x² + y² = 3² + 4² = 9 + 16 = 25.

Substituting x = 3: 2(3^2) + 3(3) - 5 = 2(9) + 9 - 5 = 18 + 9 - 5 = 22.

(3 + 1)(3 - 1) = 4 * 2 = 8.

Substituting x = 3 into the expression: 2(3^2) + 3(3) - 5 = 2(9) + 9 - 5 = 18 + 9 - 5 = 22.

2(3^2) - 5(3) + 1 = 18 - 15 + 1 = 4.

x² - y² = 4² - 5² = 16 - 25 = -9.

2x - 3 = 2(4) - 3 = 8 - 3 = 5.

3x - 2 = 3(4) - 2 = 12 - 2 = 10.

(x - 1)² = (5 - 1)² = 4² = 16.

Substituting x = 5, we get 2(5) + 3 = 10 + 3 = 13.

2(5^3) - 3(5^2) + 5 = 2(125) - 3(25) + 5 = 250 - 75 + 5 = 180.

3(5) + 2 = 15 + 2 = 17.

x = cos^(-1)(-1/2) = 2π/3

If x = cos^(-1)(1/2), then x = π/3. Therefore, sin(x) = sin(π/3) = √3/2.

If x = cos^(-1)(1/2), then cos(x) = 1/2, which corresponds to x = π/3. Therefore, sin(x) = sin(π/3) = √3/2.

Since x = cos^(-1)(1/2) = π/3, then sin^(-1)(1/2) = π/6.

Since cos^(-1)(1/2) = π/3, we have sin^(-1)(√(1 - (1/2)^2)) = sin^(-1)(√(3/4)) = π/3.

cos^(-1)(1/2) = π/3.

If x = cos^(-1)(1/2), then x = π/3, thus sin(x) = sin(π/3) = √3/2.

Using the identity sin(x) = sqrt(1 - cos^2(x)), we have sin(x) = sqrt(1 - (1/2)^2) = √3/2.

sin^(-1)(-1) corresponds to the angle -π/2.

sin^(-1)(-1) corresponds to the angle -π/2.

sin^(-1)(-1/2) = -π/6, since sin(-π/6) = -1/2.

sin^(-1)(-1/2) = -π/6, since sin(-π/6) = -1/2.

If x = sin^(-1)(1/2), then x = π/6. Therefore, cos(x) = cos(π/6) = √3/2.

If x = sin^(-1)(1/2), then x = π/6. Therefore, cos(x) = cos(π/6) = √3/2.

Using the identity cos(x) = √(1 - sin^2(x)), we find cos(sin^(-1)(1/3)) = √(1 - (1/3)^2) = √(8)/3.

Using the identity cos^(-1)(√(1 - sin^2(x))) = π/2 - x, we find that cos^(-1)(√(1 - (1/3)^2)) = π/2 - sin^(-1)(1/3).

If x = sin^(-1)(1/√2), then sin(x) = 1/√2. Therefore, cos(x) = √(1 - sin^2(x)) = √(1 - (1/√2)^2) = √(1/2) = √2/2.

Since x = sin^(-1)(1/√2) = π/4, then cos^(-1)(x) = π/2 - π/4 = π/4.