Undergraduate MCQ & Objective Questions
The undergraduate level is a crucial phase in a student's academic journey, especially for those preparing for school and competitive exams. Mastering this stage can significantly enhance your understanding and retention of key concepts. Practicing MCQs and objective questions is essential, as it not only helps in reinforcing knowledge but also boosts your confidence in tackling important questions during exams.
What You Will Practise Here
Fundamental concepts in Mathematics and Science
Key definitions and theories across various subjects
Important formulas and their applications
Diagrams and graphical representations
Critical thinking and problem-solving techniques
Subject-specific MCQs designed for competitive exams
Revision of essential topics for better retention
Exam Relevance
Undergraduate topics are integral to various examinations such as CBSE, State Boards, NEET, and JEE. These subjects often feature a mix of conceptual and application-based questions. Common patterns include multiple-choice questions that assess both theoretical knowledge and practical application, making it vital for students to be well-versed in undergraduate concepts.
Common Mistakes Students Make
Overlooking the importance of understanding concepts rather than rote memorization
Misinterpreting questions due to lack of careful reading
Neglecting to practice numerical problems that require application of formulas
Failing to review mistakes made in previous practice tests
FAQs
Question: What are some effective strategies for solving undergraduate MCQ questions?Answer: Focus on understanding the concepts, practice regularly, and review your answers to learn from mistakes.
Question: How can I improve my speed in answering objective questions?Answer: Time yourself while practicing and gradually increase the number of questions you attempt in a set time.
Start your journey towards mastering undergraduate subjects today! Solve practice MCQs and test your understanding to ensure you are well-prepared for your exams. Your success is just a question away!
Q. If a 10Ω resistor is connected in parallel with a 5Ω resistor, what is the equivalent resistance? (2022)
A.
3.33Ω
B.
5Ω
C.
7.5Ω
D.
15Ω
Show solution
Solution
For parallel resistors, 1/R_eq = 1/R1 + 1/R2 = 1/10 + 1/5 = 1/10 + 2/10 = 3/10. Therefore, R_eq = 10/3 = 3.33Ω.
Correct Answer:
A
— 3.33Ω
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Q. If a 10Ω resistor is connected in parallel with a 5Ω resistor, what is the total resistance? (2022)
A.
3.33Ω
B.
5Ω
C.
7.5Ω
D.
15Ω
Show solution
Solution
For resistors in parallel, 1/R_eq = 1/R1 + 1/R2 = 1/10 + 1/5 = 1/10 + 2/10 = 3/10. Therefore, R_eq = 10/3 = 3.33Ω.
Correct Answer:
A
— 3.33Ω
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Q. If a 10Ω resistor is connected to a 20V battery, what is the power consumed by the resistor? (2023)
A.
20W
B.
40W
C.
10W
D.
5W
Show solution
Solution
Power (P) can be calculated using the formula P = V^2 / R. Here, P = 20V^2 / 10Ω = 40W.
Correct Answer:
B
— 40W
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Q. If a 1500 kg car is moving at a speed of 30 m/s, what is its kinetic energy?
A.
675,000 J
B.
450,000 J
C.
225,000 J
D.
900,000 J
Show solution
Solution
Kinetic Energy = 0.5 × mass × velocity² = 0.5 × 1500 kg × (30 m/s)² = 675,000 J
Correct Answer:
B
— 450,000 J
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Q. If a 15Ω resistor is connected in parallel with a 30Ω resistor, what is the equivalent resistance? (2021)
A.
10Ω
B.
7.5Ω
C.
5Ω
D.
12Ω
Show solution
Solution
For resistors in parallel, 1/R_eq = 1/R1 + 1/R2 = 1/15 + 1/30 = 2/30 + 1/30 = 3/30. Therefore, R_eq = 30/3 = 10Ω.
Correct Answer:
B
— 7.5Ω
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Q. If a 15Ω resistor is connected in parallel with a 5Ω resistor, what is the equivalent resistance? (2023)
A.
3.75Ω
B.
4Ω
C.
5Ω
D.
10Ω
Show solution
Solution
1/R_eq = 1/15 + 1/5 = 1/15 + 3/15 = 4/15; R_eq = 15/4 = 3.75Ω.
Correct Answer:
A
— 3.75Ω
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Q. If a 2 kg object is dropped from a height, what is its velocity just before hitting the ground (g = 10 m/s²)? (2023)
A.
