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Q. A light ray strikes a glass surface at an angle of 45 degrees. If the refractive index of glass is 1.5, what is the angle of refraction?

A. 30 degrees
B. 45 degrees
C. 60 degrees
D. 90 degrees

Solution

Using Snell's law, sin(r) = (n1/n2) * sin(i) = (1/1.5) * sin(45) = 0.471, giving r ≈ 30 degrees.

Correct Answer: A — 30 degrees

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Q. A pendulum swings to and fro. If the length of the pendulum is 1 m, what is the time period of the pendulum? (Take g = 10 m/s²)

A. 1 s
B. 2 s
C. 3 s
D. 4 s

Solution

Time period T = 2π√(l/g) = 2π√(1/10) = 2π/√10 ≈ 2 s.

Correct Answer: B — 2 s

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Q. A pendulum swings to and fro. If the length of the pendulum is 2 m, what is the time period of the pendulum? (Take g = 10 m/s²)

A. 1.4 s
B. 2.0 s
C. 1.0 s
D. 3.0 s

Solution

Time period T = 2π√(l/g) = 2π√(2/10) = 2π√(0.2) ≈ 2.0 s.

Correct Answer: B — 2.0 s

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Q. A pendulum swings with a period of 2 seconds. What is the length of the pendulum? (Take g = 10 m/s²)

A. 1 m
B. 2 m
C. 0.5 m
D. 0.25 m

Solution

Using the formula T = 2π√(l/g), we have l = (T² * g)/(4π²) = (2² * 10)/(4π²) = 1 m.

Correct Answer: B — 2 m

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Q. A person walks 3 km at a speed of 4 km/h and then runs 2 km at a speed of 8 km/h. What is the total time taken? (2020)

A. 1 hour
B. 1.25 hours
C. 1.5 hours
D. 1.75 hours

Solution

Time walking = 3 km / 4 km/h = 0.75 hours; Time running = 2 km / 8 km/h = 0.25 hours. Total time = 0.75 + 0.25 = 1 hour.

Correct Answer: B — 1.25 hours

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Q. A person walks 3 km in 30 minutes. What is his speed in km/h? (2023)

A. 4 km/h
B. 5 km/h
C. 6 km/h
D. 7 km/h

Solution

Speed = Distance / Time = 3 km / 0.5 h = 6 km/h.

Correct Answer: B — 5 km/h

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Q. A person walks 3 km north and then 4 km east. What is the straight-line distance from the starting point? (2021)

A. 5 km
B. 6 km
C. 7 km
D. 8 km

Solution

Using Pythagoras theorem, distance = √(3² + 4²) = √(9 + 16) = √25 = 5 km.

Correct Answer: A — 5 km

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Q. A person walks 3 km towards the north and then 4 km towards the east. What is the straight-line distance from the starting point? (2020)

A. 5 km
B. 6 km
C. 7 km
D. 8 km

Solution

Using Pythagoras theorem, distance = √(3² + 4²) = √(9 + 16) = √25 = 5 km.

Correct Answer: A — 5 km

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Q. A person walks 4 km at a speed of 4 km/h and then runs 3 km at a speed of 6 km/h. What is the total time taken? (2020)

A. 1 hour
B. 1.5 hours
C. 2 hours
D. 2.5 hours

Solution

Time walking = 4 km / 4 km/h = 1 hour; Time running = 3 km / 6 km/h = 0.5 hours. Total time = 1 + 0.5 = 1.5 hours.

Correct Answer: B — 1.5 hours

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Q. A plane mirror is placed at an angle of 60 degrees to the incident ray. What is the angle of reflection?

A. 30 degrees
B. 60 degrees
C. 90 degrees
D. 120 degrees

Solution

According to the law of reflection, the angle of reflection is equal to the angle of incidence. Therefore, the angle of reflection is also 60 degrees.

Correct Answer: B — 60 degrees

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Q. A projectile is launched at an angle of 30° with the horizontal with an initial velocity of 40 m/s. What is the horizontal range of the projectile? (Take g = 10 m/s²)

A. 160 m
B. 200 m
C. 80 m
D. 120 m

Solution

Range R = (u² * sin(2θ))/g = (40² * sin(60°))/10 = (1600 * √3/2)/10 = 80√3 m ≈ 138.56 m.

Correct Answer: B — 200 m

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Q. A projectile is launched with an initial velocity of 30 m/s at an angle of 30 degrees to the horizontal. What is the horizontal range of the projectile? (Take g = 10 m/s²)

A. 90 m
B. 75 m
C. 100 m
D. 120 m

Solution

Range R = (u² * sin(2θ))/g = (30² * sin(60°))/10 = (900 * √3/2)/10 = 45√3 m ≈ 90 m.

Correct Answer: A — 90 m

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Q. A projectile is launched with an initial velocity of 30 m/s at an angle of 30 degrees. What is the horizontal range of the projectile? (Take g = 10 m/s²)

A. 90 m
B. 75 m
C. 100 m
D. 120 m

Solution

Range R = (u² * sin(2θ))/g = (30² * sin(60°))/10 = (900 * √3/2)/10 = 45√3 m ≈ 90 m.

Correct Answer: A — 90 m

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Q. A projectile is launched with an initial velocity of 30 m/s at an angle of 30° to the horizontal. What is the horizontal range of the projectile? (Take g = 10 m/s²)

A. 90 m
B. 75 m
C. 100 m
D. 120 m

Solution

Range R = (u² * sin(2θ))/g = (30² * sin(60°))/10 = (900 * √3/2)/10 = 45√3 m ≈ 90 m.

