Work = mgh = 15 kg * 9.8 m/s² * 4 m = 588 J.

Kinetic Energy (KE) = 0.5 × m × v² = 0.5 × 15 kg × (4 m/s)² = 0.5 × 15 × 16 = 120 J.

Momentum = mass × velocity = 15 kg × 4 m/s = 60 kg m/s.

Work done = Change in Kinetic Energy = 0.5 * m * v² = 0.5 * 1500 kg * (25 m/s)² = 468,750 J.

Kinetic Energy = 0.5 × mass × velocity² = 0.5 × 1500 kg × (25 m/s)² = 468,750 J

Using conservation of energy, Potential Energy at height = Kinetic Energy just before hitting ground. mgh = 1/2 mv^2. Solving gives v = sqrt(2gh) = sqrt(2 * 10 m/s² * 10 m) = 14.14 m/s.

Using energy conservation, v = sqrt(2gh) = sqrt(2 * 9.8 m/s² * 10 m) = 14 m/s.

Using energy conservation, Potential Energy = Kinetic Energy at the ground: mgh = 0.5 mv^2; v = sqrt(2gh) = sqrt(2 * 10 m/s² * 20 m) = 20 m/s

Using v² = u² + 2as, 0 = (20 m/s)² + 2(-9.8 m/s²)(h). Solving gives h = 20.4 m.

Using conservation of energy, potential energy at the top = kinetic energy at the bottom: mgh = 0.5mv². Solving gives v = √(2gh) = √(2 * 9.8 * 5) = 10 m/s.

Heat absorbed = mass * latent heat = 2 kg * 334,000 J/kg = 668,000 J.

Using the heat transfer equation, the final temperature can be calculated to be 50°C.

Using conservation of energy, Potential Energy at top = Kinetic Energy at bottom: mgh = 1/2 mv^2; v = sqrt(2gh) = sqrt(2 * 9.8 m/s² * 3 m) = 7.75 m/s (approx. 6 m/s)

The force acting on it is its weight, F = mg = 2 kg × 10 m/s² = 20 N.

Using the formula v = √(2gh) = √(2 * 10 m/s² * 20 m) = √400 = 20 m/s

The force acting on the object is its weight, F = mg = 2 kg × 9.8 m/s² = 19.6 N.

Q = mcΔT = 2 kg * 0.5 kJ/kg°C * (80°C - 20°C) = 60 kJ.

Work Done (W) = m * g * h = 2 kg * 9.8 m/s^2 * 3 m = 58.8 J (approx. 60 J)

Work Done = mgh = 2 kg * 9.8 m/s² * 3 m = 58.8 J

Potential Energy = mass × g × height = 2 kg × 10 m/s² × 5 m = 100 J

Potential Energy = mass × g × height = 2 kg × 9.8 m/s² × 5 m = 98 J

Momentum = Mass × Velocity = 2 kg × 10 m/s = 20 kg·m/s.

Kinetic Energy (KE) = 1/2 * m * v^2 = 1/2 * 2 kg * (4 m/s)^2 = 16 J.

Momentum (p) = m * v = 2 kg * 4 m/s = 8 kg m/s

Work done = Force * Distance = 10 N * 5 m = 50 J.

Using F = ma, a = F/m = 8 N / 2 kg = 4 m/s².

Net force = 80 N - 20 N = 60 N. Acceleration a = F/m = 60 N / 20 kg = 3 m/s².

Using F = ma, we find a = F/m = 80 N / 20 kg = 4 m/s².

Acceleration = Net force / Mass = 80 N / 20 kg = 4 m/s².

Kinetic energy KE = 0.5 * m * v² = 0.5 * 20 kg * (5 m/s)² = 0.5 * 20 * 25 = 250 J.