In 1 day, the worker completes 1/10 of the job. In 3 days, he completes 3 * (1/10) = 3/10.

Work done in 1 day = 1/10. Work done in 2 days = 2/10 = 1/5.

In 2.5 hours, the worker completes (2.5/10) = 0.25 of the task.

A non-leap year has 365 days, which is 52 weeks and 1 day. Therefore, if the year starts on a Friday, it will end on a Saturday.

A non-leap year has 365 days, which is 52 weeks and 1 day. Therefore, if the year starts on a Wednesday, it will end on a Wednesday.

Total investment = 15000 + 25000 + 10000 = 50000. Profit share for C = (10000/50000) * 18000 = $3,600.

Total parts = 1 + 2 + 3 = 6. A's share = (1/6) * 1200 = $200.

Total parts = 4 + 5 + 6 = 15. C's share = (6/15) * 1500 = $600.

Total investment = 15000 + 25000 + 10000 = 50000. B's share = 25000/50000 * 50000 = $25,000.

Total Amount = 1200(1 + 0.05)^5 = 1200(1.27628156) = 1531.54

Time = (Interest / (Principal * Rate)) = 120 / (800 * 0.05) = 120 / 40 = 3 years

Let J's age be x. Then I's age is x + 10. So, x + (x + 10) = 70. Solving gives x = 30, hence I = 40.

Let J's age be x. Then I's age is x + 3. So, x + (x + 3) = 45. Solving gives x = 21, thus I = 24.

Let J's age be x. Then I's age is x + 5. So, x + (x + 5) = 45. Solving gives x = 20.

Adding 3 hours and 45 minutes to 6:00 PM gives 9:45 PM.

Adding 3 hours and 45 minutes to 6:00 PM gives 9:45 PM.

At 9:15, the hour hand is at 97.5 degrees (9*30 + 15*0.5) and the minute hand is at 90 degrees. The angle between them is |97.5 - 90| = 7.5 degrees.

2023 is not a leap year, so it has 365 days. 365 days = 52 weeks + 1 day. Therefore, January 1, 2024 will be one day after Sunday, which is Monday.

log10(0.1) = -1, so z = -1.

log10(1) = 0, since 10^0 = 1.

log10(100) = log10(10^2) = 2.

log10(1000) = 3, so b = 3.

10x = 10^2, so x = 10.

log10(10^5) = 5.

log10(25) = log10(5^2) = 2 * log10(5) = 2a.

log10(x) = 2 - 1 = 1, so x = 10^1 = 10.

x = 10^-1 = 0.1.

x = 10^2 = 100.

log2(8) = 3, so y = 3.

log2(x) = 7 - log2(8) = 7 - 3 = 4, so x = 2^4 = 16.