Q. If z = 5 + 12i, what is the imaginary part of z? (2022)
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Solution
The imaginary part of the complex number z = 5 + 12i is 12.
Correct Answer:
B
— 12
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Q. If \( B = \begin{pmatrix} 2 & 3 \\ 1 & 4 \end{pmatrix} \), what is \( |B| \)? (2022)
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Solution
The determinant of \( B \) is \( 2*4 - 3*1 = 8 - 3 = 5 \).
Correct Answer:
A
— 5
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Q. If \( E = \begin{pmatrix} 0 & 1 \\ 1 & 0 \end{pmatrix} \), what is \( |E| \)? (2023)
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Solution
The determinant is calculated as \( 0*0 - 1*1 = 0 - 1 = -1 \).
Correct Answer:
C
— -1
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Q. If \( E = \begin{pmatrix} 1 & 1 \\ 1 & 1 \end{pmatrix} \), what is \( |E| \)? (2022)
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Solution
The determinant is \( 1*1 - 1*1 = 1 - 1 = 0 \).
Correct Answer:
A
— 0
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Q. If \( I = \begin{pmatrix} 1 & 1 \\ 1 & 1 \end{pmatrix} \), what is \( |I| \)? (2021)
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Solution
The determinant is \( 1*1 - 1*1 = 1 - 1 = 0 \).
Correct Answer:
A
— 0
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Q. In a buffer solution, which component resists changes in pH? (2020)
A.
Strong acid
B.
Weak acid and its salt
C.
Strong base
D.
Water
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Solution
A buffer solution typically consists of a weak acid and its conjugate base (salt), which helps to resist changes in pH when small amounts of acid or base are added.
Correct Answer:
B
— Weak acid and its salt
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Q. In a buffer solution, which of the following components is essential? (2023)
A.
Strong acid
B.
Weak acid and its salt
C.
Strong base
D.
Water
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Solution
A buffer solution is made from a weak acid and its conjugate base (salt), which helps maintain pH.
Correct Answer:
B
— Weak acid and its salt
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Q. In a Carnot engine operating between 500 K and 300 K, what is the maximum efficiency of the engine? (2021)
A.
40%
B.
60%
C.
50%
D.
20%
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Solution
Efficiency (η) = 1 - (T_cold / T_hot) = 1 - (300 K / 500 K) = 0.4 or 40%.
Correct Answer:
B
— 60%
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Q. In a Carnot engine operating between temperatures of 500 K and 300 K, what is the maximum efficiency? (2023)
A.
40%
B.
60%
C.
50%
D.
70%
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Solution
Efficiency (η) = 1 - (T_cold / T_hot) = 1 - (300 K / 500 K) = 0.4 or 40%.
Correct Answer:
B
— 60%
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Q. In a Carnot engine operating between temperatures of 500 K and 300 K, what is the efficiency of the engine? (2023)
A.
40%
B.
50%
C.
60%
D.
70%
Show solution
Solution
Efficiency (η) = 1 - (T_cold / T_hot) = 1 - (300 K / 500 K) = 0.4 or 40%.
Correct Answer:
C
— 60%
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Q. In a Carnot engine operating between temperatures T1 and T2, what is the efficiency (η) of the engine? (2023)
A.
1 - T2/T1
B.
T1/T2
C.
T2/T1
D.
T1 - T2
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Solution
The efficiency of a Carnot engine is given by η = 1 - T2/T1.
Correct Answer:
A
— 1 - T2/T1
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Q. In a Carnot engine operating between two heat reservoirs at temperatures 500 K and 300 K, what is the maximum efficiency of the engine? (2023)
A.
40%
B.
60%
C.
80%
D.
20%
Show solution
Solution
Efficiency (η) = 1 - (T_cold / T_hot) = 1 - (300 K / 500 K) = 0.4 or 40%.
Correct Answer:
B
— 60%
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Q. In a Carnot engine, the efficiency depends on which of the following? (2023)
A.
Temperature of the hot reservoir
B.
Temperature of the cold reservoir
C.
Both temperatures
D.
Type of working substance
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Solution
The efficiency of a Carnot engine is determined by the temperatures of the hot and cold reservoirs, given by the formula η = 1 - (T_c/T_h).
Correct Answer:
C
— Both temperatures
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Q. In a circuit with a 24V battery and two 8Ω resistors in series, what is the total current? (2022)
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Solution
Total resistance R = 8Ω + 8Ω = 16Ω. Current I = V/R = 24V / 16Ω = 1.5A.
Correct Answer:
B
— 2A
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Q. In a circuit with a 24V battery and two resistors of 4Ω and 8Ω in parallel, what is the total current supplied by the battery? (2022)
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Solution
First, find the equivalent resistance: 1/R_eq = 1/4 + 1/8 = 3/8, so R_eq = 8/3Ω. Then, I = V/R_eq = 24V / (8/3)Ω = 9A.
Correct Answer:
D
— 6A
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Q. In a circuit with a 5Ω and a 10Ω resistor in parallel, what is the total current if the voltage across them is 20V? (2022)
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Solution
First, find the equivalent resistance: 1/R_eq = 1/5 + 1/10 = 3/10, R_eq = 10/3Ω. Then, I = V/R_eq = 20V / (10/3)Ω = 6A.
Correct Answer:
A
— 4A
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Q. In a circuit with a 9V battery and a 3Ω resistor, what is the current flowing through the resistor? (2023)
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Solution
Using Ohm's law, I = V/R = 9V / 3Ω = 3A.
Correct Answer:
B
— 2A
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Q. In a circuit with a 9V battery and a 3Ω resistor, what is the power dissipated by the resistor? (2021)
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Solution
Power is given by P = V²/R = (9V)² / 3Ω = 81V² / 3Ω = 27W.
