Q. What is the number of atoms in 2 moles of CaCO3?
A.
6.022 x 10^23
B.
1.2044 x 10^24
C.
3.011 x 10^23
D.
1.8066 x 10^24
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Solution
Each CaCO3 has 5 atoms (1 Ca, 1 C, 3 O). Number of atoms = moles x atoms per molecule x Avogadro's number = 2 moles x 5 x 6.022 x 10^23 = 1.206 x 10^24 atoms.
Correct Answer:
D
— 1.8066 x 10^24
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Q. What is the number of atoms in 2 moles of Na2SO4?
A.
6.022 x 10^23
B.
1.2044 x 10^24
C.
1.2044 x 10^25
D.
3.011 x 10^23
Show solution
Solution
Na2SO4 has 2 Na + 1 S + 4 O = 7 atoms. Number of atoms = moles x atoms per mole = 2 moles x 7 atoms = 14 atoms = 1.2044 x 10^24 atoms.
Correct Answer:
B
— 1.2044 x 10^24
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Q. What is the number of atoms in 2 moles of NaCl? (2044)
A.
6.022 x 10^23
B.
1.2044 x 10^24
C.
1.2044 x 10^25
D.
3.011 x 10^23
Show solution
Solution
Each NaCl unit has 2 atoms (Na and Cl). Therefore, 2 moles of NaCl contain 2 x 6.022 x 10^23 x 2 = 1.2044 x 10^24 atoms.
Correct Answer:
B
— 1.2044 x 10^24
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Q. What is the number of moles in 10 grams of Na?
A.
0.43
B.
0.22
C.
0.5
D.
0.1
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Solution
Molar mass of Na = 23 g/mol. Number of moles = mass / molar mass = 10 g / 23 g/mol = 0.43 moles.
Correct Answer:
A
— 0.43
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Q. What is the number of moles in 10 grams of NaOH?
A.
0.25
B.
0.5
C.
0.75
D.
1
Show solution
Solution
Molar mass of NaOH = 23 + 16 + 1 = 40 g/mol. Number of moles = mass/molar mass = 10 g / 40 g/mol = 0.25 moles.
Correct Answer:
B
— 0.5
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Q. What is the number of moles in 100 grams of NaOH?
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Solution
Molar mass of NaOH = 23 + 16 + 1 = 40 g/mol. Number of moles = mass/molar mass = 100 g / 40 g/mol = 2.5 moles.
Correct Answer:
A
— 1
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Q. What is the number of moles in 180 grams of glucose (C6H12O6)?
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Solution
Molar mass of C6H12O6 = 6*12 + 12*1 + 6*16 = 180 g/mol. Number of moles = mass/molar mass = 180 g / 180 g/mol = 1 mole.
Correct Answer:
A
— 1
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Q. What is the number of moles in 44 grams of CO2?
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Solution
Molar mass of CO2 = 12 + 16*2 = 44 g/mol. Number of moles = mass/molar mass = 44 g / 44 g/mol = 1 mole.
Correct Answer:
A
— 1
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Q. What is the number of moles in 5 liters of a 2 M NaCl solution?
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Solution
Moles = Molarity x Volume = 2 moles/L x 5 L = 10 moles.
Correct Answer:
A
— 2.5
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Q. What is the order of the reaction if the rate constant has the unit L/mol·s?
A.
Zero order
B.
First order
C.
Second order
D.
Third order
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Solution
If the rate constant has the unit L/mol·s, the reaction is second order.
Correct Answer:
C
— Second order
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Q. What is the osmotic pressure of a 0.2 M NaCl solution at 25 °C? (R = 0.0821 L atm/(K mol))
A.
4.92 atm
B.
2.46 atm
C.
1.23 atm
D.
0.61 atm
Show solution
Solution
Osmotic pressure = iCRT = 2 * 0.2 * 0.0821 * 298 = 4.92 atm (i = 2 for NaCl)
Correct Answer:
A
— 4.92 atm
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Q. What is the osmotic pressure of a solution containing 0.2 moles of solute in 1 liter of solution at 25 °C? (R = 0.0821 L·atm/(K·mol))
A.
