The electric field just outside a conductor in electrostatic equilibrium is perpendicular to the surface.

The electric field at the surface of a sphere is given by E = Q/(4πε₀R²). If R is halved, E increases by a factor of 4.

The electric field E due to a point charge decreases with the square of the distance from the charge, so if the radius is doubled, the electric field halves.

The electric field due to a point charge is independent of the radius of the Gaussian surface; it remains the same.

The electric field E due to a point charge decreases with the square of the distance from the charge, so if the radius is doubled, the electric field halves.

If the total charge enclosed is zero, the electric field can still be non-zero at points on the surface due to external charges.

The electric flux Φ through a surface area A in a uniform electric field E is given by Φ = EA when the surface is perpendicular to the field.

The electric flux is maximum when the angle between the electric field and the normal to the surface is 0°, as Φ = E·A·cos(θ).

A plane is the simplest Gaussian surface for uniform electric fields, as it allows for straightforward calculation of flux.

Inside a uniformly charged cylindrical shell, the electric field is zero due to symmetry, as the contributions from all parts of the shell cancel out.

Gauss's law states that the electric flux through a closed surface is proportional to the charge enclosed within that surface.

In electrostatic equilibrium, the electric field inside a conductor is zero.

Inserting a dielectric material between the plates of a capacitor decreases the electric field due to polarization.

Inserting a dielectric material into a capacitor decreases the electric field inside the capacitor due to polarization.

Increasing the permittivity of the medium decreases the electric field due to a point charge, as E = Q/(4πε₀r²).

The electric field due to a point charge decreases with distance, but the total flux remains constant as the charge is fixed.

The electric field due to a charged plane sheet is directly proportional to the surface charge density; increasing σ increases E.

The electric field due to an infinitely long charged wire is given by E = λ/(2πε₀d).

The electric field at a distance r from a uniformly charged disk is given by E = σ/(2ε₀) * (1 - r/√(R² + r²)).

For r > R, the electric field behaves as if all the charge were concentrated at the center, thus E = Q/(4πε₀r²).

The electric field due to an infinite line charge is given by E = λ/2πε₀r.

The electric field due to an infinitely long line of charge is given by E = λ/(2πε₀r), directed radially outward from the line.

The electric field just outside a charged conductor is given by E = σ/ε₀, where σ is the surface charge density.

The electric field along the axis of a dipole at a distance d is given by E = (1/(4πε₀)) * (2p/d³), where p is the dipole moment.

For a point outside a uniformly charged sphere, the electric field behaves as if all the charge were concentrated at the center, so E = Q/(4πε₀R²).

According to Gauss's law, the electric field due to an infinite plane sheet with surface charge density σ is E = σ/2ε₀, directed away from the sheet.

Using Gauss's law, the electric field due to a uniformly charged line of charge is E = λ/(2πε₀r).

The electric field due to an infinite plane sheet of charge is given by E = σ/2ε₀, directed away from the sheet if the charge is positive.

According to Gauss's law, the electric field inside a uniformly charged hollow sphere is zero.

For a uniformly charged sphere, outside the sphere, the electric field behaves as if all the charge were concentrated at the center, E = Q/(4πε₀R²).