Arithmetic Aptitude MCQ & Objective Questions
Arithmetic Aptitude is a crucial component of many school and competitive exams in India. Mastering this subject not only enhances your mathematical skills but also boosts your confidence in tackling objective questions. Regular practice with MCQs and practice questions helps you identify important questions and improves your exam preparation, ensuring you score better in your assessments.
What You Will Practise Here
Basic arithmetic operations: addition, subtraction, multiplication, and division
Fractions and decimals: conversion and operations
Percentage calculations: increase, decrease, and comparisons
Ratio and proportion: understanding and application
Averages: calculating and interpreting data
Simple and compound interest: formulas and problem-solving
Time, speed, and distance: concepts and related problems
Exam Relevance
Arithmetic Aptitude is a significant topic in various examinations, including CBSE, State Boards, NEET, and JEE. Students can expect questions that test their understanding of basic concepts, calculations, and problem-solving abilities. Common question patterns include direct application of formulas, word problems, and data interpretation, making it essential to practice thoroughly.
Common Mistakes Students Make
Misunderstanding the question requirements, leading to incorrect answers.
Overlooking the order of operations in complex calculations.
Confusing percentages with fractions, resulting in calculation errors.
Neglecting to convert units properly in time, speed, and distance problems.
Failing to apply the correct formula for interest calculations.
FAQs
Question: What are some effective strategies for solving Arithmetic Aptitude MCQs?Answer: Practice regularly, understand the underlying concepts, and familiarize yourself with different question types to enhance your speed and accuracy.
Question: How can I improve my speed in solving Arithmetic Aptitude questions?Answer: Time yourself while practicing and focus on shortcuts and tricks that can simplify calculations.
Start your journey towards mastering Arithmetic Aptitude today! Solve practice MCQs and test your understanding to ensure you are well-prepared for your exams. Your success is just a question away!
Q. A train travels from city X to city Y at a speed of 120 km/h and returns at a speed of 80 km/h. What is the average speed for the entire journey?
A.
90 km/h
B.
96 km/h
C.
100 km/h
D.
110 km/h
Show solution
Solution
Average Speed = 2 * (Speed1 * Speed2) / (Speed1 + Speed2) = 2 * (120 * 80) / (120 + 80) = 96 km/h.
Correct Answer:
B
— 96 km/h
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Q. A train travels from city X to city Y at a speed of 45 km/h and returns at a speed of 60 km/h. What is the average speed for the entire journey?
A.
50 km/h
B.
52 km/h
C.
54 km/h
D.
56 km/h
Show solution
Solution
Average Speed = 2 * (Speed1 * Speed2) / (Speed1 + Speed2) = 2 * (45 * 60) / (45 + 60) = 54 km/h.
Correct Answer:
B
— 52 km/h
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Q. A train travels from City X to City Y at a speed of 75 km/h. If the distance is 225 km, how long will it take to reach City Y?
A.
2 hours
B.
2.5 hours
C.
3 hours
D.
3.5 hours
Show solution
Solution
Time = Distance / Speed = 225 km / 75 km/h = 3 hours.
Correct Answer:
C
— 3 hours
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Q. A train travels from city X to city Y at a speed of 80 km/h and returns at a speed of 60 km/h. What is the average speed for the entire journey?
A.
70 km/h
B.
72 km/h
C.
75 km/h
D.
78 km/h
Show solution
Solution
Average speed = 2xy / (x + y) where x = 80 and y = 60. Average speed = 2 * 80 * 60 / (80 + 60) = 72 km/h.
Correct Answer:
B
— 72 km/h
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Q. A trapezoid has bases of 10 m and 6 m, and a height of 4 m. What is its area?
A.
32 m²
B.
36 m²
C.
40 m²
D.
44 m²
Show solution
Solution
Area = 1/2 × (base1 + base2) × height = 1/2 × (10 m + 6 m) × 4 m = 32 m².
Correct Answer:
A
— 32 m²
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Q. A trapezoid has bases of 10 meters and 20 meters, and a height of 5 meters. What is the area of the trapezoid in square meters?
