Quantitative Aptitude & Reasoning MCQ & Objective Questions
Quantitative Aptitude & Reasoning is a crucial component of many school and competitive exams in India. Mastering this subject not only enhances your problem-solving skills but also boosts your confidence during exams. Practicing MCQs and objective questions helps you familiarize yourself with the exam format and improves your ability to tackle important questions efficiently. Regular practice is key to achieving higher scores in your exam preparation.
What You Will Practise Here
Basic Arithmetic Operations and their applications
Number Series and Patterns
Percentage, Ratio, and Proportion
Time, Speed, and Distance problems
Data Interpretation and Analysis
Logical Reasoning and Puzzles
Algebraic Expressions and Equations
Exam Relevance
Quantitative Aptitude & Reasoning is a significant part of various examinations, including CBSE, State Boards, NEET, and JEE. In these exams, you can expect questions that test your analytical skills and numerical ability. Common question patterns include multiple-choice questions that require quick calculations and logical deductions, making it essential to practice regularly to excel.
Common Mistakes Students Make
Misinterpreting the question requirements, leading to incorrect answers.
Overlooking the importance of units in measurement problems.
Failing to apply the correct formulas in different scenarios.
Rushing through calculations, resulting in careless mistakes.
FAQs
Question: What are the best strategies for solving Quantitative Aptitude MCQs?Answer: Focus on understanding the concepts, practice regularly, and learn to manage your time effectively during exams.
Question: How can I improve my reasoning skills for competitive exams?Answer: Engage in regular practice with a variety of reasoning questions and puzzles to enhance your logical thinking.
Start your journey towards mastering Quantitative Aptitude & Reasoning today! Solve practice MCQs and test your understanding to ensure you are well-prepared for your exams. Your success is just a question away!
Q. A mixture of two types of tea costs $5 per kg and $7 per kg. If a mixture of 10 kg is made and sold for $6 per kg, what is the profit or loss?
A.
$0
B.
$5
C.
$10
D.
$15
Show solution
Solution
Cost of mixture = 10 kg * $6 = $60. Selling price = 10 kg * $6 = $60. Profit = $60 - $60 = $0.
Correct Answer:
B
— $5
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Q. A mutual fund has an annual return of 8%. If you invest $1,000, how much will you have after 3 years with compound interest?
A.
$1,080
B.
$1,259.71
C.
$1,343.92
D.
$1,500
Show solution
Solution
Amount = Principal * (1 + Rate)^Time = 1000 * (1 + 0.08)^3 = 1000 * 1.25971 = $1,259.71
Correct Answer:
C
— $1,343.92
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Q. A person borrowed $5000 at a compound interest rate of 10% per annum. What will be the amount after 2 years?
A.
$6050
B.
$5500
C.
$6000
D.
$6100
Show solution
Solution
Amount = P(1 + r)^n = 5000(1 + 0.1)^2 = 5000(1.21) = $6050.
Correct Answer:
A
— $6050
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Q. A person borrows $5000 at a rate of 8% per annum for 3 years. What is the total interest paid?
A.
$1200
B.
$1500
C.
$2000
D.
$1800
Show solution
Solution
Simple Interest = Principal * Rate * Time = 5000 * 0.08 * 3 = $1200.
Correct Answer:
D
— $1800
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Q. A person borrows $5000 at a rate of 8% per annum for 4 years. What is the total amount to be paid back?
A.
$6000
B.
$6400
C.
$6800
D.
$7200
Show solution
Solution
Total Amount = Principal + Simple Interest = 5000 + (5000 * 8 * 4) / 100 = 5000 + 1600 = $6600.
Correct Answer:
B
— $6400
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Q. A person bought a laptop for $800 and sold it for $720. What is the loss percentage?
A.
10%
B.
15%
C.
20%
D.
5%
Show solution
Solution
Loss = Cost Price - Selling Price = 800 - 720 = 80. Loss Percentage = (Loss/Cost Price) * 100 = (80/800) * 100 = 10%.
Correct Answer:
B
— 15%
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Q. A person bought a watch for $300 and sold it for $360. What is the profit percentage?
A.
15%
B.
20%
C.
25%
D.
