Q. A charged particle moves in a magnetic field. What is the nature of the force acting on it?
A.
Always in the direction of motion
B.
Always opposite to the direction of motion
C.
Perpendicular to the direction of motion
D.
Depends on the charge of the particle
Solution
The magnetic force on a charged particle moving in a magnetic field is given by the Lorentz force law, which states that the force is perpendicular to both the velocity of the particle and the magnetic field.
Correct Answer:
C
— Perpendicular to the direction of motion
Q. A charged particle moves in a magnetic field. What is the path of the particle if it enters the field perpendicularly? (2023)
A.
Straight line
B.
Circular path
C.
Elliptical path
D.
Parabolic path
Solution
A charged particle moving perpendicularly to a magnetic field experiences a magnetic force that acts as a centripetal force, causing it to move in a circular path.
Q. A charged particle moves perpendicular to a uniform magnetic field. What is the path of the particle? (2021)
A.
Straight line
B.
Circle
C.
Ellipse
D.
Parabola
Solution
A charged particle moving perpendicular to a uniform magnetic field will move in a circular path due to the magnetic force acting as a centripetal force.
Q. A charged sphere has a radius R and a total charge Q. What is the electric potential at a point outside the sphere at a distance r from the center (r > R)?
A.
kQ/R
B.
kQ/r
C.
kQ/(R+r)
D.
0
Solution
For a charged sphere, the electric potential outside the sphere behaves as if all the charge were concentrated at the center, so V = kQ/r.
Q. A chemist has a solution that is 25% acid. How much of this solution must be mixed with 10 liters of a solution that is 50% acid to obtain a solution that is 40% acid?
A.
5 liters
B.
10 liters
C.
15 liters
D.
20 liters
Solution
Let x be the liters of 25% solution. The equation is 0.25x + 0.5(10) = 0.4(x + 10). Solving gives x = 15 liters.
Q. A child is sitting on a merry-go-round that is rotating. If the child moves towards the center, what happens to the rotational speed of the merry-go-round?
A.
Increases
B.
Decreases
C.
Remains the same
D.
Becomes zero
Solution
As the child moves towards the center, the moment of inertia decreases, causing the rotational speed to increase to conserve angular momentum.
Q. A child is sitting on a merry-go-round that is spinning. If the child moves closer to the center, what happens to the angular velocity of the merry-go-round?
A.
Increases
B.
Decreases
C.
Remains the same
D.
Becomes zero
Solution
As the child moves closer to the center, the moment of inertia decreases, causing the angular velocity to increase to conserve angular momentum.
Q. A child is sitting on a merry-go-round that is spinning. If the child moves towards the center, what happens to the angular velocity of the merry-go-round?
A.
Increases
B.
Decreases
C.
Remains the same
D.
Becomes zero
Solution
As the child moves towards the center, the moment of inertia decreases, and to conserve angular momentum, the angular velocity must increase.
Q. A child is sitting on a merry-go-round that is spinning. If the child moves towards the center of the merry-go-round, what happens to the angular velocity of the system?
A.
Increases
B.
Decreases
C.
Remains the same
D.
Becomes zero
Solution
As the child moves towards the center, the moment of inertia decreases, thus the angular velocity increases to conserve angular momentum.
Q. A child sitting at the edge of a merry-go-round throws a ball tangentially. What happens to the angular momentum of the system (merry-go-round + child + ball)?
A.
Increases
B.
Decreases
C.
Remains constant
D.
Becomes zero
Solution
Angular momentum of the system remains constant due to conservation of angular momentum.