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Solution
Area = (1/2) × (base1 + base2) × height; Area = (1/2) × (10 + 20) × 5 = 75 square meters.
Correct Answer:
B
— 80
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Q. A trapezoid has bases of 10 meters and 6 meters, and a height of 4 meters. What is the area of the trapezoid in square meters?
Show solution
Solution
Area = (1/2) × (base1 + base2) × height; Area = (1/2) × (10 + 6) × 4 = 32 square meters.
Correct Answer:
B
— 36
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Q. A trapezoid has bases of 10 meters and 6 meters, and a height of 4 meters. What is the area of the trapezoid?
Show solution
Solution
Area = (1/2) × (base1 + base2) × height = (1/2) × (10 + 6) × 4 = 32 square meters.
Correct Answer:
B
— 36
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Q. A trapezoid has bases of 8 meters and 5 meters, and a height of 4 meters. What is the area of the trapezoid in square meters?
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Solution
Area = (1/2) × (base1 + base2) × height = (1/2) × (8 + 5) × 4 = 26 square meters.
Correct Answer:
C
— 32
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Q. A trapezoidal garden has bases of 8 meters and 12 meters, and a height of 5 meters. What is the area of the garden in square meters?
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Solution
Area = (1/2) × (base1 + base2) × height = (1/2) × (8 + 12) × 5 = 50 square meters.
Correct Answer:
B
— 60
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Q. A tree casts a shadow of 10 meters long. If the angle of elevation of the sun is 30 degrees, what is the height of the tree?
A.
5√3 meters
B.
10 meters
C.
10√3 meters
D.
15 meters
Show solution
Solution
Height = shadow * tan(angle) = 10 * √3 = 5√3 meters.
Correct Answer:
A
— 5√3 meters
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Q. A tree casts a shadow of 10 meters when the angle of elevation of the sun is 30 degrees. What is the height of the tree?
A.
5 meters
B.
10 meters
C.
15 meters
D.
20 meters
Show solution
Solution
Height = shadow * tan(angle) = 10 * √3 = 10 * 1.732 = 17.32 meters.
Correct Answer:
C
— 15 meters
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Q. A tree casts a shadow of 10 meters when the angle of elevation of the sun is 45 degrees. What is the height of the tree?
A.
10 meters
B.
15 meters
C.
20 meters
D.
25 meters
Show solution
Solution
Height = shadow * tan(45) = 10 * 1 = 10 meters.
Correct Answer:
A
— 10 meters
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Q. A tree is 10 meters tall. From a point 20 meters away from the base of the tree, the angle of elevation to the top of the tree is what?
A.
26.57 degrees
B.
30 degrees
C.
36.87 degrees
D.
45 degrees
Show solution
Solution
tan(θ) = height/distance = 10/20 => θ = tan⁻¹(0.5) = 26.57 degrees
Correct Answer:
C
— 36.87 degrees
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Q. A tree is 15 meters tall. From a point 20 meters away from the base of the tree, what is the angle of elevation to the top of the tree?
A.
36.87 degrees
B.
45 degrees
C.
53.13 degrees
D.
60 degrees
Show solution
Solution
tan(θ) = height/distance = 15/20; θ = tan⁻¹(15/20) = 36.87 degrees.
Correct Answer:
C
— 53.13 degrees
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Q. A tree is 15 meters tall. If the angle of elevation from a point 20 meters away from the base of the tree is θ, what is tan(θ)?
A.
0.75
B.
1.25
C.
1.5
D.
2
Show solution
Solution
tan(θ) = height / distance = 15 / 20 = 0.75
Correct Answer:
A
— 0.75
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Q. A tree is 15 meters tall. If the angle of elevation from a point on the ground 20 meters away from the base of the tree is θ, what is tan(θ)?
A.
0.75
B.
0.6
C.
0.5
D.
0.8
Show solution
Solution
tan(θ) = height/base = 15/20 = 0.75.