30%
Show solution
Solution
Profit = Selling Price - Cost Price = 360 - 300 = 60. Profit Percentage = (60/300) * 100 = 20%.
Correct Answer:
B
— 20%
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Q. A person has an average of 80 marks in 5 subjects. If he scores 90 in the 6th subject, what will be his new average?
Show solution
Solution
Total marks in 5 subjects = 80 × 5 = 400. New total = 400 + 90 = 490. New average = 490/6 = 81.67, rounded to 82.
Correct Answer:
C
— 84
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Q. A person invests $1000 at a compound interest rate of 5% per annum. What will be the amount after 2 years?
A.
$1100.25
B.
$1025
C.
$1050
D.
$1200
Show solution
Solution
Amount = P(1 + r/n)^(nt) = 1000(1 + 0.05/1)^(1*2) = 1000(1.05)^2 = 1102.5.
Correct Answer:
A
— $1100.25
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Q. A person runs 10 km in 50 minutes. What is his speed in km/h?
A.
10 km/h
B.
12 km/h
C.
14 km/h
D.
15 km/h
Show solution
Solution
Speed = Distance / Time = 10 km / (50/60) h = 12 km/h.
Correct Answer:
B
— 12 km/h
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Q. A person sold a laptop for $1200 at a loss of 20%. What was the cost price?
A.
$1400
B.
$1500
C.
$1600
D.
$1700
Show solution
Solution
Let Cost Price = x. Selling Price = x - 20% of x = 0.8x. 0.8x = 1200. x = 1200/0.8 = 1500.
Correct Answer:
B
— $1500
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Q. A product is marked at $500 and sold at a discount of 20%. What is the selling price?
A.
$400
B.
$450
C.
$350
D.
$300
Show solution
Solution
Discount = 20% of 500 = 100. Selling Price = Marked Price - Discount = 500 - 100 = 400.
Correct Answer:
B
— $450
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Q. A pyramid has a square base with a side length of 6 cm and a height of 9 cm. What is its volume?
A.
54 cm³
B.
72 cm³
C.
108 cm³
D.
36 cm³
Show solution
Solution
Volume = (1/3) × base area × height = (1/3) × (6²) × 9 = 108 cm³.
Correct Answer:
B
— 72 cm³
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Q. A retailer bought a shirt for $30 and sold it for $45. What is the profit percentage?
A.
50%
B.
40%
C.
30%
D.
20%
Show solution
Solution
Profit = Selling Price - Cost Price = 45 - 30 = 15. Profit Percentage = (15/30) * 100 = 50%.
Correct Answer:
A
— 50%
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Q. A shopkeeper bought an article for $200 and sold it for $250. What is the percentage profit?
A.
20%
B.
25%
C.
30%
D.
15%
Show solution
Solution
Profit = Selling Price - Cost Price = 250 - 200 = 50. Percentage Profit = (Profit/Cost Price) * 100 = (50/200) * 100 = 25%.
Correct Answer:
B
— 25%
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Q. A shopkeeper bought an article for $200 and sold it for $250. What is the profit percentage?
A.
20%
B.
25%
C.
30%
D.
15%
Show solution
Solution
Profit = Selling Price - Cost Price = 250 - 200 = 50. Profit Percentage = (Profit/Cost Price) * 100 = (50/200) * 100 = 25%.
Correct Answer:
B
— 25%
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Q. A shopkeeper marks a price of $200 on an item and offers a discount of 15%. What is the selling price?
A.
$170
B.
$180
C.
$190
D.
$200
Show solution
Solution
Selling Price = Marked Price - Discount = 200 - (15/100 * 200) = 200 - 30 = $170.
Correct Answer:
B
— $180
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Q. A shopkeeper marks a price of $200 on an item and offers a discount of 25%. What is the selling price?
A.
$150
B.
$160
C.
$140
D.
$170
Show solution
Solution
Discount = 25% of 200 = 50. Selling price = 200 - 50 = 150.
Correct Answer:
A
— $150
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Q. A shopkeeper marks a price of $500 on an item and offers a discount of 10%. What is the selling price?
A.
$450
B.
$475
C.
$400
D.
$425
Show solution
Solution
Discount = 10% of 500 = 50. Selling Price = Marked Price - Discount = 500 - 50 = 450.
