Current Electricity Study Materials for Competitive Exams

Current Electricity

Circuits & Kirchhoff Laws Ohms Law Potentiometer Resistivity Wheatstone Bridge

Q. If a 6Ω resistor is connected to a 9V battery, what is the power dissipated by the resistor?

A. 6W
B. 9W
C. 12W
D. 15W

Solution

Power P = V^2 / R = (9V)^2 / 6Ω = 81 / 6 = 13.5W.

Correct Answer: C — 12W

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Q. If a 9V battery is connected to a 3Ω resistor, what is the power consumed by the resistor?

A. 3W
B. 9W
C. 27W
D. 1W

Solution

Power P = V^2/R = (9V)^2 / 3Ω = 81/3 = 27W.

Correct Answer: B — 9W

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Q. If a battery provides a voltage of 9 V and is connected to a circuit with a total resistance of 3 ohms, what is the power consumed by the circuit?

A. 27 W
B. 18 W
C. 9 W
D. 3 W

Solution

Power P = V^2 / R. Here, P = 9^2 / 3 = 81 / 3 = 27 W.

Correct Answer: B — 18 W

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Q. If a circuit contains a 12V battery and two resistors in series of 3Ω and 9Ω, what is the current flowing through the circuit?

A. 0.5A
B. 1A
C. 1.5A
D. 2A

Solution

Total resistance R = R1 + R2 = 3Ω + 9Ω = 12Ω. Using Ohm's law, I = V/R = 12V/12Ω = 1A.

Correct Answer: B — 1A

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Q. If a circuit contains a 9V battery and three resistors (R1 = 3Ω, R2 = 3Ω, R3 = 3Ω) in parallel, what is the total current supplied by the battery?

A. 1A
B. 2A
C. 3A
D. 4A

Solution

The equivalent resistance for resistors in parallel is 1/R_total = 1/R1 + 1/R2 + 1/R3 = 1/3 + 1/3 + 1/3 = 1Ω. The total current is I = V/R_total = 9V / 1Ω = 9A.

Correct Answer: C — 3A

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Q. If a circuit has a 10V source and a total resistance of 5Ω, what is the total current in the circuit?

A. 1A
B. 2A
C. 3A
D. 4A

Solution

Using Ohm's law, I = V/R = 10V / 5Ω = 2A.

Correct Answer: B — 2A

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Q. If a circuit has a 12V battery and two resistors of 3Ω and 6Ω in series, what is the total current flowing through the circuit?

A. 1A
B. 2A
C. 3A
D. 4A

Solution

Total resistance R = R1 + R2 = 3Ω + 6Ω = 9Ω. Using Ohm's law, I = V/R = 12V / 9Ω = 1.33A.

Correct Answer: B — 2A

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Q. If a circuit has a 12V battery and two resistors of 4 ohms and 8 ohms in series, what is the voltage across the 8 ohm resistor?

A. 4 V
B. 8 V
C. 6 V
D. 12 V

Solution

The total resistance is 4 + 8 = 12 ohms. The current is I = V/R = 12V / 12 ohms = 1 A. The voltage across the 8 ohm resistor is V = I * R = 1 A * 8 ohms = 8 V.

Correct Answer: B — 8 V

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Q. If a circuit has a 15V battery and two resistors (5Ω and 10Ω) in series, what is the voltage across the 10Ω resistor?

A. 5V
B. 10V
C. 15V
D. 0V

Solution

Using the voltage divider rule, V2 = (R2 / (R1 + R2)) * Vtotal = (10 / (5 + 10)) * 15 = 10V.

Correct Answer: B — 10V

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Q. If a circuit has a 15V battery and two resistors (R1 = 5Ω, R2 = 10Ω) in series, what is the voltage across R2?

A. 10V
B. 5V
C. 15V
D. 0V

Solution

Voltage across R2 = (R2 / (R1 + R2)) * V = (10Ω / (5Ω + 10Ω)) * 15V = 10V.

Correct Answer: A — 10V

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Q. If a circuit has a 15V battery and two resistors of 5Ω and 10Ω in series, what is the power dissipated by the 10Ω resistor?

