Major Competitive Exams

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Major Competitive Exams

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Major Competitive Exams MCQ & Objective Questions

Major Competitive Exams play a crucial role in shaping the academic and professional futures of students in India. These exams not only assess knowledge but also test problem-solving skills and time management. Practicing MCQs and objective questions is essential for scoring better, as they help in familiarizing students with the exam format and identifying important questions that frequently appear in tests.

What You Will Practise Here

Key concepts and theories related to major subjects
Important formulas and their applications
Definitions of critical terms and terminologies
Diagrams and illustrations to enhance understanding
Practice questions that mirror actual exam patterns
Strategies for solving objective questions efficiently
Time management techniques for competitive exams

Exam Relevance

The topics covered under Major Competitive Exams are integral to various examinations such as CBSE, State Boards, NEET, and JEE. Students can expect to encounter a mix of conceptual and application-based questions that require a solid understanding of the subjects. Common question patterns include multiple-choice questions that test both knowledge and analytical skills, making it essential to be well-prepared with practice MCQs.

Common Mistakes Students Make

Rushing through questions without reading them carefully
Overlooking the negative marking scheme in MCQs
Confusing similar concepts or terms
Neglecting to review previous years’ question papers
Failing to manage time effectively during the exam

FAQs

Question: How can I improve my performance in Major Competitive Exams?
Answer: Regular practice of MCQs and understanding key concepts will significantly enhance your performance.

Question: What types of questions should I focus on for these exams?
Answer: Concentrate on important Major Competitive Exams questions that frequently appear in past papers and mock tests.

Question: Are there specific strategies for tackling objective questions?
Answer: Yes, practicing under timed conditions and reviewing mistakes can help develop effective strategies.

Start your journey towards success by solving practice MCQs today! Test your understanding and build confidence for your upcoming exams. Remember, consistent practice is the key to mastering Major Competitive Exams!

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Q. If a force of 10 N is applied to an object of mass 2 kg, what is its acceleration?

A. 2 m/s²
B. 5 m/s²
C. 10 m/s²
D. 20 m/s²

Solution

Using F = ma, acceleration a = F/m = 10 N / 2 kg = 5 m/s².

Correct Answer: B — 5 m/s²

Q. If a force of 10 N is applied to an object with a mass of 2 kg, what is its acceleration?

A. 2 m/s²
B. 5 m/s²
C. 10 m/s²
D. 20 m/s²

Solution

Using F = ma, acceleration a = F/m = 10 N / 2 kg = 5 m/s².

Correct Answer: B — 5 m/s²

Q. If a force of 10 N is applied to move an object 3 m in the direction of the force, what is the work done?

A. 30 J
B. 10 J
C. 3 J
D. 0 J

Solution

Work done = Force * Distance = 10 N * 3 m = 30 J.

Correct Answer: A — 30 J

Q. If a force of 10 N is applied to move an object 5 m in the direction of the force, what is the work done?

A. 50 J
B. 30 J
C. 20 J
D. 10 J

Solution

Work Done (W) = Force * Distance = 10 N * 5 m = 50 J

Correct Answer: A — 50 J

Q. If a force of 10 N is applied to move an object 5 m, what is the work done?

A. 50 J
B. 25 J
C. 10 J
D. 5 J

Solution

Work Done (W) = Force * Distance = 10 N * 5 m = 50 J

Correct Answer: A — 50 J

Q. If a force of 10 N moves an object 5 m in the direction of the force, what is the work done? (2020)

A. 50 J
B. 10 J
C. 5 J
D. 25 J

Solution

Work Done (W) = Force (F) * Distance (d) = 10 N * 5 m = 50 J

Correct Answer: A — 50 J

Q. If a force of 12 N is applied at an angle of 30 degrees to a lever arm of 1 m, what is the torque about the pivot?

A. 6 Nm
B. 10 Nm
C. 12 Nm
D. 15 Nm

Solution

Torque = Force × Distance × sin(θ) = 12 N × 1 m × sin(30°) = 12 N × 1 m × 0.5 = 6 Nm.

