JEE Main MCQ & Objective Questions
The JEE Main exam is a crucial step for students aspiring to enter prestigious engineering colleges in India. It tests not only knowledge but also the ability to apply concepts effectively. Practicing MCQs and objective questions is essential for scoring better, as it helps in familiarizing students with the exam pattern and enhances their problem-solving skills. Engaging with practice questions allows students to identify important questions and strengthen their exam preparation.
What You Will Practise Here
Fundamental concepts of Physics, Chemistry, and Mathematics
Key formulas and their applications in problem-solving
Important definitions and theories relevant to JEE Main
Diagrams and graphical representations for better understanding
Numerical problems and their step-by-step solutions
Previous years' JEE Main questions for real exam experience
Time management strategies while solving MCQs
Exam Relevance
The topics covered in JEE Main are not only significant for the JEE exam but also appear in various CBSE and State Board examinations. Many concepts are shared with the NEET syllabus, making them relevant across multiple competitive exams. Common question patterns include conceptual applications, numerical problems, and theoretical questions that assess a student's understanding of core subjects.
Common Mistakes Students Make
Misinterpreting the question stem, leading to incorrect answers
Neglecting units in numerical problems, which can change the outcome
Overlooking negative marking and not managing time effectively
Relying too heavily on rote memorization instead of understanding concepts
Failing to review and analyze mistakes from practice tests
FAQs
Question: How can I improve my speed in solving JEE Main MCQ questions?Answer: Regular practice with timed quizzes and focusing on shortcuts can significantly enhance your speed.
Question: Are the JEE Main objective questions similar to previous years' papers?Answer: Yes, many questions are based on previous years' patterns, so practicing them can be beneficial.
Question: What is the best way to approach JEE Main practice questions?Answer: Start with understanding the concepts, then attempt practice questions, and finally review your answers to learn from mistakes.
Now is the time to take charge of your preparation! Dive into solving JEE Main MCQs and practice questions to test your understanding and boost your confidence for the exam.
Q. Which law states that the rate of heat transfer through a material is proportional to the temperature difference across it?
A.
Newton's Law of Cooling
B.
Fourier's Law
C.
Stefan-Boltzmann Law
D.
Ohm's Law
Show solution
Solution
Fourier's Law states that the rate of heat transfer through a material is proportional to the temperature difference across it.
Correct Answer:
B
— Fourier's Law
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Q. Which law states that the total energy in an isolated system remains constant?
A.
Law of Conservation of Energy
B.
Newton's First Law
C.
Hooke's Law
D.
Ohm's Law
Show solution
Solution
The Law of Conservation of Energy states that the total energy in an isolated system remains constant.
Correct Answer:
A
— Law of Conservation of Energy
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Q. Which law states that the total energy of an isolated system remains constant?
A.
First law of thermodynamics
B.
Second law of thermodynamics
C.
Zeroth law of thermodynamics
D.
Third law of thermodynamics
Show solution
Solution
The first law of thermodynamics states that the total energy of an isolated system remains constant.
Correct Answer:
A
— First law of thermodynamics
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Q. Which law states that the total enthalpy change for a reaction is the same, regardless of the number of steps in the reaction?
A.
First Law of Thermodynamics
B.
Second Law of Thermodynamics
C.
Hess's Law
D.
Gibbs Free Energy
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Solution
Hess's Law states that the total enthalpy change for a reaction is the same, regardless of the number of steps in the reaction.
Correct Answer:
C
— Hess's Law
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Q. Which law states that the total enthalpy change for a reaction is the same, regardless of the number of steps taken?
A.
First Law of Thermodynamics
B.
Second Law of Thermodynamics
C.
Hess's Law
D.
Gibbs Free Energy
Show solution
Solution
Hess's Law states that the total enthalpy change for a reaction is the same, regardless of the number of steps taken.
Correct Answer:
C
— Hess's Law
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Q. Which law states that the total entropy of an isolated system can never decrease over time?
A.
Zeroth Law
B.
First Law
C.
Second Law
D.
Third Law
Show solution
Solution
The Second Law of Thermodynamics states that the total entropy of an isolated system can never decrease over time.
Correct Answer:
C
— Second Law
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Q. Which law states that the total pressure of a gas mixture is equal to the sum of the partial pressures of its components?
A.
Dalton's Law
B.
Boyle's Law
C.
Charles's Law
D.
Avogadro's Law
Show solution
Solution
Dalton's Law states that the total pressure of a gas mixture is equal to the sum of the partial pressures of its components.
Correct Answer:
A
— Dalton's Law
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Q. Which law states that the volume of a gas is directly proportional to its temperature at constant pressure?
A.
Boyle's Law
B.
Charles's Law
C.
Avogadro's Law
D.
Ideal Gas Law
Show solution
Solution
Charles's Law states that the volume of a gas is directly proportional to its absolute temperature at constant pressure.
Correct Answer:
B
— Charles's Law
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Q. Which level of protein structure is characterized by the arrangement of multiple polypeptide chains?
A.
Primary structure
B.
Secondary structure
C.
Tertiary structure
D.
Quaternary structure
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Solution
The quaternary structure of a protein refers to the arrangement and interaction of multiple polypeptide chains.
Correct Answer:
D
— Quaternary structure
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Q. Which level of protein structure is characterized by the overall 3D shape of a single polypeptide chain?
A.
Primary structure
B.
Secondary structure
C.
Tertiary structure
D.
Quaternary structure
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Solution
The tertiary structure of a protein refers to the overall 3D shape of a single polypeptide chain, determined by interactions among side chains.
Correct Answer:
C
— Tertiary structure
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Q. Which logic gate is equivalent to an AND gate followed by a NOT gate?
A.