A. 1.5W
B. 2.5W
C. 3.75W
D. 5W

Solution

Total resistance R = 5Ω + 10Ω = 15Ω. Current I = V/R = 15V/15Ω = 1A. Power P = I^2 * R = 1^2 * 10 = 10W.

Correct Answer: C — 3.75W

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Q. If a circuit has a 24V battery and two resistors of 6Ω and 12Ω in series, what is the voltage across the 12Ω resistor?

A. 8V
B. 12V
C. 16V
D. 18V

Solution

Using the voltage divider rule, V2 = (R2 / (R1 + R2)) * Vtotal = (12 / (6 + 12)) * 24 = 16V.

Correct Answer: B — 12V

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Q. If a circuit has a 9V battery and two resistors of 3Ω and 6Ω in series, what is the voltage across the 6Ω resistor?

A. 3V
B. 6V
C. 9V
D. 4.5V

Solution

Using the voltage divider rule, V6Ω = (R6Ω / (R3Ω + R6Ω)) * Vtotal = (6 / (3 + 6)) * 9 = 6V.

Correct Answer: B — 6V

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Q. If a circuit has a current of 0.5 A and a resistance of 20 ohms, what is the voltage?

A. 10 V
B. 5 V
C. 15 V
D. 20 V

Solution

Using Ohm's Law, V = I * R = 0.5 A * 20 Ω = 10 V.

Correct Answer: A — 10 V

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Q. If a circuit has a current of 2 A flowing through a resistor of 5 ohms, what is the voltage across the resistor?

A. 5 V
B. 10 V
C. 2 V
D. 1 V

Solution

Using Ohm's Law, V = I * R. Here, V = 2 A * 5 ohms = 10 V.

Correct Answer: B — 10 V

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Q. If a circuit has a current of 2A flowing through a 5Ω resistor, what is the power dissipated by the resistor?

A. 5W
B. 10W
C. 15W
D. 20W

Solution

Power (P) = I^2 * R = (2^2) * 5 = 4 * 5 = 20W.

Correct Answer: B — 10W

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Q. If a circuit has a current of 2A flowing through a 5Ω resistor, what is the voltage across the resistor?

A. 10V
B. 5V
C. 2.5V
D. 1V

Solution

Using Ohm's Law, V = I * R = 2A * 5Ω = 10V.

Correct Answer: A — 10V

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Q. If a circuit has a current of 3 A and a resistance of 4 ohms, what is the voltage across the circuit?

A. 7 V
B. 12 V
C. 15 V
D. 20 V

Solution

Using Ohm's Law, V = IR = 3 A * 4 Ω = 12 V.

Correct Answer: B — 12 V

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Q. If a circuit has a current of 3A flowing through a 10Ω resistor, what is the power dissipated by the resistor?

A. 30W
B. 10W
C. 90W
D. 15W

Solution

Power (P) = I^2 * R = 3^2 * 10 = 9 * 10 = 90W.

Correct Answer: A — 30W

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Q. If a circuit has a current of 3A flowing through a 5Ω resistor, what is the power dissipated in the resistor?

A. 15W
B. 9W
C. 5W
D. 3W

Solution

Power (P) = I^2 * R = (3A)^2 * 5Ω = 9A^2 * 5Ω = 45W.

Correct Answer: A — 15W

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Q. If a circuit has a current of 3A flowing through a 5Ω resistor, what is the power dissipated by the resistor?

A. 5W
B. 10W
C. 15W
D. 20W

Solution

Power (P) = I^2 * R = (3A)^2 * 5Ω = 9 * 5 = 45W.

Correct Answer: C — 15W

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Q. If a circuit has a current of 5 A and a resistance of 10 Ω, what is the power consumed in the circuit?

A. 50 W
B. 25 W
C. 10 W
D. 5 W

Solution

Power (P) can be calculated using P = I^2 * R = (5 A)^2 * 10 Ω = 25 A^2 * 10 Ω = 250 W.

Correct Answer: A — 50 W

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Q. If a circuit has a current of 5 A and a resistance of 10 Ω, what is the voltage?

A. 50 V
B. 5 V
C. 10 V
D. 15 V

Solution

Using Ohm's Law, V = I * R = 5 A * 10 Ω = 50 V.

