Using the formula: acceleration = (final velocity - initial velocity) / time. Acceleration = (0 - 15) / 5 = -3 m/s².

Force F = qE = (1 × 10^-6 C)(1000 N/C) = 0.001 N.

Force F = qE = (10 × 10^-6 C) * (2000 N/C) = 0.02 N = 20 N.

Force F = qE = (10 × 10^-6 C) * (2000 N/C) = 0.02 N = 20 N.

Work done W = F * d = (E * q) * d = (1000 N/C * 5 × 10^-6 C) * 0.2 m = 0.1 J.

Work done W = F * d = (E * q) * d = (300 N/C * 5 × 10^-6 C) * 0.2 m = 0.3 J.

The force on a negative charge is in the direction opposite to the electric field, hence towards the positive charge.

First, find the equivalent resistance R_eq = 1/(1/4 + 1/6) = 2.4Ω. Then, I = V/R_eq = 12V/2.4Ω = 5 A.

Using Ohm's law, I = V/R = 15V/5Ω = 3A.

The voltage drop across the resistor is equal to the battery voltage in a simple circuit: 9V.

Using Ohm's Law, V = I * R = 2A * 6Ω = 12V.

Using Ohm's Law, V = I * R = 3A * 6Ω = 18V.

Power (P) can be calculated using P = I^2 * R = (5A)^2 * 10Ω = 25 * 10 = 250W.

Power (P) can be calculated using the formula P = I^2 * R = (5A)^2 * 2Ω = 25W.

Using Ohm's Law, V = I * R = 5A * 2Ω = 10V.

The magnetic field lines around a circular loop of wire are concentric circles centered on the axis of the loop.

Inside the loop, the magnetic field lines are nearly uniform and parallel, indicating a strong and consistent magnetic field.

Kinetic Energy is proportional to the square of the speed. If speed is doubled, KE increases by a factor of 2^2 = 4.

Kinetic Energy is proportional to the square of the speed. If speed is doubled, KE increases by a factor of 2^2 = 4.

Kinetic Energy (KE) = 1/2 * m * v^2 = 1/2 * 75 kg * (15 m/s)^2 = 8437.5 J.

Distance = speed * time = 10 m/s * 15 s = 150 m.

The moment of inertia I of a disc about its axis is (1/2)MR². Therefore, angular momentum L = Iω = (1/2)MR²ω.

The moment of inertia of a solid disc about its central axis is given by I = (1/2)MR².

The disk has a smaller moment of inertia than the ring, resulting in greater acceleration down the incline.

A diverging lens always forms a virtual and upright image when the object is placed in front of it.

The rotational kinetic energy is given by K.E. = (1/2)Iω^2.

Using the formula α = (ω - ω₀)/t, we have α = (0 - 10)/5 = -2 rad/s², so the deceleration is 2 rad/s².

Using the formula α = (ω - ω₀)/t, we have α = (0 - 30 rad/s) / 10 s = -3 rad/s².

Angular deceleration α = (final angular velocity - initial angular velocity) / time = (0 - 10) / 5 = -2 rad/s².

Rotational kinetic energy K.E. = (1/2)Iω² = (1/2)(2)(10)² = 100 J.