Using conservation of energy, potential energy at the top equals kinetic energy at the bottom. The speed v at the bottom is v = √(2gh).

At the bottom, total kinetic energy = translational + rotational. For a solid cylinder, the ratio of translational to total kinetic energy is 2:1.

For a solid cylinder, the ratio of translational kinetic energy to total kinetic energy is 2/5.

At the bottom, total mechanical energy is converted into kinetic energy, which is the sum of translational and rotational kinetic energy. For a solid cylinder, 2/3 of the energy is kinetic.

Using conservation of energy, potential energy at the top equals kinetic energy at the bottom. For a solid cylinder, v = √(3gh/2).

The solid sphere will hit the ground first because it has a smaller moment of inertia, allowing it to roll down faster.

The solid sphere will have a greater translational speed because it has a smaller moment of inertia.

The solid sphere will have a greater linear speed because it has a smaller moment of inertia, allowing it to convert more potential energy into translational kinetic energy.

The solid sphere reaches the bottom first because it has a lower moment of inertia, allowing it to convert more potential energy into translational kinetic energy.

The solid sphere has a smaller moment of inertia compared to the hollow sphere, allowing it to accelerate faster down the incline.

Total angular momentum L = Iω, where I = (2/5)MR^2 for a solid sphere.

The moment of inertia of a solid sphere about its center is I = 2/5 MR^2.

The moment of inertia of a solid sphere about an axis through its center is I = 2/5 MR^2.

The acceleration of the center of mass of a rolling object is given by a = g sin(θ) / (1 + k^2/r^2). For a solid sphere, k^2/r^2 = 2/5, thus a = g sin(θ) / (1 + 2/5) = g sin(θ) / (7/5) = (5/7)g sin(θ).

The acceleration of the center of mass of a solid sphere rolling down an incline is given by a = g sin(θ) / (1 + (2/5)) = g sin(θ) / (7/5) = (5/7) g sin(θ).

Using conservation of energy, the final velocity of the solid sphere at the bottom is v = √(5gh/7).

Using conservation of energy, potential energy at the top (mgh) converts to kinetic energy (1/2 mv^2 + 1/2 Iω^2). For a solid sphere, I = (2/5)mr^2 and ω = v/r. Solving gives v = √(2gh).

The total kinetic energy is the sum of translational and rotational kinetic energy. For a solid sphere, the ratio of translational to total kinetic energy is 2:3.

The total kinetic energy is the sum of translational and rotational kinetic energy. For a solid sphere, the ratio of translational to total kinetic energy is 2:5, which simplifies to 2:3.

For a solid sphere, the ratio of translational kinetic energy to total kinetic energy is 2:3.

Using the wave equation v = fλ, we can find λ = v/f = 340/170 = 2 m.

Using the wave equation v = fλ, we can find the wavelength: λ = v/f = 340 m/s / 1700 Hz = 0.2 m.

Using the wave equation v = fλ, we can find the wavelength: λ = v/f = 340 m/s / 680 Hz = 0.5 m.

Using the wave equation v = fλ, we can find the wavelength: λ = v/f = 340/170 = 2 m.

Sound travels faster in water than in air, so its speed increases when it enters water.

Wavelength λ = v/f = 340 m/s / 1700 Hz = 0.2 m.

Wavelength λ = v/f = 340 m/s / 1700 Hz = 0.2 m.

Wavelength λ = v/f = 340 m/s / 170 Hz = 2 m.

Wavelength = Speed / Frequency = 340 m/s / 1700 Hz = 0.2 m.

Using the formula v = fλ, we can rearrange to find λ = v/f. Thus, λ = 340 m/s / 1700 Hz = 0.2 m.