|-3| = 3, so |x| + x = 3 - 3 = 0.

The absolute value |x| of -5 is 5.

1/x = 1/(1/2) = 2.

Substituting x and y gives us 2^(2+3) = 2^5 = 32.

Calculating, we find 2^3 + 3^2 = 8 + 9 = 17.

Substituting x = 2: 3(2^2) + 4(2) - 5 = 3(4) + 8 - 5 = 12 + 8 - 5 = 15.

We have x = 8 and y = 4. Thus, x/y = 8/4 = 2.

x² + y² = 3² + 4² = 9 + 16 = 25.

Substituting x = 3: 2(3^2) + 3(3) - 5 = 2(9) + 9 - 5 = 18 + 9 - 5 = 22.

(3 + 1)(3 - 1) = 4 * 2 = 8.

Substituting x = 3 into the expression: 2(3^2) + 3(3) - 5 = 2(9) + 9 - 5 = 18 + 9 - 5 = 22.

2(3^2) - 5(3) + 1 = 18 - 15 + 1 = 4.

x² - y² = 4² - 5² = 16 - 25 = -9.

2x - 3 = 2(4) - 3 = 8 - 3 = 5.

3x - 2 = 3(4) - 2 = 12 - 2 = 10.

(x - 1)² = (5 - 1)² = 4² = 16.

Substituting x = 5, we get 2(5) + 3 = 10 + 3 = 13.

2(5^3) - 3(5^2) + 5 = 2(125) - 3(25) + 5 = 250 - 75 + 5 = 180.

3(5) + 2 = 15 + 2 = 17.

x = cos^(-1)(-1/2) = 2π/3

If x = cos^(-1)(1/2), then x = π/3. Therefore, sin(x) = sin(π/3) = √3/2.

If x = cos^(-1)(1/2), then cos(x) = 1/2, which corresponds to x = π/3. Therefore, sin(x) = sin(π/3) = √3/2.

Since x = cos^(-1)(1/2) = π/3, then sin^(-1)(1/2) = π/6.

Since cos^(-1)(1/2) = π/3, we have sin^(-1)(√(1 - (1/2)^2)) = sin^(-1)(√(3/4)) = π/3.

cos^(-1)(1/2) = π/3.

If x = cos^(-1)(1/2), then x = π/3, thus sin(x) = sin(π/3) = √3/2.

Using the identity sin(x) = sqrt(1 - cos^2(x)), we have sin(x) = sqrt(1 - (1/2)^2) = √3/2.

sin^(-1)(-1) corresponds to the angle -π/2.

sin^(-1)(-1) corresponds to the angle -π/2.

sin^(-1)(-1/2) = -π/6, since sin(-π/6) = -1/2.