Engineering Entrance Exam Preparation Resources

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Engineering Entrance MCQ & Objective Questions

Preparing for Engineering Entrance exams is crucial for aspiring engineers in India. Mastering MCQs and objective questions not only enhances your understanding of key concepts but also boosts your confidence during exams. Regular practice with these questions helps identify important topics and improves your overall exam preparation.

What You Will Practise Here

Fundamental concepts of Physics and Mathematics
Key formulas and their applications in problem-solving
Important definitions and theorems relevant to engineering
Diagrams and graphical representations for better understanding
Conceptual questions that challenge your critical thinking
Previous years' question papers and their analysis
Time management strategies while solving MCQs

Exam Relevance

The Engineering Entrance syllabus is integral to various examinations like CBSE, State Boards, NEET, and JEE. Questions often focus on core subjects such as Physics, Chemistry, and Mathematics, with formats varying from direct MCQs to application-based problems. Understanding the common question patterns can significantly enhance your performance and help you tackle the exams with ease.

Common Mistakes Students Make

Overlooking the importance of units and dimensions in calculations
Misinterpreting questions due to lack of careful reading
Neglecting to review basic concepts before attempting advanced problems
Rushing through practice questions without thorough understanding

FAQs

Question: What are the best ways to prepare for Engineering Entrance MCQs?
Answer: Focus on understanding concepts, practice regularly with objective questions, and review previous years' papers.

Question: How can I improve my speed in solving MCQs?
Answer: Regular practice, time-bound mock tests, and familiarizing yourself with common question types can help improve your speed.

Start your journey towards success by solving Engineering Entrance MCQ questions today! Test your understanding and build a strong foundation for your exams.

MHT-CET

Q. If the radius of a circle is decreased by 2 cm, how does the area change? (Use π = 3.14) (2020)

A. Decreases by 12.56 cm²
B. Decreases by 25.12 cm²
C. Increases by 12.56 cm²
D. Remains the same

Solution

Area change = π[(r-2)² - r²] = π[-4r + 4] = 3.14 * (-4r + 4).

Correct Answer: B — Decreases by 25.12 cm²

Q. If the radius of a circle is doubled, how does the area change? (2021)

A. It doubles
B. It triples
C. It quadruples
D. It remains the same

Solution

Area = πr²; if r is doubled, area = π(2r)² = 4πr², so it quadruples.

Correct Answer: C — It quadruples

Q. If the radius of a circle is halved, by what factor does the circumference decrease? (2020)

A. 1/2
B. 1/4
C. 1/3
D. 1/6

Solution

Circumference = 2πr; If r is halved, new circumference = πr; Factor = 1/2.

Correct Answer: A — 1/2

Q. If the radius of a circle is halved, how does the circumference change? (2021)

A. Halved
B. Remains the same
C. Doubled
D. Tripled

Solution

Circumference = 2πr. If radius is halved, new circumference = 2π(r/2) = πr, which is halved.

Correct Answer: A — Halved

Q. If the radius of a circle is halved, how does the circumference change? (2022) 2022

A. Halved
B. Remains the same
C. Doubled
D. Quadrupled

Solution

Circumference = 2πr. If radius is halved, new circumference = 2π(r/2) = πr, which is halved.

Correct Answer: A — Halved

Q. If the radius of a circle is tripled, by what factor does the area increase? (2021)

A. 3
B. 6
C. 9
D. 12

Solution

Area increases by a factor of (3r)²/r² = 9.

Correct Answer: C — 9

Q. If the radius of a circle is tripled, how does the area change? (2019)

A. Increases by 3 times
B. Increases by 6 times
C. Increases by 9 times
D. Remains the same

Solution

Area = πr². If radius is tripled, new area = π(3r)² = 9πr², which is 9 times the original area.

Correct Answer: C — Increases by 9 times

Q. If the radius of the Earth is doubled, what will happen to the gravitational force experienced by an object on its surface?

A. It will double
B. It will remain the same
C. It will be halved
D. It will be quartered

Solution

Gravitational force is inversely proportional to the square of the radius. If radius is doubled, F becomes F/4.

Correct Answer: D — It will be quartered

Q. If the radius of the Earth were to increase by 50%, what would happen to the weight of an object on its surface?

A. It increases by 50%
B. It increases by 25%
C. It decreases by 25%
D. It remains the same

Solution

Weight is inversely proportional to the square of the radius. If radius increases by 50%, weight decreases by 25%.

Correct Answer: C — It decreases by 25%

Q. If the radius of the Earth were to increase while keeping its mass constant, what would happen to the gravitational acceleration at the surface? (2023)

A. It increases
B. It decreases
C. It remains the same
D. It becomes zero

Solution

Gravitational acceleration is inversely proportional to the square of the radius. If radius increases, g decreases.

Correct Answer: B — It decreases

Q. If the radius of the Earth were to increase while keeping its mass constant, what would happen to the gravitational acceleration at its surface?

A. It increases
B. It decreases
C. It remains the same
D. It becomes zero

Solution

Gravitational acceleration g = GM/R². If R increases, g decreases.

Correct Answer: B — It decreases

Q. If the radius of the Earth were to increase while keeping its mass constant, what would happen to the value of g? (2023)

A. g increases
B. g decreases
C. g remains the same
D. g becomes zero

Solution

If the radius increases while mass remains constant, g decreases because g = G * M / r^2.

