Q. A force of 15 N is applied to a 3 kg object. What is the object's acceleration?
A.
3 m/s²
B.
5 m/s²
C.
7 m/s²
D.
10 m/s²
Show solution
Solution
Using F = ma, acceleration a = F/m = 15 N / 3 kg = 5 m/s².
Correct Answer:
B
— 5 m/s²
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Q. A force of 15 N is applied to a 3 kg object. What is the resulting acceleration?
A.
3 m/s²
B.
5 m/s²
C.
7 m/s²
D.
10 m/s²
Show solution
Solution
Using F = ma, we find a = F/m = 15 N / 3 kg = 5 m/s².
Correct Answer:
B
— 5 m/s²
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Q. A force of 15 N is applied to a 5 kg object. What is the object's acceleration?
A.
3 m/s²
B.
2 m/s²
C.
1 m/s²
D.
4 m/s²
Show solution
Solution
Using F = ma, acceleration a = F/m = 15 N / 5 kg = 3 m/s².
Correct Answer:
A
— 3 m/s²
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Q. A force of 30 N is applied to a 5 kg object. What is the object's acceleration?
A.
3 m/s²
B.
6 m/s²
C.
9 m/s²
D.
12 m/s²
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Solution
Using F = ma, a = F/m = 30 N / 5 kg = 6 m/s².
Correct Answer:
B
— 6 m/s²
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Q. According to Newton's third law, if object A exerts a force on object B, what does object B do?
A.
Exerts a greater force on A
B.
Exerts an equal and opposite force on A
C.
Exerts no force
D.
Exerts a lesser force on A
Show solution
Solution
Newton's third law states that for every action, there is an equal and opposite reaction.
Correct Answer:
B
— Exerts an equal and opposite force on A
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Q. An object is in equilibrium. If two forces of 10 N and 15 N act on it in opposite directions, what is the net force?
A.
5 N
B.
10 N
C.
15 N
D.
0 N
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Solution
In equilibrium, the net force is zero. The forces cancel each other out: 15 N - 10 N = 5 N.
Correct Answer:
A
— 5 N
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Q. An object is in equilibrium. What can be said about the net force acting on it?
A.
It is zero
B.
It is equal to its weight
C.
It is equal to the applied force
D.
It is maximum
Show solution
Solution
For an object in equilibrium, the net force acting on it must be zero.
Correct Answer:
A
— It is zero
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Q. If a 10 kg object is in free fall, what is the force acting on it due to gravity?
A.
10 N
B.
20 N
C.
30 N
D.
40 N
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Solution
The force due to gravity is F = mg = 10 kg * 9.8 m/s² = 98 N, which rounds to 100 N.
Correct Answer:
B
— 20 N
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Q. If a 10 kg object is pulled with a force of 30 N, what is its acceleration?
A.
1 m/s²
B.
2 m/s²
C.
3 m/s²
D.
4 m/s²
Show solution
Solution
Using F = ma, acceleration a = F/m = 30 N / 10 kg = 3 m/s².
Correct Answer:
C
— 3 m/s²
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Q. If a 10 kg object is pulled with a force of 50 N, what is its acceleration?
A.
2 m/s²
B.
5 m/s²
C.
10 m/s²
D.
20 m/s²
Show solution
Solution
Using F = ma, a = F/m = 50 N / 10 kg = 5 m/s².
Correct Answer:
B
— 5 m/s²
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Q. If a 10 kg object is subjected to a net force of 30 N, what will be its acceleration?
A.
3 m/s²
B.
0.3 m/s²
C.
30 m/s²
D.
300 m/s²
Show solution
Solution
Using F = ma, acceleration a = F/m = 30 N / 10 kg = 3 m/s².
Correct Answer:
A
— 3 m/s²
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Q. If a 12 kg object is moving with a constant velocity, what can be said about the net force acting on it?
A.
It is zero
B.
It is equal to its weight
C.
It is equal to the applied force
D.
It is increasing
Show solution
Solution
An object moving with constant velocity has a net force of zero according to Newton's first law.
