General Aptitude Study Materials for Competitive Exams

General Aptitude

Arithmetic Aptitude Data Interpretation

Q. If the length of a rectangle is doubled and the width is halved, how does the area change?

A. Remains the same
B. Doubles
C. Halves
D. Quadruples

Solution

New area = (2 × length) × (width/2) = length × width = original area. Area doubles.

Correct Answer: B — Doubles

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Q. If the minute hand of a clock moves 360 degrees in 60 minutes, how many degrees does it move in 15 minutes?

A. 90 degrees
B. 60 degrees
C. 45 degrees
D. 75 degrees

Solution

In 15 minutes, the minute hand moves (360 degrees / 60 minutes) * 15 minutes = 90 degrees.

Correct Answer: A — 90 degrees

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Q. If the population of a town increases from 20,000 to 25,000, what is the percentage increase?

A. 20%
B. 25%
C. 30%
D. 15%

Solution

Percentage Increase = [(New Population - Old Population) / Old Population] × 100 = [(25000 - 20000) / 20000] × 100 = 25%.

Correct Answer: B — 25%

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Q. If the present age of a father is 45 years and his son is 15 years old, in how many years will the father be twice as old as his son?

A. 10
B. 15
C. 20
D. 5

Solution

Let the number of years be x. In x years, the father's age will be 45 + x and the son's age will be 15 + x. The equation is 45 + x = 2(15 + x), which simplifies to 45 + x = 30 + 2x, so x = 15.

Correct Answer: A — 10

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Q. If the present age of a grandfather is 80 years and the age of his grandson is 20 years, how many years ago was the grandfather 3 times as old as the grandson?

A. 10
B. 20
C. 30
D. 40

Solution

Let x years ago, grandfather's age was 80 - x and grandson's age was 20 - x. We need 80 - x = 3(20 - x). Solving gives x = 10.

Correct Answer: B — 20

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Q. If the present age of a man is 3 times that of his son and the sum of their ages is 48 years, what is the age of the son?

A. 8
B. 12
C. 16
D. 20

Solution

Let the son's age be x. Then the man's age is 3x. So, x + 3x = 48. Solving gives x = 12.

Correct Answer: C — 16

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Q. If the present age of a man is 4 times that of his son, and after 5 years, the man will be 3 times as old as his son. What is the present age of the son?

A. 5
B. 10
C. 15
D. 20

Solution

Let the son's age be x. Then the man's age is 4x. In 5 years, 4x + 5 = 3(x + 5). Solving gives x = 10.

Correct Answer: B — 10

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Q. If the present age of a mother is 4 times that of her daughter and the daughter is 5 years old, what is the mother's age?

A. 15
B. 20
C. 25
D. 30

Solution

If the daughter is 5 years old, then the mother is 4 * 5 = 20 years old.

Correct Answer: C — 25

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Q. If the present age of a mother is 4 times that of her son, and the son is 5 years old, what will be the mother's age in 5 years?

A. 20
B. 25
C. 30
D. 35

Solution

The mother is currently 4 * 5 = 20 years old. In 5 years, she will be 20 + 5 = 25 years old.

Correct Answer: B — 25

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Q. If the present age of a woman is 5 years more than twice the age of her son, and the son is currently 10 years old, what is the age of the woman?

A. 25
B. 30
C. 20
D. 35

Solution

The son's age is 10. Therefore, the woman's age is 2 * 10 + 5 = 20 + 5 = 25.

Correct Answer: A — 25

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Q. If the present age of C is 3 times that of D and the sum of their ages is 48, what is the present age of D?

A. 8
B. 12
C. 16
D. 20

Solution

Let D's age be x. Then C's age is 3x. So, x + 3x = 48, which gives 4x = 48, hence x = 12.

Correct Answer: C — 16

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Q. If the present age of C is 3 times that of D, and D is 8 years old, what is C's age?

A. 20
B. 24
C. 30
D. 32

Solution

If D is 8 years old, then C is 3 * 8 = 24 years old.

Correct Answer: B — 24

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Q. If the present age of C is 3 times that of D, and the sum of their ages is 48 years, what is D's age?

A. 8
B. 12
C. 16
D. 20

Solution

Let D's age be x. Then C's age is 3x. So, x + 3x = 48, which gives 4x = 48, hence x = 12.

Correct Answer: B — 12

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Q. If the present age of C is 4 times that of D, and the sum of their ages is 50 years, what is D's age?

A. 10
B. 12
C. 15
D. 20

Solution

Let D's age be x. Then C's age is 4x. So, x + 4x = 50. Solving gives x = 10.

Correct Answer: A — 10

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Q. If the present age of C is 4 times that of D, and the sum of their ages is 50 years, what is the age of C?

A. 20
B. 25
C. 30
D. 35

Solution

Let D's age be x. Then C's age is 4x. So, x + 4x = 50. Solving gives x = 10, hence C = 40.

