Major Competitive Exams

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Major Competitive Exams

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Major Competitive Exams MCQ & Objective Questions

Major Competitive Exams play a crucial role in shaping the academic and professional futures of students in India. These exams not only assess knowledge but also test problem-solving skills and time management. Practicing MCQs and objective questions is essential for scoring better, as they help in familiarizing students with the exam format and identifying important questions that frequently appear in tests.

What You Will Practise Here

Key concepts and theories related to major subjects
Important formulas and their applications
Definitions of critical terms and terminologies
Diagrams and illustrations to enhance understanding
Practice questions that mirror actual exam patterns
Strategies for solving objective questions efficiently
Time management techniques for competitive exams

Exam Relevance

The topics covered under Major Competitive Exams are integral to various examinations such as CBSE, State Boards, NEET, and JEE. Students can expect to encounter a mix of conceptual and application-based questions that require a solid understanding of the subjects. Common question patterns include multiple-choice questions that test both knowledge and analytical skills, making it essential to be well-prepared with practice MCQs.

Common Mistakes Students Make

Rushing through questions without reading them carefully
Overlooking the negative marking scheme in MCQs
Confusing similar concepts or terms
Neglecting to review previous years’ question papers
Failing to manage time effectively during the exam

FAQs

Question: How can I improve my performance in Major Competitive Exams?
Answer: Regular practice of MCQs and understanding key concepts will significantly enhance your performance.

Question: What types of questions should I focus on for these exams?
Answer: Concentrate on important Major Competitive Exams questions that frequently appear in past papers and mock tests.

Question: Are there specific strategies for tackling objective questions?
Answer: Yes, practicing under timed conditions and reviewing mistakes can help develop effective strategies.

Start your journey towards success by solving practice MCQs today! Test your understanding and build confidence for your upcoming exams. Remember, consistent practice is the key to mastering Major Competitive Exams!

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Q. If the pair of lines represented by the equation ax^2 + 2hxy + by^2 = 0 are perpendicular, then:

A. a + b = 0
B. a - b = 0
C. h = 0
D. a = b

Solution

For the lines to be perpendicular, the condition a*b + h^2 = 0 must hold.

Correct Answer: A — a + b = 0

Q. If the paper is folded in half, which shape will appear?

A. Shape A
B. Shape B
C. Shape C
D. Shape D

Solution

Shape A will appear when the paper is folded in half along the specified line.

Correct Answer: A — Shape A

Q. If the parabola y = ax^2 + bx + c has its vertex at (1, -2), what is the value of a if it passes through the point (0, 0)?

A. 1
B. 2
C. 3
D. 4

Solution

Using the vertex form y = a(x - 1)^2 - 2 and substituting (0, 0), we get 0 = a(0 - 1)^2 - 2 => 2 = a => a = 2.

Correct Answer: B — 2

Q. If the parabola y^2 = 16x opens to the right, what is the value of p?

A. 2
B. 4
C. 8
D. 16

Solution

In the equation y^2 = 4px, we have 4p = 16, thus p = 4.

Correct Answer: B — 4

Q. If the parabola y^2 = 20x opens to the right, what is the value of p?

A. 5
B. 10
C. 20
D. 2

Solution

In the equation y^2 = 4px, we have 4p = 20, thus p = 20/4 = 5.

Correct Answer: A — 5

Q. If the Parliament has 790 members and 20% are women, how many women are there in the Parliament?

A. 158
B. 160
C. 150
D. 170

Solution

Number of women = 20% of 790 = 0.2 * 790 = 158.

Correct Answer: A — 158

Q. If the Parliament has 790 members and 30% are women, how many women members are there?

A. 210
B. 220
C. 230
D. 240

Solution

Number of women members = 30% of 790 = 0.3 * 790 = 237.

Correct Answer: A — 210

Q. If the Parliament has 790 members and 30% of them are from the ruling party, how many members are from the ruling party?