Correct Answer:
B
— 9W
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Q. In a circuit with a 9V battery and a 3Ω resistor, what is the power dissipated in the resistor? (2023)
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Solution
Power P = V²/R = (9V)² / 3Ω = 81 / 3 = 27W.
Correct Answer:
B
— 9W
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Q. In a circuit, if the current is doubled while the resistance remains constant, what happens to the power? (2020)
A.
It doubles
B.
It quadruples
C.
It remains the same
D.
It halves
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Solution
Power is given by P = I²R. If I is doubled, P becomes (2I)²R = 4I²R, which is quadrupled.
Correct Answer:
B
— It quadruples
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Q. In a circuit, if the current is doubled while the resistance remains constant, what happens to the power consumed? (2020)
A.
It doubles
B.
It triples
C.
It remains the same
D.
It halves
Show solution
Solution
Power is given by P = I²R. If I is doubled, P becomes (2I)²R = 4I²R, which means power quadruples.
Correct Answer:
A
— It doubles
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Q. In a circuit, if the resistance is halved while the voltage remains constant, what happens to the current? (2022)
A.
It halves
B.
It doubles
C.
It remains the same
D.
It quadruples
Show solution
Solution
According to Ohm's law, I = V/R. If R is halved, I will double.
Correct Answer:
B
— It doubles
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Q. In a circuit, if the voltage is doubled and the resistance remains constant, what happens to the current? (2020)
A.
Doubles
B.
Halves
C.
Remains the same
D.
Quadruples
Show solution
Solution
According to Ohm's law, I = V/R. If V is doubled, I also doubles.
Correct Answer:
A
— Doubles
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Q. In a class of 30 students, 18 are girls. What is the probability of randomly selecting a boy? (2021)
A.
3/5
B.
2/5
C.
1/2
D.
1/3
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Solution
Number of boys = 30 - 18 = 12. Probability = 12/30 = 2/5.
Correct Answer:
B
— 2/5
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Q. In a closed system, if 100 J of heat is added and 40 J of work is done by the system, what is the change in internal energy? (2022)
A.
60 J
B.
40 J
C.
100 J
D.
Zero
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Solution
According to the First Law of Thermodynamics, ΔU = Q - W. Here, ΔU = 100 J - 40 J = 60 J.
Correct Answer:
A
— 60 J
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Q. In a concentration cell, if the concentration of one half-cell is 0.1 M and the other is 1 M, what is the cell potential?
A.
0.059 V
B.
0.118 V
C.
0.0591 V
D.
0.1181 V
Show solution
Solution
Using the Nernst equation, E = (0.0591/n) log([C1/C2]), where n=1.
Correct Answer:
B
— 0.118 V
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Q. In a cyclic process, the net work done is equal to: (2020)
A.
Net heat added
B.
Change in internal energy
C.
Zero
D.
Net heat removed
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Solution
In a cyclic process, the net work done is equal to the net heat added to the system, as the internal energy returns to its initial state.
Correct Answer:
A
— Net heat added
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Q. In a damped harmonic oscillator, what happens to the amplitude over time? (2023)
A.
Increases
B.
Decreases
C.
Remains constant
D.
Oscillates
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Solution
In a damped harmonic oscillator, the amplitude decreases over time due to energy loss.
Correct Answer:
B
— Decreases
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Q. In a Daniell cell, which metal acts as the anode?
A.
Copper
B.
Zinc
C.
Silver
D.
Lead
Show solution
Solution
In a Daniell cell, Zinc acts as the anode.
Correct Answer:
B
— Zinc
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Q. In a diffraction pattern, if the distance between the slits is decreased, what happens to the central maximum? (2022)
A.
It becomes wider
B.
It becomes narrower
C.
It disappears
D.
It remains unchanged
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Solution
Decreasing the distance between the slits increases the diffraction effect, causing the central maximum to become wider.
Correct Answer:
A
— It becomes wider
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Showing 1141 to 1170 of 2530 (85 Pages)
MHT-CET MCQ & Objective Questions
The MHT-CET exam is a crucial stepping stone for students aspiring to pursue engineering and pharmacy courses in Maharashtra. Mastering the MHT-CET MCQ format is essential, as it not only tests your knowledge but also enhances your exam preparation strategy. Practicing objective questions helps in identifying important concepts and improves your chances of scoring better in this competitive exam.
What You Will Practise Here
Fundamental concepts in Physics, Chemistry, and Mathematics
Key formulas and their applications in problem-solving
Important definitions and terminologies relevant to MHT-CET
Diagrams and illustrations for better conceptual understanding
Practice questions that mirror the exam pattern
Analysis of previous years' MHT-CET questions
Techniques for tackling tricky MCQs effectively
Exam Relevance
The MHT-CET exam is aligned with the syllabus of CBSE, State Boards, and is also relevant for students preparing for NEET and JEE. Many concepts from the MHT-CET syllabus appear in these competitive exams, often in the form of application-based questions or conceptual MCQs. Understanding the common question patterns can significantly enhance your preparation and performance.
Common Mistakes Students Make
Misinterpreting questions due to lack of clarity in reading
Neglecting to review fundamental concepts before attempting MCQs
Overlooking units and dimensions in Physics and Chemistry problems
Rushing through practice questions without thorough understanding
Failing to manage time effectively during the exam
FAQs
Question: What are the best resources for MHT-CET MCQ questions?Answer: Utilizing online platforms like SoulShift, which offer a variety of practice questions and mock tests, can be very beneficial.
Question: How can I improve my speed in solving MHT-CET objective questions?Answer: Regular practice and timed mock tests can help enhance your speed and accuracy in solving MCQs.
Start your journey towards success by solving MHT-CET practice MCQs today! Test your understanding and build your confidence for the exam ahead.
