Mechanics MCQ & Objective Questions
Mechanics is a fundamental branch of physics that plays a crucial role in various school and competitive exams. Understanding mechanics not only helps in grasping essential concepts but also enhances problem-solving skills. Practicing MCQs and objective questions in mechanics is vital for effective exam preparation, as it allows students to familiarize themselves with important questions and boosts their confidence in tackling exam challenges.
What You Will Practise Here
Newton's Laws of Motion
Work, Energy, and Power
Gravitation and its Applications
Motion in One and Two Dimensions
Rotational Motion and Dynamics
Fluid Mechanics and Properties of Matter
Simple Harmonic Motion
Exam Relevance
Mechanics is a significant topic in various examinations, including CBSE, State Boards, NEET, and JEE. Questions from mechanics often appear in different formats, such as numerical problems, conceptual questions, and application-based scenarios. Students can expect to encounter both direct and indirect questions that test their understanding of key concepts and their ability to apply formulas effectively. Familiarity with common question patterns in mechanics can greatly enhance performance in these exams.
Common Mistakes Students Make
Confusing the application of Newton's laws in different scenarios.
Misunderstanding the concepts of work and energy, particularly in non-conservative forces.
Overlooking the significance of vector quantities in motion problems.
Failing to apply the right formulas in rotational motion questions.
Neglecting the importance of free-body diagrams in solving mechanics problems.
FAQs
Question: What are some effective ways to prepare for mechanics MCQs?Answer: Regular practice of MCQs, understanding key concepts, and solving previous years' question papers can significantly improve your preparation.
Question: How can I improve my speed in solving mechanics objective questions?Answer: Time yourself while practicing and focus on mastering the formulas and concepts to enhance your speed and accuracy.
Now is the time to take charge of your learning! Dive into our collection of mechanics MCQs and practice questions to solidify your understanding and excel in your exams. Remember, consistent practice is the key to success!
Q. If a 15 kg object is dropped from a height of 20 m, what is its potential energy just before it hits the ground?
A.
300 J
B.
1500 J
C.
600 J
D.
1200 J
Show solution
Solution
Potential energy PE = mgh = 15 kg * 9.81 m/s² * 20 m = 2943 J.
Correct Answer:
B
— 1500 J
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Q. If a 2 kg ball is thrown with a velocity of 4 m/s, what is the impulse imparted to the ball?
A.
8 Ns
B.
4 Ns
C.
2 Ns
D.
16 Ns
Show solution
Solution
Impulse (J) = change in momentum = mass (m) × velocity (v) = 2 kg × 4 m/s = 8 Ns.
Correct Answer:
A
— 8 Ns
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Q. If a 2 kg object is lifted to a height of 3 m, what is the gravitational potential energy gained?
A.
6 J
B.
12 J
C.
18 J
D.
24 J
Show solution
Solution
Potential Energy = mgh = 2 kg × 9.8 m/s² × 3 m = 58.8 J.
Correct Answer:
B
— 12 J
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Q. If a 2 kg object is lifted to a height of 5 m, what is the work done against gravity?
A.
10 J
B.
20 J
C.
30 J
D.
40 J
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Solution
Work done W = mgh = 2 kg * 9.81 m/s² * 5 m = 98.1 J.
Correct Answer:
B
— 20 J
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Q. If a 2 kg object is moving at 3 m/s, what is its momentum?
A.
6 kg·m/s
B.
5 kg·m/s
C.
3 kg·m/s
D.
2 kg·m/s
Show solution
Solution
Momentum is calculated using the formula p = mv. Thus, p = 2 kg * 3 m/s = 6 kg·m/s.
Correct Answer:
A
— 6 kg·m/s
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Q. If a 4 kg object is moving with a velocity of 2 m/s and collides elastically with a stationary object of mass 4 kg, what is the final velocity of the first object?
A.
0 m/s
B.
1 m/s
C.
2 m/s
D.
4 m/s
Show solution
Solution
In an elastic collision, the velocities are exchanged. The first object comes to rest, so final velocity = 0 m/s.
Correct Answer:
A
— 0 m/s
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Q. If a 5 kg object is subjected to a net force of 15 N, what is its acceleration?
A.
3 m/s²
B.
2 m/s²
C.
1 m/s²
D.
4 m/s²
Show solution
Solution
Using Newton's second law, F = ma, we can find acceleration: a = F/m = 15 N / 5 kg = 3 m/s².
