Major Competitive Exams

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Major Competitive Exams

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Major Competitive Exams MCQ & Objective Questions

Major Competitive Exams play a crucial role in shaping the academic and professional futures of students in India. These exams not only assess knowledge but also test problem-solving skills and time management. Practicing MCQs and objective questions is essential for scoring better, as they help in familiarizing students with the exam format and identifying important questions that frequently appear in tests.

What You Will Practise Here

Key concepts and theories related to major subjects
Important formulas and their applications
Definitions of critical terms and terminologies
Diagrams and illustrations to enhance understanding
Practice questions that mirror actual exam patterns
Strategies for solving objective questions efficiently
Time management techniques for competitive exams

Exam Relevance

The topics covered under Major Competitive Exams are integral to various examinations such as CBSE, State Boards, NEET, and JEE. Students can expect to encounter a mix of conceptual and application-based questions that require a solid understanding of the subjects. Common question patterns include multiple-choice questions that test both knowledge and analytical skills, making it essential to be well-prepared with practice MCQs.

Common Mistakes Students Make

Rushing through questions without reading them carefully
Overlooking the negative marking scheme in MCQs
Confusing similar concepts or terms
Neglecting to review previous years’ question papers
Failing to manage time effectively during the exam

FAQs

Question: How can I improve my performance in Major Competitive Exams?
Answer: Regular practice of MCQs and understanding key concepts will significantly enhance your performance.

Question: What types of questions should I focus on for these exams?
Answer: Concentrate on important Major Competitive Exams questions that frequently appear in past papers and mock tests.

Question: Are there specific strategies for tackling objective questions?
Answer: Yes, practicing under timed conditions and reviewing mistakes can help develop effective strategies.

Start your journey towards success by solving practice MCQs today! Test your understanding and build confidence for your upcoming exams. Remember, consistent practice is the key to mastering Major Competitive Exams!

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Q. A car is negotiating a curve of radius 100 m at a speed of 15 m/s. What is the minimum coefficient of friction required to prevent the car from skidding?

A. 0.15
B. 0.25
C. 0.30
D. 0.35

Solution

Frictional force = m * a_c; μmg = mv²/r; μ = v²/(rg) = (15 m/s)² / (100 m * 9.8 m/s²) ≈ 0.23.

Correct Answer: B — 0.25

Q. A car is to a road as a boat is to a _____.

A. river
B. ocean
C. lake
D. sea

Solution

A boat travels on the ocean, just as a car travels on a road.

Correct Answer: B — ocean

Q. A car is to driving as a bicycle is to _____.

A. riding
B. walking
C. running
D. skating

Solution

A car is driven, just as a bicycle is ridden.

Correct Answer: A — riding

Q. A car moves in a circular path of radius 50 m at a constant speed of 20 m/s. What is the centripetal acceleration?

A. 4 m/s²
B. 8 m/s²
C. 10 m/s²
D. 16 m/s²

Solution

Centripetal acceleration (a_c) = v²/r = (20²)/50 = 8 m/s².

Correct Answer: C — 10 m/s²

Q. A car moves in a circular path of radius 50 m with a constant speed of 20 m/s. What is the centripetal acceleration?

A. 4 m/s²
B. 8 m/s²
C. 10 m/s²
D. 16 m/s²

Solution

Centripetal acceleration (a_c) = v²/r = (20²)/50 = 8 m/s².

Correct Answer: C — 10 m/s²

Q. A car moving at 15 m/s comes to a stop in 5 seconds. What is its acceleration? (2019)

A. -2 m/s²
B. -3 m/s²
C. -4 m/s²
D. -5 m/s²

Solution

Using the formula: acceleration = (final velocity - initial velocity) / time. Acceleration = (0 - 15) / 5 = -3 m/s².

Correct Answer: A — -2 m/s²

Q. A car moving at 30 m/s applies brakes and comes to a stop in 6 seconds. What is the distance covered during braking? (2023)

A. 90 m
B. 120 m
C. 150 m
D. 180 m

Solution

Using the formula: distance = initial velocity * time + 0.5 * acceleration * time^2. Here, acceleration = (0 - 30) / 6 = -5 m/s². Distance = 30 * 6 + 0.5 * (-5) * 6^2 = 180 - 90 = 90 m.

