Work, Energy & Power: Essential Concepts for Exam Prep

Work, Energy & Power

Conservation of Energy Power Work Energy Theorem

Q. A 3 kg object is dropped from a height of 12 m. What is the potential energy at the top?

A. 30 J
B. 36 J
C. 60 J
D. 120 J

Solution

Potential energy = mgh = 3 kg × 9.8 m/s² × 12 m = 352.8 J.

Correct Answer: D — 120 J

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Q. A 3 kg object is dropped from a height of 15 m. What is its potential energy at the top? (g = 9.8 m/s²)

A. 441 J
B. 294 J
C. 147 J
D. 0 J

Solution

Potential Energy (PE) = m * g * h = 3 kg * 9.8 m/s² * 15 m = 441 J

Correct Answer: B — 294 J

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Q. A 3 kg object is dropped from a height of 15 m. What is the potential energy at the top?

A. 30 J
B. 45 J
C. 60 J
D. 75 J

Solution

Potential energy = mass × g × height = 3 kg × 9.8 m/s² × 15 m = 441 J.

Correct Answer: D — 75 J

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Q. A 3 kg object is dropped from a height of 5 m. What is the potential energy at the height?

A. 15 J
B. 30 J
C. 45 J
D. 60 J

Solution

Potential energy = mass × g × height = 3 kg × 9.8 m/s² × 5 m = 147 J.

Correct Answer: B — 30 J

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Q. A 3 kg object is lifted to a height of 4 m. What is the work done against gravity?

A. 12 J
B. 24 J
C. 36 J
D. 48 J

Solution

Work done = mgh = 3 * 9.8 * 4 = 117.6 J.

Correct Answer: B — 24 J

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Q. A 3 kg object is lifted to a height of 5 m. What is the work done against gravity? (g = 9.8 m/s²)

A. 147 J
B. 294 J
C. 441 J
D. 588 J

Solution

Work done = mgh = 3 kg × 9.8 m/s² × 5 m = 147 J.

Correct Answer: B — 294 J

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Q. A 3 kg object is moving with a speed of 10 m/s. What is its kinetic energy?

A. 150 J
B. 300 J
C. 450 J
D. 600 J

Solution

Kinetic energy = 0.5mv² = 0.5 * 3 * (10)² = 150 J.

Correct Answer: B — 300 J

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Q. A 3 kg object is moving with a speed of 10 m/s. What is its total mechanical energy?

A. 150 J
B. 300 J
C. 450 J
D. 600 J

Solution

Total mechanical energy = KE + PE. Assuming PE = 0, KE = 0.5mv² = 0.5 * 3 * (10)² = 150 J.

Correct Answer: B — 300 J

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Q. A 3 kg object is moving with a speed of 4 m/s. If a net work of 24 J is done on the object, what will be its final speed?

A. 4 m/s
B. 6 m/s
C. 8 m/s
D. 10 m/s

Solution

Initial kinetic energy = 0.5 × m × v^2 = 0.5 × 3 kg × (4 m/s)^2 = 24 J. Final kinetic energy = Initial + Work done = 24 J + 24 J = 48 J. Final speed = √(2 × KE/m) = √(2 × 48 J / 3 kg) = 6.93 m/s.

Correct Answer: C — 8 m/s

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Q. A 3 kg object is moving with a speed of 4 m/s. What is its kinetic energy?

A. 12 J
B. 24 J
C. 36 J
D. 48 J

Solution

Kinetic energy = 0.5mv² = 0.5 * 3 * (4)² = 24 J.

Correct Answer: B — 24 J

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Q. A 3 kg object is moving with a speed of 4 m/s. What is its total mechanical energy?

A. 24 J
B. 32 J
C. 48 J
D. 60 J

Solution

Total mechanical energy = KE + PE. Assuming it is at ground level, PE = 0. KE = 0.5mv² = 0.5 * 3 * (4)² = 24 J.

Correct Answer: B — 32 J

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Q. A 3 kg object is moving with a speed of 5 m/s. What is its kinetic energy?

A. 15 J
B. 25 J
C. 35 J
D. 45 J

Solution

Kinetic energy is given by KE = 0.5mv² = 0.5 * 3 * (5)² = 37.5 J, approximately 35 J.

Correct Answer: B — 25 J

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Q. A 3 kg object is moving with a velocity of 4 m/s. If it comes to a stop, what is the work done by the friction force?

A. -24 J
B. -48 J
C. -12 J
D. -36 J

Solution

Work done by friction = - Kinetic Energy = - (0.5 × 3 kg × (4 m/s)²) = -24 J.

Correct Answer: B — -48 J

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Q. A 3 kg object is moving with a velocity of 4 m/s. What is its kinetic energy?

A. 12 J
B. 24 J
C. 36 J
D. 48 J

Solution

Kinetic Energy = 0.5 × mass × velocity² = 0.5 × 3 kg × (4 m/s)² = 24 J.

Correct Answer: B — 24 J

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Q. A 3 kg object is moving with a velocity of 4 m/s. What is its momentum?

A. 6 kg·m/s
B. 12 kg·m/s
C. 9 kg·m/s
D. 15 kg·m/s

Solution

Momentum = mass × velocity = 3 kg × 4 m/s = 12 kg·m/s.

Correct Answer: B — 12 kg·m/s

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Q. A 3 kg object is moving with a velocity of 6 m/s. What is its kinetic energy?

