The JEE Main exam is a crucial step for students aspiring to enter prestigious engineering colleges in India. It tests not only knowledge but also the ability to apply concepts effectively. Practicing MCQs and objective questions is essential for scoring better, as it helps in familiarizing students with the exam pattern and enhances their problem-solving skills. Engaging with practice questions allows students to identify important questions and strengthen their exam preparation.
What You Will Practise Here
Fundamental concepts of Physics, Chemistry, and Mathematics
Key formulas and their applications in problem-solving
Important definitions and theories relevant to JEE Main
Diagrams and graphical representations for better understanding
Numerical problems and their step-by-step solutions
Previous years' JEE Main questions for real exam experience
Time management strategies while solving MCQs
Exam Relevance
The topics covered in JEE Main are not only significant for the JEE exam but also appear in various CBSE and State Board examinations. Many concepts are shared with the NEET syllabus, making them relevant across multiple competitive exams. Common question patterns include conceptual applications, numerical problems, and theoretical questions that assess a student's understanding of core subjects.
Common Mistakes Students Make
Misinterpreting the question stem, leading to incorrect answers
Neglecting units in numerical problems, which can change the outcome
Overlooking negative marking and not managing time effectively
Relying too heavily on rote memorization instead of understanding concepts
Failing to review and analyze mistakes from practice tests
FAQs
Question: How can I improve my speed in solving JEE Main MCQ questions? Answer: Regular practice with timed quizzes and focusing on shortcuts can significantly enhance your speed.
Question: Are the JEE Main objective questions similar to previous years' papers? Answer: Yes, many questions are based on previous years' patterns, so practicing them can be beneficial.
Question: What is the best way to approach JEE Main practice questions? Answer: Start with understanding the concepts, then attempt practice questions, and finally review your answers to learn from mistakes.
Now is the time to take charge of your preparation! Dive into solving JEE Main MCQs and practice questions to test your understanding and boost your confidence for the exam.
Q. A person is running at 3 m/s on a moving escalator that moves at 2 m/s in the same direction. What is the speed of the person relative to a stationary observer?
A.
1 m/s
B.
3 m/s
C.
5 m/s
D.
2 m/s
Solution
Speed of person relative to observer = Speed of escalator + Speed of person = 2 m/s + 3 m/s = 5 m/s.
Q. A person is running at a speed of 10 m/s. If he is running towards a train moving at 20 m/s in the opposite direction, what is the relative speed of the train with respect to the person?
A.
10 m/s
B.
20 m/s
C.
30 m/s
D.
40 m/s
Solution
Relative speed = speed of train + speed of person = 20 + 10 = 30 m/s.
Q. A person is standing 100 meters away from a building. If the angle of elevation to the top of the building is 45 degrees, what is the height of the building?
A.
100 m
B.
50 m
C.
75 m
D.
25 m
Solution
Using tan(45°) = height/distance, we have height = distance * tan(45°) = 100 * 1 = 100 m.
Q. A person is standing 20 meters away from a vertical cliff. If the angle of elevation to the top of the cliff is 60 degrees, what is the height of the cliff?
A.
10√3 m
B.
20√3 m
C.
30√3 m
D.
40√3 m
Solution
Using tan(60°) = height/20, we have √3 = height/20. Therefore, height = 20√3 m.
Q. A person is standing 25 meters away from a vertical cliff. If the angle of elevation to the top of the cliff is 60 degrees, what is the height of the cliff?
A.
10 m
B.
15 m
C.
20 m
D.
25 m
Solution
Using tan(60°) = height/25, we have √3 = height/25. Therefore, height = 25√3 ≈ 43.3 m.
Q. A person is standing 25 meters away from a vertical pole. If the angle of elevation to the top of the pole is 36.87 degrees, what is the height of the pole?
A.
15 m
B.
20 m
C.
25 m
D.
30 m
Solution
Using tan(36.87°) = height/distance, we have height = distance * tan(36.87°) = 25 * 0.75 = 15 m.
Q. A person is standing 30 m away from the base of a tree. If the angle of elevation to the top of the tree is 60 degrees, what is the height of the tree?
A.
15 m
B.
20 m
C.
25 m
D.
30 m
Solution
Using tan(60°) = height/30, we have √3 = height/30. Therefore, height = 30√3 = 25 m.
