Engineering Entrance Exam Preparation Resources

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Engineering Entrance MCQ & Objective Questions

Preparing for Engineering Entrance exams is crucial for aspiring engineers in India. Mastering MCQs and objective questions not only enhances your understanding of key concepts but also boosts your confidence during exams. Regular practice with these questions helps identify important topics and improves your overall exam preparation.

What You Will Practise Here

Fundamental concepts of Physics and Mathematics
Key formulas and their applications in problem-solving
Important definitions and theorems relevant to engineering
Diagrams and graphical representations for better understanding
Conceptual questions that challenge your critical thinking
Previous years' question papers and their analysis
Time management strategies while solving MCQs

Exam Relevance

The Engineering Entrance syllabus is integral to various examinations like CBSE, State Boards, NEET, and JEE. Questions often focus on core subjects such as Physics, Chemistry, and Mathematics, with formats varying from direct MCQs to application-based problems. Understanding the common question patterns can significantly enhance your performance and help you tackle the exams with ease.

Common Mistakes Students Make

Overlooking the importance of units and dimensions in calculations
Misinterpreting questions due to lack of careful reading
Neglecting to review basic concepts before attempting advanced problems
Rushing through practice questions without thorough understanding

FAQs

Question: What are the best ways to prepare for Engineering Entrance MCQs?
Answer: Focus on understanding concepts, practice regularly with objective questions, and review previous years' papers.

Question: How can I improve my speed in solving MCQs?
Answer: Regular practice, time-bound mock tests, and familiarizing yourself with common question types can help improve your speed.

Start your journey towards success by solving Engineering Entrance MCQ questions today! Test your understanding and build a strong foundation for your exams.

MHT-CET

Q. If the roots of the equation x² + 7x + p = 0 are -3 and -4, find the value of p. (2019)

A. 12
B. 7
C. 10
D. 15

Solution

Using the product of roots: p = (-3)(-4) = 12.

Correct Answer: A — 12

Q. If the roots of the equation x² + 7x + p = 0 are -3 and -4, what is the value of p? (2019)

A. 12
B. 7
C. 15
D. 10

Solution

Using the product of roots: p = (-3)(-4) = 12.

Correct Answer: A — 12

Q. If the roots of the equation x² + mx + n = 0 are 1 and -1, find m and n. (2020)

A. 0, 1
B. 2, 1
C. 0, 0
D. 1, 1

Solution

The sum of the roots is 0 (m = 0) and the product is -1 (n = 1).

Correct Answer: A — 0, 1

Q. If the roots of the equation x² + px + 12 = 0 are 3 and 4, find p. (2020)

A. -7
B. -5
C. -6
D. -8

Solution

Using the sum of the roots: p = -(3 + 4) = -7.

Correct Answer: A — -7

Q. If the roots of the equation x² + px + 12 = 0 are 3 and 4, what is the value of p? (2020)

A. -7
B. -5
C. 7
D. 5

Solution

The sum of the roots is -p = 3 + 4 = 7, hence p = -7.

Correct Answer: A — -7

Q. If the roots of the equation x² + px + q = 0 are 3 and -2, what is the value of p? (2019)

A. -1
B. 1
C. 5
D. -5

Solution

Using the sum of roots formula, p = -(3 + (-2)) = -1, hence p = -1.

Correct Answer: C — 5

Q. If the roots of the equation x² - 6x + p = 0 are 2 and 4, what is the value of p? (2023)

A. 8
B. 12
C. 6
D. 10

Solution

The product of the roots gives p = 2 * 4 = 8.

Correct Answer: B — 12

Q. If the speed of light in a vacuum is 3 x 10^8 m/s, what is its speed in water (n = 1.33)?

A. 2.26 x 10^8 m/s
B. 2.25 x 10^8 m/s
C. 2.27 x 10^8 m/s
D. 2.28 x 10^8 m/s

Solution

The speed of light in a medium is given by v = c/n. Thus, v = (3 x 10^8 m/s) / 1.33 ≈ 2.26 x 10^8 m/s.