Correct Answer: B — 120 m

Q. A car moving with a speed of 30 m/s applies brakes and comes to a stop in 5 seconds. What is the deceleration of the car?

A. 3 m/s²
B. 4 m/s²
C. 5 m/s²
D. 6 m/s²

Solution

Deceleration = (final velocity - initial velocity) / time = (0 - 30) / 5 = -6 m/s².

Correct Answer: A — 3 m/s²

Q. A car of mass 1000 kg accelerates at 2 m/s². What is the net force acting on the car?

A. 2000 N
B. 500 N
C. 1000 N
D. 1500 N

Solution

Using F = ma, the net force is F = 1000 kg * 2 m/s² = 2000 N.

Correct Answer: A — 2000 N

Q. A car of mass 1000 kg accelerates from rest to a speed of 20 m/s in 10 seconds. What is the net force acting on the car? (2000)

A. 100 N
B. 200 N
C. 300 N
D. 400 N

Solution

Acceleration a = (final speed - initial speed) / time = (20 m/s - 0) / 10 s = 2 m/s². Net force F = ma = 1000 kg * 2 m/s² = 2000 N.

Correct Answer: B — 200 N

Q. A car of mass 1000 kg accelerates from rest to a speed of 20 m/s. What is the kinetic energy gained?

A. 200,000 J
B. 100,000 J
C. 50,000 J
D. 20,000 J

Solution

Kinetic Energy = 0.5 * m * v² = 0.5 * 1000 kg * (20 m/s)² = 200,000 J.

Correct Answer: B — 100,000 J

Q. A car of mass 1000 kg accelerates from rest to a speed of 20 m/s. What is the work done on the car?

A. 20000 J
B. 40000 J
C. 80000 J
D. 100000 J

Solution

Kinetic energy = 0.5 × m × v^2 = 0.5 × 1000 kg × (20 m/s)^2 = 200000 J.

Correct Answer: B — 40000 J

Q. A car of mass 1000 kg accelerates from rest to a speed of 20 m/s. What is the work done by the engine? (2000)

A. 20000 J
B. 40000 J
C. 50000 J
D. 80000 J

Solution

Kinetic Energy = 0.5 × mass × velocity^2 = 0.5 × 1000 kg × (20 m/s)^2 = 200000 J.

Correct Answer: B — 40000 J

Q. A car of mass 1000 kg is moving at a speed of 15 m/s. What is the kinetic energy of the car?

A. 11250 J
B. 22500 J
C. 33750 J
D. 45000 J

Solution

Kinetic energy KE = (1/2)mv² = (1/2)(1000 kg)(15 m/s)² = 11250 J.

Correct Answer: B — 22500 J

Q. A car of mass 1000 kg is moving at a speed of 20 m/s. What is its kinetic energy?

A. 200 J
B. 400 J
C. 200,000 J
D. 400,000 J

Solution

Kinetic energy is given by KE = 0.5mv². Here, KE = 0.5 * 1000 * (20)² = 200,000 J.

Correct Answer: C — 200,000 J

Q. A car of mass 1000 kg is moving at a speed of 20 m/s. What is its total mechanical energy assuming no friction?

A. 200,000 J
B. 400,000 J
C. 300,000 J
D. 100,000 J

Solution

Total Mechanical Energy = Kinetic Energy + Potential Energy. KE = 1/2 * m * v^2 = 1/2 * 1000 * (20^2) = 200,000 J (assuming PE = 0)

Correct Answer: B — 400,000 J

Q. A car of mass 1000 kg is moving with a speed of 20 m/s. What is its kinetic energy?

A. 200,000 J
B. 400,000 J
C. 800,000 J
D. 1,000,000 J

Solution

Kinetic Energy = 0.5 × mass × velocity² = 0.5 × 1000 kg × (20 m/s)² = 200,000 J.

Correct Answer: B — 400,000 J

Q. A car of mass 1000 kg is moving with a velocity of 15 m/s. What is the kinetic energy of the car?

A. 11250 J
B. 15000 J
C. 22500 J
D. 30000 J

Solution

Kinetic energy KE = (1/2)mv² = (1/2)(1000 kg)(15 m/s)² = 11250 J.

Correct Answer: A — 11250 J

Q. A car of mass 1000 kg is moving with a velocity of 20 m/s. If the brakes are applied and the car comes to a stop in 5 seconds, what is the average force applied by the brakes?

