Engineering Entrance Exam Preparation Resources

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Engineering Entrance MCQ & Objective Questions

Preparing for Engineering Entrance exams is crucial for aspiring engineers in India. Mastering MCQs and objective questions not only enhances your understanding of key concepts but also boosts your confidence during exams. Regular practice with these questions helps identify important topics and improves your overall exam preparation.

What You Will Practise Here

Fundamental concepts of Physics and Mathematics
Key formulas and their applications in problem-solving
Important definitions and theorems relevant to engineering
Diagrams and graphical representations for better understanding
Conceptual questions that challenge your critical thinking
Previous years' question papers and their analysis
Time management strategies while solving MCQs

Exam Relevance

The Engineering Entrance syllabus is integral to various examinations like CBSE, State Boards, NEET, and JEE. Questions often focus on core subjects such as Physics, Chemistry, and Mathematics, with formats varying from direct MCQs to application-based problems. Understanding the common question patterns can significantly enhance your performance and help you tackle the exams with ease.

Common Mistakes Students Make

Overlooking the importance of units and dimensions in calculations
Misinterpreting questions due to lack of careful reading
Neglecting to review basic concepts before attempting advanced problems
Rushing through practice questions without thorough understanding

FAQs

Question: What are the best ways to prepare for Engineering Entrance MCQs?
Answer: Focus on understanding concepts, practice regularly with objective questions, and review previous years' papers.

Question: How can I improve my speed in solving MCQs?
Answer: Regular practice, time-bound mock tests, and familiarizing yourself with common question types can help improve your speed.

Start your journey towards success by solving Engineering Entrance MCQ questions today! Test your understanding and build a strong foundation for your exams.

MHT-CET

Q. If the inductance of a coil is 0.5H and the frequency is 60Hz, what is the inductive reactance? (2023)

A. 31.42 ohms
B. 18.85 ohms
C. 37.70 ohms
D. 25.13 ohms

Solution

Xl = 2πfL = 2π × 60 × 0.5 = 31.42 ohms.

Correct Answer: A — 31.42 ohms

Q. If the inductive reactance of a coil is 30Ω and the resistance is 10Ω, what is the total impedance? (2018)

A. 10Ω
B. 30Ω
C. 33.33Ω
D. 40Ω

Solution

Total impedance Z = √(R² + (XL)²) = √(10² + 30²) = √(100 + 900) = √1000 = 31.62Ω.

Correct Answer: C — 33.33Ω

Q. If the latent heat of fusion of ice is 334 J/g, how much heat is required to melt 50 g of ice? (2019)

A. 1670 J
B. 3340 J
C. 5000 J
D. 1000 J

Solution

Heat required = mass × latent heat = 50 g × 334 J/g = 16700 J.

Correct Answer: A — 1670 J

Q. If the latent heat of vaporization of water is 2260 kJ/kg, how much energy is required to convert 0.5 kg of water at 100°C to steam at 100°C?

A. 1130 kJ
B. 2260 kJ
C. 3390 kJ
D. 4520 kJ

Solution

Energy required = mass * latent heat = 0.5 kg * 2260 kJ/kg = 1130 kJ.

Correct Answer: A — 1130 kJ

Q. If the line 2x + 3y = 6 intersects the x-axis, what is the point of intersection?

A. (3, 0)
B. (0, 2)
C. (0, 3)
D. (2, 0)

Solution

Setting y = 0 gives 2x = 6, thus x = 3. The point of intersection is (3, 0).

Correct Answer: A — (3, 0)

Q. If the line 2x + 3y = 6 intersects the x-axis, what is the x-coordinate of the intersection point?

A. 0
B. 2
C. 3
D. 6

Solution

Setting y = 0 gives 2x = 6, thus x = 3. The x-coordinate of the intersection point is 3.

Correct Answer: B — 2

Q. If the line 3x + 4y = 12 intersects the y-axis, what is the point of intersection? (2021)

A. (0, 3)
B. (0, 4)
C. (0, 2)
D. (0, 1)

Solution

Setting x = 0 gives 4y = 12, thus y = 3. The point of intersection is (0, 3).