Correct Answer:
A
— 3 m/s²
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Q. If a car accelerates from rest to 20 m/s in 5 seconds, what is its average acceleration?
A.
2 m/s²
B.
4 m/s²
C.
5 m/s²
D.
1 m/s²
Show solution
Solution
Average acceleration (a) = (final velocity - initial velocity) / time = (20 m/s - 0 m/s) / 5 s = 4 m/s².
Correct Answer:
A
— 2 m/s²
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Q. If a car accelerates from rest to 20 m/s in 5 seconds, what is the average power output if the car has a mass of 1000 kg?
A.
4000 W
B.
8000 W
C.
16000 W
D.
20000 W
Show solution
Solution
Work done = Change in Kinetic Energy = 0.5 × 1000 kg × (20 m/s)² = 200000 J. Power = Work / Time = 200000 J / 5 s = 40000 W.
Correct Answer:
C
— 16000 W
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Q. If a car accelerates from rest to a speed of 20 m/s in 10 seconds, what is the average power output if the car has a mass of 1000 kg?
A.
2000 W
B.
4000 W
C.
6000 W
D.
8000 W
Show solution
Solution
Work done = Change in Kinetic Energy = 0.5 × 1000 kg × (20 m/s)² = 200000 J. Power = Work / Time = 200000 J / 10 s = 20000 W.
Correct Answer:
C
— 6000 W
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Q. If a car accelerates from rest to a speed of 20 m/s in 5 seconds, what is its acceleration?
A.
2 m/s²
B.
4 m/s²
C.
5 m/s²
D.
10 m/s²
Show solution
Solution
Acceleration is calculated using the formula a = (v - u)/t. Here, a = (20 m/s - 0)/5 s = 4 m/s².
Correct Answer:
A
— 2 m/s²
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Q. If a car is moving at 80 km/h and a cyclist is moving at 20 km/h in the opposite direction, what is the speed of the cyclist relative to the car?
A.
60 km/h
B.
100 km/h
C.
80 km/h
D.
20 km/h
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Solution
The speed of the cyclist relative to the car is the sum of their speeds since they are moving in opposite directions: 80 km/h + 20 km/h = 100 km/h.
Correct Answer:
B
— 100 km/h
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Q. If a car is moving at a constant speed of 60 km/h, how far will it travel in 2 hours?
A.
60 km
B.
120 km
C.
180 km
D.
240 km
Show solution
Solution
Distance = speed × time = 60 km/h × 2 h = 120 km.
Correct Answer:
B
— 120 km
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Q. If a car traveling at 20 m/s comes to a stop in 5 seconds, what is its deceleration?
A.
2 m/s²
B.
4 m/s²
C.
5 m/s²
D.
10 m/s²
Show solution
Solution
Deceleration a = (final velocity - initial velocity) / time = (0 - 20 m/s) / 5 s = -4 m/s².
Correct Answer:
B
— 4 m/s²
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Q. If a car travels 100 m in 5 seconds, what is its average speed?
A.
20 m/s
B.
25 m/s
C.
15 m/s
D.
30 m/s
Show solution
Solution
Average speed is calculated as speed = distance/time, so speed = 100 m / 5 s = 20 m/s.
Correct Answer:
B
— 25 m/s
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Q. If a conductor moves perpendicular to a magnetic field, what is the induced emf proportional to?
A.
Speed of the conductor
B.
Angle of movement
C.
Length of the conductor
D.
Both speed and length
Show solution
Solution
The induced emf is proportional to both the speed of the conductor and the length of the conductor when moving perpendicular to the magnetic field.
Correct Answer:
D
— Both speed and length
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Q. If a force of 15 N is applied to a 3 kg object, what is the resulting acceleration?
A.
3 m/s²
B.
5 m/s²
C.
7 m/s²
D.
10 m/s²
Show solution
Solution
Using F = ma, we find acceleration: a = F/m = 15 N / 3 kg = 5 m/s².
Correct Answer:
B
— 5 m/s²
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Q. If a force of 15 N is applied to move an object 4 m, how much work is done?
A.
30 J
B.
60 J
C.
75 J
D.
90 J
Show solution
Solution
Work = Force × Distance = 15 N × 4 m = 60 J.
Correct Answer:
D
— 90 J
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Q. If a particle moves in a circular path with a constant speed, what type of acceleration does it experience?
A.
Centripetal acceleration
B.
Tangential acceleration
C.
No acceleration
D.
Linear acceleration
Show solution
Solution
A particle moving in a circular path with constant speed experiences centripetal acceleration directed towards the center of the circle.
