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Q. A cyclist accelerates from rest to a speed of 10 m/s in 5 seconds. What is the acceleration? (2023)

A. 1 m/s²
B. 2 m/s²
C. 3 m/s²
D. 4 m/s²

Solution

Acceleration = (final velocity - initial velocity) / time = (10 m/s - 0) / 5 s = 2 m/s².

Correct Answer: B — 2 m/s²

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Q. A cyclist accelerates from rest to a speed of 10 m/s in 5 seconds. What is the cyclist's acceleration? (2021)

A. 1 m/s²
B. 2 m/s²
C. 3 m/s²
D. 4 m/s²

Solution

Acceleration a = (final velocity - initial velocity) / time = (10 m/s - 0) / 5 s = 2 m/s².

Correct Answer: B — 2 m/s²

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Q. A cyclist accelerates from rest to a speed of 15 m/s. If the mass of the cyclist and the bicycle is 75 kg, what is the kinetic energy at that speed?

A. 500 J
B. 750 J
C. 1000 J
D. 1250 J

Solution

Kinetic Energy = 0.5 × mass × velocity² = 0.5 × 75 kg × (15 m/s)² = 8437.5 J.

Correct Answer: C — 1000 J

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Q. A cyclist accelerates from rest to a speed of 15 m/s. If the mass of the cyclist and the bicycle is 75 kg, what is the work done by the cyclist?

A. 800 J
B. 900 J
C. 1000 J
D. 1200 J

Solution

Work done = Change in Kinetic Energy = 0.5 × mass × (final velocity² - initial velocity²) = 0.5 × 75 kg × (15 m/s)² = 843.75 J.

Correct Answer: C — 1000 J

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Q. A cyclist covers 15 km in 30 minutes. What is the speed in km/h? (2023)

A. 20 km/h
B. 25 km/h
C. 30 km/h
D. 35 km/h

Solution

Speed = Distance/Time = 15 km/(30/60) h = 30 km/h

Correct Answer: B — 25 km/h

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Q. A cyclist covers a distance of 30 km at a speed of 15 km/h. How long does it take to complete the journey? (2022)

A. 1 hour
B. 2 hours
C. 2.5 hours
D. 3 hours

Solution

Time = Distance / Speed = 30 km / 15 km/h = 2 hours.

Correct Answer: B — 2 hours

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Q. A cyclist covers a distance of 30 km at a speed of 15 km/h. How long does it take to cover this distance? (2022)

A. 1 hour
B. 2 hours
C. 2.5 hours
D. 3 hours

Solution

Time = Distance / Speed = 30 km / 15 km/h = 2 hours.

Correct Answer: B — 2 hours

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Q. A cyclist covers a distance of 30 km in 1.5 hours. What is his speed in m/s? (2022)

A. 5 m/s
B. 10 m/s
C. 15 m/s
D. 20 m/s

Solution

Speed = Distance / Time = 30 km / 1.5 h = 20 km/h = (20 × 1000 m) / (3600 s) = 5.56 m/s, approximately 5 m/s.

Correct Answer: B — 10 m/s

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Q. A cyclist covers a distance of 45 km in 1.5 hours. What is his average speed?

A. 30 km/h
B. 25 km/h
C. 20 km/h
D. 35 km/h

Solution

Average speed = total distance / total time. Thus, average speed = 45 km / 1.5 h = 30 km/h.

Correct Answer: A — 30 km/h

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Q. A cyclist covers a distance of 90 km in 3 hours. What is the average speed of the cyclist? (2022)

A. 25 km/h
B. 30 km/h
C. 35 km/h
D. 40 km/h

Solution

Average Speed = Total Distance / Total Time = 90 km / 3 h = 30 km/h.

