Newton's Laws for Competitive Exam Success

Newtons Laws

Q. A force of 15 N is applied to a 3 kg object. What is the object's acceleration?

A. 3 m/s²
B. 5 m/s²
C. 7 m/s²
D. 10 m/s²

Solution

Using F = ma, acceleration a = F/m = 15 N / 3 kg = 5 m/s².

Correct Answer: B — 5 m/s²

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Q. A force of 15 N is applied to a 3 kg object. What is the resulting acceleration?

A. 3 m/s²
B. 5 m/s²
C. 7 m/s²
D. 10 m/s²

Solution

Using F = ma, we find a = F/m = 15 N / 3 kg = 5 m/s².

Correct Answer: B — 5 m/s²

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Q. A force of 15 N is applied to a 5 kg object. What is the object's acceleration?

A. 3 m/s²
B. 2 m/s²
C. 1 m/s²
D. 4 m/s²

Solution

Using F = ma, acceleration a = F/m = 15 N / 5 kg = 3 m/s².

Correct Answer: A — 3 m/s²

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Q. A force of 30 N is applied to a 5 kg object. What is the object's acceleration?

A. 3 m/s²
B. 6 m/s²
C. 9 m/s²
D. 12 m/s²

Solution

Using F = ma, a = F/m = 30 N / 5 kg = 6 m/s².

Correct Answer: B — 6 m/s²

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Q. According to Newton's third law, if object A exerts a force on object B, what does object B do?

A. Exerts a greater force on A
B. Exerts an equal and opposite force on A
C. Exerts no force
D. Exerts a lesser force on A

Solution

Newton's third law states that for every action, there is an equal and opposite reaction.

Correct Answer: B — Exerts an equal and opposite force on A

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Q. An object is in equilibrium. If two forces of 10 N and 15 N act on it in opposite directions, what is the net force?

A. 5 N
B. 10 N
C. 15 N
D. 0 N

Solution

In equilibrium, the net force is zero. The forces cancel each other out: 15 N - 10 N = 5 N.

Correct Answer: A — 5 N

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Q. An object is in equilibrium. What can be said about the net force acting on it?

A. It is zero
B. It is equal to its weight
C. It is equal to the applied force
D. It is maximum

Solution

For an object in equilibrium, the net force acting on it must be zero.

Correct Answer: A — It is zero

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Q. If a 10 kg object is in free fall, what is the force acting on it due to gravity?

A. 10 N
B. 20 N
C. 30 N
D. 40 N

Solution

The force due to gravity is F = mg = 10 kg * 9.8 m/s² = 98 N, which rounds to 100 N.

Correct Answer: B — 20 N

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Q. If a 10 kg object is pulled with a force of 30 N, what is its acceleration?

A. 1 m/s²
B. 2 m/s²
C. 3 m/s²
D. 4 m/s²

Solution

Using F = ma, acceleration a = F/m = 30 N / 10 kg = 3 m/s².

Correct Answer: C — 3 m/s²

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Q. If a 10 kg object is pulled with a force of 50 N, what is its acceleration?

A. 2 m/s²
B. 5 m/s²
C. 10 m/s²
D. 20 m/s²

Solution

Using F = ma, a = F/m = 50 N / 10 kg = 5 m/s².

Correct Answer: B — 5 m/s²

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Q. If a 10 kg object is subjected to a net force of 30 N, what will be its acceleration?

A. 3 m/s²
B. 0.3 m/s²
C. 30 m/s²
D. 300 m/s²

Solution

Using F = ma, acceleration a = F/m = 30 N / 10 kg = 3 m/s².

Correct Answer: A — 3 m/s²

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Q. If a 12 kg object is moving with a constant velocity, what can be said about the net force acting on it?

A. It is zero
B. It is equal to its weight
C. It is equal to the applied force
D. It is increasing

Solution

An object moving with constant velocity has a net force of zero according to Newton's first law.

Correct Answer: A — It is zero

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Q. If a 12 kg object is pushed with a force of 48 N, what is the acceleration of the object?

A. 2 m/s²
B. 4 m/s²
C. 6 m/s²
D. 8 m/s²

Solution

Using F = ma, acceleration a = F/m = 48 N / 12 kg = 4 m/s².

Correct Answer: B — 4 m/s²

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Q. If a 2 kg object is acted upon by a net force of 6 N, what is the object's acceleration?

A. 2 m/s²
B. 3 m/s²
C. 4 m/s²
D. 5 m/s²

Solution

Using F = ma, we find a = F/m = 6 N / 2 kg = 3 m/s².

Correct Answer: B — 3 m/s²

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Q. If a 2 kg object is moving with a velocity of 3 m/s and a force of 6 N is applied in the opposite direction, what will be its final velocity after 2 seconds?

A. 0 m/s
B. 1 m/s
C. 2 m/s
D. 3 m/s

Solution

Net force = -6 N, acceleration = F/m = -6 N / 2 kg = -3 m/s². Final velocity = initial velocity + at = 3 m/s + (-3 m/s² * 2 s) = 0 m/s.

