The HCF of 14, 28, and 42 is 14, as it is the largest number that divides all three.

The HCF of 24 and 36 is 6, as it is the largest number that divides both.

The HCF of 56, 98, and 42 is 14, as it is the largest number that divides all three.

The HCF of 81 and 27 is 27, as it is the largest number that divides both.

The LCM of 12, 15, and 20 is 60, as it is the smallest number that is a multiple of all three.

The LCM of 4 and 5 is 20, as it is the smallest number that is a multiple of both.

The LCM of 6 and 8 is 24, as it is the smallest number that is a multiple of both.

The LCM of 6, 8, and 12 is 24, as it is the smallest number that is a multiple of all three.

The LCM of 8, 12, and 15 is 120, as it is the smallest number that is a multiple of all three.

The LCM of 9 and 21 is 63, as it is the smallest number that is a multiple of both.

The product of the roots is c/a = -10/1 = -10.

The product of the roots is c/a = 6/1 = 6.

The product of the roots is given by c/a = 10/1 = 10.

The relationship is HCF * LCM = a * b, which holds for any two integers a and b.

29 divided by 5 is 5 with a remainder of 4.

√(2) * √(8) = √(16) = 4, but simplified is 2√(2).

√(a^2) * √(b^2) = ab.

The sum of the roots is given by -b/a = 5/1 = 5.

The sum of the roots is given by -b/a = 6/1 = 6.

The sum of the roots is given by -b/a = 7/1 = 7.

Using the property (a^m)^n = a^(m*n), we have (3^(2))^(3) = 3^(2*3) = 3^(6).

√(2) * √(8) = √(16) = 4.

(√(2) + √(3))^2 = 2 + 3 + 2√(6) = 5 + 2√(6).

(√(3) + √(2))^2 = 3 + 2 + 2√(6) = 5 + 2√(6).

4^(1/2) = 2, thus 2 * 2 = 4.

4^(1/2) = √(4) = 2.

4^(3/2) = (√4)^3 = 2^3 = 8.

Any non-zero number raised to the power of 0 is 1.

9^(1/2) = 3 and 16^(1/2) = 4, so 3 + 4 = 7.

log4(64) = log4(4^3) = 3.