4.92 atm
B.
1.64 atm
C.
0.82 atm
D.
2.46 atm
Show solution
Solution
Osmotic pressure = (n/V)RT = (0.2/1) * 0.0821 * 298 = 4.92 atm.
Correct Answer:
A
— 4.92 atm
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Q. What is the osmotic pressure of a solution containing 0.5 moles of glucose in 1 L of water at 25 °C? (R = 0.0821 L·atm/(K·mol))
A.
12.3 atm
B.
1.23 atm
C.
0.5 atm
D.
2.5 atm
Show solution
Solution
Osmotic pressure (π) = nRT/V = (0.5 moles * 0.0821 * 298) / 1 = 12.3 atm.
Correct Answer:
B
— 1.23 atm
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Q. What is the osmotic pressure of a solution containing 0.5 moles of glucose in 1 liter of solution at 25 °C? (R = 0.0821 L·atm/(K·mol))
A.
12.3 atm
B.
0.5 atm
C.
1.0 atm
D.
2.5 atm
Show solution
Solution
Osmotic pressure (π) = nRT/V = (0.5 mol)(0.0821 L·atm/(K·mol))(298 K) = 12.3 atm.
Correct Answer:
A
— 12.3 atm
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Q. What is the osmotic pressure of a solution containing 0.5 moles of glucose in 1 liter of water at 25 °C?
A.
12.3 atm
B.
24.6 atm
C.
6.1 atm
D.
3.1 atm
Show solution
Solution
Osmotic pressure (π) = iCRT = 1 * 0.5 * 0.0821 * 298 = 12.3 atm.
Correct Answer:
A
— 12.3 atm
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Q. What is the osmotic pressure of a solution containing 0.5 moles of glucose in 1 L of solution at 25 °C? (R = 0.0821 L·atm/(K·mol))
A.
12.3 atm
B.
10.2 atm
C.
8.2 atm
D.
6.1 atm
Show solution
Solution
Osmotic pressure (π) = nRT/V = (0.5 moles)(0.0821 L·atm/(K·mol))(298 K) = 12.3 atm.
Correct Answer:
A
— 12.3 atm
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Q. What is the osmotic pressure of a solution containing 0.5 moles of glucose in 2 liters of solution at 25 °C? (R = 0.0821 L·atm/(K·mol))
A.
6.13 atm
B.
12.26 atm
C.
3.07 atm
D.
1.54 atm
Show solution
Solution
Osmotic pressure (π) = nRT/V = (0.5 moles)(0.0821 L·atm/(K·mol))(298 K) / 2 L = 6.13 atm.
Correct Answer:
A
— 6.13 atm
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Q. What is the osmotic pressure of a solution containing 0.5 moles of glucose in 2 liters of solution? (R = 0.0821 L·atm/(K·mol), T = 298 K)
A.
6.14 atm
B.
12.28 atm
C.
3.07 atm
D.
1.54 atm
Show solution
Solution
Osmotic pressure (π) = (n/V)RT = (0.5/2) * 0.0821 * 298 = 6.14 atm.
Correct Answer:
A
— 6.14 atm
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Q. What is the osmotic pressure of a solution containing 0.5 moles of solute in 2 liters of solution at 25 °C? (R = 0.0821 L·atm/(K·mol))
A.
10.25 atm
B.
5.12 atm
C.
2.03 atm
D.
1.23 atm
Show solution
Solution
Osmotic pressure (π) = nRT/V = (0.5 moles * 0.0821 * 298) / 2 = 12.21 atm.
Correct Answer:
B
— 5.12 atm
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Q. What is the osmotic pressure of a solution containing 1 mole of glucose in 2 liters of solution at 25 °C? (R = 0.0821 L·atm/(K·mol))
A.
0.41 atm
B.
0.82 atm
C.
1.23 atm
D.
1.64 atm
Show solution
Solution
Osmotic pressure (π) = nRT/V = (1 mol)(0.0821 L·atm/(K·mol))(298 K) / 2 L = 0.82 atm.
Correct Answer:
B
— 0.82 atm
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Q. What is the osmotic pressure of a solution directly proportional to?