Correct Answer: A — 6 Nm

Q. If a force of 12 N is applied at an angle of 30 degrees to the horizontal while moving an object 3 m, what is the work done by the force?

A. 18 J
B. 24 J
C. 30 J
D. 36 J

Solution

Work done = F × d × cos(θ) = 12 N × 3 m × cos(30°) = 12 N × 3 m × (√3/2) = 18 J.

Correct Answer: B — 24 J

Q. If a force of 12 N is applied to a 4 kg object, what is the resulting acceleration?

A. 2 m/s²
B. 3 m/s²
C. 4 m/s²
D. 5 m/s²

Solution

Using F = ma, we find a = F/m = 12 N / 4 kg = 3 m/s².

Correct Answer: B — 3 m/s²

Q. If a force of 15 N acts on an object and moves it 4 m in the direction of the force, what is the work done?

A. 30 J
B. 60 J
C. 75 J
D. 90 J

Solution

Work done = Force × Distance = 15 N × 4 m = 60 J.

Correct Answer: B — 60 J

Q. If a force of 15 N is applied at a distance of 0.4 m from the pivot, what is the torque?

A. 6 Nm
B. 12 Nm
C. 15 Nm
D. 20 Nm

Solution

Torque = Force × Distance = 15 N × 0.4 m = 6 Nm.

Correct Answer: B — 12 Nm

Q. If a force of 15 N is applied at an angle of 30 degrees to the lever arm of length 1.5 m, what is the torque about the pivot?

A. 3.75 Nm
B. 7.5 Nm
C. 11.25 Nm
D. 12.99 Nm

Solution

Torque (τ) = F × r × sin(θ) = 15 N × 1.5 m × sin(30°) = 15 × 1.5 × 0.5 = 11.25 Nm.

Correct Answer: B — 7.5 Nm

Q. If a force of 15 N is applied at an angle of 30 degrees to the lever arm of length 1 m, what is the torque about the pivot?

A. 7.5 Nm
B. 15 Nm
C. 12.99 Nm
D. 10 Nm

Solution

Torque (τ) = F × r × sin(θ) = 15 N × 1 m × sin(30°) = 15 N × 1 m × 0.5 = 7.5 Nm.

Correct Answer: C — 12.99 Nm

Q. If a force of 15 N is applied at an angle of 60 degrees to the horizontal while moving an object 4 m, what is the work done by the force?

A. 30 J
B. 60 J
C. 120 J
D. 180 J

Solution

Work done = F × d × cos(θ) = 15 N × 4 m × cos(60°) = 15 N × 4 m × 0.5 = 30 J.

Correct Answer: C — 120 J

Q. If a force of 15 N is applied at an angle of 60° to the horizontal and moves an object 4 m, what is the work done? (2021)

A. 30 J
B. 60 J
C. 45 J
D. 20 J

Solution

Work done (W) = F × d × cos(θ) = 15 N × 4 m × cos(60°) = 15 N × 4 m × 0.5 = 30 J.

Correct Answer: C — 45 J

Q. If a force of 15 N is applied at an angle of 60° to the horizontal while moving an object 4 m, what is the work done by the force?

A. 30 J
B. 60 J
C. 120 J
D. 180 J

Solution

Work done = F × d × cos(θ) = 15 N × 4 m × cos(60°) = 15 N × 4 m × 0.5 = 30 J.

Correct Answer: C — 120 J

Q. If a force of 15 N is applied to a 3 kg object, what is the net force acting on the object if it is already moving with a velocity of 5 m/s? (2022)

A. 15 N
B. 3 N
C. 0 N
D. 18 N

Solution

The net force is still 15 N as it does not depend on the velocity of the object.

Correct Answer: A — 15 N

Q. If a force of 15 N is applied to a 3 kg object, what is the object's acceleration? (2023)

A. 3 m/s²
B. 5 m/s²
C. 7 m/s²
D. 10 m/s²

Solution

Using F = ma, a = F/m = 15 N / 3 kg = 5 m/s².

