Q. According to the first law of thermodynamics, what happens to the internal energy of a system when heat is added and work is done by the system?
A.
Increases
B.
Decreases
C.
Remains constant
D.
Cannot be determined
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Solution
The first law states ΔU = Q - W. If heat Q is added and work W is done by the system, the internal energy decreases.
Correct Answer:
B
— Decreases
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Q. According to the kinetic theory of gases, what is the relationship between temperature and the average kinetic energy of gas molecules?
A.
Directly proportional
B.
Inversely proportional
C.
Independent
D.
Exponential
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Solution
The average kinetic energy of gas molecules is directly proportional to the absolute temperature of the gas.
Correct Answer:
A
— Directly proportional
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Q. According to the kinetic theory, what happens to the pressure of a gas if the temperature is doubled while keeping the volume constant?
A.
Pressure remains the same
B.
Pressure doubles
C.
Pressure triples
D.
Pressure halves
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Solution
According to the ideal gas law, if temperature is doubled and volume is constant, pressure also doubles.
Correct Answer:
B
— Pressure doubles
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Q. According to the kinetic theory, what is the relationship between pressure and the number of gas molecules in a container?
A.
Pressure is independent of the number of molecules
B.
Pressure decreases with more molecules
C.
Pressure increases with more molecules
D.
Pressure is inversely proportional to the number of molecules
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Solution
According to the kinetic theory, pressure is directly proportional to the number of gas molecules in a container, assuming temperature and volume are constant.
Correct Answer:
C
— Pressure increases with more molecules
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Q. According to the third law of thermodynamics, what happens as the temperature approaches absolute zero?
A.
Entropy approaches zero
B.
Entropy approaches infinity
C.
Internal energy approaches zero
D.
All molecular motion stops
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Solution
The third law states that as the temperature approaches absolute zero, the entropy of a perfect crystal approaches zero.
Correct Answer:
A
— Entropy approaches zero
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Q. An object is dropped from a height of 80 m. How long will it take to reach the ground? (Assume g = 9.8 m/s²)
A.
2 s
B.
4 s
C.
6 s
D.
8 s
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Solution
Using the formula t = √(2h/g), where h = 80 m and g = 9.8 m/s², we get t = √(2 * 80 / 9.8) ≈ 4.04 s.
Correct Answer:
C
— 6 s
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Q. An object is thrown vertically upward with an initial velocity of 20 m/s. How high will it go before coming to a stop?
A.
10 m
B.
20 m
C.
40 m
D.
50 m
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Solution
Using the formula h = (v²)/(2g), where v = 20 m/s and g = 9.8 m/s², we get h = (20)²/(2 * 9.8) ≈ 20.4 m.
Correct Answer:
C
— 40 m
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Q. An object moves in a straight line with a constant acceleration of 3 m/s². If its initial velocity is 5 m/s, what will be its velocity after 4 seconds?
A.
5 m/s
B.
11 m/s
C.
17 m/s
D.
23 m/s
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Solution
Using the formula v = v_i + at, where v_i = 5 m/s, a = 3 m/s², and t = 4 s, we get v = 5 + (3 * 4) = 17 m/s.
Correct Answer:
C
— 17 m/s
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Q. An object moves with a constant acceleration of 3 m/s². If it starts from rest, what is its velocity after 4 seconds?
A.
6 m/s
B.
9 m/s
C.
12 m/s
D.
15 m/s
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Solution
Using the formula v = u + at, where u = 0, a = 3 m/s², and t = 4 s, we get v = 0 + 3 * 4 = 12 m/s.
Correct Answer:
C
— 12 m/s
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Q. An object with a mass of 4 kg is moving with a velocity of 3 m/s. What is its kinetic energy?
A.
6 J
B.
12 J
C.
24 J
D.
36 J
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Solution
Kinetic Energy = 0.5 × m × v² = 0.5 × 4 kg × (3 m/s)² = 18 J.
Correct Answer:
C
— 24 J
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Q. During the transient response of an RC circuit, what is the behavior of the voltage across the capacitor?
A.
It increases linearly
B.
It decreases exponentially
C.
It increases exponentially
D.
It remains constant
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Solution
During the transient response of an RC circuit, the voltage across the capacitor increases exponentially until it reaches the supply voltage.
Correct Answer:
C
— It increases exponentially
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Q. How much work is done when a force of 25 N moves an object 8 m in the direction of the force?
A.
100 J
B.
150 J
C.
200 J
D.
250 J
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Solution
Work = Force × Distance = 25 N × 8 m = 200 J.
Correct Answer:
C
— 200 J
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Q. How much work is done when a force of 50 N is applied to move an object 2 m horizontally?
A.
100 J
B.
50 J
C.
25 J
D.
200 J
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Solution
Work = Force × Distance = 50 N × 2 m = 100 J.
Correct Answer:
A
— 100 J
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Q. If a 10 kg object experiences an impulse of 30 Ns, what is the change in its velocity?
A.
3 m/s
B.
2 m/s
C.
1 m/s
D.
4 m/s
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Solution
Impulse (J) = mass (m) × change in velocity (Δv) => Δv = J/m = 30 Ns / 10 kg = 3 m/s.
Correct Answer:
A
— 3 m/s
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Q. If a 10 V battery is connected to a 5 Ω resistor, what is the current flowing through the resistor?
A.
2 A
B.
0.5 A
C.
5 A
D.
10 A
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Solution
Using Ohm's law, I = V/R = 10 V / 5 Ω = 2 A.
