Q. If the wavelength of light in a vacuum is 600 nm, what is its wavelength in glass (n = 1.5)?
A.
400 nm
B.
600 nm
C.
900 nm
D.
300 nm
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Solution
The wavelength in a medium is given by λ' = λ/n. Thus, λ' = 600 nm / 1.5 = 400 nm.
Correct Answer:
A
— 400 nm
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Q. If the wavelength of light in air is 600 nm, what is its wavelength in glass (n=1.5)?
A.
400 nm
B.
450 nm
C.
600 nm
D.
900 nm
Show solution
Solution
Wavelength in glass (λ') = λ/n = 600 nm / 1.5 = 400 nm.
Correct Answer:
A
— 400 nm
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Q. If the wavelength of light in vacuum is 600 nm, what is its wavelength in water (n = 1.33)? (2023)
A.
450 nm
B.
600 nm
C.
750 nm
D.
800 nm
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Solution
Wavelength in medium = Wavelength in vacuum / n. Thus, λ = 600 nm / 1.33 ≈ 450 nm.
Correct Answer:
A
— 450 nm
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Q. If the wavelength of light is halved, what happens to its frequency? (2021)
A.
It is halved
B.
It remains the same
C.
It is doubled
D.
It is quadrupled
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Solution
Frequency (f) is inversely proportional to wavelength (λ). If λ is halved, f is doubled.
Correct Answer:
C
— It is doubled
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Q. If the wavelength of light is halved, what happens to the energy of the photons? (2020)
A.
It is halved
B.
It is doubled
C.
It remains the same
D.
It is quadrupled
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Solution
Energy is inversely proportional to wavelength. Halving the wavelength doubles the energy.
Correct Answer:
B
— It is doubled
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Q. If the wavelength of light is halved, what happens to the frequency of the light?
A.
It doubles
B.
It halves
C.
It remains the same
D.
It quadruples
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Solution
Frequency (f) is inversely proportional to wavelength (λ). If λ is halved, f doubles.
Correct Answer:
A
— It doubles
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Q. If the wavelength of light used in a diffraction experiment is halved, what happens to the position of the minima?
A.
They move closer together
B.
They move further apart
C.
They remain unchanged
D.
They disappear
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Solution
Halving the wavelength causes the minima to move closer together, as the angle for minima is directly proportional to the wavelength.
Correct Answer:
A
— They move closer together
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Q. If the wavelength of light used in a diffraction experiment is halved, what happens to the position of the first diffraction minimum?
A.
It moves closer to the center
B.
It moves further from the center
C.
It remains unchanged
D.
It disappears
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Solution
Halving the wavelength results in the first minimum moving closer to the center, as the position of minima is directly related to the wavelength.
Correct Answer:
A
— It moves closer to the center
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Q. If the wavelength of light used in a diffraction experiment is halved, what happens to the angular position of the first minimum in a single-slit diffraction pattern?
A.
It remains the same
B.
It doubles
C.
It halves
D.
It quadruples
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Solution
Halving the wavelength will halve the angle for the first minimum, as the position of minima is directly proportional to the wavelength.
Correct Answer:
C
— It halves
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Q. If the wavelength of light used in a diffraction experiment is increased, what happens to the diffraction pattern?
A.
It becomes sharper
B.
It becomes broader
C.
It remains unchanged
D.
It disappears
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Solution
Increasing the wavelength results in a broader diffraction pattern as the angles for minima and maxima increase.
Correct Answer:
B
— It becomes broader
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Q. If the wavelength of light used in a diffraction grating is increased, what happens to the angular separation of the fringes? (2023)
A.
Increases
B.
Decreases
C.
Remains the same
D.
Becomes zero
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Solution
The angular separation (θ) is directly proportional to the wavelength (λ). Therefore, increasing λ increases the angular separation.
Correct Answer:
A
— Increases
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Q. If the wavelength of light used in a double-slit experiment is 600 nm and the distance between the slits is 0.3 mm, what is the distance between the first and second bright fringes on the screen placed 2 m away?
A.
0.4 m
B.
0.6 m
C.
0.8 m
D.
0.2 m
Show solution
Solution
Distance between fringes = (λD)/d = (600 x 10^-9 m * 2 m) / (0.3 x 10^-3 m) = 0.004 m = 0.4 m.
Correct Answer:
A
— 0.4 m
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Q. If the wavelength of light used in a double-slit experiment is increased, what happens to the position of the interference fringes?
A.
Fringes move closer together
B.
Fringes move further apart
C.
Fringes disappear
D.
Fringes become brighter
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Solution
Increasing the wavelength increases the fringe width, causing the fringes to move further apart.
Correct Answer:
B
— Fringes move further apart
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Q. If the wavelength of light used in a double-slit experiment is increased, what happens to the fringe separation? (2022)
A.
Increases
B.
Decreases
C.
Remains the same
D.
Becomes zero
Show solution
Solution
Fringe separation is directly proportional to the wavelength. If the wavelength increases, the fringe separation also increases.
Correct Answer:
A
— Increases
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Q. If the wavelength of light used in a double-slit experiment is increased, what happens to the distance between the fringes? (2022)
A.
Increases
B.
Decreases
C.
Remains the same
D.
Becomes zero
Show solution
Solution
The fringe width is directly proportional to the wavelength. Therefore, increasing the wavelength increases the distance between the fringes.
Correct Answer:
A
— Increases
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Q. If the wavelength of light used in a single-slit diffraction experiment is increased, what will happen to the position of the first minimum? (2022)
A.
It moves closer to the center
B.