10 m/s
B.
20 m/s
C.
30 m/s
D.
40 m/s
Show solution
Solution
Using v = √(2gh), for h = 10 m, v = √(2 * 10 m/s² * 10 m) = √200 = 20 m/s.
Correct Answer:
B
— 20 m/s
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Q. If a 2 kg object is dropped from a height, what is its velocity just before hitting the ground? (g = 9.8 m/s², h = 20 m) (2023)
A.
14 m/s
B.
19.6 m/s
C.
20 m/s
D.
28 m/s
Show solution
Solution
Using v² = u² + 2gh, where u = 0, we find v = √(2 * 9.8 * 20) = 19.6 m/s.
Correct Answer:
B
— 19.6 m/s
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Q. If a 2 kg object is lifted to a height of 10 m, what is the potential energy gained by the object? (g = 9.8 m/s²)
A.
19.6 J
B.
98 J
C.
39.2 J
D.
78.4 J
Show solution
Solution
Potential Energy (PE) = mgh = 2 kg × 9.8 m/s² × 10 m = 196 J.
Correct Answer:
B
— 98 J
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Q. If a 2 kg object is lifted to a height of 3 m, what is the potential energy gained by the object? (g = 9.8 m/s²)
A.
58.8 J
B.
19.6 J
C.
29.4 J
D.
39.2 J
Show solution
Solution
Potential Energy (PE) = mgh = 2 kg × 9.8 m/s² × 3 m = 58.8 J.
Correct Answer:
A
— 58.8 J
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Q. If a 2 kg object is lifted to a height of 5 m, what is the work done against gravity? (g = 10 m/s²) (2019)
A.
20 J
B.
10 J
C.
50 J
D.
30 J
Show solution
Solution
Work Done = mgh = 2 kg * 10 m/s² * 5 m = 100 J
Correct Answer:
A
— 20 J
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Q. If a 2 kg object is moving with a velocity of 15 m/s, what is its kinetic energy?
A.
225 J
B.
150 J
C.
300 J
D.
450 J
Show solution
Solution
Kinetic Energy = 1/2 * m * v^2 = 1/2 * 2 kg * (15 m/s)^2 = 225 J.
Correct Answer:
A
— 225 J
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Q. If a 2 kg object is moving with a velocity of 3 m/s, what is its kinetic energy?
A.
9 J
B.
6 J
C.
3 J
D.
12 J
Show solution
Solution
Kinetic Energy = 0.5 * m * v² = 0.5 * 2 kg * (3 m/s)² = 9 J.
Correct Answer:
A
— 9 J
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Q. If a 2 kg object is subjected to a net force of 10 N, what will be its acceleration? (2022)
A.
2 m/s²
B.
5 m/s²
C.
10 m/s²
D.
20 m/s²
Show solution
Solution
Using F = ma, a = F/m = 10 N / 2 kg = 5 m/s².
Correct Answer:
B
— 5 m/s²
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Q. If a 3 kg object is moving with a speed of 4 m/s, what is its kinetic energy?
A.
12 J
B.
24 J
C.
36 J
D.
48 J
Show solution
Solution
KE = 0.5 × m × v² = 0.5 × 3 kg × (4 m/s)² = 0.5 × 3 × 16 = 24 J.
Correct Answer:
B
— 24 J
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Q. If a 3 kg object is subjected to a net force of 12 N, what is its acceleration? (2023)
A.
4 m/s²
B.
3 m/s²
C.
2 m/s²
D.
1 m/s²
Show solution
Solution
Acceleration a = F/m = 12 N / 3 kg = 4 m/s².
Correct Answer:
A
— 4 m/s²
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Q. If a 4 kg object is lifted to a height of 2 m, what is the work done against gravity? (2021)
A.
40 J
B.
80 J
C.
20 J
D.
60 J
Show solution
Solution
Work done = mass × g × height = 4 kg × 10 m/s² × 2 m = 80 J
Correct Answer:
B
— 80 J
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Q. If a 4 kg object is moving with a speed of 5 m/s, what is its kinetic energy?
A.
50 J
B.
40 J
C.
100 J
D.
80 J
Show solution
Solution
Kinetic Energy (KE) = 0.5 × m × v² = 0.5 × 4 kg × (5 m/s)² = 0.5 × 4 × 25 = 50 J.
