Mathematics is a crucial subject in school education, forming the foundation for various competitive exams. Mastering Mathematics (School) not only enhances problem-solving skills but also boosts confidence during exams. Practicing MCQs and objective questions is essential for effective exam preparation, as it helps students identify important questions and understand concepts clearly.
What You Will Practise Here
Number Systems and their properties
Algebraic Expressions and Equations
Geometry: Angles, Triangles, and Circles
Statistics and Probability concepts
Mensuration: Area, Volume, and Surface Area
Trigonometry basics and applications
Functions and Graphs
Exam Relevance
Mathematics (School) is a significant part of the curriculum for CBSE and State Boards, as well as competitive exams like NEET and JEE. Students can expect a variety of question patterns, including direct application of formulas, conceptual understanding, and problem-solving scenarios. Familiarity with MCQs in this subject can greatly enhance performance in both board and competitive examinations.
Common Mistakes Students Make
Misinterpreting the question, leading to incorrect answers.
Overlooking the importance of units in measurement-related problems.
Confusing similar formulas, especially in Geometry and Algebra.
Neglecting to check calculations, resulting in simple arithmetic errors.
Failing to understand the underlying concepts, which affects problem-solving ability.
FAQs
Question: How can I improve my speed in solving Mathematics (School) MCQs? Answer: Regular practice with timed quizzes and mock tests can significantly enhance your speed and accuracy.
Question: Are there any specific topics I should focus on for competitive exams? Answer: Focus on Algebra, Geometry, and Statistics, as these areas frequently appear in competitive exams.
Start your journey towards mastering Mathematics (School) today! Solve practice MCQs to test your understanding and prepare effectively for your exams. Remember, consistent practice leads to success!
Q. If two parallel lines are intersected by a transversal, and one of the exterior angles is 120 degrees, what is the measure of the opposite exterior angle?
A.
60 degrees
B.
120 degrees
C.
180 degrees
D.
90 degrees
Solution
Opposite exterior angles are equal, so the measure is also 120 degrees.
Q. If two parallel lines are represented by the equations y = 3x + 1 and y = 3x - 4, what is the distance between these two lines?
A.
5/√10
B.
5/√13
C.
5/√3
D.
5/√2
Solution
The distance d between two parallel lines of the form y = mx + b1 and y = mx + b2 is given by d = |b2 - b1| / √(1 + m^2). Here, d = |(-4) - 1| / √(1 + 3^2) = 5 / √10.
Q. If two parallel lines are represented by the equations y = 3x + 2 and y = 3x - 4, what is the distance between these two lines?
A.
6/√10
B.
2/√10
C.
4/√10
D.
8/√10
Solution
The distance between two parallel lines of the form y = mx + b1 and y = mx + b2 is given by |b2 - b1| / √(1 + m^2). Here, |(-4) - 2| / √(1 + 3^2) = 6 / √10.
Q. If two parallel lines are represented by the equations y = 4x + 1 and y = 4x - 3, what is the distance between them?
A.
1
B.
2
C.
3
D.
4
Solution
The distance between two parallel lines of the form y = mx + b1 and y = mx + b2 is given by |b2 - b1| / sqrt(1 + m^2). Here, |(-3) - 1| / sqrt(1 + 4) = 4 / sqrt(5) which approximates to 1.
Q. If two sides of a triangle are 7 cm and 10 cm, what is the range of possible lengths for the third side?
A.
3 cm to 17 cm
B.
4 cm to 16 cm
C.
5 cm to 15 cm
D.
6 cm to 13 cm
Solution
By the triangle inequality theorem, the length of the third side must be greater than the difference of the other two sides and less than their sum: |7 - 10| < x < 7 + 10, which gives 3 < x < 17.
Q. If two tangents are drawn from a point outside a circle to the circle, and the lengths of the tangents are equal, what can be said about the point and the circle?
A.
The point is inside the circle
B.
The point is outside the circle
C.
The point is on the circle
D.
The point is the center of the circle
Solution
The point is outside the circle, and the lengths of the tangents from a point outside a circle are equal.
Correct Answer:
B
— The point is outside the circle
Q. If two triangles are similar and the length of a side in the first triangle is 5 cm and the corresponding side in the second triangle is 15 cm, what is the ratio of their sides?
A.
1:2
B.
1:3
C.
1:4
D.
1:5
Solution
The ratio of the sides of the two similar triangles is 5:15, which simplifies to 1:3.
Q. If two triangles are similar and the length of a side in the first triangle is 6 cm while the corresponding side in the second triangle is 9 cm, what is the scale factor from the first triangle to the second?
A.
2:3
B.
3:2
C.
1:1.5
D.
1.5:1
Solution
The scale factor is the ratio of the lengths of corresponding sides. Therefore, the scale factor is 6:9, which simplifies to 2:3.
Q. If two triangles are similar and the lengths of the sides of the first triangle are 3, 4, and 5, what are the lengths of the sides of the second triangle if the ratio is 2:1?
A.
6, 8, 10
B.
3, 4, 5
C.
1.5, 2, 2.5
D.
4, 5, 6
Solution
If the triangles are similar with a ratio of 2:1, the sides of the second triangle will be 2 * (3, 4, 5) = (6, 8, 10).
Q. If two triangles are similar and the lengths of the sides of the first triangle are 3 cm, 4 cm, and 5 cm, what are the lengths of the sides of the second triangle if the ratio of similarity is 2:1?
A.
6 cm, 8 cm, 10 cm
B.
3 cm, 4 cm, 5 cm
C.
1.5 cm, 2 cm, 2.5 cm
D.
4 cm, 5 cm, 6 cm
Solution
In similar triangles, corresponding sides are in the same ratio. If the ratio is 2:1, the sides of the second triangle will be 2 × (3 cm, 4 cm, 5 cm) = (6 cm, 8 cm, 10 cm).
Q. If two triangles are similar and the lengths of the sides of the first triangle are 3, 4, and 5, what are the lengths of the sides of the second triangle if the shortest side is 6?
A.
6, 8, 10
B.
9, 12, 15
C.
12, 16, 20
D.
15, 20, 25
Solution
The ratio of similarity is 6/3 = 2. Therefore, the sides are 6*2, 4*2, 5*2 = 6, 8, 10.
Q. If two triangles are similar and the lengths of the sides of the first triangle are 3, 4, and 5, what are the lengths of the sides of the second triangle if the ratio of similarity is 2:1?
A.
6, 8, 10
B.
3, 4, 5
C.
1.5, 2, 2.5
D.
4, 5, 6
Solution
If the ratio of similarity is 2:1, then the sides of the second triangle are 2 times the sides of the first triangle: 3*2, 4*2, 5*2 = 6, 8, 10.
Q. If two triangles are similar, and the lengths of the sides of the first triangle are 3, 4, and 5, what are the lengths of the corresponding sides of the second triangle if the ratio is 2:3?
A.
4, 5, 6
B.
6, 8, 10
C.
2, 3, 4
D.
1.5, 2, 2.5
Solution
If the ratio is 2:3, then the sides of the second triangle are (3 * 3/2), (4 * 3/2), (5 * 3/2) = 4.5, 6, 7.5. The closest whole numbers are 6, 8, 10.