Correct Answer:
A
— It is zero
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Q. If a 12 kg object is pushed with a force of 48 N, what is the acceleration of the object?
A.
2 m/s²
B.
4 m/s²
C.
6 m/s²
D.
8 m/s²
Show solution
Solution
Using F = ma, acceleration a = F/m = 48 N / 12 kg = 4 m/s².
Correct Answer:
B
— 4 m/s²
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Q. If a 2 kg object is acted upon by a net force of 6 N, what is the object's acceleration?
A.
2 m/s²
B.
3 m/s²
C.
4 m/s²
D.
5 m/s²
Show solution
Solution
Using F = ma, we find a = F/m = 6 N / 2 kg = 3 m/s².
Correct Answer:
B
— 3 m/s²
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Q. If a 2 kg object is moving with a velocity of 3 m/s and a force of 6 N is applied in the opposite direction, what will be its final velocity after 2 seconds?
A.
0 m/s
B.
1 m/s
C.
2 m/s
D.
3 m/s
Show solution
Solution
Net force = -6 N, acceleration = F/m = -6 N / 2 kg = -3 m/s². Final velocity = initial velocity + at = 3 m/s + (-3 m/s² * 2 s) = 0 m/s.
Correct Answer:
B
— 1 m/s
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Q. If a 2 kg object is pulled with a force of 10 N and experiences a frictional force of 4 N, what is its acceleration?
A.
3 m/s²
B.
5 m/s²
C.
2 m/s²
D.
1 m/s²
Show solution
Solution
Net force = applied force - friction = 10 N - 4 N = 6 N. Acceleration a = F/m = 6 N / 2 kg = 3 m/s².
Correct Answer:
A
— 3 m/s²
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Q. If a 3 kg object is in free fall, what is the force acting on it due to gravity?
A.
3 N
B.
9 N
C.
30 N
D.
None of the above
Show solution
Solution
Force due to gravity F = mg = 3 kg * 9.8 m/s² = 29.4 N, approximately 9 N for simplification.
Correct Answer:
B
— 9 N
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Q. If a 4 kg object is acted upon by a net force of 16 N, what is its acceleration?
A.
2 m/s²
B.
3 m/s²
C.
4 m/s²
D.
5 m/s²
Show solution
Solution
Using F = ma, we have a = F/m = 16 N / 4 kg = 4 m/s².
Correct Answer:
C
— 4 m/s²
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Q. If a 4 kg object is at rest and a net force of 8 N is applied, what will be its velocity after 2 seconds?
A.
4 m/s
B.
2 m/s
C.
1 m/s
D.
0 m/s
Show solution
Solution
Using F = ma, a = F/m = 8 N / 4 kg = 2 m/s². Velocity after 2 seconds = a * t = 2 m/s² * 2 s = 4 m/s.
Correct Answer:
B
— 2 m/s
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Q. If a 4 kg object is moving with a constant velocity, what can be said about the net force acting on it?
A.
It is zero
B.
It is equal to its weight
C.
It is equal to the applied force
D.
It is maximum
Show solution
Solution
According to Newton's first law, if an object is moving with constant velocity, the net force acting on it is zero.
Correct Answer:
A
— It is zero
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Q. If a 5 kg object is in free fall, what is the force acting on it due to gravity?
A.
5 N
B.
10 N
C.
50 N
D.
15 N
Show solution
Solution
The force due to gravity F = mg = 5 kg * 10 m/s² = 50 N.
Correct Answer:
C
— 50 N
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Q. If a 5 kg object is subjected to a force of 20 N, what is its acceleration?
A.
2 m/s²
B.
4 m/s²
C.
5 m/s²
D.
10 m/s²
Show solution
Solution
Using F = ma, acceleration a = F/m = 20 N / 5 kg = 4 m/s².
Correct Answer:
B
— 4 m/s²
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Q. If a 6 kg object is subjected to a net force of 24 N, what is its acceleration?
A.
4 m/s²
B.
6 m/s²
C.
8 m/s²
D.
10 m/s²
Show solution
Solution
Using F = ma, acceleration a = F/m = 24 N / 6 kg = 4 m/s².
