Arithmetic Aptitude for Competitive Exam Success

Arithmetic Aptitude

Approximation & Simplification Banking Awareness Cloze Test Data Interpretation - Caselets Data Sufficiency - Banking Type Error Detection - Grammar Financial Markets Basics Mixtures and Alligations Mixtures and Alligations - Common Mistakes Mixtures and Alligations - Practice Problems with Solutions Mixtures and Alligations - Shortcuts and Tricks Number Series Para Jumbles Problems on Trains and Boats Problems on Trains and Boats - Common Mistakes Problems on Trains and Boats - Practice Problems with Solutions Problems on Trains and Boats - Shortcuts and Tricks Profit and Loss Problems Profit and Loss Problems - Common Mistakes Profit and Loss Problems - Practice Problems with Solutions Profit and Loss Problems - Shortcuts and Tricks Quadratic Equations for Banking Ratio, Proportion and Partnership Ratio, Proportion and Partnership - Common Mistakes Ratio, Proportion and Partnership - Practice Problems with Solutions Ratio, Proportion and Partnership - Shortcuts and Tricks Reading Comprehension - Banking Level Sentence Improvement Simple and Compound Interest Simple and Compound Interest - Common Mistakes Simple and Compound Interest - Practice Problems with Solutions Simple and Compound Interest - Shortcuts and Tricks Time and Work Problems Time and Work Problems - Common Mistakes Time and Work Problems - Practice Problems with Solutions Time and Work Problems - Shortcuts and Tricks Time, Speed and Distance Time, Speed and Distance - Common Mistakes Time, Speed and Distance - Practice Problems with Solutions Time, Speed and Distance - Shortcuts and Tricks

Q. A shopkeeper bought an article for $200 and sold it for $250. What is the percentage profit?

A. 20%
B. 25%
C. 30%
D. 15%

Solution

Profit = Selling Price - Cost Price = 250 - 200 = 50. Percentage Profit = (Profit/Cost Price) * 100 = (50/200) * 100 = 25%.

Correct Answer: B — 25%

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Q. A shopkeeper bought an article for $200 and sold it for $250. What is the profit percentage?

A. 20%
B. 25%
C. 30%
D. 15%

Solution

Profit = Selling Price - Cost Price = 250 - 200 = 50. Profit Percentage = (Profit/Cost Price) * 100 = (50/200) * 100 = 25%.

Correct Answer: B — 25%

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Q. A shopkeeper marks a price of $200 on an item and offers a discount of 15%. What is the selling price?

A. $170
B. $180
C. $190
D. $200

Solution

Selling Price = Marked Price - Discount = 200 - (15/100 * 200) = 200 - 30 = $170.

Correct Answer: B — $180

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Q. A shopkeeper marks a price of $200 on an item and offers a discount of 25%. What is the selling price?

A. $150
B. $160
C. $140
D. $170

Solution

Discount = 25% of 200 = 50. Selling price = 200 - 50 = 150.

Correct Answer: A — $150

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Q. A shopkeeper marks a price of $500 on an item and offers a discount of 10%. What is the selling price?

A. $450
B. $475
C. $400
D. $425

Solution

Discount = 10% of 500 = 50. Selling Price = Marked Price - Discount = 500 - 50 = 450.

Correct Answer: B — $475

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Q. A shopkeeper sells a mixture of two types of nuts at a profit of 20%. If the cost price of the mixture is $50, what is the selling price?

A. $60
B. $55
C. $65
D. $70

Solution

Selling Price = Cost Price + Profit = 50 + (20% of 50) = 50 + 10 = $60.

Correct Answer: A — $60

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Q. A solution contains 25% salt. If 8 liters of the solution is removed and replaced with water, what is the new concentration of salt in the solution?

A. 20%
B. 25%
C. 30%
D. 15%

Solution

Salt removed = 25% of 8L = 2L. New solution = 32L, new salt % = (25L / 32L) * 100 = 20%.

