Major Competitive Exams MCQ & Objective Questions
Major Competitive Exams play a crucial role in shaping the academic and professional futures of students in India. These exams not only assess knowledge but also test problem-solving skills and time management. Practicing MCQs and objective questions is essential for scoring better, as they help in familiarizing students with the exam format and identifying important questions that frequently appear in tests.
What You Will Practise Here
Key concepts and theories related to major subjects
Important formulas and their applications
Definitions of critical terms and terminologies
Diagrams and illustrations to enhance understanding
Practice questions that mirror actual exam patterns
Strategies for solving objective questions efficiently
Time management techniques for competitive exams
Exam Relevance
The topics covered under Major Competitive Exams are integral to various examinations such as CBSE, State Boards, NEET, and JEE. Students can expect to encounter a mix of conceptual and application-based questions that require a solid understanding of the subjects. Common question patterns include multiple-choice questions that test both knowledge and analytical skills, making it essential to be well-prepared with practice MCQs.
Common Mistakes Students Make
Rushing through questions without reading them carefully
Overlooking the negative marking scheme in MCQs
Confusing similar concepts or terms
Neglecting to review previous years’ question papers
Failing to manage time effectively during the exam
FAQs
Question: How can I improve my performance in Major Competitive Exams?Answer: Regular practice of MCQs and understanding key concepts will significantly enhance your performance.
Question: What types of questions should I focus on for these exams?Answer: Concentrate on important Major Competitive Exams questions that frequently appear in past papers and mock tests.
Question: Are there specific strategies for tackling objective questions?Answer: Yes, practicing under timed conditions and reviewing mistakes can help develop effective strategies.
Start your journey towards success by solving practice MCQs today! Test your understanding and build confidence for your upcoming exams. Remember, consistent practice is the key to mastering Major Competitive Exams!
Q. If a shirt is on sale for 25% off and the original price is $40, what is the sale price?
A.
$30
B.
$25
C.
$20
D.
$15
Show solution
Solution
Sale price = Original price - (Discount × Original price) = $40 - (0.25 × $40) = $30.
Correct Answer:
B
— $25
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Q. If a shopkeeper marks a price of $400 on a product and offers a discount of 25%, what is the profit if the cost price is $250?
A.
$50
B.
$100
C.
$75
D.
$125
Show solution
Solution
Selling Price = 400 - (25% of 400) = 400 - 100 = $300. Profit = Selling Price - Cost Price = 300 - 250 = $50.
Correct Answer:
B
— $100
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Q. If a shopkeeper sells a bicycle for $240 after a discount of 20%, what was the marked price?
A.
$280
B.
$300
C.
$320
D.
$350
Show solution
Solution
Let the marked price be x. Selling Price = x - 20% of x = 240. Thus, 0.8x = 240, so x = 300.
Correct Answer:
B
— $300
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Q. If a shopkeeper sells a product for $240 after a discount of 20%, what was the marked price?
A.
$300
B.
$280
C.
$250
D.
$320
Show solution
Solution
Let the marked price be x. After a 20% discount, Selling Price = x - 0.2x = 0.8x. 0.8x = 240, x = 240/0.8 = 300.
Correct Answer:
A
— $300
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Q. If a shopkeeper sells a product for $80 after a discount of 20%, what was the marked price?
A.
$100
B.
$90
C.
$110
D.
$120
Show solution
Solution
Let the marked price be x. Selling Price = x - (20% of x) = 0.80x. Thus, 0.80x = $80, so x = $80 / 0.80 = $100.
Correct Answer:
A
— $100
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Q. If a shopkeeper sells a watch for $300 after a profit of 25%, what was the cost price?
A.
$220
B.
$240
C.
$250
D.
$260
Show solution
Solution
Let the cost price be x. Selling Price = x + 0.25x = 1.25x. Therefore, 1.25x = 300. x = 300 / 1.25 = $240.
Correct Answer:
B
— $240
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Q. If a shopkeeper sells an item at a loss of 10% and the cost price is $200, what is the selling price?
A.
$180
B.
$190
C.
$200
D.
$210
Show solution
Solution
Selling Price = Cost Price - (Loss Percentage * Cost Price) = $200 - (0.10 * $200) = $200 - $20 = $180.