Correct Answer: A — 2.26 x 10^8 m/s

Q. If the speed of light in a vacuum is approximately 3 x 10^8 m/s, what is its value in km/s?

A. 300 km/s
B. 3000 km/s
C. 30000 km/s
D. 300000 km/s

Solution

To convert m/s to km/s, divide by 1000. Therefore, 3 x 10^8 m/s = 300000 km/s.

Correct Answer: D — 300000 km/s

Q. If the speed of light in a vacuum is approximately 3 x 10^8 m/s, what is the wavelength of light with a frequency of 6 x 10^14 Hz?

A. 500 nm
B. 600 nm
C. 700 nm
D. 800 nm

Solution

Using the formula c = fλ, where c = 3 x 10^8 m/s and f = 6 x 10^14 Hz. Thus, λ = c/f = (3 x 10^8)/(6 x 10^14) = 500 nm.

Correct Answer: A — 500 nm

Q. If the speed of light in vacuum is 3 x 10^8 m/s, what is its speed in a medium with refractive index 1.5?

A. 2 x 10^8 m/s
B. 2.5 x 10^8 m/s
C. 3 x 10^8 m/s
D. 1.5 x 10^8 m/s

Solution

The speed of light in a medium is given by v = c/n, where c is the speed of light in vacuum and n is the refractive index. Thus, v = 3 x 10^8 m/s / 1.5 = 2 x 10^8 m/s.

Correct Answer: A — 2 x 10^8 m/s

Q. If the speed of light in vacuum is 3 x 10^8 m/s, what is its speed in a medium with a refractive index of 1.5?

A. 2 x 10^8 m/s
B. 2.5 x 10^8 m/s
C. 3 x 10^8 m/s
D. 1.5 x 10^8 m/s

Solution

Speed of light in a medium = speed of light in vacuum / refractive index = (3 x 10^8 m/s) / 1.5 = 2 x 10^8 m/s.

Correct Answer: A — 2 x 10^8 m/s

Q. If the speed of light in vacuum is 3 x 10^8 m/s, what is its speed in glass (n = 1.5)?

A. 2 x 10^8 m/s
B. 2.5 x 10^8 m/s
C. 3 x 10^8 m/s
D. 1.5 x 10^8 m/s

Solution

The speed of light in a medium is given by v = c/n. Therefore, v = (3 x 10^8 m/s) / 1.5 = 2 x 10^8 m/s.

Correct Answer: A — 2 x 10^8 m/s

Q. If the speed of light is 3 x 10^8 m/s, what is its value in km/s? (2021)

A. 3 x 10^5 km/s
B. 3 x 10^6 km/s
C. 3 x 10^7 km/s
D. 3 x 10^8 km/s

Solution

To convert m/s to km/s, divide by 1000. Therefore, 3 x 10^8 m/s = 3 x 10^5 km/s.

Correct Answer: A — 3 x 10^5 km/s

Q. If the temperature of a gas is doubled at constant volume, what happens to its pressure? (2021)

A. It doubles
B. It triples
C. It halves
D. It remains the same

Solution

According to Gay-Lussac's law, pressure is directly proportional to temperature at constant volume.

Correct Answer: A — It doubles

Q. If the total current in an AC circuit is 5A and the voltage is 120V, what is the impedance? (2023)

A. 24Ω
B. 20Ω
C. 30Ω
D. 15Ω

Solution

Impedance (Z) = Voltage (V) / Current (I) = 120V / 5A = 24Ω.

Correct Answer: B — 20Ω

Q. If the total impedance in an AC circuit is 20Ω and the current is 2A, what is the voltage across the circuit? (2023)

A. 10V
B. 20V
C. 30V
D. 40V

Solution

Using Ohm's law, V = IZ = 2A * 20Ω = 40V.