A.
Temperature
B.
Concentration of solute
C.
Volume of solvent
D.
Both A and B
Show solution
Solution
Osmotic pressure is directly proportional to both the temperature and the concentration of solute.
Correct Answer:
D
— Both A and B
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Q. What is the oxidation state of chlorine in NaClO3?
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Solution
In NaClO3, chlorine has an oxidation state of +5.
Correct Answer:
C
— +5
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Q. What is the oxidation state of chromium in K2Cr2O7?
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Solution
In K2Cr2O7, the total oxidation state of the two potassium ions and seven oxygen ions is -12, leading to +6 for each chromium.
Correct Answer:
C
— +6
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Q. What is the oxidation state of chromium in K2[Cr2O7]?
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Solution
In K2[Cr2O7], the overall charge is 0. Each potassium (K) has a +1 charge, and each oxygen (O) has a -2 charge. Solving for chromium gives an oxidation state of +6.
Correct Answer:
C
— +6
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Q. What is the oxidation state of chromium in the complex [Cr(NH3)4Cl2]Cl?
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Solution
Let the oxidation state of Cr be x. The equation is x + 4(0) + 2(-1) = +1 (from Cl). Solving gives x = +3.
Correct Answer:
B
— +3
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Q. What is the oxidation state of chromium in [Cr(NH3)4Cl2]+?
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Solution
Let the oxidation state of Cr be x. The equation is x + 4(0) + 2(-1) = +1. Solving gives x = +3.
Correct Answer:
B
— +3
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Q. What is the oxidation state of chromium in [Cr(NH3)4Cl2]Cl?
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Solution
Let the oxidation state of Cr be x. The equation is x + 4(0) + 2(-1) = +1. Solving gives x = +3.
Correct Answer:
B
— +3
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Q. What is the oxidation state of chromium in [Cr(NH3)6]Cl3?
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Solution
The complex is neutral, and the three chloride ions contribute -3 charge. Therefore, the oxidation state of Cr must be +3.
Correct Answer:
B
— +3
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Q. What is the oxidation state of hydrogen in H2O?
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Solution
In water (H2O), the oxidation state of hydrogen is +1.
Correct Answer:
A
— +1
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Q. What is the oxidation state of hydrogen in metal hydrides?
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Solution
In metal hydrides, hydrogen has an oxidation state of -1.
Correct Answer:
C
— -1
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Chemistry Syllabus (JEE Main) MCQ & Objective Questions
The Chemistry Syllabus for JEE Main is crucial for students aiming to excel in their exams. Understanding this syllabus not only helps in grasping fundamental concepts but also enhances performance in objective questions and MCQs. Regular practice with these types of questions is essential for scoring better and mastering important topics.
What You Will Practise Here
Basic Concepts of Chemistry
Atomic Structure and Chemical Bonding
States of Matter: Gases and Liquids
Thermodynamics and Thermochemistry
Equilibrium: Chemical and Ionic
Redox Reactions and Electrochemistry
Hydrocarbons and Environmental Chemistry
Exam Relevance
The Chemistry syllabus is a significant part of CBSE, State Boards, NEET, and JEE exams. Questions from this syllabus often appear in various formats, including multiple-choice questions, assertion-reason type questions, and numerical problems. Familiarity with the common question patterns can greatly enhance your exam preparation and confidence.
Common Mistakes Students Make
Misunderstanding the periodic trends and their implications.
Confusing different types of chemical bonds and their properties.
Neglecting to balance redox reactions properly.
Overlooking the significance of units in thermodynamic calculations.
Failing to apply concepts of equilibrium in problem-solving.
FAQs
Question: What are the key topics I should focus on in the Chemistry syllabus for JEE Main?Answer: Focus on atomic structure, chemical bonding, thermodynamics, and equilibrium as they are frequently tested.
Question: How can I improve my performance in Chemistry MCQs?Answer: Regular practice with past papers and understanding concepts deeply will help you tackle MCQs effectively.
Start your journey towards mastering the Chemistry Syllabus (JEE Main) by solving practice MCQs today. Test your understanding and build confidence for your exams!