Correct Answer: A — (0, 3)

Q. If the line 3x - 4y + 12 = 0 intersects the x-axis, what is the x-coordinate of the intersection point? (2021)

A. -4
B. 4
C. 3
D. -3

Solution

Setting y = 0 in the equation gives 3x + 12 = 0, thus x = -4.

Correct Answer: A — -4

Q. If the line 3x - 4y + 12 = 0 intersects the y-axis, what is the point of intersection?

A. (0, 3)
B. (0, -3)
C. (0, 4)
D. (0, -4)

Solution

Setting x = 0 gives -4y + 12 = 0, thus y = -3. The point of intersection is (0, -3).

Correct Answer: D — (0, -4)

Q. If the line 3x - 4y + 12 = 0 is parallel to another line, what is the slope of the parallel line?

A. 3/4
B. -3/4
C. 4/3
D. -4/3

Solution

Rearranging gives y = (3/4)x + 3. The slope of the line is 3/4, so the slope of the parallel line is -3/4.

Correct Answer: B — -3/4

Q. If the line 3x - 4y + 12 = 0 is parallel to which of the following lines?

A. 6x - 8y + 24 = 0
B. 3x + 4y - 12 = 0
C. x + 2y - 5 = 0
D. 2x - 3y + 6 = 0

Solution

Parallel lines have the same slope. The slope of the given line is 3/4, which is the same as the slope of 6x - 8y + 24 = 0.

Correct Answer: A — 6x - 8y + 24 = 0

Q. If the line 7x + 2y = 14 is transformed to slope-intercept form, what is the slope?

A. -7/2
B. 7/2
C. 2/7
D. -2/7

Solution

Rearranging to y = -7/2x + 7 shows that the slope is -7/2.

Correct Answer: A — -7/2

Q. If the magnetic field strength is doubled, what happens to the force experienced by a current-carrying conductor? (2022)

A. It doubles
B. It halves
C. It remains the same
D. It quadruples

Solution

The force experienced by a current-carrying conductor in a magnetic field is directly proportional to the magnetic field strength. Therefore, if the magnetic field strength is doubled, the force also doubles.

Correct Answer: A — It doubles

Q. If the magnetic field strength is doubled, what happens to the force experienced by a current-carrying conductor in that field? (2022)

A. It doubles
B. It halves
C. It remains the same
D. It quadruples

Solution

The force experienced by a current-carrying conductor in a magnetic field is directly proportional to the magnetic field strength. Therefore, if the magnetic field strength is doubled, the force also doubles.

Correct Answer: A — It doubles

Q. If the magnetic field strength is doubled, what happens to the force on a current-carrying conductor in that field? (2022)

A. It doubles
B. It halves
C. It remains the same
D. It quadruples

Solution

The force on a current-carrying conductor is directly proportional to the magnetic field strength, so if the field strength is doubled, the force also doubles.

Correct Answer: A — It doubles

Q. If the magnetic field strength is doubled, what happens to the force on a current-carrying conductor? (2022)

A. It doubles
B. It halves
C. It remains the same
D. It quadruples

Solution

The force on a current-carrying conductor is directly proportional to the magnetic field strength, so if the magnetic field strength is doubled, the force also doubles.

Correct Answer: A — It doubles

Q. If the magnetic flux through a coil changes from 0.2 Wb to 0.5 Wb in 2 seconds, what is the average induced EMF? (2021)

A. 150 V
B. 100 V
C. 75 V
D. 50 V

Solution

Average induced EMF = -ΔΦ/Δt = -(0.5 Wb - 0.2 Wb) / 2 s = -0.15 Wb/s = 150 V.

Correct Answer: B — 100 V

Q. If the magnetic flux through a coil changes from 0.2 Wb to 0.5 Wb in 2 seconds, what is the average induced EMF in the coil? (2021)

A. 150 V
B. 100 V
C. 75 V
D. 50 V

Solution

Average induced EMF (ε) = -ΔΦ/Δt = -(0.5 Wb - 0.2 Wb) / 2 s = -0.3 Wb / 2 s = -0.15 V. The absolute value is 0.15 V or 150 mV.