OR
B.
NAND
C.
NOR
D.
XOR
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Solution
The NAND gate is equivalent to an AND gate followed by a NOT gate, as it inverts the output of the AND gate.
Correct Answer:
B
— NAND
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Q. Which logic gate is represented by the symbol '⊕'?
A.
AND Gate
B.
OR Gate
C.
NAND Gate
D.
XOR Gate
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Solution
The symbol '⊕' represents the XOR gate.
Correct Answer:
D
— XOR Gate
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Q. Which logic gate outputs true only when all inputs are false?
A.
AND
B.
OR
C.
NOR
D.
NAND
Show solution
Solution
The NOR gate outputs true (1) only when all inputs are false (0).
Correct Answer:
C
— NOR
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Q. Which logic gate outputs true only when all inputs are true?
A.
AND
B.
OR
C.
NOT
D.
NAND
Show solution
Solution
The AND gate outputs true only when all its inputs are true.
Correct Answer:
A
— AND
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Q. Which logic gate outputs true only when all its inputs are true?
A.
AND Gate
B.
OR Gate
C.
NOT Gate
D.
NAND Gate
Show solution
Solution
The AND gate outputs true only when all its inputs are true.
Correct Answer:
A
— AND Gate
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Q. Which logic gate outputs true only when both inputs are false?
A.
AND
B.
OR
C.
NAND
D.
NOR
Show solution
Solution
The NOR gate outputs true only when both inputs are false.
Correct Answer:
D
— NOR
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Q. Which material has the highest resistivity?
A.
Copper
B.
Aluminum
C.
Iron
D.
Rubber
Show solution
Solution
Rubber has a much higher resistivity compared to metals like copper, aluminum, and iron.
Correct Answer:
D
— Rubber
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Q. Which material has the lowest resistivity?
A.
Copper
B.
Aluminum
C.
Silver
D.
Iron
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Solution
Silver has the lowest resistivity among common materials.
Correct Answer:
C
— Silver
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Q. Which measure of dispersion is affected by extreme values?
A.
Range
B.
Variance
C.
Standard Deviation
D.
All of the above
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Solution
All of these measures are affected by extreme values in the data set.
Correct Answer:
D
— All of the above
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Q. Which measure of dispersion is not affected by extreme values?
A.
Range
B.
Variance
C.
Standard Deviation
D.
Interquartile Range
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Solution
Interquartile Range is not affected by extreme values.
Correct Answer:
D
— Interquartile Range
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Q. Which modulation technique is most commonly used in digital communication systems?
A.
Amplitude Modulation (AM)
B.
Frequency Modulation (FM)
C.
Phase Shift Keying (PSK)
D.
Quadrature Amplitude Modulation (QAM)
Show solution
Solution
Quadrature Amplitude Modulation (QAM) is widely used in digital communication systems due to its efficiency in transmitting data.
Correct Answer:
D
— Quadrature Amplitude Modulation (QAM)
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Q. Which modulation technique is most commonly used in FM radio broadcasting?
A.
Amplitude Modulation
B.
Frequency Modulation
C.
Phase Modulation
D.
Pulse Code Modulation
Show solution
Solution
Frequency Modulation (FM) is the standard technique used in FM radio broadcasting due to its resistance to noise.
Correct Answer:
B
— Frequency Modulation
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Q. Which modulation technique is most commonly used in television broadcasting?
A.
Amplitude Modulation (AM)
B.
Frequency Modulation (FM)
C.
Phase Modulation (PM)
D.
Pulse Code Modulation (PCM)
Show solution
Solution
Frequency Modulation (FM) is commonly used in television broadcasting due to its better noise immunity.
Correct Answer:
B
— Frequency Modulation (FM)
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Q. Which modulation technique is used to transmit digital data over an analog channel?
A.
AM
B.
FM
C.
PSK
D.
ASK
Show solution
Solution
Phase Shift Keying (PSK) is a modulation technique used to transmit digital data over an analog channel.
Correct Answer:
C
— PSK
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Q. Which modulation technique varies the amplitude of the carrier signal?
A.
Frequency Modulation
B.
Amplitude Modulation
C.
Phase Modulation
D.
Pulse Modulation
Show solution
Solution
Amplitude Modulation (AM) varies the amplitude of the carrier signal.
Correct Answer:
B
— Amplitude Modulation
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Q. Which molecule exhibits sp hybridization?
A.
CCl4
B.
CO2
C.
NH3
D.
H2O
Show solution
Solution
In CO2, the carbon atom is sp hybridized as it forms two double bonds with oxygen.
Correct Answer:
B
— CO2
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Q. Which molecule has a bent shape due to lone pairs?
A.
CO2
B.
O3
C.
CH4
D.
BF3
Show solution
Solution
O3 (ozone) has a bent shape due to the presence of a lone pair on the central oxygen atom.
Correct Answer:
B
— O3
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Q. Which molecule has a central atom with dsp3 hybridization?
A.
SF6
B.
PCl5
C.
NH3
D.
CCl4
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Solution
PCl5 has phosphorus in the center, which is dsp3 hybridized, leading to a trigonal bipyramidal geometry.
Correct Answer:
B
— PCl5
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Q. Which molecule has a central atom with sp hybridization?
A.
CO2
B.
H2O
C.
NH3
D.
CCl4
Show solution
Solution
In CO2, the carbon atom is sp hybridized, forming two double bonds with oxygen.
Correct Answer:
A
— CO2
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Q. Which molecule has a square planar geometry?
A.
XeF4
B.
SF4
C.
ClF3
D.
NH4+
Show solution
Solution
XeF4 has four bonding pairs and two lone pairs, leading to a square planar geometry.
Correct Answer:
A
— XeF4
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