Correct Answer: B — 1 m/s

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Q. If a 2 kg object is pulled with a force of 10 N and experiences a frictional force of 4 N, what is its acceleration?

A. 3 m/s²
B. 5 m/s²
C. 2 m/s²
D. 1 m/s²

Solution

Net force = applied force - friction = 10 N - 4 N = 6 N. Acceleration a = F/m = 6 N / 2 kg = 3 m/s².

Correct Answer: A — 3 m/s²

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Q. If a 3 kg object is in free fall, what is the force acting on it due to gravity?

A. 3 N
B. 9 N
C. 30 N
D. None of the above

Solution

Force due to gravity F = mg = 3 kg * 9.8 m/s² = 29.4 N, approximately 9 N for simplification.

Correct Answer: B — 9 N

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Q. If a 4 kg object is acted upon by a net force of 16 N, what is its acceleration?

A. 2 m/s²
B. 3 m/s²
C. 4 m/s²
D. 5 m/s²

Solution

Using F = ma, we have a = F/m = 16 N / 4 kg = 4 m/s².

Correct Answer: C — 4 m/s²

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Q. If a 4 kg object is at rest and a net force of 8 N is applied, what will be its velocity after 2 seconds?

A. 4 m/s
B. 2 m/s
C. 1 m/s
D. 0 m/s

Solution

Using F = ma, a = F/m = 8 N / 4 kg = 2 m/s². Velocity after 2 seconds = a * t = 2 m/s² * 2 s = 4 m/s.

Correct Answer: B — 2 m/s

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Q. If a 4 kg object is moving with a constant velocity, what can be said about the net force acting on it?

A. It is zero
B. It is equal to its weight
C. It is equal to the applied force
D. It is maximum

Solution

According to Newton's first law, if an object is moving with constant velocity, the net force acting on it is zero.

Correct Answer: A — It is zero

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Q. If a 5 kg object is in free fall, what is the force acting on it due to gravity?

A. 5 N
B. 10 N
C. 50 N
D. 15 N

Solution

The force due to gravity F = mg = 5 kg * 10 m/s² = 50 N.

Correct Answer: C — 50 N

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Q. If a 5 kg object is subjected to a force of 20 N, what is its acceleration?

A. 2 m/s²
B. 4 m/s²
C. 5 m/s²
D. 10 m/s²

Solution

Using F = ma, acceleration a = F/m = 20 N / 5 kg = 4 m/s².

Correct Answer: B — 4 m/s²

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Q. If a 6 kg object is subjected to a net force of 24 N, what is its acceleration?

A. 4 m/s²
B. 6 m/s²
C. 8 m/s²
D. 10 m/s²

Solution

Using F = ma, acceleration a = F/m = 24 N / 6 kg = 4 m/s².

Correct Answer: A — 4 m/s²

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Q. If a car accelerates from rest to 20 m/s in 5 seconds, what is its acceleration?

A. 2 m/s²
B. 4 m/s²
C. 5 m/s²
D. 10 m/s²

Solution

Acceleration a = (final velocity - initial velocity) / time = (20 m/s - 0) / 5 s = 4 m/s².

Correct Answer: B — 4 m/s²

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Q. If a force of 12 N is applied to a 4 kg object, what is the resulting acceleration?

A. 2 m/s²
B. 3 m/s²
C. 4 m/s²
D. 5 m/s²

Solution

Using F = ma, we find a = F/m = 12 N / 4 kg = 3 m/s².

Correct Answer: B — 3 m/s²

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Q. If two forces of 10 N and 15 N act in the same direction on an object, what is the resultant force?

A. 5 N
B. 10 N
C. 15 N
D. 25 N

Solution

The resultant force is the sum of the two forces: 10 N + 15 N = 25 N.

Correct Answer: D — 25 N

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Q. If two forces of 10 N and 5 N act in the same direction on an object, what is the net force?

A. 15 N
B. 5 N
C. 10 N
D. 20 N

Solution

The net force is the sum of the forces: 10 N + 5 N = 15 N.

Correct Answer: A — 15 N

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Q. If two forces of 5 N and 10 N act in the same direction on an object, what is the net force?

A. 15 N
B. 5 N
C. 10 N
D. 0 N

Solution

Net force = 5 N + 10 N = 15 N.

Correct Answer: A — 15 N

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Q. What happens to the acceleration of an object if the net force acting on it is doubled while its mass remains constant?

A. It doubles
B. It halves
C. It remains the same
D. It quadruples

Solution

According to F = ma, if the force is doubled, the acceleration also doubles.

Correct Answer: A — It doubles

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Q. What is the force required to keep a 15 kg object moving at a constant velocity?

A. 0 N
B. 15 N
C. 150 N
D. None of the above

Solution

According to Newton's first law, no net force is required to maintain constant velocity.

Correct Answer: A — 0 N

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Newtons Laws

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