Correct Answer:
A
— Centripetal acceleration
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Q. If a particle's momentum changes from p1 to p2, what is the impulse experienced by the particle?
A.
p2 - p1
B.
p1 + p2
C.
p1 * p2
D.
p1 / p2
Show solution
Solution
Impulse is defined as the change in momentum of an object, which is calculated as the difference between the final and initial momentum, J = p2 - p1.
Correct Answer:
A
— p2 - p1
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Q. If a person walks at 4 km/h on a train that is moving at 60 km/h in the same direction, what is the person's speed relative to the ground?
A.
56 km/h
B.
60 km/h
C.
64 km/h
D.
4 km/h
Show solution
Solution
The person's speed relative to the ground is 60 km/h + 4 km/h = 64 km/h.
Correct Answer:
C
— 64 km/h
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Q. If a plane is flying at 200 km/h and the wind is blowing at 50 km/h in the opposite direction, what is the plane's speed relative to the ground?
A.
150 km/h
B.
250 km/h
C.
200 km/h
D.
50 km/h
Show solution
Solution
The plane's speed relative to the ground is the speed of the plane minus the speed of the wind: 200 km/h - 50 km/h = 150 km/h.
Correct Answer:
A
— 150 km/h
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Q. If a rigid body rotates about a fixed axis, which of the following quantities remains constant?
A.
Angular velocity
B.
Angular acceleration
C.
Moment of inertia
D.
Torque
Show solution
Solution
If no external torques act on the body, the angular velocity can remain constant during rotation.
Correct Answer:
A
— Angular velocity
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Q. If a rolling object has a radius of 0.5 m and rolls with a linear speed of 2 m/s, what is its angular speed?
A.
4 rad/s
B.
2 rad/s
C.
1 rad/s
D.
3 rad/s
Show solution
Solution
The angular speed (ω) can be calculated using the formula ω = v/r. Here, ω = 2 m/s / 0.5 m = 4 rad/s.
Correct Answer:
A
— 4 rad/s
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Q. If a rolling object has a translational speed of v and a radius r, what is its angular speed?
A.
v/r
B.
rv
C.
v^2/r
D.
r/v
Show solution
Solution
The angular speed (ω) of a rolling object is related to its translational speed (v) by the equation ω = v/r.
Correct Answer:
A
— v/r
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Q. If a rotating object has a kinetic energy of 50 J and a moment of inertia of 5 kg·m², what is its angular velocity?
A.
5 rad/s
B.
10 rad/s
C.
15 rad/s
D.
20 rad/s
Show solution
Solution
Using KE = (1/2)Iω², we have 50 J = (1/2)(5 kg·m²)ω², solving gives ω = 10 rad/s.
Correct Answer:
B
— 10 rad/s
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Q. If a rotating object has a moment of inertia of 2 kg·m² and an angular acceleration of 3 rad/s², what is the torque applied?
A.
6 N·m
B.
5 N·m
C.
3 N·m
D.
2 N·m
Show solution
Solution
Torque is calculated as τ = I * α, where I is the moment of inertia and α is the angular acceleration. Here, τ = 2 kg·m² * 3 rad/s² = 6 N·m.
Correct Answer:
A
— 6 N·m
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Q. If a rotating object has a moment of inertia of 4 kg·m² and an angular velocity of 3 rad/s, what is its kinetic energy?
A.
6 J
B.
12 J
C.
18 J
D.
24 J
Show solution
Solution
Rotational kinetic energy is given by KE = 0.5 Iω² = 0.5 * 4 kg·m² * (3 rad/s)² = 18 J.
Correct Answer:
B
— 12 J
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Q. If a rotating object has an angular momentum of 20 kg·m²/s and a moment of inertia of 4 kg·m², what is its angular velocity?
A.
2 rad/s
B.
5 rad/s
C.
10 rad/s
D.
15 rad/s
Show solution
Solution
Using L = Iω, we find ω = L/I = 20 kg·m²/s / 4 kg·m² = 5 rad/s.
Correct Answer:
B
— 5 rad/s
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Q. If a solid sphere and a hollow sphere of the same mass and radius roll down an incline, which will reach the bottom first?
A.
Solid sphere
B.
Hollow sphere
C.
Both will reach at the same time
D.
It depends on the angle of the incline
Show solution
Solution
The solid sphere has a lower moment of inertia compared to the hollow sphere, allowing it to accelerate faster down the incline.
Correct Answer:
A
— Solid sphere
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