Correct Answer: B — 30 km/h

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Q. A cyclist covers a distance of 90 km in 4.5 hours. What is the average speed of the cyclist? (2020)

A. 15 km/h
B. 20 km/h
C. 25 km/h
D. 30 km/h

Solution

Average Speed = Total Distance / Total Time = 90 km / 4.5 h = 20 km/h

Correct Answer: C — 25 km/h

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Q. A cyclist does 1500 J of work to climb a hill. If he takes 5 minutes, what is his average power output?

A. 5 W
B. 10 W
C. 15 W
D. 20 W

Solution

Power = Work / Time = 1500 J / (5 * 60 s) = 5 W.

Correct Answer: B — 10 W

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Q. A cyclist does 300 J of work to climb a hill. If the cyclist's mass is 75 kg, what is the height of the hill? (2023)

A. 0.4 m
B. 0.5 m
C. 0.6 m
D. 0.8 m

Solution

Potential Energy = mass × g × height; 300 J = 75 kg × 10 m/s² × height; height = 300 J / (75 kg × 10 m/s²) = 0.4 m

Correct Answer: B — 0.5 m

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Q. A cyclist does 300 J of work to climb a hill. If the height of the hill is 5 m, what is the effective weight of the cyclist?

A. 30 kg
B. 60 kg
C. 90 kg
D. 120 kg

Solution

Weight = Work / Height = 300 J / 5 m = 60 N; mass = Weight / g = 60 N / 9.8 m/s² ≈ 6.12 kg.

Correct Answer: B — 60 kg

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Q. A cyclist does 300 J of work to climb a hill. If the height of the hill is 5 m, what is the mass of the cyclist? (g = 9.8 m/s²)

A. 6.12 kg
B. 10 kg
C. 15 kg
D. 20 kg

Solution

Using Work = mgh; m = Work / (gh) = 300 J / (9.8 m/s² * 5 m) = 6.12 kg.

Correct Answer: A — 6.12 kg

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Q. A cyclist does 300 J of work to climb a hill. If the hill is 5 m high, what is the weight of the cyclist? (2020)

A. 60 kg
B. 30 kg
C. 50 kg
D. 40 kg

Solution

Work = m × g × h. 300 J = m × 9.8 m/s² × 5 m. m = 300 J / (9.8 m/s² × 5 m) = 6.12 kg.

Correct Answer: A — 60 kg

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Q. A cyclist does 300 J of work to climb a hill. If the hill is 5 m high, what is the effective weight of the cyclist? (2022)

A. 30 kg
B. 60 kg
C. 90 kg
D. 120 kg

Solution

Weight = Work done / height = 300 J / 5 m = 60 kg

Correct Answer: B — 60 kg

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Q. A cyclist does 600 J of work to climb a hill. If he takes 30 seconds, what is his average power output? (2022)

A. 10 W
B. 20 W
C. 30 W
D. 40 W

Solution

Power = Work / Time = 600 J / 30 s = 20 W.

Correct Answer: B — 20 W

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Q. A cyclist exerts a force of 100 N to maintain a speed of 5 m/s. What is the power output of the cyclist?

A. 200 W
B. 500 W
C. 1000 W
D. 250 W

Solution

Power can be calculated using P = F * v. Here, F = 100 N and v = 5 m/s. Thus, P = 100 N * 5 m/s = 500 W.

Correct Answer: B — 500 W

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Q. A cyclist is moving around a circular track of radius 100 m. If he completes one lap in 40 seconds, what is his average speed?

A. 5 m/s
B. 10 m/s
C. 15 m/s
D. 20 m/s

Solution

Circumference = 2πr = 2π(100 m). Average speed = distance/time = (2π(100 m))/40 s ≈ 15.7 m/s.

Correct Answer: B — 10 m/s

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Q. A cyclist is moving at 15 m/s and a pedestrian at 5 m/s in the same direction. How fast does the cyclist appear to be moving to the pedestrian?

A. 10 m/s
B. 15 m/s
C. 20 m/s
D. 5 m/s

Solution

Relative speed = Speed of cyclist - Speed of pedestrian = 15 m/s - 5 m/s = 10 m/s.