Correct Answer: B — 5 m/s²

Q. If a force of 15 N is applied to a mass of 3 kg, what is the acceleration of the mass? (2023)

A. 3 m/s²
B. 4 m/s²
C. 5 m/s²
D. 6 m/s²

Solution

Using F = ma, a = F/m = 15 N / 3 kg = 5 m/s².

Correct Answer: B — 4 m/s²

Q. If a force of 15 N is applied to a mass of 3 kg, what is the net force acting on the mass if it is also experiencing a frictional force of 5 N?

A. 10 N
B. 15 N
C. 20 N
D. 5 N

Solution

Net force = applied force - frictional force = 15 N - 5 N = 10 N.

Correct Answer: A — 10 N

Q. If a force of 15 N is applied to a mass of 3 kg, what is the net force acting on the mass if there is a frictional force of 5 N opposing the motion?

A. 10 N
B. 15 N
C. 20 N
D. 5 N

Solution

Net force = applied force - frictional force = 15 N - 5 N = 10 N.

Correct Answer: A — 10 N

Q. If a force of 15 N is applied to move an object 3 m in the direction of the force, what is the work done?

A. 45 J
B. 30 J
C. 15 J
D. 60 J

Solution

Work done = Force × Distance = 15 N × 3 m = 45 J.

Correct Answer: A — 45 J

Q. If a force of 15 N is applied to move an object 3 m, what is the work done? (2023)

A. 45 J
B. 30 J
C. 60 J
D. 15 J

Solution

Work Done (W) = Force * Distance = 15 N * 3 m = 45 J

Correct Answer: A — 45 J

Q. If a force of 15 N is applied to move an object 4 m in the direction of the force, what is the work done?

A. 30 J
B. 60 J
C. 45 J
D. 75 J

Solution

Work done = Force × Distance = 15 N × 4 m = 60 J.

Correct Answer: B — 60 J

Q. If a force of 15 N moves an object 3 m in the direction of the force, what is the work done? (2022)

A. 45 J
B. 30 J
C. 60 J
D. 15 J

Solution

Work done = Force × Distance = 15 N × 3 m = 45 J

Correct Answer: A — 45 J

Q. If a force of 20 N moves an object 5 m in the direction of the force, what is the work done?

A. 100 J
B. 50 J
C. 20 J
D. 200 J

Solution

Work = Force * Distance = 20 N * 5 m = 100 J.

Correct Answer: A — 100 J

Q. If a force of 30 N is applied to a mass of 10 kg, what is the net force acting on the mass if there is a frictional force of 10 N opposing the motion?

A. 20 N
B. 30 N
C. 40 N
D. 10 N

Solution

Net force = applied force - frictional force = 30 N - 10 N = 20 N.

Correct Answer: A — 20 N

Q. If a force of 5 N acts on an object and moves it 4 m in the direction of the force, what is the work done?

A. 10 J
B. 15 J
C. 20 J
D. 25 J

Solution

Work done = Force × Distance = 5 N × 4 m = 20 J.

Correct Answer: C — 20 J

Q. If a force of 5 N is applied at an angle of 60 degrees to the horizontal while moving an object 3 m, what is the work done by the force?

A. 7.5 J
B. 15 J
C. 12.99 J
D. 10 J

Solution

Work done = Force × Distance × cos(θ) = 5 N × 3 m × cos(60°) = 5 N × 3 m × 0.5 = 7.5 J.

Correct Answer: C — 12.99 J

Q. If a force of 5 N is applied at an angle of 60 degrees to the horizontal while moving an object 4 m, what is the work done by the force?

A. 10 J
B. 20 J
C. 5 J
D. 15 J

Solution

Work done = Force × Distance × cos(θ) = 5 N × 4 m × cos(60°) = 5 N × 4 m × 0.5 = 10 J.

Correct Answer: A — 10 J

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