Correct Answer: A — 20%

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Q. A solution contains 40% sugar. If 5 liters of the solution is removed and replaced with water, what is the new percentage of sugar if the total volume remains the same?

A. 30%
B. 35%
C. 40%
D. 45%

Solution

Sugar removed = 40% of 5L = 2L. Remaining sugar = 40L - 2L = 38L. New percentage = (38/50) * 100 = 76%.

Correct Answer: B — 35%

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Q. A solution contains 60% sugar. If 15 liters of the solution is diluted with water to make it 40% sugar, how much water is added?

A. 5 liters
B. 10 liters
C. 15 liters
D. 20 liters

Solution

Let x be the amount of water added. 0.6 * 15 = 0.4 * (15 + x). Solving gives x = 15 liters.

Correct Answer: C — 15 liters

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Q. A student scored 80% in Mathematics and 70% in Science. If both subjects have equal weightage, what is the average percentage?

A. 75%
B. 76%
C. 77%
D. 78%

Solution

Average = (80 + 70) / 2 = 75%.

Correct Answer: A — 75%

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Q. A sum of $1000 is invested at a compound interest rate of 5% per annum. What will be the amount after 4 years?

A. $1200
B. $1215.51
C. $1250
D. $1300

Solution

Total Amount = P(1 + r/100)^n = 1000(1 + 0.05)^4 = 1000(1.21550625) = $1215.51.

Correct Answer: B — $1215.51

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Q. A sum of $1500 is invested at a simple interest rate of 4% per annum. What will be the total amount after 5 years?

A. $1800
B. $1600
C. $1700
D. $1500

Solution

Simple Interest = 1500 * 0.04 * 5 = $300. Total Amount = 1500 + 300 = $1800.

Correct Answer: B — $1600

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Q. A sum of $800 is invested at a compound interest rate of 5% per annum. What will be the amount after 2 years?

A. $882
B. $840
C. $900
D. $850

Solution

Amount = Principal * (1 + Rate/100)^Time = 800 * (1 + 0.05)^2 = 800 * 1.1025 = $882

Correct Answer: A — $882

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Q. A sum of $800 is invested at a rate of 5% per annum for 3 years. What will be the total amount at the end of 3 years?

A. $920
B. $840
C. $860
D. $880

Solution

Total Amount = Principal + Simple Interest = 800 + (800 * 5 * 3) / 100 = 800 + 120 = $920.

Correct Answer: B — $840

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Q. A sum of $800 is invested at a rate of 5% per annum. What will be the total amount after 3 years using simple interest?

A. $920
B. $840
C. $860
D. $880

Solution

Simple Interest = Principal * Rate * Time = 800 * 0.05 * 3 = $120. Total Amount = Principal + Interest = 800 + 120 = $920.

Correct Answer: D — $880

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Q. A trader bought 100 kg of sugar at $2 per kg and sold it at $2.50 per kg. What is the profit percentage?

A. 20%
B. 25%
C. 30%
D. 15%

Solution

Cost Price = 100 * 2 = 200. Selling Price = 100 * 2.5 = 250. Profit = 250 - 200 = 50. Profit Percentage = (50/200) * 100 = 25%.

Correct Answer: B — 25%

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Q. A trader bought 100 shares at $20 each and sold them at $25 each. What is the total profit?

A. $300
B. $400
C. $500
D. $600

Solution

Total Profit = (Selling Price - Cost Price) * Number of Shares = (25 - 20) * 100 = $500

Correct Answer: C — $500

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Q. A trader bought two articles for $500 each and sold them for $600 and $400 respectively. What is his overall profit or loss?

A. $0
B. $100 profit
C. $100 loss
D. $200 profit

Solution

Total Cost Price = 500 + 500 = 1000. Total Selling Price = 600 + 400 = 1000. Overall Profit/Loss = 1000 - 1000 = $0.

Correct Answer: B — $100 profit

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Q. A trader marks his goods 25% above the cost price. If he sells them at a discount of 10%, what is his profit percentage?

