JEE Main MCQ & Objective Questions
The JEE Main exam is a crucial step for students aspiring to enter prestigious engineering colleges in India. It tests not only knowledge but also the ability to apply concepts effectively. Practicing MCQs and objective questions is essential for scoring better, as it helps in familiarizing students with the exam pattern and enhances their problem-solving skills. Engaging with practice questions allows students to identify important questions and strengthen their exam preparation.
What You Will Practise Here
Fundamental concepts of Physics, Chemistry, and Mathematics
Key formulas and their applications in problem-solving
Important definitions and theories relevant to JEE Main
Diagrams and graphical representations for better understanding
Numerical problems and their step-by-step solutions
Previous years' JEE Main questions for real exam experience
Time management strategies while solving MCQs
Exam Relevance
The topics covered in JEE Main are not only significant for the JEE exam but also appear in various CBSE and State Board examinations. Many concepts are shared with the NEET syllabus, making them relevant across multiple competitive exams. Common question patterns include conceptual applications, numerical problems, and theoretical questions that assess a student's understanding of core subjects.
Common Mistakes Students Make
Misinterpreting the question stem, leading to incorrect answers
Neglecting units in numerical problems, which can change the outcome
Overlooking negative marking and not managing time effectively
Relying too heavily on rote memorization instead of understanding concepts
Failing to review and analyze mistakes from practice tests
FAQs
Question: How can I improve my speed in solving JEE Main MCQ questions?Answer: Regular practice with timed quizzes and focusing on shortcuts can significantly enhance your speed.
Question: Are the JEE Main objective questions similar to previous years' papers?Answer: Yes, many questions are based on previous years' patterns, so practicing them can be beneficial.
Question: What is the best way to approach JEE Main practice questions?Answer: Start with understanding the concepts, then attempt practice questions, and finally review your answers to learn from mistakes.
Now is the time to take charge of your preparation! Dive into solving JEE Main MCQs and practice questions to test your understanding and boost your confidence for the exam.
Q. What is the total power consumed in a circuit with a 12V battery and a 4Ω resistor?
A.
12W
B.
24W
C.
36W
D.
48W
Show solution
Solution
Power P = V^2/R = (12V)^2/4Ω = 36W.
Correct Answer:
B
— 24W
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Q. What is the total power consumed in a circuit with a current of 5A and a total resistance of 4Ω?
A.
10W
B.
20W
C.
30W
D.
40W
Show solution
Solution
Power (P) = I^2 * R = 5^2 * 4 = 25 * 4 = 100W.
Correct Answer:
D
— 40W
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Q. What is the total power of two lenses of power +5 D and -3 D placed in contact?
A.
2 D
B.
8 D
C.
15 D
D.
1 D
Show solution
Solution
Total power P = P1 + P2 = 5 D - 3 D = 2 D.
Correct Answer:
A
— 2 D
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Q. What is the total resistance in a circuit with a 10Ω resistor in series with a 5Ω resistor?
A.
5Ω
B.
10Ω
C.
15Ω
D.
50Ω
Show solution
Solution
In series, total resistance (R_total) = R1 + R2 = 10Ω + 5Ω = 15Ω.
Correct Answer:
C
— 15Ω
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Q. What is the total resistance in a circuit with a 12 ohm and a 4 ohm resistor connected in parallel?
A.
3 ohms
B.
4 ohms
C.
9 ohms
D.
16 ohms
Show solution
Solution
1/R_eq = 1/12 + 1/4 => R_eq = 3 ohms.
Correct Answer:
A
— 3 ohms
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Q. What is the total resistance in a circuit with a 12Ω resistor and a 4Ω resistor connected in series?
A.
16Ω
B.
48Ω
C.
3Ω
D.
8Ω
Show solution
Solution
In series, total resistance R_total = R1 + R2 = 12Ω + 4Ω = 16Ω.
