Engineering & Architecture Admissions MCQ & Objective Questions
Engineering & Architecture Admissions play a crucial role in shaping the future of aspiring students in India. With the increasing competition in entrance exams, mastering MCQs and objective questions is essential for effective exam preparation. Practicing these types of questions not only enhances concept clarity but also boosts confidence, helping students score better in their exams.
What You Will Practise Here
Key concepts in Engineering Mathematics
Fundamentals of Physics relevant to architecture and engineering
Important definitions and terminologies in engineering disciplines
Essential formulas for solving objective questions
Diagrams and illustrations for better understanding
Conceptual theories related to structural engineering
Analysis of previous years' important questions
Exam Relevance
The topics covered under Engineering & Architecture Admissions are highly relevant for various examinations such as CBSE, State Boards, NEET, and JEE. Students can expect to encounter MCQs that test their understanding of core concepts, application of formulas, and analytical skills. Common question patterns include multiple-choice questions that require selecting the correct answer from given options, as well as assertion-reason type questions that assess deeper comprehension.
Common Mistakes Students Make
Misinterpreting the question stem, leading to incorrect answers.
Overlooking units in numerical problems, which can change the outcome.
Confusing similar concepts or terms, especially in definitions.
Neglecting to review diagrams, which are often crucial for solving problems.
Rushing through practice questions without understanding the underlying concepts.
FAQs
Question: What are the best ways to prepare for Engineering & Architecture Admissions MCQs?Answer: Regular practice of objective questions, reviewing key concepts, and taking mock tests can significantly enhance your preparation.
Question: How can I improve my accuracy in solving MCQs?Answer: Focus on understanding the concepts thoroughly, practice regularly, and learn to eliminate incorrect options to improve accuracy.
Start your journey towards success by solving practice MCQs today! Test your understanding and strengthen your knowledge in Engineering & Architecture Admissions to excel in your exams.
Q. What is the vapor pressure of a solution containing 1 mole of solute in 3 moles of solvent, assuming ideal behavior?
A.
0.25 P0
B.
0.75 P0
C.
0.5 P0
D.
P0
Show solution
Solution
Using Raoult's law, the vapor pressure of the solution = (moles of solvent / total moles) * P0 = (3 / (3 + 1)) * P0 = 0.75 P0.
Correct Answer:
B
— 0.75 P0
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Q. What is the vapor pressure of a solution containing a non-volatile solute compared to the pure solvent?
A.
Higher than the pure solvent
B.
Lower than the pure solvent
C.
Equal to the pure solvent
D.
Unpredictable
Show solution
Solution
The vapor pressure of a solution containing a non-volatile solute is lower than that of the pure solvent due to the presence of solute particles.
Correct Answer:
B
— Lower than the pure solvent
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Q. What is the variance of the data set {4, 8, 6, 5, 3}?
Show solution
Solution
Mean = 5.2; Variance = [(4-5.2)² + (8-5.2)² + (6-5.2)² + (5-5.2)² + (3-5.2)²] / 5 = 2.56.
Correct Answer:
A
— 2.5
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Q. What is the variance of the data set: 1, 2, 3, 4, 5?
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Solution
Mean = 3. Variance = [(1-3)² + (2-3)² + (3-3)² + (4-3)² + (5-3)²] / 5 = 2.
Correct Answer:
B
— 1.5
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Q. What is the variance of the data set: 2, 4, 4, 4, 5, 5, 7, 9?
A.
2.5
B.
3.5
C.
4.5
D.
5.5
Show solution
Solution
Mean = 5.0; Variance = [(2-5)^2 + (4-5)^2 + (4-5)^2 + (4-5)^2 + (5-5)^2 + (5-5)^2 + (7-5)^2 + (9-5)^2] / 8 = 2.5.
Correct Answer:
A
— 2.5
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Q. What is the variance of the following data set: {5, 7, 8, 9, 10}?
Show solution
Solution
Mean = 7.8, Variance = [(5-7.8)² + (7-7.8)² + (8-7.8)² + (9-7.8)² + (10-7.8)²] / 5 = 3.