Correct Answer: B — g decreases

Q. If the rate of a reaction doubles when the temperature increases by 10°C, what is the approximate activation energy? (2020)

A. 20 kJ/mol
B. 40 kJ/mol
C. 60 kJ/mol
D. 80 kJ/mol

Solution

Using the Arrhenius equation, if the rate doubles for a 10°C increase, Ea is approximately 40 kJ/mol.

Correct Answer: B — 40 kJ/mol

Q. If the rate of a reaction is directly proportional to the concentration of one reactant raised to the power of 3, what is the order of the reaction? (2023)

A. Zero
B. First
C. Second
D. Third

Solution

The order of the reaction is third because the rate is proportional to the concentration raised to the power of 3.

Correct Answer: D — Third

Q. If the rate of a reaction is given by rate = k[A]², what is the order of the reaction? (2021)

A. Zero
B. First
C. Second
D. Third

Solution

The reaction is second-order because the rate depends on the square of the concentration of A.

Correct Answer: C — Second

Q. If the resistance of a circuit is 10 ohms and the induced EMF is 5 V, what is the induced current? (2022)

A. 0.5 A
B. 1 A
C. 2 A
D. 5 A

Solution

Using Ohm's law, I = V/R = 5 V / 10 ohms = 0.5 A.

Correct Answer: A — 0.5 A

Q. If the resistance of a conductor is doubled, what happens to the current flowing through it when the voltage remains constant? (2022)

A. Doubles
B. Halves
C. Remains the same
D. Increases by 1.5 times

Solution

According to Ohm's law, I = V/R. If R is doubled, I will be halved.

Correct Answer: B — Halves

Q. If the revenue function is R(x) = 100x - 2x^2, find the number of units that maximizes revenue. (2021)

A. 25
B. 50
C. 75
D. 100

Solution

Max revenue occurs at x = -b/(2a) = 100/(2*2) = 25.

Correct Answer: B — 50

Q. If the revenue function is R(x) = 20x - 0.5x^2, find the quantity that maximizes revenue. (2021)

A. 10
B. 20
C. 15
D. 25

Solution

R'(x) = 20 - x = 0 gives x = 20. This maximizes revenue.

Correct Answer: B — 20

Q. If the revenue function is R(x) = 50x - 0.5x^2, find the number of units that maximizes revenue. (2023)

A. 25
B. 50
C. 30
D. 40

Solution

Max revenue occurs at x = -b/(2a) = -50/(2*-0.5) = 50.

Correct Answer: A — 25

Q. If the roots of the equation x² + 2x + k = 0 are 1 and -3, what is the value of k? (2020)

A. -3
B. 2
C. 3
D. 4

Solution

Using the sum and product of roots: 1 + (-3) = -2 and 1 * (-3) = -3, thus k = 3.

Correct Answer: C — 3

Q. If the roots of the equation x² + 2x + k = 0 are real and distinct, what is the condition for k? (2020)

A. k > 1
B. k < 1
C. k > 4
D. k < 4

Solution

The discriminant must be greater than zero: 2² - 4*1*k > 0, which simplifies to k < 1.

Correct Answer: C — k > 4

Q. If the roots of the equation x² + 5x + 6 = 0 are a and b, what is the value of a + b? (2019)

A. 5
B. 6
C. 10
D. 4

Solution

The sum of the roots is given by -b/a = -5/1 = -5.

Correct Answer: A — 5

Q. If the roots of the equation x² + 5x + k = 0 are -2 and -3, find k. (2020)

A. 6
B. 5
C. 7
D. 8

Solution

Using the product of roots: k = (-2)(-3) = 6.

Correct Answer: A — 6

Q. If the roots of the equation x² + 5x + k = 0 are 1 and 4, find k. (2020)

A. 4
B. 5
C. 6
D. 7

Solution

Using the sum and product of roots: k = 1*4 = 4, and sum = 1 + 4 = 5, thus k = 7.

Correct Answer: D — 7

Q. If the roots of the equation x² + 5x + k = 0 are real and distinct, what is the condition for k? (2020)

A. k > 25
B. k < 25
C. k = 25
D. k ≤ 25

Solution

The discriminant must be greater than zero: 5² - 4*1*k > 0, thus k < 25.

Correct Answer: A — k > 25

Q. If the roots of the equation x² + 5x + q = 0 are 1 and 4, find q. (2019)

A. 5
B. 4
C. 6
D. 7

Solution

Using the product of roots: q = 1 * 4 = 4.

Correct Answer: A — 5

Q. If the roots of the equation x² + 7x + k = 0 are -3 and -4, find k. (2022)

A. 12
B. 7
C. 15
D. 20

Solution

Using the sum of roots (-3 + -4 = -7) and product of roots (-3*-4 = 12), we find k = 12.

Correct Answer: A — 12

Q. If the roots of the equation x² + 7x + k = 0 are 1 and 6, what is the value of k? (2020)

A. 6
B. 7
C. 8
D. 9

Solution

Using the product of roots, k = 1*6 = 6.

Correct Answer: C — 8

Q. If the roots of the equation x² + 7x + p = 0 are -3 and -4, find p. (2019)

A. 12
B. 7
C. 15
D. 10

Solution

Using the sum of roots (-3 + -4 = -7) and product of roots (-3*-4 = 12), we find p = 12.

Correct Answer: A — 12

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