor of sqrt(2). Therefore, the new RMS speed will be 300 * sqrt(2), which is approximately 600 m/s.
Correct Answer:
B
— 600 m/s
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