Correct Answer:
A
— 16Ω
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Q. What is the total resistance of a circuit with a 3Ω and a 5Ω resistor in series?
A.
8Ω
B.
15Ω
C.
2Ω
D.
1.5Ω
Show solution
Solution
Total resistance R = R1 + R2 = 3Ω + 5Ω = 8Ω.
Correct Answer:
A
— 8Ω
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Q. What is the total resistance of two 10 ohm resistors connected in parallel?
A.
5 ohms
B.
10 ohms
C.
20 ohms
D.
15 ohms
Show solution
Solution
1/R_eq = 1/R1 + 1/R2 = 1/10 + 1/10 = 2/10. Thus, R_eq = 10/2 = 5 ohms.
Correct Answer:
A
— 5 ohms
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Q. What is the total resistance of two 10 ohm resistors connected in series?
A.
5 ohms
B.
10 ohms
C.
20 ohms
D.
15 ohms
Show solution
Solution
In series, R_eq = R1 + R2 = 10 + 10 = 20 ohms.
Correct Answer:
C
— 20 ohms
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Q. What is the total resistance of two 12 ohm resistors connected in parallel?
A.
6 ohms
B.
12 ohms
C.
24 ohms
D.
18 ohms
Show solution
Solution
1/R_eq = 1/R1 + 1/R2 = 1/12 + 1/12 = 2/12. Thus, R_eq = 12/2 = 6 ohms.
Correct Answer:
A
— 6 ohms
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Q. What is the total resistance of two 8Ω resistors connected in series?
A.
8Ω
B.
16Ω
C.
4Ω
D.
12Ω
Show solution
Solution
In series, R_eq = R1 + R2 = 8 + 8 = 16Ω.
Correct Answer:
B
— 16Ω
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Q. What is the total resistance of two resistors of 5 ohms and 10 ohms connected in parallel?
A.
3.33 ohms
B.
5 ohms
C.
15 ohms
D.
50 ohms
Show solution
Solution
1/R_eq = 1/5 + 1/10 => R_eq = 3.33 ohms.
Correct Answer:
A
— 3.33 ohms
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Q. What is the total resistance of two resistors of 8Ω and 12Ω connected in series?
A.
20Ω
B.
24Ω
C.
16Ω
D.
18Ω
Show solution
Solution
In series, R_eq = R1 + R2 = 8 + 12 = 20Ω.
Correct Answer:
A
— 20Ω
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Q. What is the total voltage across a parallel circuit with two branches, one with 10Ω and 20Ω resistors, if the total current is 3A?
A.
6V
B.
9V
C.
12V
D.
15V
Show solution
Solution
Using the formula V = I * R_eq. First, find R_eq = 1 / (1/10 + 1/20) = 6.67Ω. Then, V = 3A * 6.67Ω = 20V.
Correct Answer:
C
— 12V
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Q. What is the total voltage in a series circuit with a 9V battery and two resistors of 2Ω and 3Ω?
Show solution
Solution
In a series circuit, the total voltage is equal to the voltage of the battery, which is 9V.
Correct Answer:
A
— 9V
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Q. What is the trace of the matrix A = [[1, 2, 3], [4, 5, 6], [7, 8, 9]]?
Show solution
Solution
The trace of A is the sum of the diagonal elements: 1 + 5 + 9 = 15.
Correct Answer:
A
— 15
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Q. What is the trend in atomic radius as you move down a group in the periodic table?
A.
Increases
B.
Decreases
C.
Remains constant
D.
Increases then decreases
Show solution
Solution
Atomic radius increases down a group due to the addition of electron shells.
Correct Answer:
A
— Increases
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Q. What is the trend in atomic radius as you move down the group of alkali metals?
A.
Increases
B.
Decreases
C.
Remains constant
D.
Varies irregularly
Show solution
Solution
The atomic radius increases as you move down the group of alkali metals.
Correct Answer:
A
— Increases
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Q. What is the trend in electronegativity as you move from left to right across a period?