Correct Answer:
D
— 80 J
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Q. If a 4 kg object is moving with a velocity of 5 m/s, what is the momentum of the object? (2020)
A.
10 kg m/s
B.
15 kg m/s
C.
20 kg m/s
D.
25 kg m/s
Show solution
Solution
Momentum = mass × velocity = 4 kg × 5 m/s = 20 kg m/s.
Correct Answer:
C
— 20 kg m/s
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Q. If a 5 kg object is dropped from a height of 10 m, what is its potential energy just before it hits the ground? (2021)
A.
50 J
B.
100 J
C.
150 J
D.
200 J
Show solution
Solution
PE = m × g × h = 5 kg × 9.8 m/s² × 10 m = 490 J.
Correct Answer:
B
— 100 J
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Q. If a 5 kg object is dropped from a height of 10 m, what is its potential energy just before it hits the ground? (g = 9.8 m/s²)
A.
490 J
B.
980 J
C.
245 J
D.
2450 J
Show solution
Solution
Potential Energy (PE) = m × g × h = 5 kg × 9.8 m/s² × 10 m = 490 J.
Correct Answer:
B
— 980 J
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Q. If a 5 kg object is dropped from a height of 20 m, what is its potential energy at the top? (2021)
A.
100 J
B.
200 J
C.
50 J
D.
150 J
Show solution
Solution
Potential Energy (PE) = m * g * h = 5 kg * 9.8 m/s^2 * 20 m = 980 J (approx. 1000 J)
Correct Answer:
B
— 200 J
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Q. If a 5 kg object is moving with a speed of 10 m/s, what is its total mechanical energy assuming no potential energy?
A.
250 J
B.
500 J
C.
100 J
D.
50 J
Show solution
Solution
Total Mechanical Energy = Kinetic Energy = 0.5 * m * v² = 0.5 * 5 kg * (10 m/s)² = 250 J.
Correct Answer:
B
— 500 J
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Q. If a 5 kg object is moving with a velocity of 10 m/s, what is its kinetic energy? (2019)
A.
25 J
B.
50 J
C.
100 J
D.
200 J
Show solution
Solution
Kinetic Energy = 0.5 × Mass × Velocity² = 0.5 × 5 kg × (10 m/s)² = 250 J.
Correct Answer:
C
— 100 J
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Q. If a 5 kg object is moving with a velocity of 3 m/s, what is its kinetic energy? (2023)
A.
22.5 J
B.
30 J
C.
45 J
D.
60 J
Show solution
Solution
Kinetic Energy = 0.5 × mass × velocity² = 0.5 × 5 kg × (3 m/s)² = 22.5 J
Correct Answer:
C
— 45 J
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Q. If a 5 kg object is moving with a velocity of 3 m/s, what is its momentum? (2023)
A.
5 kg·m/s
B.
10 kg·m/s
C.
15 kg·m/s
D.
20 kg·m/s
Show solution
Solution
Momentum p = mv = 5 kg * 3 m/s = 15 kg·m/s.
Correct Answer:
C
— 15 kg·m/s
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Q. If a 5 kg object is subjected to a net force of 20 N, what is its acceleration? (2023)
A.
2 m/s²
B.
4 m/s²
C.
5 m/s²
D.
10 m/s²
Show solution
Solution
Using F = ma, we find a = F/m = 20 N / 5 kg = 4 m/s².
Correct Answer:
B
— 4 m/s²
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Q. If a 5Ω resistor is connected in series with a 10Ω resistor, what is the total resistance? (2022)
A.
15Ω
B.
5Ω
C.
10Ω
D.
20Ω
Show solution
Solution
In series, R_eq = R1 + R2 = 5Ω + 10Ω = 15Ω.
Correct Answer:
A
— 15Ω
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Q. If a 5Ω resistor is connected to a 10V source, what is the power dissipated? (2023)
A.
2W
B.
5W
C.
10W
D.
20W
Show solution
Solution
Power P = V²/R = (10V)² / 5Ω = 100 / 5 = 20W.
Correct Answer:
C
— 10W
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Q. If a 5Ω resistor is connected to a 15V battery, what is the power dissipated by the resistor? (2023)
A.
15W
B.
20W
C.
25W
D.
30W
Show solution
Solution
Power (P) can be calculated using P = V^2 / R. Here, P = 15V^2 / 5Ω = 45W.
Correct Answer:
C
— 25W
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