Supplementary angles sum up to 180 degrees. Therefore, the other angle = 180 - 120 = 60 degrees.

Let the smaller angle be x. Then the larger angle is 3x. Since they are supplementary, x + 3x = 180. Solving gives x = 45 degrees.

Supplementary angles sum up to 180 degrees. Therefore, the other angle = 180 - 75 = 105 degrees.

The equivalent capacitance C_eq of capacitors in series is given by 1 / C_eq = 1 / C1 + 1 / C2.

Relative speed = Speed of car 1 + Speed of car 2 = 40 km/h + 60 km/h = 100 km/h.

Relative speed = 80 km/h - 60 km/h = 20 km/h. Time = Distance / Speed = 100 km / 20 km/h = 5 hours.

Relative speed = 40 km/h + 60 km/h = 100 km/h. Time = Distance / Relative Speed = 200 km / 100 km/h = 2 hours.

At the midpoint, the electric fields due to +Q and -Q cancel each other out, resulting in a net electric field of 0.

The electric fields due to both charges at the midpoint cancel each other out, resulting in a net electric field of 0 N/C.

Using Coulomb's law, F = k * |q1 * q2| / r² = (9 × 10^9 N m²/C²) * |(3 × 10^-6 C) * (5 × 10^-6 C)| / (0.3 m)² = 0.45 N.

The electric fields due to both charges at the midpoint cancel each other out, resulting in a net electric field of 0 N/C.

Using the intersecting chords theorem: AE * EB = CE * ED. Thus, 3 * 5 = 4 * ED, so 15 = 4 * ED, giving ED = 15/4 = 3.75.

Using the intersecting chords theorem: 4 * 6 = x * y. If x + y = 10, then x = 4 and y = 6.

The maximum radius of each circle can be half the distance between the centers, which is 10 cm.

The centers of two intersecting circles are equidistant from the points of intersection.

Circles that intersect at two points are said to be secant to each other.

The centers of the circles are equidistant from the intersection points, making option 0 true.

When two coherent sources are in phase, they produce constructive interference, resulting in bright fringes.

When two coherent sources are in phase, they produce constructive interference, resulting in bright fringes.

The phase difference (Δφ) is given by (2π/λ) * path difference. For a path difference of λ/4, Δφ = (2π/λ) * (λ/4) = π/2 radians.

A path difference of λ/2 corresponds to a phase difference of π radians, leading to destructive interference.

A path difference of λ/2 results in destructive interference, as the waves will be out of phase.

Total outcomes = 4 (HH, HT, TH, TT). At least one head = 3 outcomes. Probability = 3/4.

The possible outcomes are HH, HT, TH, TT. The outcomes with at least one tail are HT, TH, TT (3 outcomes). So, the probability is 3/4.

Possible combinations for sum of 7: (1,6), (2,5), (3,4), (4,3), (5,2), (6,1) = 6 combinations. Total outcomes = 36. Probability = 6/36 = 1/6.

Possible combinations for sum 7: (1,6), (2,5), (3,4), (4,3), (5,2), (6,1) = 6 combinations. Total outcomes = 36. Probability = 6/36 = 1/6.

The combinations for a sum greater than 10 are (5,6), (6,5), (6,6), giving a probability of 3/36 = 1/12.

The combinations that give a sum of 7 are (1,6), (2,5), (3,4), (4,3), (5,2), (6,1), totaling 6 combinations. The total outcomes are 36, so the probability is 6/36 = 1/6.

The net torque is zero because the forces are equal and opposite, producing no rotational effect.

The net torque is zero because the forces are equal and opposite, resulting in no rotational effect.