A.
Increases
B.
Decreases
C.
Remains constant
D.
Varies irregularly
Show solution
Solution
Electronegativity increases from left to right across a period.
Correct Answer:
A
— Increases
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Q. What is the trend in ionization energy as you move down the group in s-block elements?
A.
Increases
B.
Decreases
C.
Remains constant
D.
Varies irregularly
Show solution
Solution
Ionization energy decreases as you move down the group in s-block elements due to increased atomic size.
Correct Answer:
B
— Decreases
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Q. What is the trend in ionization energy for alkali metals down the group?
A.
Increases
B.
Decreases
C.
Remains constant
D.
Fluctuates
Show solution
Solution
Ionization energy decreases down the group for alkali metals.
Correct Answer:
B
— Decreases
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Q. What is the trend in metallic character as you move from left to right across a period?
A.
Increases
B.
Decreases
C.
Remains constant
D.
Increases then decreases
Show solution
Solution
Metallic character decreases from left to right across a period.
Correct Answer:
B
— Decreases
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Q. What is the truth value of the expression A AND (B OR C) when A = 1, B = 0, and C = 1?
Show solution
Solution
First, evaluate B OR C, which is 0 OR 1 = 1. Then, A AND 1 = 1 AND 1 = 1.
Correct Answer:
B
— 1
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Q. What is the truth value of the expression A AND (B OR C) when A = 1, B = 0, C = 1?
A.
0
B.
1
C.
2
D.
Undefined
Show solution
Solution
B OR C = 0 OR 1 = 1. Then, A AND 1 = 1 AND 1 = 1.
Correct Answer:
B
— 1
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Q. What is the typical band gap of germanium?
A.
0.66 eV
B.
1.1 eV
C.
1.5 eV
D.
2.0 eV
Show solution
Solution
The typical band gap of germanium is approximately 0.66 eV.
Correct Answer:
A
— 0.66 eV
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Q. What is the typical charge of s-block metal ions?
Show solution
Solution
S-block metals typically form ions with a charge of +2.
Correct Answer:
B
— +2
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Q. What is the typical range of energy band gaps for semiconductors?
A.
0.1 - 0.5 eV
B.
0.5 - 1.5 eV
C.
1.5 - 3.0 eV
D.
3.0 - 5.0 eV
Show solution
Solution
The typical range of energy band gaps for semiconductors is between 0.5 eV and 1.5 eV.
Correct Answer:
B
— 0.5 - 1.5 eV
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Q. What is the typical range of the energy band gap for semiconductors?
A.
0.1 - 0.5 eV
B.
0.5 - 2.5 eV
C.
2.5 - 5 eV
D.
5 - 10 eV
Show solution
Solution
The typical range of the energy band gap for semiconductors is between 0.5 eV and 2.5 eV.
Correct Answer:
B
— 0.5 - 2.5 eV
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Q. What is the uncertainty in a measurement of 50.0 ± 0.5 g when converted to kilograms?
A.
0.0005 kg
B.
0.005 kg
C.
0.05 kg
D.
0.5 kg
Show solution
Solution
To convert grams to kilograms, divide by 1000. The uncertainty in kilograms is 0.5 g / 1000 = 0.0005 kg.
Correct Answer:
B
— 0.005 kg
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Q. What is the uncertainty in position if the uncertainty in momentum of a particle is 1.0 x 10^-24 kg m/s?
A.
1.0 x 10^-10 m
B.
6.63 x 10^-10 m
C.
1.0 x 10^-34 m
D.
6.63 x 10^-34 m
Show solution
Solution
Using Heisenberg's uncertainty principle, ΔxΔp ≥ ħ/2, we find Δx ≥ ħ/(2Δp) = (1.055 x 10^-34)/(2 x 1.0 x 10^-24) = 5.27 x 10^-11 m.
Correct Answer:
D
— 6.63 x 10^-34 m
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