Correct Answer:
B
— $475
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Q. A shopkeeper sells a mixture of two types of nuts at a profit of 20%. If the cost price of the mixture is $50, what is the selling price?
A.
$60
B.
$55
C.
$65
D.
$70
Show solution
Solution
Selling Price = Cost Price + Profit = 50 + (20% of 50) = 50 + 10 = $60.
Correct Answer:
A
— $60
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Q. A solution contains 25% salt. If 8 liters of the solution is removed and replaced with water, what is the new concentration of salt in the solution?
A.
20%
B.
25%
C.
30%
D.
15%
Show solution
Solution
Salt removed = 25% of 8L = 2L. New solution = 32L, new salt % = (25L / 32L) * 100 = 20%.
Correct Answer:
A
— 20%
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Q. A solution contains 40% sugar. If 5 liters of the solution is removed and replaced with water, what is the new percentage of sugar if the total volume remains the same?
A.
30%
B.
35%
C.
40%
D.
45%
Show solution
Solution
Sugar removed = 40% of 5L = 2L. Remaining sugar = 40L - 2L = 38L. New percentage = (38/50) * 100 = 76%.
Correct Answer:
B
— 35%
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Q. A solution contains 60% sugar. If 15 liters of the solution is diluted with water to make it 40% sugar, how much water is added?
A.
5 liters
B.
10 liters
C.
15 liters
D.
20 liters
Show solution
Solution
Let x be the amount of water added. 0.6 * 15 = 0.4 * (15 + x). Solving gives x = 15 liters.
Correct Answer:
C
— 15 liters
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Q. A student scored 80% in Mathematics and 70% in Science. If both subjects have equal weightage, what is the average percentage?
A.
75%
B.
76%
C.
77%
D.
78%
Show solution
Solution
Average = (80 + 70) / 2 = 75%.
Correct Answer:
A
— 75%
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Q. A sum of $1000 is invested at a compound interest rate of 5% per annum. What will be the amount after 4 years?
A.
$1200
B.
$1215.51
C.
$1250
D.
$1300
Show solution
Solution
Total Amount = P(1 + r/100)^n = 1000(1 + 0.05)^4 = 1000(1.21550625) = $1215.51.
Correct Answer:
B
— $1215.51
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Q. A sum of $1500 is invested at a simple interest rate of 4% per annum. What will be the total amount after 5 years?
A.
$1800
B.
$1600
C.
$1700
D.
$1500
Show solution
Solution
Simple Interest = 1500 * 0.04 * 5 = $300. Total Amount = 1500 + 300 = $1800.
Correct Answer:
B
— $1600
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Q. A sum of $800 is invested at a compound interest rate of 5% per annum. What will be the amount after 2 years?
A.
$882
B.
$840
C.
$900
D.
$850
Show solution
Solution
Amount = Principal * (1 + Rate/100)^Time = 800 * (1 + 0.05)^2 = 800 * 1.1025 = $882
Correct Answer:
A
— $882
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Q. A sum of $800 is invested at a rate of 5% per annum for 3 years. What will be the total amount at the end of 3 years?
A.
$920
B.
$840
C.
$860
D.
$880
Show solution
Solution
Total Amount = Principal + Simple Interest = 800 + (800 * 5 * 3) / 100 = 800 + 120 = $920.
Correct Answer:
B
— $840
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Q. A sum of $800 is invested at a rate of 5% per annum. What will be the total amount after 3 years using simple interest?
A.
$920
B.
$840
C.
$860
D.
$880
Show solution
Solution
Simple Interest = Principal * Rate * Time = 800 * 0.05 * 3 = $120. Total Amount = Principal + Interest = 800 + 120 = $920.
Correct Answer:
D
— $880
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Q. A trader bought 100 kg of sugar at $2 per kg and sold it at $2.50 per kg. What is the profit percentage?
A.
20%
B.
25%
C.
30%
D.
15%
Show solution
Solution
Cost Price = 100 * 2 = 200. Selling Price = 100 * 2.5 = 250. Profit = 250 - 200 = 50. Profit Percentage = (50/200) * 100 = 25%.
Correct Answer:
B
— 25%
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