Correct Answer: D — 35

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Q. If the present age of C is 4 years more than D, and D is 12 years old, what is the present age of C?

A. 14
B. 16
C. 12
D. 10

Solution

If D is 12 years old, then C is 12 + 4 = 16 years old.

Correct Answer: A — 14

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Q. If the present age of C is 4 years more than D, and D is 6 years old, what is C's age?

A. 8
B. 10
C. 6
D. 12

Solution

C's age = D's age + 4 = 6 + 4 = 10 years.

Correct Answer: A — 8

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Q. If the present age of E is 5 years more than F and the sum of their ages is 55, what is E's age?

A. 25
B. 30
C. 35
D. 40

Solution

Let F's age be x. Then E's age is x + 5. So, x + (x + 5) = 55, which gives 2x + 5 = 55, hence 2x = 50, x = 25. Therefore, E's age is 25 + 5 = 30.

Correct Answer: C — 35

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Q. If the present value of a bill is Rs. 7200 and the bankers' discount is Rs. 800, what is the face value of the bill?

A. Rs. 8000
B. Rs. 7200
C. Rs. 6000
D. Rs. 5000

Solution

Face Value = Present Value + BD = 7200 + 800 = Rs. 8000.

Correct Answer: A — Rs. 8000

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Q. If the present value of a sum is $4500 and the bankers discount is $500, what is the principal?

A. $5000
B. $5500
C. $6000
D. $6500

Solution

Principal = Present Value + Bankers Discount = 4500 + 500 = $5000.

Correct Answer: A — $5000

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Q. If the present worth of a sum is $1200 and the banker's discount is $180 at 9% per annum, what is the time period?

A. 1 year
B. 2 years
C. 3 years
D. 4 years

Solution

Banker's Discount = P × R × T / 100. 180 = 1200 × 9 × T / 100. T = 2 years.

Correct Answer: B — 2 years

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Q. If the present worth of a sum is $2000 and the true discount is $400, what is the rate of interest per annum for 2 years?

A. 5%
B. 10%
C. 15%
D. 20%

Solution

True Discount = Present Worth * Rate * Time / 100. 400 = 2000 * Rate * 2 / 100. Rate = (400 * 100) / (2000 * 2) = 10%.

Correct Answer: B — 10%

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Q. If the present worth of a sum is $600 and the true discount is $100, what is the amount after 2 years at 10% per annum?

A. $700
B. $800
C. $900
D. $1000

Solution

Amount = Present Worth + True Discount = 600 + 100 = $700. Amount after 2 years = 700 * (1 + 0.10)^2 = $800.

Correct Answer: C — $900

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Q. If the price of a shirt is increased by 20% and then decreased by 20%, what is the net change in price?

A. 0%
B. 4%
C. 8%
D. 16%

Solution

Let the original price be 100. After 20% increase: 100 + 20 = 120. After 20% decrease: 120 - 24 = 96. Net change = (96 - 100)/100 × 100% = -4%.

Correct Answer: C — 8%

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Q. If the principal amount is $2000 and the rate of interest is 5% per annum, what will be the simple interest for 3 years?

A. $300
B. $400
C. $500
D. $600

Solution

Simple Interest = (Principal * Rate * Time) / 100 = (2000 * 5 * 3) / 100 = $300.

Correct Answer: A — $300

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Q. If the principal is $15000 and the bankers discount is $2250, what is the rate of interest?

A. 10%
B. 12%
C. 15%
D. 18%

Solution

Rate = (Bankers Discount × 100) / (Principal × Time) = (2250 × 100) / (15000 × 1) = 15%.

Correct Answer: A — 10%

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Q. If the radius of a circle is 7 cm, what is its area? (Use π = 22/7)

A. 154 cm²
B. 44 cm²
C. 77 cm²
D. 88 cm²

Solution

Area = π × radius² = (22/7) × (7 cm)² = 154 cm².

Correct Answer: A — 154 cm²

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Q. If the ratio of boys to girls in a class is 2:3 and there are 30 students in total, how many boys are there?

A. 12
B. 18
C. 15
D. 10

Solution

Let the number of boys be 2x and girls be 3x. Then, 2x + 3x = 30, which gives 5x = 30. Therefore, x = 6. Number of boys = 2x = 2 * 6 = 12.

Correct Answer: A — 12

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Q. If the ratio of boys to girls in a class is 3:2 and there are 30 students, how many girls are there?

A. 10
B. 12
C. 18
D. 20

Solution

Let the number of boys be 3x and girls be 2x. Then, 3x + 2x = 30, which gives 5x = 30, so x = 6. Therefore, the number of girls is 2x = 12.

Correct Answer: B — 12

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Q. If the ratio of boys to girls in a class is 3:2, what fraction of the class are boys?

A. 3/5
B. 2/5
C. 1/2
D. 1/3

Solution

Total parts = 3 + 2 = 5. Fraction of boys = 3/5.

Correct Answer: A — 3/5

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General Aptitude

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