Correct Answer: B — 100 V

Q. If the mass of an object is measured in kilograms and its volume in cubic meters, what is the unit of density? (2022)

A. kg/m
B. kg/m^3
C. m^3/kg
D. m/kg

Solution

Density is defined as mass per unit volume, so the unit of density is kg/m³.

Correct Answer: B — kg/m^3

Q. If the mass of an object is tripled and the distance from the center of the Earth is halved, how does the gravitational force change?

A. It triples
B. It increases by a factor of 6
C. It increases by a factor of 9
D. It decreases

Solution

F ∝ m/r²; if m is tripled and r is halved, F = 3m/(1/4) = 12m, so it increases by a factor of 9.

Correct Answer: C — It increases by a factor of 9

Q. If the mass of the Earth were to double, what would happen to the gravitational force experienced by an object on its surface?

A. It doubles
B. It halves
C. It quadruples
D. It remains the same

Solution

Gravitational force is directly proportional to mass. If mass doubles, force also doubles.

Correct Answer: A — It doubles

Q. If the perimeter of a square is 40 cm, what is the length of one side? (2018)

A. 10 cm
B. 15 cm
C. 20 cm
D. 25 cm

Solution

Perimeter = 4 × side, so side = 40/4 = 10 cm.

Correct Answer: A — 10 cm

Q. If the pH of a solution is 3, what is the concentration of H+ ions? (2023)

A. 0.001 M
B. 0.01 M
C. 0.1 M
D. 0.0001 M

Solution

pH = 3 means [H+] = 10^-3 M = 0.001 M.

Correct Answer: B — 0.01 M

Q. If the pKa of acetic acid is 4.76, what is the pH of a 0.1 M solution?

A. 4.76
B. 5.76
C. 6.76
D. 3.76

Solution

For a weak acid, pH ≈ pKa for a 0.1 M solution, so pH ≈ 4.76.

Correct Answer: A — 4.76

Q. If the power factor of an AC circuit is 0.8, what is the angle between the current and voltage? (2021)

A. 36.87°
B. 53.13°
C. 60°
D. 45°

Solution

The angle θ can be found using cos(θ) = power factor. Thus, θ = cos⁻¹(0.8) ≈ 36.87°.

Correct Answer: B — 53.13°

Q. If the pressure of a gas is increased while keeping the temperature constant, what happens to its volume? (2020)

A. It increases
B. It decreases
C. It remains the same
D. It becomes zero

Solution

According to Boyle's Law, P * V = constant at constant temperature, so if P increases, V must decrease.

Correct Answer: B — It decreases

Q. If the quadratic equation x² + 5x + k = 0 has roots -2 and -3, find k. (2020)

A. 6
B. 5
C. 7
D. 8

Solution

The product of the roots gives k = (-2)(-3) = 6.

Correct Answer: A — 6

Q. If the radius of a circle is 4 cm, what is the length of a chord that is 3 cm from the center? (2014)

A. 5 cm
B. 6 cm
C. 7 cm
D. 8 cm

Solution

Using Pythagoras theorem: chord length = 2√(r² - d²) = 2√(4² - 3²) = 2√(16 - 9) = 2√7 ≈ 5.29 cm.

Correct Answer: A — 5 cm

Q. If the radius of a circle is 7 cm, what is its circumference? (Use π = 22/7) (2014)

A. 44 cm
B. 22 cm
C. 14 cm
D. 28 cm

Solution

Circumference = 2πr = 2 × (22/7) × 7 = 44 cm.

Correct Answer: A — 44 cm

Q. If the radius of a circle is decreased by 2 cm, how does the area change? (Original radius is 10 cm) (2021)

A. Decreases by 12.56 cm²
B. Decreases by 25.12 cm²
C. Decreases by 31.4 cm²
D. Decreases by 50.24 cm²

Solution

Original area = π(10)² = 314 cm²; New area = π(8)² = 201.06 cm². Change = 314 - 201.06 = 112.94 cm².

Correct Answer: B — Decreases by 25.12 cm²

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