Correct Answer:
A
— 0.75
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Q. A tree is 15 meters tall. If the angle of elevation from a point on the ground to the top of the tree is 30 degrees, how far is the point from the base of the tree?
A.
15√3 meters
B.
15/√3 meters
C.
15 meters
D.
30 meters
Show solution
Solution
Using tan(30) = height/distance, distance = height/tan(30) = 15/√3 meters.
Correct Answer:
B
— 15/√3 meters
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Q. A tree is 30 meters tall. If the angle of elevation from a point 40 meters away from the base of the tree is θ, what is tan(θ)?
A.
0.75
B.
0.6
C.
0.5
D.
0.8
Show solution
Solution
tan(θ) = height / distance = 30 / 40 = 0.75
Correct Answer:
A
— 0.75
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Q. A triangle has a base of 10 m and a height of 6 m. What is its area?
A.
30 m²
B.
40 m²
C.
50 m²
D.
60 m²
Show solution
Solution
Area = 1/2 × base × height = 1/2 × 10 m × 6 m = 30 m².
Correct Answer:
A
— 30 m²
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Q. A triangle has a base of 10 meters and a height of 5 meters. What is its area in square meters?
Show solution
Solution
Area = (1/2) × base × height = (1/2) × 10 × 5 = 25 square meters.
Correct Answer:
B
— 25
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Q. A triangle has a base of 10 meters and a height of 5 meters. What is the area of the triangle in square meters?
Show solution
Solution
Area = (1/2) × base × height = (1/2) × 10 × 5 = 25 square meters.
Correct Answer:
A
— 25
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Q. A triangle has a base of 8 m and a height of 5 m. What is its area?
A.
20 m²
B.
30 m²
C.
40 m²
D.
10 m²
Show solution
Solution
Area = 1/2 × base × height = 1/2 × 8 m × 5 m = 20 m².
Correct Answer:
A
— 20 m²
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Q. A triangle has an area of 36 square meters and a base of 9 meters. What is the height of the triangle in meters?
Show solution
Solution
Area = (1/2) × base × height; 36 = (1/2) × 9 × height; height = (36 × 2) / 9 = 8 meters.
Correct Answer:
A
— 6
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Q. A triangle has an area of 36 square meters and a height of 6 meters. What is the base of the triangle in meters?
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Solution
Area = (1/2) × base × height; 36 = (1/2) × base × 6; base = (36 × 2) / 6 = 12 meters.
Correct Answer:
B
— 12
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Q. A vehicle covers a distance of 300 km in 5 hours. What is its speed?
A.
50 km/h
B.
55 km/h
C.
60 km/h
D.
65 km/h
Show solution
Solution
Speed = Distance / Time = 300 km / 5 h = 60 km/h
Correct Answer:
C
— 60 km/h
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Q. A vehicle travels 180 km in 3 hours. What is its speed in m/s?
A.
10 m/s
B.
15 m/s
C.
20 m/s
D.
25 m/s
Show solution
Solution
Speed = (180 km / 3 h) x (1000 m / 1 km) x (1 h / 3600 s) = 15 m/s
Correct Answer:
B
— 15 m/s
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Q. A woman is 3 years older than her brother. If the sum of their ages is 27 years, how old is the brother?
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Solution
Let the brother's age be x. Then the woman's age is x + 3. The equation is x + (x + 3) = 27, which simplifies to 2x + 3 = 27, so 2x = 24, and x = 12.
Correct Answer:
B
— 10
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Q. A woman is 5 years older than her sister. If the sister is 15 years old, how old is the woman?
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Solution
If the sister is 15, then the woman is 15 + 5 = 20 years old.
Correct Answer:
A
— 20
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Q. A worker can complete a job in 10 days. How much of the job can he complete in 3 days?
A.
1/10
B.
1/5
C.
3/10
D.
1/3
Show solution
Solution
Work done in 1 day = 1/10. Work done in 3 days = 3 * (1/10) = 3/10.
Correct Answer:
C
— 3/10
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