Profits should be divided in accordance with their capital contributions, hence 60% to A and 40% to B.

Despite the capital contribution, the partners agreed to split profits equally, hence 50% to each.

Profits should be divided in accordance with their capital contributions, so A receives 60% and B receives 40%.

In the absence of any other agreement, profits are typically divided in the ratio of capital contributions.

Product A's sales across all quarters total $9000 ($1000 + $2000 + $2500 + $3000).

Product A's Q3 sales are $1000. A 20% increase results in $1200.

If Product B's sales in Q3 were 327 units, a 10% increase would result in approximately 360 units.

The expected growth rate from Q3 (320 units) to Q4 (400 units) is 25%.

Sales in Q2 were 200 + (25% of 200) = 200 + 50 = 250 units.

Product D's sales increased from 200 units in Q1 to 300 units in Q2, which is a 50% increase.

The sales in Q2 were 390 units, which is a 30% increase from Q1.

The sales increased to 390 units in Q2, which is a 30% increase from Q1.

Sales grew from $2000 in Q3 to $3000 in Q4, which is a 50% growth.

R is in the middle as Q is to the left and S is to the right.

A relation is a function if every element in the domain (set A) maps to exactly one element in the codomain. Here, 1 maps to 2, and 2 maps to 3, but 3 has no mapping, so R is not a function.

A relation is symmetric if for every (a, b) in R, (b, a) is also in R. Since R only contains pairs of the form (a, a), it is symmetric.

A relation R is reflexive if every element in set A is related to itself. Since R contains (1, 1), (2, 2), and (3, 3), R is reflexive.

A relation R is transitive if whenever (a, b) ∈ R and (b, c) ∈ R, then (a, c) must also be in R. Here, (1, 2) and (2, 3) are in R, but (1, 3) is not, so R is not transitive.

R is not reflexive as (1,1), (2,2), (3,3) are not in R. It is symmetric as (2,3) implies (3,2) is not in R. It is transitive as (1,2) and (2,3) implies (1,3) is not in R. Thus, R is not all of the above.

R is reflexive because it contains all pairs (a, a) and symmetric because (1,2) implies (2,1).

R is reflexive and symmetric, but not transitive. Thus, both 1 and 2 are true.

R is not a partial order because it is not transitive; (1,2) and (2,2) do not imply (1,2).

R is neither reflexive, symmetric, nor transitive as it does not satisfy any of the properties.

R is not symmetric as (b,c) does not imply (c,b) is in R. It is reflexive and transitive.

R is neither reflexive, symmetric, nor transitive.

Since R is between S and T, and U is opposite S, T must be next to U.

Since R is to the left of S, R is also to the right of S, making R the one sitting to the right of S.

The arrangement is T, S, R. Thus, S is in the middle.

Using the balance condition R1/R2 = R3/R4, we find R4 = (R2 * R3) / R1 = (15 * 5) / 10 = 7.5Ω.

For balance, R1/R2 = R3/R4, thus R4 = (R2 * R3) / R1 = (20 * 30) / 10 = 60Ω.