It moves away from the center
C.
It remains unchanged
D.
It disappears
Show solution
Solution
The position of the first minimum in single-slit diffraction is given by a sin(θ) = λ. Increasing λ will cause θ to increase, moving the minimum away from the center.
Correct Answer:
B
— It moves away from the center
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Q. If the wavelength of light used in a single-slit diffraction experiment is increased, what happens to the width of the central maximum? (2023)
A.
It decreases
B.
It increases
C.
It remains the same
D.
It becomes zero
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Solution
The width of the central maximum in single-slit diffraction is directly proportional to the wavelength. Increasing the wavelength increases the width.
Correct Answer:
B
— It increases
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Q. If the wavelength of light used in an interference experiment is 500 nm, what is the fringe separation when the screen is placed 2 m away from the slits separated by 0.1 mm?
A.
0.01 m
B.
0.025 m
C.
0.05 m
D.
0.1 m
Show solution
Solution
Fringe separation β = λD/d = (500 x 10^-9 m)(2 m)/(0.1 x 10^-3 m) = 0.01 m.
Correct Answer:
C
— 0.05 m
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Q. If the wavelength of light used in Young's experiment is 600 nm and the distance between the slits is 0.1 mm, what is the distance between the first and second bright fringes on a screen 2 m away?
A.
0.12 m
B.
0.24 m
C.
0.36 m
D.
0.48 m
Show solution
Solution
Fringe separation (β) = λD/d. β = (600 x 10^-9 * 2) / 0.0001 = 0.012 m. Distance between first and second bright fringes = 2β = 0.024 m.
Correct Answer:
B
— 0.24 m
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Q. If the wavelength of light used in Young's experiment is 600 nm, what is the fringe width when the distance between the slits is 0.1 mm and the distance to the screen is 2 m?
A.
0.03 mm
B.
0.06 mm
C.
0.12 mm
D.
0.15 mm
Show solution
Solution
Fringe width (β) = (λD)/d = (600 x 10^-9 * 2)/(0.1 x 10^-3) = 0.012 mm = 0.06 mm.
Correct Answer:
B
— 0.06 mm
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Q. If the weight of an object is measured as 50.0 kg with an uncertainty of 0.5 kg, what is the relative error?
A.
1%
B.
0.5%
C.
2%
D.
0.1%
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Solution
Relative error = (Uncertainty / Measured value) * 100 = (0.5 / 50.0) * 100 = 1%.
Correct Answer:
B
— 0.5%
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Q. If the Wheatstone bridge is balanced, what is the potential difference across the galvanometer?
A.
Maximum.
B.
Minimum.
C.
Zero.
D.
Equal to the supply voltage.
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Solution
When the bridge is balanced, the potential difference across the galvanometer is zero.
Correct Answer:
C
— Zero.
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Q. If the Wheatstone bridge is unbalanced, what can be inferred about the potential difference across the galvanometer?
A.
It is zero
B.
It is positive
C.
It is negative
D.
It is non-zero
Show solution
Solution
An unbalanced Wheatstone bridge will have a non-zero potential difference across the galvanometer.
Correct Answer:
D
— It is non-zero
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Q. If the Wheatstone bridge is unbalanced, what can be inferred about the resistances?
A.
R1/R2 = R3/R4
B.
R1/R2 ≠ R3/R4
C.
R1 + R2 = R3 + R4
D.
R1 - R2 = R3 - R4
Show solution
Solution
An unbalanced Wheatstone bridge indicates that the ratio of the resistances is not equal.
Correct Answer:
B
— R1/R2 ≠ R3/R4
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Q. If the Wheatstone bridge is unbalanced, what can be said about the potential difference across the galvanometer?
A.
It is zero.
B.
It is maximum.
C.
It is equal to the supply voltage.
D.
It is constant.
Show solution
Solution
In an unbalanced bridge, there is a potential difference across the galvanometer, leading to maximum current flow.
Correct Answer:
B
— It is maximum.
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Q. If the Wheatstone bridge is unbalanced, what happens to the current through the galvanometer?
A.
It becomes zero.
B.
It increases.
C.
It decreases.
D.
It becomes infinite.
Show solution
Solution
In an unbalanced bridge, there is a potential difference across the galvanometer, causing current to flow.
Correct Answer:
B
— It increases.
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Q. If the width of a river is 200 meters and the depth is 5 meters, what is the volume of water in one kilometer length of the river? (2021)
A.
100,000 m³
B.
1,000,000 m³
C.
500,000 m³
D.
200,000 m³
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Solution
Volume = width × depth × length = 200 m × 5 m × 1000 m = 1,000,000 m³.
Correct Answer:
B
— 1,000,000 m³
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Q. If the width of a river is 200 meters and the depth is 5 meters, what is the volume of water in cubic meters that flows through the river in one second if the velocity of the water is 3 m/s?
A.
3000
B.
1000
C.
6000
D.
5000
Show solution
Solution
Volume = Width × Depth × Velocity = 200 m × 5 m × 3 m/s = 3000 m³/s.
Correct Answer:
A
— 3000
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Q. If the wind is blowing from the north at 10 km/h, what is the wind direction?
A.
North
B.
South
C.
East
D.
West
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Solution
The wind direction is named from where it originates, so it is blowing from the North.
Correct Answer:
A
— North
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Q. If the word 'CAT' is coded as '3120', what is the code for 'DOG'?
A.
415
B.
416
C.
417
D.
418
Show solution
Solution
D=4, O=15, G=7; combined gives 415.
Correct Answer:
A
— 415
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