Correct Answer:
A
— $180
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Q. If a shopkeeper sells an item at a loss of 10% and the cost price is $500, what is the selling price?
A.
$450
B.
$500
C.
$550
D.
$400
Show solution
Solution
Selling Price = Cost Price - (Loss Percentage * Cost Price) = $500 - (0.10 * $500) = $500 - $50 = $450.
Correct Answer:
A
— $450
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Q. If a shopkeeper sells an item at a loss of 10% and the selling price is $90, what was the cost price?
A.
$100
B.
$110
C.
$80
D.
$90
Show solution
Solution
Let the cost price be x. Selling Price = Cost Price - (10% of Cost Price) = x - 0.10x = 0.90x. Thus, 0.90x = $90, so x = $90 / 0.90 = $100.
Correct Answer:
A
— $100
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Q. If a shopkeeper sells an item for $120 after applying a discount of 20%, what was the original price?
A.
$140
B.
$150
C.
$160
D.
$180
Show solution
Solution
Let the original price be x. Selling Price = x - 20% of x = 120. Thus, 0.8x = 120, so x = 150.
Correct Answer:
A
— $140
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Q. If a shopkeeper sells an item for $120 after giving a discount of 20%, what was the original price?
A.
$140
B.
$150
C.
$160
D.
$180
Show solution
Solution
Let the original price be x. Then, 120 = x - 20% of x => 120 = x - 0.2x => 120 = 0.8x => x = 150.
Correct Answer:
A
— $140
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Q. If a shopkeeper sells an item for $120 after giving a discount of 20%, what was the marked price?
A.
$140
B.
$150
C.
$160
D.
$170
Show solution
Solution
Let the marked price be x. Selling Price = Marked Price - Discount = x - 0.20x = 0.80x. So, 0.80x = 120. Therefore, x = 120 / 0.80 = 150.
Correct Answer:
B
— $150
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Q. If a shopkeeper sells an item for $150 at a profit of 50%, what was the cost price?
A.
$100
B.
$110
C.
$120
D.
$130
Show solution
Solution
Let the cost price be x. Selling Price = Cost Price + Profit = x + 0.5x = 1.5x. 1.5x = 150, so x = 150/1.5 = 100.
Correct Answer:
A
— $100
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Q. If a shopkeeper sells an item for $240 after a discount of 20%, what was the marked price?
A.
$280
B.
$300
C.
$320
D.
$350
Show solution
Solution
Let the marked price be x. Selling Price = Marked Price - Discount = x - 0.2x = 0.8x. So, 0.8x = 240. Therefore, x = 240/0.8 = $300.
Correct Answer:
B
— $300
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Q. If a shopkeeper sells an item for $240 after applying a discount of 20%, what was the marked price? (2023)
A.
$280
B.
$300
C.
$320
D.
$350
Show solution
Solution
Let the marked price be x. Then, Selling Price = x - (20% of x) = 240 => 0.8x = 240 => x = 300.
Correct Answer:
B
— $300
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Q. If a shopkeeper sells an item for $240 after applying a discount of 20%, what was the original marked price? (2023)
A.
$250
B.
$300
C.
$320
D.
$350
Show solution
Solution
Let the marked price be x. Selling Price = Marked Price - Discount = x - 0.2x = 0.8x. Thus, 0.8x = 240, so x = 300.
Correct Answer:
B
— $300
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Q. If a shopkeeper sells an item for $240 after applying a discount of 20%, what was the original price of the item?
A.
$300
B.
$280
C.
$250
D.
$320
Show solution
Solution
Let the original price be x. Selling Price = x - 20% of x = 0.8x. Thus, 0.8x = 240, so x = 300.
Correct Answer:
A
— $300
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Q. If a shopkeeper sells an item for $80 after a discount of 20%, what was the marked price?
A.
$100
B.
$90
C.
$110
D.
$120
Show solution
Solution
Let the marked price be x. After a 20% discount, the selling price is x - (0.20 * x) = 0.80x. Setting this equal to $80 gives 0.80x = $80, so x = $80 / 0.80 = $100.