Correct Answer:
B
— 3
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Q. What is the vertex of the parabola defined by the equation y = -2(x - 1)^2 + 4?
A.
(1, 4)
B.
(1, -4)
C.
(4, 1)
D.
(-1, 4)
Show solution
Solution
The vertex form of a parabola is y = a(x - h)^2 + k. Here, h = 1 and k = 4, so the vertex is (1, 4).
Correct Answer:
A
— (1, 4)
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Q. What is the vertex of the parabola given by the equation y = -2(x - 1)^2 + 4?
A.
(1, 4)
B.
(1, -4)
C.
(4, 1)
D.
(-1, 4)
Show solution
Solution
The vertex form of a parabola is y = a(x - h)^2 + k. Here, h = 1 and k = 4, so the vertex is (1, 4).
Correct Answer:
A
— (1, 4)
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Q. What is the vertex of the parabola represented by the equation y = -2(x - 1)^2 + 4?
A.
(1, 4)
B.
(1, -4)
C.
(-1, 4)
D.
(-1, -4)
Show solution
Solution
The vertex form of a parabola is y = a(x - h)^2 + k. Here, h = 1 and k = 4, so the vertex is (1, 4).
Correct Answer:
A
— (1, 4)
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Q. What is the vertex of the parabola represented by the equation y = 2x^2 - 8x + 5?
A.
(2, -3)
B.
(2, -7)
C.
(4, -3)
D.
(4, -7)
Show solution
Solution
The vertex can be found using x = -b/(2a) = 4. Substituting x = 4 into the equation gives y = -3.
Correct Answer:
A
— (2, -3)
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Q. What is the viscosity of water at 20°C?
A.
0.001 Pa·s
B.
0.01 Pa·s
C.
0.1 Pa·s
D.
1 Pa·s
Show solution
Solution
The viscosity of water at 20°C is approximately 0.001 Pa·s.
Correct Answer:
A
— 0.001 Pa·s
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Q. What is the voltage across a 10 ohm resistor carrying a current of 0.5 A?
A.
5 V
B.
10 V
C.
15 V
D.
20 V
Show solution
Solution
Using Ohm's law, V = I * R = 0.5 A * 10 Ω = 5 V.
Correct Answer:
A
— 5 V
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Q. What is the voltage drop across a 3 ohm resistor carrying a current of 2 A?
A.
3 V
B.
6 V
C.
9 V
D.
12 V
Show solution
Solution
Using Ohm's law, V = I * R = 2 A * 3 ohms = 6 V.
Correct Answer:
B
— 6 V
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Q. What is the voltage drop across a 5 ohm resistor carrying a current of 2 A?
A.
5 V
B.
10 V
C.
15 V
D.
20 V
Show solution
Solution
Using Ohm's law, V = I * R = 2 A * 5 ohms = 10 V.
Correct Answer:
B
— 10 V
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Q. What is the voltage drop across a 5 ohm resistor carrying a current of 3 A?
A.
15 V
B.
10 V
C.
5 V
D.
20 V
Show solution
Solution
Using Ohm's law, V = I * R = 3 A * 5Ω = 15 V.
Correct Answer:
A
— 15 V
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Q. What is the voltage drop across a 5Ω resistor carrying a current of 3A?
A.
5V
B.
10V
C.
15V
D.
20V
Show solution
Solution
Using Ohm's law, V = I * R = 3A * 5Ω = 15V.
Correct Answer:
C
— 15V
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Q. What is the volume occupied by 1 mole of an ideal gas at STP (Standard Temperature and Pressure)?
A.
22.4 L
B.
24.0 L
C.
18.0 L
D.
20.0 L
Show solution
Solution
At STP, 1 mole of an ideal gas occupies 22.4 liters.
Correct Answer:
A
— 22.4 L
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Q. What is the volume occupied by 1 mole of an ideal gas at STP?
A.
22.4 L
B.
24 L
C.