A. 54 J
B. 36 J
C. 18 J
D. 72 J

Solution

Kinetic Energy (KE) = 1/2 * m * v^2 = 1/2 * 3 * (6^2) = 54 J

Correct Answer: B — 36 J

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Q. A 3 kg object is pushed with a force of 12 N over a distance of 4 m. If the object starts from rest, what is its final speed? (Assume no friction)

A. 2 m/s
B. 3 m/s
C. 4 m/s
D. 5 m/s

Solution

Work done = Force × Distance = 12 N × 4 m = 48 J. Kinetic energy = 0.5 × mass × v²; 48 J = 0.5 × 3 kg × v²; v² = 32; v = 4 m/s.

Correct Answer: C — 4 m/s

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Q. A 3 kg object is pushed with a force of 12 N over a distance of 4 m. What is the net work done if friction does 8 J of work?

A. 28 J
B. 32 J
C. 36 J
D. 40 J

Solution

Net work done = Work done by force - Work done against friction = (12 N × 4 m) - 8 J = 48 J - 8 J = 40 J.

Correct Answer: B — 32 J

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Q. A 3 kg object is pushed with a force of 15 N over a distance of 4 m. If the object experiences a frictional force of 3 N, what is the net work done on the object?

A. 48 J
B. 60 J
C. 72 J
D. 84 J

Solution

Net force = Applied force - Friction = 15 N - 3 N = 12 N. Work done = Net force × Distance = 12 N × 4 m = 48 J.

Correct Answer: B — 60 J

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Q. A 3 kg object is pushed with a force of 15 N over a distance of 4 m. What is the work done on the object?

A. 30 J
B. 45 J
C. 60 J
D. 75 J

Solution

Work done = Force × Distance = 15 N × 4 m = 60 J.

Correct Answer: C — 60 J

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Q. A 4 kg object is lifted to a height of 3 m. What is the change in gravitational potential energy?

A. 12 J
B. 24 J
C. 36 J
D. 48 J

Solution

Change in potential energy = mgh = 4 kg × 9.8 m/s² × 3 m = 117.6 J.

Correct Answer: B — 24 J

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Q. A 4 kg object is lifted to a height of 3 m. What is the increase in gravitational potential energy?

A. 12 J
B. 24 J
C. 36 J
D. 48 J

Solution

Increase in potential energy = mgh = 4 kg × 9.8 m/s² × 3 m = 117.6 J.

Correct Answer: B — 24 J

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Q. A 4 kg object is lifted to a height of 3 m. What is the increase in gravitational potential energy? (g = 9.8 m/s²)

A. 117.6 J
B. 117 J
C. 120 J
D. 150 J

Solution

Potential energy increase = mgh = 4 kg × 9.8 m/s² × 3 m = 117.6 J.

Correct Answer: A — 117.6 J

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Q. A 4 kg object is moving with a speed of 5 m/s. If it comes to rest, what is the work done by friction?

A. 50 J
B. 75 J
C. 100 J
D. 125 J

Solution

Work done = change in kinetic energy = 0 - 0.5 × 4 kg × (5 m/s)² = -50 J.

Correct Answer: C — 100 J

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Q. A 4 kg object is moving with a speed of 5 m/s. What is its kinetic energy?

A. 10 J
B. 20 J
C. 50 J
D. 100 J

Solution

Kinetic energy = 0.5 × m × v² = 0.5 × 4 kg × (5 m/s)² = 50 J.

Correct Answer: C — 50 J

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Q. A 4 kg object is moving with a speed of 5 m/s. What is the total mechanical energy if it is at a height of 2 m?

A. 50 J
B. 60 J
C. 70 J
D. 80 J

Solution

Total mechanical energy = Kinetic energy + Potential energy = 0.5 × 4 kg × (5 m/s)² + 4 kg × 9.8 m/s² × 2 m = 50 J + 78.4 J = 128.4 J.

Correct Answer: C — 70 J

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Q. A 4 kg object is moving with a velocity of 2 m/s. What is its kinetic energy?

A. 8 J
B. 4 J
C. 16 J
D. 2 J

Solution

Kinetic Energy (KE) = 1/2 * m * v^2 = 1/2 * 4 * (2^2) = 8 J

Correct Answer: A — 8 J

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Q. A 4 kg object is pushed with a force of 20 N over a distance of 3 m. If the object starts from rest, what is its final speed? (Assume no friction)

A. 2 m/s
B. 3 m/s
C. 4 m/s
D. 5 m/s

Solution

Work done = Force × Distance = 20 N × 3 m = 60 J. Kinetic energy = 0.5 × m × v². 60 J = 0.5 × 4 kg × v². v² = 30, v = √30 ≈ 5.48 m/s.

Correct Answer: C — 4 m/s

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Q. A 4 kg object is pushed with a force of 20 N over a distance of 3 m. If the object starts from rest, what is its final speed?

A. 2 m/s
B. 3 m/s
C. 4 m/s
D. 5 m/s

Solution

Work done = Force × Distance = 20 N × 3 m = 60 J. K.E = 0.5 × m × v², 60 J = 0.5 × 4 kg × v², v = 3.87 m/s.

Correct Answer: C — 4 m/s

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Q. A 5 kg object is dropped from a height of 10 m. What is the total mechanical energy just before it hits the ground?

A. 0 J
B. 50 J
C. 100 J
D. 200 J

Solution

Total mechanical energy is conserved. At height, PE = mgh = 5 * 9.8 * 10 = 490 J. Just before hitting the ground, total energy = 490 J.

Correct Answer: C — 100 J

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Showing 61 to 90 of 252 (9 Pages)

Work, Energy & Power

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