Q. What is the maximum number of electrons that can occupy a single p-orbital?
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Solution
A single p-orbital can hold a maximum of 2 electrons.
Correct Answer:
A
— 2
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Q. What is the maximum number of electrons that can occupy a subshell with the quantum numbers n=3 and l=2?
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Solution
The maximum number of electrons in a subshell is given by the formula 2(2l + 1). For l=2, this gives 2(2*2 + 1) = 10.
Correct Answer:
C
— 10
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Q. What is the maximum number of electrons that can occupy a subshell with the quantum number l = 2?
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Solution
The maximum number of electrons in a subshell is given by the formula 2(2l + 1). For l = 2, this gives 2(2*2 + 1) = 10.
Correct Answer:
C
— 10
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Q. What is the maximum number of electrons that can occupy the 3rd energy level?
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Solution
The maximum number of electrons in an energy level is given by the formula 2n^2. For n=3, it is 2(3^2) = 18.
Correct Answer:
C
— 18
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Q. What is the maximum number of electrons that can occupy the n=3 shell?
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Solution
The maximum number of electrons in a shell is given by the formula 2n^2. For n=3, it is 2(3^2) = 18.
Correct Answer:
C
— 18
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Q. What is the maximum number of orbitals in a subshell where l = 1?
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Solution
For l=1, the number of orbitals is given by 2l + 1 = 3.
Correct Answer:
B
— 3
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Q. What is the maximum number of orbitals in a subshell with l = 3?
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Solution
The number of orbitals in a subshell is given by 2l + 1. For l = 3, it is 2*3 + 1 = 7.
Correct Answer:
C
— 7
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Q. What is the maximum oxidation state exhibited by manganese?
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Solution
Manganese can exhibit a maximum oxidation state of +7 in compounds like KMnO4.
Correct Answer:
D
— +7
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Q. What is the maximum oxidation state of the element in group 14?
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Solution
The maximum oxidation state of group 14 elements, such as Carbon and Silicon, is +4.
Correct Answer:
C
— +6
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Q. What is the maximum value of the magnetic quantum number (m_l) when l = 3?
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Solution
The magnetic quantum number m_l can take values from -l to +l. For l = 3, m_l can be -3, -2, -1, 0, +1, +2, +3, giving a maximum value of 3.
Correct Answer:
A
— 3
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Q. What is the molality of a solution containing 3 moles of KCl dissolved in 1 kg of water?
A.
3 m
B.
1.5 m
C.
2 m
D.
4 m
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Solution
Molality (m) = moles of solute / kg of solvent = 3 moles / 1 kg = 3 m.
Correct Answer:
A
— 3 m
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Q. What is the molality of a solution prepared by dissolving 3 moles of KCl in 1 kg of water?
A.
3 m
B.
1.5 m
C.
2 m
D.
4 m
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Solution
Molality (m) = moles of solute / kg of solvent = 3 moles / 1 kg = 3 m.
Correct Answer:
A
— 3 m
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Q. What is the molality of a solution prepared by dissolving 5 moles of NaCl in 2 kg of water?
A.
2.5 mol/kg
B.
5 mol/kg
C.
1.5 mol/kg
D.
3 mol/kg
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Solution
Molality (m) = moles of solute / mass of solvent (kg) = 5 moles / 2 kg = 2.5 mol/kg.
Correct Answer:
A
— 2.5 mol/kg
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Q. What is the molar mass of CaCO3?
A.
100 g/mol
B.
120 g/mol
C.
80 g/mol
D.
60 g/mol
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Solution
Molar mass of CaCO3 = 40 + 12 + 16*3 = 100 g/mol.
Correct Answer:
A
— 100 g/mol
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Q. What is the molar mass of sulfuric acid (H2SO4)?
A.
98 g/mol
B.
96 g/mol
C.
100 g/mol
D.
92 g/mol
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Solution
Molar mass = 2*1 + 32 + 4*16 = 98 g/mol.
Correct Answer:
A
— 98 g/mol
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Q. What is the molar mass of the product formed when 1 mole of Mg reacts with 2 moles of HCl?
A.
24.3 g
B.
36.5 g
C.
58.5 g
D.
74.5 g
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Solution
Mg + 2HCl → MgCl2 + H2. Molar mass of MgCl2 = 24.3 + 2*35.5 = 95.3 g.
Correct Answer:
D
— 74.5 g
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Q. What is the molar mass of the product formed when 1 mole of nitrogen reacts with 3 moles of hydrogen?
A.
28 g
B.
14 g
C.
32 g
D.
18 g
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Solution
N2 + 3H2 → 2NH3. Molar mass of NH3 = 14 + 3 = 17 g.
Correct Answer:
A
— 28 g
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Q. What is the molar mass of water (H2O)?
A.
16 g/mol
B.
18 g/mol
C.
20 g/mol
D.
22 g/mol
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Solution
The molar mass of water is calculated as follows: H (1 g/mol) x 2 + O (16 g/mol) = 18 g/mol.
Correct Answer:
B
— 18 g/mol
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Q. What is the molar volume of an ideal gas at standard temperature and pressure (STP)?
A.
22.4 L
B.
24.5 L
C.
18.0 L
D.
30.0 L
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Solution
The molar volume of an ideal gas at STP is 22.4 L.
Correct Answer:
A
— 22.4 L
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Q. What is the molar volume of an ideal gas at STP (Standard Temperature and Pressure)?
A.