20 L
D.
18 L
Show solution
Solution
At STP, 1 mole of an ideal gas occupies 22.4 liters.
Correct Answer:
A
— 22.4 L
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Q. What is the volume occupied by 4 moles of an ideal gas at STP?
A.
22.4 L
B.
44.8 L
C.
67.2 L
D.
89.6 L
Show solution
Solution
At STP, 1 mole of gas occupies 22.4 L. Therefore, 4 moles occupy 4 x 22.4 L = 89.6 L.
Correct Answer:
B
— 44.8 L
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Q. What is the volume of 1 liter in cubic meters?
A.
0.001
B.
0.01
C.
1
D.
1000
Show solution
Solution
1 liter is equal to 0.001 cubic meters.
Correct Answer:
A
— 0.001
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Q. What is the volume of 1 M NaOH solution required to obtain 0.5 moles of NaOH?
A.
0.5 L
B.
1 L
C.
2 L
D.
0.25 L
Show solution
Solution
Using the formula M = moles/volume, Volume = moles/M = 0.5 moles / 1 M = 0.5 L.
Correct Answer:
A
— 0.5 L
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Q. What is the volume of 1 mole of an ideal gas at STP (Standard Temperature and Pressure)?
A.
22.4 L
B.
24.0 L
C.
18.0 L
D.
20.0 L
Show solution
Solution
At STP, 1 mole of an ideal gas occupies 22.4 liters.
Correct Answer:
A
— 22.4 L
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Q. What is the volume of 1 mole of an ideal gas at STP?
A.
22.4 L
B.
24 L
C.
10 L
D.
1 L
Show solution
Solution
At STP (Standard Temperature and Pressure), 1 mole of an ideal gas occupies 22.4 liters.
Correct Answer:
A
— 22.4 L
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Q. What is the volume of 1 mole of gas at STP?
A.
22.4 L
B.
24 L
C.
20 L
D.
18 L
Show solution
Solution
At STP, 1 mole of gas occupies 22.4 liters.
Correct Answer:
A
— 22.4 L
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Q. What is the volume of 4 moles of an ideal gas at STP?
A.
22.4 L
B.
44.8 L
C.
89.6 L
D.
112 L
Show solution
Solution
Volume = moles x volume per mole = 4 moles x 22.4 L/mole = 89.6 L.
Correct Answer:
C
— 89.6 L
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Q. What is the volume of a 2 M solution that contains 4 moles of solute?
A.
2 L
B.
4 L
C.
1 L
D.
0.5 L
Show solution
Solution
Volume = moles of solute / molarity = 4 moles / 2 M = 2 L.
Correct Answer:
B
— 4 L
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Q. What is the volume of a cube with a side length of 2 meters?
A.
4 m³
B.
6 m³
C.
8 m³
D.
10 m³
Show solution
Solution
Volume = side³ = 2³ = 8 m³.
Correct Answer:
C
— 8 m³
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Q. What is the volume of a cube with a side length of 3 cm?
A.
9 cm³
B.
18 cm³
C.
27 cm³
D.
36 cm³
Show solution
Solution
The volume of a cube is given by side³, so 3 cm³ = 27 cm³.
Correct Answer:
C
— 27 cm³
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Q. What is the volume of CO2 produced at STP when 2 moles of C2H5OH are completely combusted?
A.
22.4 L
B.
44.8 L
C.
67.2 L
D.
89.6 L
Show solution
Solution
C2H5OH + 3O2 → 2CO2 + 3H2O. 2 moles of C2H5OH produce 4 moles of CO2. Volume = 4 * 22.4 L = 89.6 L.
Correct Answer:
B
— 44.8 L
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Q. What is the volume percent concentration of a solution containing 30 mL of ethanol in 150 mL of solution?
A.
20%
B.
25%
C.
30%
D.
15%
Show solution
Solution
Volume percent = (volume of solute / total volume) x 100 = (30 mL / 150 mL) x 100 = 20%.
Correct Answer:
B
— 25%
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