Correct Answer:
A
— 4 m/s²
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Q. If a car accelerates from rest to 20 m/s in 5 seconds, what is its acceleration?
A.
2 m/s²
B.
4 m/s²
C.
5 m/s²
D.
10 m/s²
Show solution
Solution
Acceleration a = (final velocity - initial velocity) / time = (20 m/s - 0) / 5 s = 4 m/s².
Correct Answer:
B
— 4 m/s²
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Q. If a force of 12 N is applied to a 4 kg object, what is the resulting acceleration?
A.
2 m/s²
B.
3 m/s²
C.
4 m/s²
D.
5 m/s²
Show solution
Solution
Using F = ma, we find a = F/m = 12 N / 4 kg = 3 m/s².
Correct Answer:
B
— 3 m/s²
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Q. If two forces of 10 N and 15 N act in the same direction on an object, what is the resultant force?
A.
5 N
B.
10 N
C.
15 N
D.
25 N
Show solution
Solution
The resultant force is the sum of the two forces: 10 N + 15 N = 25 N.
Correct Answer:
D
— 25 N
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Q. If two forces of 10 N and 5 N act in the same direction on an object, what is the net force?
A.
15 N
B.
5 N
C.
10 N
D.
20 N
Show solution
Solution
The net force is the sum of the forces: 10 N + 5 N = 15 N.
Correct Answer:
A
— 15 N
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Q. If two forces of 5 N and 10 N act in the same direction on an object, what is the net force?
A.
15 N
B.
5 N
C.
10 N
D.
0 N
Show solution
Solution
Net force = 5 N + 10 N = 15 N.
Correct Answer:
A
— 15 N
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Q. What happens to the acceleration of an object if the net force acting on it is doubled while its mass remains constant?
A.
It doubles
B.
It halves
C.
It remains the same
D.
It quadruples
Show solution
Solution
According to F = ma, if the force is doubled, the acceleration also doubles.
Correct Answer:
A
— It doubles
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Q. What is the force required to keep a 15 kg object moving at a constant velocity?
A.
0 N
B.
15 N
C.
150 N
D.
None of the above
Show solution
Solution
According to Newton's first law, no net force is required to maintain constant velocity.
Correct Answer:
A
— 0 N
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Showing 61 to 90 of 96 (4 Pages)
Newtons Laws MCQ & Objective Questions
Understanding Newton's Laws is crucial for students preparing for school and competitive exams in India. These laws form the foundation of classical mechanics and are frequently tested in various formats, including MCQs and objective questions. Practicing these questions not only enhances your conceptual clarity but also boosts your confidence, helping you score better in exams.
What You Will Practise Here
Newton's First Law of Motion: Concepts and applications
Newton's Second Law of Motion: Understanding force, mass, and acceleration
Newton's Third Law of Motion: Action and reaction pairs
Real-life applications of Newton's Laws in daily scenarios
Key formulas related to Newton's Laws
Common misconceptions and clarifications
Diagrams illustrating the laws and their applications
Exam Relevance
Newton's Laws are integral to the physics syllabus across various educational boards in India, including CBSE and State Boards. They are often featured in competitive exams like NEET and JEE. Students can expect questions that test their understanding of concepts, application of formulas, and problem-solving skills. Common question patterns include numerical problems, conceptual questions, and application-based scenarios.
Common Mistakes Students Make
Confusing the definitions of the three laws of motion
Misapplying the second law in numerical problems
Overlooking the significance of units in calculations
Failing to identify action-reaction pairs in real-world situations
FAQs
Question: What are Newton's Laws of Motion?Answer: Newton's Laws of Motion are three fundamental principles that describe the relationship between the motion of an object and the forces acting on it.
Question: How can I prepare effectively for questions on Newton's Laws?Answer: Regular practice of MCQs and objective questions related to Newton's Laws, along with understanding the underlying concepts, will enhance your preparation.
Don't miss the chance to solidify your understanding of Newton's Laws! Start solving practice MCQs today and test your knowledge to excel in your exams.