Correct Answer:
A
— $100
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Q. If a shopkeeper sells an item for $90 at a loss of 10%, what was the cost price?
A.
$100
B.
$95
C.
$85
D.
$80
Show solution
Solution
Let the cost price be x. Selling price = cost price - loss = x - (0.10 * x) = 0.90x. Setting this equal to $90 gives 0.90x = $90, so x = $100.
Correct Answer:
A
— $100
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Q. If a simple harmonic oscillator has a frequency of 1 Hz, what is the time period?
A.
0.5 s
B.
1 s
C.
2 s
D.
4 s
Show solution
Solution
Time period (T) is the reciprocal of frequency (f). T = 1/f = 1/1 = 1 s.
Correct Answer:
B
— 1 s
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Q. If a simple harmonic oscillator has a maximum displacement of 5 cm, what is the amplitude?
A.
2.5 cm
B.
5 cm
C.
10 cm
D.
0 cm
Show solution
Solution
The amplitude of a simple harmonic oscillator is defined as the maximum displacement from the equilibrium position, which is 5 cm in this case.
Correct Answer:
B
— 5 cm
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Q. If a simple harmonic oscillator has a total energy E, what is the kinetic energy when the displacement is half of the amplitude?
A.
E/4
B.
E/2
C.
3E/4
D.
E
Show solution
Solution
The total energy E is conserved. When the displacement is half the amplitude, the potential energy is (1/2)E, so the kinetic energy is E - (1/2)E = (1/2)E.
Correct Answer:
C
— 3E/4
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Q. If a smartphone costs $800 and is on a 20% discount, what is the sale price?
A.
$640
B.
$720
C.
$760
D.
$800
Show solution
Solution
Sale price = Original price - (Discount * Original price) = 800 - (0.20 * 800) = 800 - 160 = $640.
Correct Answer:
A
— $640
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Q. If a smartwatch is bought for $250 and sold for $300, what is the percentage profit?
A.
20%
B.
25%
C.
30%
D.
15%
Show solution
Solution
Profit = Selling price - Cost price = 300 - 250 = 50. Percentage profit = (Profit / Cost price) * 100 = (50 / 250) * 100 = 20%.
Correct Answer:
B
— 25%
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Q. If a soap film is formed on a wire frame, what is the effect of adding more soap to the film?
A.
Surface tension increases
B.
Surface tension decreases
C.
Surface tension remains the same
D.
Surface tension becomes zero
Show solution
Solution
Adding more soap decreases the surface tension because soap molecules disrupt the cohesive forces between water molecules.
Correct Answer:
B
— Surface tension decreases
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Q. If a social welfare program increases the average income of the bottom 30% of earners by $2000, what is the total increase for 1 million people?
A.
$200 million
B.
$300 million
C.
$400 million
D.
$500 million
Show solution
Solution
Total increase = 1,000,000 * $2000 = $200 million.
Correct Answer:
A
— $200 million
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Q. If a solar panel generates 250 watts and operates for 5 hours a day, how much energy does it produce in a week?
A.
8750 watt-hours
B.
10000 watt-hours
C.
12500 watt-hours
D.
15000 watt-hours
Show solution
Solution
Energy produced = Power * Hours per day * Days in a week = 250 * 5 * 7 = 8750 watt-hours.
Correct Answer:
A
— 8750 watt-hours
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Q. If a solar panel generates 300 watts of power per hour, how much power will it generate in 5 hours?
A.
1200 watts
B.
1500 watts
C.
1800 watts
D.
2000 watts
Show solution
Solution
300 watts/hour * 5 hours = 1500 watts
Correct Answer:
C
— 1800 watts
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Q. If a solar panel generates 300 watts per hour, how much energy does it generate in 5 hours?
A.
1500 watts
B.
1200 watts
C.
1800 watts
D.
1000 watts
Show solution
Solution
300 watts/hour * 5 hours = 1500 watts
Correct Answer:
C
— 1800 watts
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Q. If a solar panel generates 300 watts per hour, how much energy will it generate in 5 hours?
A.
1500 watts
B.
1200 watts
C.
1800 watts
D.
2000 watts
Show solution
Solution
300 watts/hour * 5 hours = 1500 watts
Correct Answer:
A
— 1500 watts
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