Q. A person is standing 30 m away from the foot of a tree. If the angle of elevation to the top of the tree is 60 degrees, what is the height of the tree?
A.
15 m
B.
20 m
C.
25 m
D.
30 m
Solution
Using tan(60°) = height/30, we have √3 = height/30. Therefore, height = 30√3 = 25 m.
Q. A person is standing 30 meters away from the foot of a tree. If the angle of elevation to the top of the tree is 60 degrees, what is the height of the tree?
A.
15√3 m
B.
30 m
C.
30√3 m
D.
45 m
Solution
Using tan(60°) = height/distance, we have height = distance * tan(60°) = 30√3 m.
Q. A person is standing 40 m away from a building. If the angle of elevation to the top of the building is 30 degrees, what is the height of the building?
A.
20 m
B.
40 m
C.
30 m
D.
10 m
Solution
Using tan(30°) = height/distance, we have height = distance * tan(30°) = 40 * (1/√3) ≈ 20 m.
Q. A person is standing 40 m away from a building. If the angle of elevation to the top of the building is 60 degrees, what is the height of the building?
A.
20√3 m
B.
40 m
C.
30 m
D.
50 m
Solution
Using tan(60°) = height/40, we have √3 = height/40. Therefore, height = 40√3 m.
Q. A person is standing 50 m away from a building. If the angle of elevation to the top of the building is 30 degrees, what is the height of the building?
A.
25√3 m
B.
50 m
C.
30 m
D.
40 m
Solution
Using tan(30°) = height/50, we have 1/√3 = height/50. Therefore, height = 50/√3 m.
Q. A person is standing 50 meters away from a vertical pole. If the angle of elevation to the top of the pole is 60 degrees, what is the height of the pole?
A.
25 m
B.
30 m
C.
35 m
D.
40 m
Solution
Using tan(60°) = height/50, we have √3 = height/50. Therefore, height = 50√3 ≈ 86.6 m.
Q. A person is standing 50 meters away from a vertical pole. If the angle of elevation of the top of the pole is 60 degrees, what is the height of the pole?
A.
25 m
B.
30 m
C.
35 m
D.
40 m
Solution
Using tan(60°) = height/50, we have √3 = height/50. Therefore, height = 50√3 ≈ 86.6 m.
Q. A person is standing at a distance of 20 m from a vertical pole. If the angle of elevation to the top of the pole is 45 degrees, what is the height of the pole?
A.
20 m
B.
10 m
C.
30 m
D.
15 m
Solution
Using tan(45°) = height/distance, we have height = distance * tan(45°) = 20 * 1 = 20 m.
Q. A person is standing at a distance of 40 m from a tree. If the angle of elevation to the top of the tree is 60 degrees, what is the height of the tree?
A.
20√3 m
B.
40 m
C.
30 m
D.
10√3 m
Solution
Using tan(60°) = height/distance, we have height = distance * tan(60°) = 40√3 m.
Q. A person is standing at a distance of 40 meters from the base of a building. If the angle of elevation to the top of the building is 60 degrees, what is the height of the building?
A.
20 m
B.
30 m
C.
40 m
D.
50 m
Solution
Using tan(60°) = height/40, we have √3 = height/40. Therefore, height = 40√3 ≈ 69.28 m.
Q. A person is standing on a hill 100 meters high. If he looks at a point on the ground at an angle of depression of 30 degrees, how far is the point from the base of the hill?
Q. A person is standing on a hill 80 m high. The angle of depression to a car on the ground is 60 degrees. How far is the car from the base of the hill?
A.
40 m
B.
80 m
C.
20√3 m
D.
40√3 m
Solution
Using tan(60°) = height/distance, we have distance = height/tan(60°) = 80/√3 = 40√3 m.
Q. A person is standing on a hill that is 80 meters high. If the angle of depression to a point on the ground is 45 degrees, how far is the point from the base of the hill?
A.
80 m
B.
40 m
C.
80√2 m
D.
40√2 m
Solution
Using tan(45°) = height/distance, we have distance = height/tan(45°) = 80/1 = 80 m.
Q. A person is standing on the ground and looking at the top of a building. If the angle of elevation is 45 degrees and the person is 20 meters away from the building, what is the height of the building?