A. 210
B. 220
C. 230
D. 240

Solution

Members from ruling party = 30% of 790 = 0.30 * 790 = 237.

Correct Answer: C — 230

Q. If the Parliament has 790 members and 40% are from the opposition, how many members are from the opposition?

A. 316
B. 320
C. 300
D. 310

Solution

Opposition members = 40% of 790 = 0.4 * 790 = 316.

Correct Answer: A — 316

Q. If the Parliament is in session for 100 days in a year and the Lok Sabha meets for 60% of those days, how many days does the Lok Sabha meet?

A. 60
B. 70
C. 80
D. 90

Solution

Days Lok Sabha meets = 60% of 100 = 0.6 * 100 = 60 days.

Correct Answer: A — 60

Q. If the Parliament is in session for 120 days in a year and the Lok Sabha meets for 75% of those days, how many days does the Lok Sabha meet?

A. 90
B. 80
C. 75
D. 100

Solution

Days Lok Sabha meets = 75% of 120 = 0.75 * 120 = 90.

Correct Answer: A — 90

Q. If the Parliament is in session for 90 days in a year and the Lok Sabha meets for 60% of those days, how many days does the Lok Sabha meet?

A. 54
B. 60
C. 66
D. 72

Solution

Days Lok Sabha meets = 60% of 90 = 0.60 * 90 = 54 days.

Correct Answer: A — 54

Q. If the Parliament meets for 120 days in a year and the Lok Sabha meets for 75% of those days, how many days does the Lok Sabha meet?

A. 90
B. 80
C. 75
D. 100

Solution

75% of 120 = 0.75 * 120 = 90 days.

Correct Answer: A — 90

Q. If the passage discusses the effects of climate change, which of the following would be an appropriate title?

A. The Unseen Consequences of Global Warming.
B. The Benefits of Renewable Energy.
C. The History of Environmental Movements.
D. The Role of Government in Climate Policy.

Solution

The title 'The Unseen Consequences of Global Warming' directly relates to the effects of climate change, making option A appropriate.

Correct Answer: A — The Unseen Consequences of Global Warming.

Q. If the passage were to be rearranged, which of the following sequences would maintain the logical flow of ideas? (2023)

A. Introduction, Anecdotes, Argument, Conclusion
B. Anecdotes, Conclusion, Argument, Introduction
C. Argument, Introduction, Anecdotes, Conclusion
D. Conclusion, Argument, Introduction, Anecdotes

Solution

The logical flow starts with an introduction, followed by supporting anecdotes, leading to the main argument and concluding remarks.

Correct Answer: A — Introduction, Anecdotes, Argument, Conclusion

Q. If the passage were to be rearranged, which sentence would logically follow the first sentence?

A. However, not all students benefit equally from these advancements.
B. Many educators are excited about these new tools.
C. Technology has transformed the way we learn.
D. Students are more engaged than ever before.

Solution

The first sentence introduces the topic of technology in education, making the third option a logical continuation.

Correct Answer: C — Technology has transformed the way we learn.

Q. If the passage were to be restructured, which of the following sequences would best maintain the logical flow of ideas? (2023)

A. A, B, C, D
B. B, A, D, C
C. C, D, A, B
D. D, C, B, A

Solution

The sequence A, B, C, D logically presents the argument, starting with the problem, followed by evidence, implications, and concluding with a call to action.

Correct Answer: A — A, B, C, D

Q. If the passage were to be restructured, which of the following would be the most logical order?

A. Introduction, Importance of Verbal Ability, Preparation Strategies, Conclusion
B. Conclusion, Introduction, Importance of Verbal Ability, Preparation Strategies
C. Importance of Verbal Ability, Introduction, Conclusion, Preparation Strategies
D. Preparation Strategies, Importance of Verbal Ability, Conclusion, Introduction

Solution

The logical flow starts with an introduction, followed by the importance of verbal ability, then preparation strategies, and concludes with a summary.