A. 2000 N
B. 4000 N
C. 5000 N
D. 6000 N

Solution

The change in momentum is 1000 kg * 20 m/s = 20000 kg·m/s. The average force is F = Δp/Δt = 20000 kg·m/s / 5 s = 4000 N.

Correct Answer: B — 4000 N

Q. A car of mass 1000 kg is moving with a velocity of 20 m/s. What is the momentum of the car?

A. 2000 kg·m/s
B. 10000 kg·m/s
C. 5000 kg·m/s
D. 40000 kg·m/s

Solution

Momentum p = mv = 1000 kg * 20 m/s = 20000 kg·m/s.

Correct Answer: B — 10000 kg·m/s

Q. A car of mass 1000 kg is moving with a velocity of 20 m/s. What is the net force required to bring it to rest in 5 seconds?

A. 4000 N
B. 2000 N
C. 1000 N
D. 500 N

Solution

First, find the deceleration: a = (final velocity - initial velocity) / time = (0 - 20 m/s) / 5 s = -4 m/s². Then, F = ma = 1000 kg * 4 m/s² = 4000 N.

Correct Answer: A — 4000 N

Q. A car travels 100 km in 1.5 hours. What is its average speed? (2019)

A. 60 km/h
B. 65 km/h
C. 70 km/h
D. 75 km/h

Solution

Average speed = Distance / Time = 100 km / 1.5 hours = 66.67 km/h, which rounds to 60 km/h.

Correct Answer: A — 60 km/h

Q. A car travels 100 km in 2 hours and then 50 km in 1 hour. What is the average speed of the car for the entire journey? (2021)

A. 50 km/h
B. 60 km/h
C. 70 km/h
D. 75 km/h

Solution

Total distance = 100 km + 50 km = 150 km. Total time = 2 h + 1 h = 3 h. Average speed = Total distance / Total time = 150 km / 3 h = 50 km/h.

Correct Answer: C — 70 km/h

Q. A car travels 100 km in 2 hours and then 50 km in 1 hour. What is the total average speed of the car? (2019)

A. 50 km/h
B. 60 km/h
C. 70 km/h
D. 80 km/h

Solution

Total distance = 100 + 50 = 150 km. Total time = 2 + 1 = 3 hours. Average speed = Total distance / Total time = 150/3 = 50 km/h.

Correct Answer: B — 60 km/h

Q. A car travels 100 m in 4 seconds. What is its average speed?

A. 20 m/s
B. 25 m/s
C. 30 m/s
D. 35 m/s

Solution

Average speed = total distance / total time = 100 m / 4 s = 25 m/s.

Correct Answer: B — 25 m/s

Q. A car travels 100 m in 5 seconds. What is its average speed?

A. 20 m/s
B. 25 m/s
C. 15 m/s
D. 30 m/s

Solution

Average speed = total distance / total time = 100 m / 5 s = 20 m/s.

Correct Answer: B — 25 m/s

Q. A car travels 100 m north and then 100 m east. What is the magnitude of the displacement from the starting point? (2000)

A. 100 m
B. 141.42 m
C. 200 m
D. 50 m

Solution

Displacement = √(100^2 + 100^2) = √20000 = 141.42 m.

Correct Answer: B — 141.42 m

Q. A car travels 120 km at a speed of 60 km/h. How long does the journey take?

A. 1 hour
B. 2 hours
C. 3 hours
D. 4 hours

Solution

Time = Distance / Speed = 120 km / 60 km/h = 2 hours.

Correct Answer: B — 2 hours

Q. A car travels 120 km in 2 hours. How long will it take to travel 180 km at the same speed?

A. 2.5 hours
B. 3 hours
C. 3.5 hours
D. 4 hours

Solution

Speed = 120 km / 2 hours = 60 km/h. Time = Distance / Speed = 180 km / 60 km/h = 3 hours.

Correct Answer: B — 3 hours

Q. A car travels 120 km in 2 hours. How long will it take to travel 300 km at the same speed?

A. 4 hours
B. 5 hours
C. 6 hours
D. 7 hours

Solution

Speed = 120 km / 2 hours = 60 km/h. Time = Distance / Speed = 300 km / 60 km/h = 5 hours.

Correct Answer: B — 5 hours

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