A. 12.5%
B. 15%
C. 10%
D. 20%

Solution

Let Cost Price = 100. Marked Price = 125. Selling Price = 90% of 125 = 112.5. Profit = 112.5 - 100 = 12.5. Profit Percentage = (12.5/100) * 100 = 12.5%.

Correct Answer: A — 12.5%

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Q. A train and a boat start from the same point and travel in opposite directions. If the train travels at 80 km/h and the boat at 20 km/h, how far apart will they be after 2 hours?

A. 200 km
B. 160 km
C. 140 km
D. 120 km

Solution

Distance covered by train = 80 km/h * 2 hours = 160 km. Distance covered by boat = 20 km/h * 2 hours = 40 km. Total distance apart = 160 km + 40 km = 200 km.

Correct Answer: A — 200 km

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Q. A train covers a distance of 180 km at a speed of 60 km/h. How long does it take?

A. 2 hours
B. 2.5 hours
C. 3 hours
D. 3.5 hours

Solution

Time = Distance / Speed = 180 km / 60 km/h = 3 hours.

Correct Answer: C — 3 hours

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Q. A train covers a distance of 300 km in 5 hours. What is its speed?

A. 50 km/h
B. 60 km/h
C. 70 km/h
D. 80 km/h

Solution

Speed = Distance / Time = 300 km / 5 hours = 60 km/h.

Correct Answer: B — 60 km/h

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Q. A train travels 120 km at a speed of 60 km/h. How long does it take to cover this distance?

A. 1 hour
B. 2 hours
C. 3 hours
D. 4 hours

Solution

Time = Distance / Speed = 120 km / 60 km/h = 2 hours.

Correct Answer: B — 2 hours

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Q. A train travels 150 km in 3 hours. If it increases its speed by 20 km/h, how long will it take to cover the same distance?

A. 1 hour
B. 2 hours
C. 3 hours
D. 4 hours

Solution

Original speed = 150 km / 3 hours = 50 km/h. New speed = 50 km/h + 20 km/h = 70 km/h. Time = Distance / Speed = 150 km / 70 km/h = 2.14 hours.

Correct Answer: A — 1 hour

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Q. A train travels 180 km at a speed of 60 km/h. How long does it take to complete the journey?

A. 2 hours
B. 3 hours
C. 4 hours
D. 5 hours

Solution

Time = Distance / Speed = 180 km / 60 km/h = 3 hours.

Correct Answer: B — 3 hours

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Q. A train travels 300 km at a speed of 75 km/h. How long does it take?

A. 3 hours
B. 4 hours
C. 5 hours
D. 6 hours

Solution

Time = Distance / Speed = 300 km / 75 km/h = 4 hours.

Correct Answer: C — 5 hours

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Q. A vehicle travels 150 km in 2.5 hours. What is its average speed?

A. 55 km/h
B. 60 km/h
C. 65 km/h
D. 70 km/h

Solution

Average Speed = Total Distance / Total Time = 150 km / 2.5 h = 60 km/h

Correct Answer: B — 60 km/h

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Q. A vehicle travels 240 km in 4 hours. What is its speed?

A. 50 km/h
B. 55 km/h
C. 60 km/h
D. 65 km/h

Solution

Speed = Distance / Time = 240 km / 4 h = 60 km/h.

Correct Answer: C — 60 km/h

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Q. A's income is 20% more than B's income. If B's income is $5000, what is A's income?

A. $6000
B. $5500
C. $5000
D. $6500

Solution

A's income = B's income + 20% of B's income = 5000 + 0.2 * 5000 = 5000 + 1000 = $6000.

Correct Answer: A — $6000

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Q. If $1000 is invested at a compound interest rate of 6% per annum, what will be the amount after 2 years?

A. $1123.60
B. $1260
C. $1156.16
D. $1200

Solution

Amount = Principal * (1 + Rate)^Time = 1000 * (1 + 0.06)^2 = 1000 * 1.1236 = $1123.60.

Correct Answer: C — $1156.16

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Arithmetic Aptitude

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