22.4 L
B.
24.5 L
C.
18.0 L
D.
30.0 L
Show solution
Solution
The molar volume of an ideal gas at STP is 22.4 L.
Correct Answer:
A
— 22.4 L
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Q. What is the molar volume of an ideal gas at STP?
A.
22.4 L
B.
24.5 L
C.
18.0 L
D.
30.0 L
Show solution
Solution
The molar volume of an ideal gas at standard temperature and pressure (STP) is 22.4 L.
Correct Answer:
A
— 22.4 L
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Q. What is the molarity of a solution containing 5 moles of solute in 2 liters of solution?
A.
2.5 M
B.
5 M
C.
10 M
D.
0.5 M
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Solution
Molarity (M) = moles of solute / liters of solution = 5 moles / 2 L = 2.5 M.
Correct Answer:
A
— 2.5 M
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Q. What is the molarity of a solution if 10 g of glucose (C6H12O6) is dissolved in 250 mL of water? (Molar mass = 180 g/mol)
A.
0.22 M
B.
0.5 M
C.
0.75 M
D.
1 M
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Solution
Moles of glucose = 10 g / 180 g/mol = 0.0556 moles. Molarity = 0.0556 moles / 0.25 L = 0.222 M.
Correct Answer:
A
— 0.22 M
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Q. What is the molarity of a solution if 10 grams of CaCl2 is dissolved in 250 mL of solution? (Molar mass of CaCl2 = 110 g/mol)
A.
0.25 M
B.
0.5 M
C.
1 M
D.
2 M
Show solution
Solution
Moles of CaCl2 = 10 g / 110 g/mol = 0.0909 moles. Molarity = 0.0909 moles / 0.25 L = 0.3636 M.
Correct Answer:
B
— 0.5 M
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Q. What is the molarity of a solution if 5 moles of solute are dissolved in 2 liters of solution?
A.
2.5 M
B.
5 M
C.
10 M
D.
0.5 M
Show solution
Solution
Molarity (M) = moles of solute / liters of solution = 5 / 2 = 2.5 M
Correct Answer:
A
— 2.5 M
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Q. What is the molarity of a solution prepared by dissolving 5 moles of NaCl in 2 liters of water?
A.
2.5 M
B.
5 M
C.
10 M
D.
1 M
Show solution
Solution
Molarity (M) = moles of solute / liters of solution = 5 moles / 2 L = 2.5 M.
Correct Answer:
A
— 2.5 M
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Q. What is the mole fraction of solute in a solution containing 2 moles of solute and 8 moles of solvent?
A.
0.2
B.
0.25
C.
0.5
D.
0.1
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Solution
Mole fraction of solute = moles of solute / (moles of solute + moles of solvent) = 2 / (2 + 8) = 2 / 10 = 0.2.
Correct Answer:
B
— 0.25
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Q. What is the mole fraction of solute in a solution containing 3 moles of solute and 7 moles of solvent?
A.
0.3
B.
0.7
C.
0.5
D.
0.2
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Solution
Mole fraction of solute = moles of solute / total moles = 3 / (3 + 7) = 0.3.
Correct Answer:
A
— 0.3
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Q. What is the molecular formula of benzene?
A.
C6H6
B.
C6H12
C.
C6H10
D.
C6H8
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Solution
Benzene has the molecular formula C6H6, indicating it is an aromatic hydrocarbon.
Correct Answer:
A
— C6H6
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Q. What is the molecular formula of ethylene?
A.
C2H2
B.
C2H4
C.
C3H6
D.
C4H8
Show solution
Solution
Ethylene is an alkene with the molecular formula C2H4.
Correct Answer:
B
— C2H4
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Showing 1021 to 1050 of 2802 (94 Pages)
Chemistry Syllabus (JEE Main) MCQ & Objective Questions
The Chemistry Syllabus for JEE Main is crucial for students aiming to excel in their exams. Understanding this syllabus not only helps in grasping fundamental concepts but also enhances performance in objective questions and MCQs. Regular practice with these types of questions is essential for scoring better and mastering important topics.
What You Will Practise Here
Basic Concepts of Chemistry
Atomic Structure and Chemical Bonding
States of Matter: Gases and Liquids
Thermodynamics and Thermochemistry
Equilibrium: Chemical and Ionic
Redox Reactions and Electrochemistry
Hydrocarbons and Environmental Chemistry
Exam Relevance
The Chemistry syllabus is a significant part of CBSE, State Boards, NEET, and JEE exams. Questions from this syllabus often appear in various formats, including multiple-choice questions, assertion-reason type questions, and numerical problems. Familiarity with the common question patterns can greatly enhance your exam preparation and confidence.
Common Mistakes Students Make
Misunderstanding the periodic trends and their implications.
Confusing different types of chemical bonds and their properties.
Neglecting to balance redox reactions properly.
Overlooking the significance of units in thermodynamic calculations.
Failing to apply concepts of equilibrium in problem-solving.
FAQs
Question: What are the key topics I should focus on in the Chemistry syllabus for JEE Main?Answer: Focus on atomic structure, chemical bonding, thermodynamics, and equilibrium as they are frequently tested.
Question: How can I improve my performance in Chemistry MCQs?Answer: Regular practice with past papers and understanding concepts deeply will help you tackle MCQs effectively.
Start your journey towards mastering the Chemistry Syllabus (JEE Main) by solving practice MCQs today. Test your understanding and build confidence for your exams!