Correct Answer: B — 20V

Q. If the voltage across a capacitor in an AC circuit is 100 V and the capacitive reactance is 50 ohms, what is the current? (2020)

A. 2 A
B. 0.5 A
C. 5 A
D. 10 A

Solution

Using Ohm's law, I = V/Xc = 100 V / 50 ohms = 2 A.

Correct Answer: B — 0.5 A

Q. If the voltage across a capacitor in an AC circuit is 100 V and the capacitive reactance is 50 Ω, what is the current through the capacitor? (2021)

A. 2 A
B. 0.5 A
C. 5 A
D. 10 A

Solution

Using Ohm's law, I = V/Xc = 100 V / 50 Ω = 2 A.

Correct Answer: B — 0.5 A

Q. If the voltage across a capacitor in an AC circuit is 100 V and the capacitive reactance is 50 ohms, what is the current through the capacitor? (2021)

A. 2 A
B. 1 A
C. 0.5 A
D. 0.25 A

Solution

Current I = V/Xc = 100 V / 50 ohms = 2 A.

Correct Answer: B — 1 A

Q. If the voltage across a capacitor in an AC circuit is 100V and the capacitive reactance is 50Ω, what is the current through the capacitor? (2023)

A. 1A
B. 2A
C. 3A
D. 4A

Solution

Current (I) = Voltage (V) / Capacitive Reactance (XC) = 100V / 50Ω = 2A.

Correct Answer: B — 2A

Q. If the voltage across a capacitor in an AC circuit is 100V and the capacitive reactance is 50Ω, what is the current? (2021)

A. 2A
B. 0.5A
C. 5A
D. 100A

Solution

Using Ohm's law, I = V/Xc = 100V/50Ω = 2A.

Correct Answer: B — 0.5A

Q. If the voltage across a capacitor in an AC circuit is 100V and the capacitive reactance is 50 ohms, what is the current? (2023)

A. 2A
B. 0.5A
C. 5A
D. 10A

Solution

Using Ohm's law, I = V/Xc = 100V/50Ω = 2A.

Correct Answer: A — 2A

Q. If the voltage across a capacitor is 100V and the capacitive reactance is 50 ohms, what is the current through the capacitor? (2022)

A. 2 A
B. 1 A
C. 0.5 A
D. 0.25 A

Solution

I = V/Xc = 100/50 = 2 A.

Correct Answer: B — 1 A

Q. If the voltage across a resistor is 240V and the resistance is 60 ohms, what is the current flowing through it? (2020)

A. 2A
B. 4A
C. 6A
D. 8A

Solution

I = V / R = 240V / 60Ω = 4A.

Correct Answer: C — 6A

Q. If the voltage across a resistor is halved, what happens to the current through it? (2020)

A. It doubles
B. It halves
C. It remains the same
D. It quadruples

Solution

According to Ohm's law, if voltage is halved and resistance remains constant, the current also halves.

Correct Answer: B — It halves

Q. If the voltage across an inductor is 12V and the current is 2A, what is the inductive reactance? (2023)

A. 6Ω
B. 12Ω
C. 24Ω
D. 18Ω

Solution

Inductive reactance XL = V/I = 12V/2A = 6Ω.

Correct Answer: A — 6Ω

Q. If the volume of a gas is doubled at constant temperature, what happens to its pressure?

A. It doubles
B. It halves
C. It remains the same
D. It quadruples

Solution

According to Boyle's Law, at constant temperature, pressure is inversely proportional to volume. Therefore, if the volume is doubled, the pressure is halved.

Correct Answer: B — It halves

Q. If the volume of a gas is halved at constant temperature, what happens to its pressure? (2023)

A. It doubles
B. It halves
C. It remains the same
D. It quadruples

Solution

According to Boyle's Law, if the volume is halved, the pressure doubles at constant temperature.

Correct Answer: A — It doubles

Q. If the volume of a gas is halved while keeping the temperature constant, what happens to the pressure of the gas?

A. Halves
B. Doubles
C. Remains the same
D. Increases by 50%

Solution

According to Boyle's Law, if the volume is halved, the pressure doubles.

Correct Answer: B — Doubles

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