Correct Answer: A — 50 V

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Q. If a circuit has a current of 5 amperes and a resistance of 10 ohms, what is the voltage?

A. 50 volts
B. 5 volts
C. 10 volts
D. 15 volts

Solution

Using Ohm's Law, V = I * R = 5 A * 10 Ω = 50 V.

Correct Answer: A — 50 volts

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Q. If a circuit has a current of 5A flowing through a 10Ω resistor, what is the power dissipated by the resistor?

A. 25W
B. 50W
C. 75W
D. 100W

Solution

Power (P) = I^2 * R = 5^2 * 10 = 25 * 10 = 250W.

Correct Answer: B — 50W

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Q. If a circuit has a current of 5A flowing through a resistor of 10Ω, what is the voltage across the resistor?

A. 5V
B. 10V
C. 15V
D. 50V

Solution

Using Ohm's Law (V = IR), the voltage is V = 5A * 10Ω = 50V.

Correct Answer: B — 10V

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Q. If a circuit has a total current of 3 A and a total resistance of 6 ohms, what is the voltage supplied by the battery?

A. 9 V
B. 6 V
C. 3 V
D. 12 V

Solution

Using Ohm's law, V = I * R, we have V = 3 A * 6 ohms = 18 V.

Correct Answer: A — 9 V

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Q. If a circuit has a total current of 5 A and a total resistance of 10 ohms, what is the voltage across the circuit?

A. 50 V
B. 5 V
C. 10 V
D. 2 V

Solution

Using Ohm's law, V = I * R, we have V = 5 A * 10 ohms = 50 V.

Correct Answer: A — 50 V

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Q. If a circuit has a total current of 5A and a total resistance of 10Ω, what is the total voltage supplied by the battery?

A. 25V
B. 50V
C. 75V
D. 100V

Solution

Using Ohm's Law, V = I * R = 5A * 10Ω = 50V.

Correct Answer: B — 50V

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Q. If a circuit has a total resistance of 10 ohms and a total voltage of 50V, what is the total current?

A. 5 A
B. 10 A
C. 2 A
D. 0.5 A

Solution

Using Ohm's law, I = V/R = 50V / 10 ohms = 5 A.

Correct Answer: A — 5 A

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Showing 61 to 90 of 607 (21 Pages)

Current Electricity MCQ & Objective Questions

Current Electricity is a crucial topic in physics that students must master for their exams. Understanding this concept not only helps in grasping fundamental principles but also significantly boosts your performance in objective questions. Practicing MCQs and important questions related to Current Electricity can enhance your exam preparation and increase your chances of scoring higher marks.

What You Will Practise Here

Ohm's Law and its applications
Series and parallel circuits
Electrical power and energy calculations
Resistance, resistivity, and factors affecting resistance
Kirchhoff's laws and their practical applications
Concept of current, voltage, and their relationship
Diagrams and circuit analysis techniques

Exam Relevance

The topic of Current Electricity is frequently tested in various examinations, including CBSE, State Boards, NEET, and JEE. Students can expect questions that assess their understanding of fundamental concepts, application of formulas, and problem-solving skills. Common question patterns include numerical problems, theoretical questions, and circuit analysis, making it essential to be well-prepared with Current Electricity MCQ questions.

Common Mistakes Students Make

Confusing current with voltage and their units
Misapplying Ohm's Law in complex circuits
Overlooking the effects of temperature on resistance
Failing to differentiate between series and parallel connections
Neglecting to draw circuit diagrams for better understanding

FAQs

Question: What is the formula for calculating electrical power?
Answer: The formula for electrical power is P = VI, where P is power, V is voltage, and I is current.

Question: How does resistance change in series and parallel circuits?
Answer: In series circuits, total resistance increases, while in parallel circuits, total resistance decreases.

Now is the time to enhance your understanding of Current Electricity! Dive into our practice MCQs and test your knowledge to ensure you are well-prepared for your exams. Start solving today and boost your confidence!

Current Electricity

Current Electricity MCQ & Objective Questions

What You Will Practise Here

Exam Relevance

Common Mistakes Students Make

FAQs

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