If a member in a truss is in tension, the force acting on it is pulling away from the joint.

The Method of Joints is commonly used to determine the forces in the members of a truss by analyzing the equilibrium of each joint.

In structural analysis, 'stiffness' refers to the load per unit deflection, indicating how much a structure deforms under a given load.

The primary consideration for structural safety in the limit state design method is the Ultimate Limit State, which ensures the structure can withstand maximum loads.

In the stiffness method, the primary unknowns are the displacements at the nodes of the structure.

A structure is statically determinate when the number of equations of equilibrium is equal to the number of unknowns.

The critical load (P_cr) for a column is given by P_cr = π²EI/L², where E is the modulus of elasticity and L is the effective length.

The deflection at the midpoint of a simply supported beam subjected to a uniform load w is given by δ = wL^4/8EI.

The deflection (δ) at the center of a simply supported beam under a uniform load (w) is given by δ = 5wL^4/384EI.

The deflection (δ) at the center of a simply supported beam with a point load (P) at the center is given by δ = (P * L^3) / (48 * E * I), where E is the modulus of elasticity and I is the moment of inertia.

Increasing the length of a beam under a given load will increase its deflection, as deflection is proportional to the cube of the length (L^3).

Increasing the length of a beam under a uniform load increases its deflection, as deflection is proportional to the length cubed.

Increasing the length of a beam under a constant load will increase its deflection, as deflection is proportional to the cube of the length (L^3).

Increasing the length of a simply supported beam under a uniform load increases its deflection, as deflection is proportional to the cube of the length (L^3).

Increasing the length of a simply supported beam increases its deflection under a given load, as deflection is proportional to the length cubed.

Increasing the moment of inertia (I) of a beam decreases its deflection under a given load, as deflection is inversely proportional to I.

Increasing the moment of inertia (I) of a beam decreases its deflection, as deflection is inversely proportional to I.

Increasing the moment of inertia I of a beam decreases its deflection, as deflection is inversely proportional to I.

Factor of Safety = Yield Strength / (Max Load / Area) = 250 MPa / (10 kN / 50 cm²) = 250 / 20 = 12.5, which is incorrect. The correct calculation should yield a factor of safety of 2.0.

The factor of safety (FoS) is calculated as FoS = Yield Strength / Maximum Stress = 150 MPa / 30 MPa = 5.

The factor of safety (FS) is calculated as FS = Ultimate Load / Working Load = 150 kN / 75 kN = 2.0.

The factor of safety (FS) is calculated as FS = Ultimate Load / Allowable Load = 100 kN / 50 kN = 2.0.

Factor of Safety = Ultimate Load / Working Load = 50 kN / 20 kN = 2.5.

The factor of safety (FS) is calculated as FS = Ultimate Load / Allowable Load = 100 kN / 50 kN = 2.0.

The deflection (δ) at the center of a simply supported beam with a point load (P) is given by δ = PL^3 / 48EI.

The moment of inertia (I) for a rectangular beam section is given by I = bh^3/12, where b is the width and h is the height.

The moment of inertia I for a rectangular section is calculated as I = bh^3/12, where b is the base and h is the height.

The reaction forces at the supports of a simply supported beam with a uniform load (w) are each equal to wL/2.

The shear force V at a section of a beam subjected to a point load P and a uniformly distributed load w is given by V = P - w * x, where x is the distance from the load.

The shear force (V) at a distance 'x' from the left support is given by V = R - wx, where R is the reaction at the support and w is the uniform load.