Correct Answer: A — 10 m/s

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Q. A cyclist is moving at 15 m/s and a pedestrian is walking at 5 m/s in the same direction. What is the relative speed of the pedestrian with respect to the cyclist?

A. 10 m/s
B. 5 m/s
C. 20 m/s
D. 15 m/s

Solution

Relative speed = Speed of pedestrian - Speed of cyclist = 5 m/s - 15 m/s = -10 m/s (10 m/s behind).

Correct Answer: A — 10 m/s

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Q. A cyclist is moving at 15 m/s and a pedestrian is walking at 5 m/s in the same direction. What is the speed of the cyclist relative to the pedestrian?

A. 10 m/s
B. 15 m/s
C. 5 m/s
D. 20 m/s

Solution

Relative speed = Speed of cyclist - Speed of pedestrian = 15 m/s - 5 m/s = 10 m/s.

Correct Answer: A — 10 m/s

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Q. A cyclist is moving at 15 m/s and passes a stationary observer. If the observer starts moving at 5 m/s in the same direction, what is the speed of the cyclist relative to the observer?

A. 10 m/s
B. 15 m/s
C. 20 m/s
D. 5 m/s

Solution

Relative speed = Speed of cyclist - Speed of observer = 15 m/s - 5 m/s = 10 m/s.

Correct Answer: A — 10 m/s

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Q. A cyclist is moving at 15 m/s towards the east while a car is moving at 25 m/s towards the west. What is the relative speed of the cyclist with respect to the car?

A. 10 m/s
B. 15 m/s
C. 40 m/s
D. 25 m/s

Solution

Relative speed = Speed of cyclist + Speed of car = 15 m/s + 25 m/s = 40 m/s.

Correct Answer: C — 40 m/s

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Q. A cyclist is moving at 15 m/s while a car is moving at 25 m/s in the same direction. What is the speed of the cyclist relative to the car?

A. 10 m/s
B. 15 m/s
C. 25 m/s
D. 40 m/s

Solution

Relative speed = Speed of car - Speed of cyclist = 25 m/s - 15 m/s = 10 m/s.

Correct Answer: A — 10 m/s

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Q. A cyclist is moving at a speed of 10 m/s. If he doubles his speed, how much more kinetic energy will he have? (2023)

A. 4 times
B. 2 times
C. 3 times
D. 1.5 times

Solution

Kinetic Energy is proportional to the square of the speed. If speed is doubled, KE increases by a factor of 2^2 = 4.

Correct Answer: A — 4 times

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Q. A cyclist is moving at a speed of 15 km/h. If a car is moving in the same direction at 30 km/h, what is the relative speed of the car with respect to the cyclist?

A. 15 km/h
B. 30 km/h
C. 45 km/h
D. 0 km/h

Solution

Relative speed = speed of car - speed of cyclist = 30 - 15 = 15 km/h.

Correct Answer: A — 15 km/h

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Q. A cyclist is moving at a speed of 15 m/s. If the mass of the cyclist and the bicycle is 75 kg, what is the total kinetic energy?

A. 800 J
B. 900 J
C. 1000 J
D. 1200 J

Solution

KE = 0.5 × m × v² = 0.5 × 75 kg × (15 m/s)² = 0.5 × 75 × 225 = 8437.5 J.

Correct Answer: C — 1000 J

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Q. A cyclist is moving at a speed of 15 m/s. If the total mass of the cyclist and the bicycle is 75 kg, what is the kinetic energy?

A. 843.75 J
B. 562.5 J
C. 1687.5 J
D. 1125 J

Solution

Kinetic Energy (KE) = 0.5 × m × v² = 0.5 × 75 kg × (15 m/s)² = 0.5 × 75 × 225 = 8437.5 J.

Correct Answer: A — 843.75 J

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Major Competitive Exams

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