Correct Answer: A — 90 m

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Q. A projectile is launched with an initial velocity of 40 m/s at an angle of 30 degrees. What is the horizontal range of the projectile? (Take g = 10 m/s²)

A. 160 m
B. 200 m
C. 80 m
D. 120 m

Solution

Range R = (u² * sin(2θ))/g = (40² * sin(60°))/10 = (1600 * √3/2)/10 = 80√3 m ≈ 138.56 m.

Correct Answer: B — 200 m

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Q. A ray of light strikes a plane mirror at an angle of 30 degrees to the normal. What is the angle of reflection? (2022)

A. 30 degrees
B. 45 degrees
C. 60 degrees
D. 90 degrees

Solution

According to the law of reflection, the angle of reflection is equal to the angle of incidence. Therefore, the angle of reflection is 30 degrees.

Correct Answer: A — 30 degrees

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Q. A runner completes a 400 m lap in 50 seconds. What is the average speed of the runner in m/s? (2019)

A. 6 m/s
B. 7 m/s
C. 8 m/s
D. 9 m/s

Solution

Average speed = Total distance / Total time = 400 m / 50 s = 8 m/s.

Correct Answer: A — 6 m/s

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Q. A sound wave has a frequency of 440 Hz. What is its period?

A. 0.00227 s
B. 0.00455 s
C. 0.01 s
D. 0.1 s

Solution

The period (T) is the inverse of frequency (f), T = 1/f = 1/440 ≈ 0.00227 s.

Correct Answer: B — 0.00455 s

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Q. A spring has a spring constant of 200 N/m. How much force is required to stretch the spring by 0.1 m?

A. 5 N
B. 10 N
C. 15 N
D. 20 N

Solution

Using Hooke's law, F = kx = 200 N/m * 0.1 m = 20 N.

Correct Answer: A — 5 N

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Q. A spring has a spring constant of 200 N/m. How much force is required to stretch the spring by 0.5 m?

A. 50 N
B. 100 N
C. 150 N
D. 200 N

Solution

Using Hooke's law, F = kx = 200 N/m * 0.5 m = 100 N.

Correct Answer: B — 100 N

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Q. A spring stretches 0.1 m when a force of 10 N is applied. What is the spring constant?

A. 100 N/m
B. 50 N/m
C. 200 N/m
D. 10 N/m

Solution

Using Hooke's Law, F = kx, we have k = F/x = 10 N / 0.1 m = 100 N/m.

Correct Answer: A — 100 N/m

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Q. A stone is thrown vertically upwards with a speed of 15 m/s. How long will it take to reach the highest point? (Take g = 10 m/s²) (2023)

A. 1.5 s
B. 2 s
C. 3 s
D. 4 s

Solution

Time to reach highest point = u/g = 15/10 = 1.5 s.

Correct Answer: B — 2 s

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Q. A train leaves a station and travels at a speed of 80 km/h. How far will it travel in 3 hours? (2022)

A. 200 km
B. 240 km
C. 260 km
D. 300 km

Solution

Distance = Speed × Time = 80 km/h × 3 h = 240 km.

Correct Answer: B — 240 km

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Q. A train leaves a station and travels at a speed of 90 km/h. How long will it take to cover 270 km? (2022)

A. 2 hours
B. 3 hours
C. 4 hours
D. 5 hours

Solution

Time = Distance / Speed = 270 km / 90 km/h = 3 hours.

Correct Answer: B — 3 hours

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Q. A train leaves a station at 2 PM traveling at 80 km/h. If it travels for 3 hours, at what time will it arrive at the next station? (2022)

A. 4 PM
B. 5 PM
C. 6 PM
D. 7 PM

Solution

Departure time = 2 PM, travel time = 3 hours. Arrival time = 2 PM + 3 hours = 5 PM.

Correct Answer: C — 6 PM

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Q. A train travels 120 km at a speed of 60 km/h and then 180 km at 90 km/h. What is the average speed for the entire journey? (2019)

A. 72 km/h
B. 75 km/h
C. 80 km/h
D. 85 km/h

Solution

Total time = (120/60) + (180/90) = 2 + 2 = 4 hours. Total distance = 120 + 180 = 300 km. Average speed = Total distance / Total time = 300/4 = 75 km/h.

Correct Answer: C — 80 km/h

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Q. A train travels at a speed of 90 km/h. How long will it take to cover 450 km? (2019)

A. 4 hours
B. 5 hours
C. 6 hours
D. 7 hours

Solution

Time = Distance / Speed = 450 km / 90 km/h = 5 hours.

Correct Answer: C — 6 hours

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Q. A train travels from station A to station B, a distance of 300 km, at a speed of 75 km/h. How long does the journey take? (2019)

A. 3 hours
B. 4 hours
C. 5 hours
D. 6 hours

Solution

Time = Distance / Speed = 300 km / 75 km/h = 4 hours.

Correct Answer: C — 5 hours

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Q. A vehicle accelerates from rest at a rate of 2 m/s². How far does it travel in 10 seconds? (2020)

A. 50 m
B. 100 m
C. 150 m
D. 200 m

Solution

Using the formula s = ut + (1/2)at²; s = 0 + (1/2)(2)(10²) = 100 m.

Correct Answer: B — 100 m

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Q. A vehicle accelerates from rest to a speed of 36 m/s in 12 seconds. What is the distance covered during this time? (2023)

A. 108 m
B. 144 m
C. 180 m
D. 216 m

Solution

Using the formula s = ut + (1/2)at², where a = (v-u)/t = (36-0)/12 = 3 m/s², we find s = 0 + (1/2)(3)(12²) = 216 m.

Correct Answer: B — 144 m

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