Correct Answer: A — Introduction, Importance of Verbal Ability, Preparation Strategies, Conclusion

Q. If the pattern is 2, 4, 6, 8, what is the next number?

A. 10
B. 12
C. 14
D. 16

Solution

The pattern increases by 2, so the next number is 10.

Correct Answer: A — 10

Q. If the peak current in an AC circuit is 5 A, what is the average current over one complete cycle?

A. 5 A
B. 2.5 A
C. 0 A
D. 7.07 A

Solution

The average current over one complete cycle is I_avg = I_peak/√2 = 5/√2 = 2.5 A.

Correct Answer: B — 2.5 A

Q. If the peak voltage of an AC source is 200 V, what is the RMS voltage?

A. 100 V
B. 141.42 V
C. 200 V
D. 282.84 V

Solution

The RMS voltage (V_rms) is given by V_rms = V_peak / √2. Therefore, V_rms = 200 V / √2 = 141.42 V.

Correct Answer: B — 141.42 V

Q. If the peak voltage of an AC source is 220 V, what is the RMS voltage?

A. 110 V
B. 154 V
C. 220 V
D. 311 V

Solution

The RMS voltage (V_rms) is given by V_rms = V_peak / √2. Therefore, V_rms = 220 V / √2 = 110 V.

Correct Answer: A — 110 V

Q. If the perimeter of a rectangle is 20 cm and the length is 6 cm, what is the width?

A. 4 cm
B. 5 cm
C. 6 cm
D. 7 cm

Solution

Perimeter P = 2(length + width). So, 20 = 2(6 + width). Solving gives width = 4 cm.

Correct Answer: B — 5 cm

Q. If the perimeter of a rectangle is 30 cm and the length is 10 cm, what is the width?

A. 5 cm
B. 10 cm
C. 7.5 cm
D. 15 cm

Solution

Perimeter P = 2(length + width). So, 30 = 2(10 + width). Dividing by 2 gives 15 = 10 + width. Thus, width = 15 - 10 = 5 cm.

Correct Answer: A — 5 cm

Q. If the perimeter of a rectangle is 50 cm and the length is 15 cm, what is the width? (2020)

A. 10 cm
B. 12.5 cm
C. 15 cm
D. 20 cm

Solution

Perimeter = 2(length + width). So, 50 = 2(15 + width). Solving gives width = 10 cm.

Correct Answer: B — 12.5 cm

Q. If the perimeter of a regular hexagon is 72 cm, what is the length of each side?

A. 10 cm
B. 12 cm
C. 14 cm
D. 8 cm

Solution

The perimeter of a regular hexagon is the sum of the lengths of its 6 equal sides. Therefore, each side is 72 cm / 6 = 12 cm.

Correct Answer: B — 12 cm

Q. If the perimeter of a regular octagon is 64 cm, what is the length of each side? (2023)

A. 6 cm
B. 8 cm
C. 10 cm
D. 12 cm

Solution

The perimeter of a regular octagon is 8 times the length of one side. Therefore, each side is 64 cm / 8 = 8 cm.

Correct Answer: B — 8 cm

Q. If the perimeter of a square is 36 cm, what is the length of one side? (2023)

A. 9 cm
B. 12 cm
C. 6 cm
D. 15 cm

Solution

The perimeter of a square is given by 4 times the length of one side. Therefore, if the perimeter is 36 cm, the length of one side is 36 cm / 4 = 9 cm.

Correct Answer: B — 12 cm

Q. If the perimeter of a square is 40 cm, what is the length of one side? (2018)

A. 10 cm
B. 15 cm
C. 20 cm
D. 25 cm

Solution

Perimeter = 4 × side, so side = 40/4 = 10 cm.

Correct Answer: A — 10 cm

Q. If the perimeter of a square is 64 cm, what is the length of one side? (2023)

A. 12 cm
B. 14 cm
C. 16 cm
D. 18 cm

Solution

Perimeter of a square = 4 × side. Therefore, 4 × side = 64 cm, giving side = 64/4 = 16 cm.

Correct Answer: C — 16 cm

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