Correct Answer:
A
— 2 A
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Q. If a 12 V battery is connected to a 3 Ω resistor, what is the current flowing through the circuit?
A.
2 A
B.
3 A
C.
4 A
D.
5 A
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Solution
Using Ohm's law, I = V/R = 12 V / 3 Ω = 4 A.
Correct Answer:
A
— 2 A
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Q. If a 15 kg object is dropped from a height of 20 m, what is its potential energy just before it hits the ground?
A.
300 J
B.
1500 J
C.
600 J
D.
1200 J
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Solution
Potential energy PE = mgh = 15 kg * 9.81 m/s² * 20 m = 2943 J.
Correct Answer:
B
— 1500 J
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Q. If a 2 kg ball is thrown with a velocity of 4 m/s, what is the impulse imparted to the ball?
A.
8 Ns
B.
4 Ns
C.
2 Ns
D.
16 Ns
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Solution
Impulse (J) = change in momentum = mass (m) × velocity (v) = 2 kg × 4 m/s = 8 Ns.
Correct Answer:
A
— 8 Ns
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Q. If a 2 kg object is lifted to a height of 3 m, what is the gravitational potential energy gained?
A.
6 J
B.
12 J
C.
18 J
D.
24 J
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Solution
Potential Energy = mgh = 2 kg × 9.8 m/s² × 3 m = 58.8 J.
Correct Answer:
B
— 12 J
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Q. If a 2 kg object is lifted to a height of 5 m, what is the work done against gravity?
A.
10 J
B.
20 J
C.
30 J
D.
40 J
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Solution
Work done W = mgh = 2 kg * 9.81 m/s² * 5 m = 98.1 J.
Correct Answer:
B
— 20 J
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Q. If a 2 kg object is moving at 3 m/s, what is its momentum?
A.
6 kg·m/s
B.
5 kg·m/s
C.
3 kg·m/s
D.
2 kg·m/s
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Solution
Momentum is calculated using the formula p = mv. Thus, p = 2 kg * 3 m/s = 6 kg·m/s.
Correct Answer:
A
— 6 kg·m/s
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Q. If a 4 kg object is moving with a velocity of 2 m/s and collides elastically with a stationary object of mass 4 kg, what is the final velocity of the first object?
A.
0 m/s
B.
1 m/s
C.
2 m/s
D.
4 m/s
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Solution
In an elastic collision, the velocities are exchanged. The first object comes to rest, so final velocity = 0 m/s.
Correct Answer:
A
— 0 m/s
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Q. If a 5 kg object is subjected to a net force of 15 N, what is its acceleration?
A.
3 m/s²
B.
2 m/s²
C.
1 m/s²
D.
4 m/s²
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Solution
Using Newton's second law, F = ma, we can find acceleration: a = F/m = 15 N / 5 kg = 3 m/s².
Correct Answer:
A
— 3 m/s²
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Q. If a capacitor discharges through a resistor, what is the formula for the voltage across the capacitor at time t?
A.
V(t) = V0 * e^(-t/RC)
B.
V(t) = V0 * (1 - e^(-t/RC))
C.
V(t) = V0 * t/RC
D.
V(t) = V0 * e^(t/RC)
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Solution
The voltage across a discharging capacitor is given by V(t) = V0 * e^(-t/RC).
Correct Answer:
A
— V(t) = V0 * e^(-t/RC)
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Q. If a capacitor discharges through a resistor, what is the voltage across the capacitor after one time constant?
A.
V0/e
B.
V0/2
C.
V0
D.
0
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Solution
After one time constant (τ), the voltage across the capacitor will be V0/e, where V0 is the initial voltage.
Correct Answer:
A
— V0/e
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Q. If a capacitor has a capacitance of 10μF and is charged to a voltage of 5V, what is the charge stored in the capacitor?
A.
50μC
B.
5μC
C.
10μC
D.
100μC
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Solution
The charge stored in a capacitor is given by Q = C * V = 10μF * 5V = 50μC.
Correct Answer:
A
— 50μC
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Q. If a capacitor has a capacitance of 2μF and is charged to 10V, what is the charge stored in the capacitor?
A.
20μC
B.
5μC
C.
2μC
D.
10μC
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Solution
The charge stored in the capacitor is given by Q = C*V = 2μF * 10V = 20μC.
Correct Answer:
A
— 20μC
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Q. If a capacitor has a capacitance of 5μF and is charged to a voltage of 10V, what is the charge stored in the capacitor?
A.
0.05C
B.
0.1C
C.
0.5C
D.
1C
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Solution
Charge (Q) is given by Q = C * V = 5μF * 10V = 0.05C.
Correct Answer:
A
— 0.05C
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Q. If a capacitor is charged to a voltage of 20 V and then connected in parallel with another uncharged capacitor of the same capacitance, what is the new voltage across both capacitors?
A.
10 V
B.
20 V
C.
30 V
D.
40 V
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Solution
When two identical capacitors are connected in parallel, the charge is shared equally. The new voltage is halved: 20 V / 2 = 10 V.
Correct Answer:
A
— 10 V
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Q. If a capacitor is charged to a voltage V and then disconnected from the power source, what happens to the charge on the capacitor over time?
A.
It remains constant
B.
It decreases exponentially
C.
It increases exponentially
D.
It becomes zero instantly
Show solution
Solution
When a capacitor is disconnected from the power source, the charge decreases exponentially over time due to leakage.
Correct Answer:
B
— It decreases exponentially
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