Using the formula: acceleration = (final velocity - initial velocity) / time. Acceleration = (0 - 15) / 5 = -3 m/s².

Force F = qE = (1 × 10^-6 C)(1000 N/C) = 0.001 N.

Force F = qE = (10 × 10^-6 C) * (2000 N/C) = 0.02 N = 20 N.

Force F = qE = (10 × 10^-6 C) * (2000 N/C) = 0.02 N = 20 N.

Work done W = F * d = (E * q) * d = (1000 N/C * 5 × 10^-6 C) * 0.2 m = 0.1 J.

Work done W = F * d = (E * q) * d = (300 N/C * 5 × 10^-6 C) * 0.2 m = 0.3 J.

The force on a negative charge is in the direction opposite to the electric field, hence towards the positive charge.

First, find the equivalent resistance R_eq = 1/(1/4 + 1/6) = 2.4Ω. Then, I = V/R_eq = 12V/2.4Ω = 5 A.

Using Ohm's law, I = V/R = 15V/5Ω = 3A.

The voltage drop across the resistor is equal to the battery voltage in a simple circuit: 9V.

Using Ohm's Law, V = I * R = 2A * 6Ω = 12V.

Using Ohm's Law, V = I * R = 3A * 6Ω = 18V.

Power (P) can be calculated using P = I^2 * R = (5A)^2 * 10Ω = 25 * 10 = 250W.

Power (P) can be calculated using the formula P = I^2 * R = (5A)^2 * 2Ω = 25W.

Using Ohm's Law, V = I * R = 5A * 2Ω = 10V.

Inside the loop, the magnetic field lines are nearly uniform and parallel, indicating a strong and consistent magnetic field.

The magnetic field lines around a circular loop of wire are concentric circles centered on the axis of the loop.

Kinetic Energy is proportional to the square of the speed. If speed is doubled, KE increases by a factor of 2^2 = 4.

Kinetic Energy is proportional to the square of the speed. If speed is doubled, KE increases by a factor of 2^2 = 4.

Kinetic Energy (KE) = 1/2 * m * v^2 = 1/2 * 75 kg * (15 m/s)^2 = 8437.5 J.

Distance = speed * time = 10 m/s * 15 s = 150 m.

The moment of inertia of a solid disc about its central axis is given by I = (1/2)MR².

The moment of inertia I of a disc about its axis is (1/2)MR². Therefore, angular momentum L = Iω = (1/2)MR²ω.

The disk has a smaller moment of inertia than the ring, resulting in greater acceleration down the incline.

A diverging lens always forms a virtual and upright image when the object is placed in front of it.

The rotational kinetic energy is given by K.E. = (1/2)Iω^2.

Using the formula α = (ω - ω₀)/t, we have α = (0 - 10)/5 = -2 rad/s², so the deceleration is 2 rad/s².

Using the formula α = (ω - ω₀)/t, we have α = (0 - 30 rad/s) / 10 s = -3 rad/s².

Angular deceleration α = (final angular velocity - initial angular velocity) / time = (0 - 10) / 5 = -2 rad/s².

Rotational kinetic energy K.E. = (1/2)Iω² = (1/2)(2)(10)² = 100 J.