Major Competitive Exams

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Major Competitive Exams

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Major Competitive Exams MCQ & Objective Questions

Major Competitive Exams play a crucial role in shaping the academic and professional futures of students in India. These exams not only assess knowledge but also test problem-solving skills and time management. Practicing MCQs and objective questions is essential for scoring better, as they help in familiarizing students with the exam format and identifying important questions that frequently appear in tests.

What You Will Practise Here

Key concepts and theories related to major subjects
Important formulas and their applications
Definitions of critical terms and terminologies
Diagrams and illustrations to enhance understanding
Practice questions that mirror actual exam patterns
Strategies for solving objective questions efficiently
Time management techniques for competitive exams

Exam Relevance

The topics covered under Major Competitive Exams are integral to various examinations such as CBSE, State Boards, NEET, and JEE. Students can expect to encounter a mix of conceptual and application-based questions that require a solid understanding of the subjects. Common question patterns include multiple-choice questions that test both knowledge and analytical skills, making it essential to be well-prepared with practice MCQs.

Common Mistakes Students Make

Rushing through questions without reading them carefully
Overlooking the negative marking scheme in MCQs
Confusing similar concepts or terms
Neglecting to review previous years’ question papers
Failing to manage time effectively during the exam

FAQs

Question: How can I improve my performance in Major Competitive Exams?
Answer: Regular practice of MCQs and understanding key concepts will significantly enhance your performance.

Question: What types of questions should I focus on for these exams?
Answer: Concentrate on important Major Competitive Exams questions that frequently appear in past papers and mock tests.

Question: Are there specific strategies for tackling objective questions?
Answer: Yes, practicing under timed conditions and reviewing mistakes can help develop effective strategies.

Start your journey towards success by solving practice MCQs today! Test your understanding and build confidence for your upcoming exams. Remember, consistent practice is the key to mastering Major Competitive Exams!

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Q. A capacitor of capacitance C is connected to a battery of voltage V. If the battery is removed and the capacitor is connected to another capacitor of capacitance 2C, what is the final voltage across the combination?

A. V/3
B. V/2
C. V
D. 2V

Solution

When the charged capacitor C is connected to an uncharged capacitor 2C, the final voltage is V_final = Q_total / C_eq = V/(1 + 1/2) = V/3.

Correct Answer: B — V/2

Q. A capacitor of capacitance C is connected to an AC source of frequency f. What is the capacitive reactance? (2020)

A. 1/(2πfC)
B. 2πfC
C. C/(2πf)
D. 2πf

Solution

The capacitive reactance is given by XC = 1/(2πfC).

Correct Answer: A — 1/(2πfC)

Q. A capacitor stores 5 microfarads of charge at a voltage of 10 volts. What is the energy stored in the capacitor?

A. 0.25 mJ
B. 0.5 mJ
C. 0.75 mJ
D. 1 mJ

Solution

The energy stored in a capacitor is given by the formula E = 0.5 * C * V^2. Here, E = 0.5 * 5 * 10^-6 F * (10 V)^2 = 0.5 * 5 * 10^-6 * 100 = 0.25 mJ.

Correct Answer: B — 0.5 mJ

Q. A capacitor stores energy in the form of which type of field?

A. Electric field
B. Magnetic field
C. Gravitational field
D. Electromagnetic field

Solution

A capacitor stores energy in the form of an electric field between its plates.

Correct Answer: A — Electric field

Q. A capillary tube is dipped in water. The height of the water column in the tube is determined by which of the following?

A. Surface tension and density of the liquid
B. Only surface tension
C. Only density of the liquid
D. Viscosity of the liquid

Solution

The height of the water column in a capillary tube is determined by both surface tension and the density of the liquid.

Correct Answer: A — Surface tension and density of the liquid

Q. A capillary tube is dipped in water. What is the shape of the water surface inside the tube?

A. Flat
B. Concave
C. Convex
D. Irregular

Solution

The water surface inside the capillary tube is concave due to the adhesive forces between water and the tube material being stronger than the cohesive forces among water molecules.

Correct Answer: B — Concave

Q. A capillary tube is dipped into water. How high will the water rise in the tube if the radius is 1 mm?

A. 2.5 cm
B. 5 cm
C. 10 cm
D. 15 cm

Solution

Using the capillary rise formula, h = (2γcosθ)/(ρgr), where γ is surface tension, θ is contact angle, ρ is density, g is acceleration due to gravity, and r is radius.

Correct Answer: B — 5 cm

Q. A capillary tube is dipped into water. The height to which water rises in the tube is determined by:

A. Surface tension and density of the liquid
B. Only surface tension
C. Only density of the liquid
D. Viscosity of the liquid

Solution

The height of the liquid column in a capillary tube is determined by both surface tension and the density of the liquid, as described by the capillary rise formula.

Correct Answer: A — Surface tension and density of the liquid

Q. A capillary tube is dipped into water. The water rises in the tube due to which of the following?

A. Surface tension and adhesion
B. Surface tension and cohesion
C. Only adhesion
D. Only cohesion

Solution

The rise of water in a capillary tube is due to both surface tension (which pulls the liquid up) and adhesion (the attraction between water molecules and the tube's surface).

Correct Answer: A — Surface tension and adhesion

Q. A capillary tube is dipped into water. What will happen to the water level inside the tube?

A. It will rise
B. It will fall
C. It will remain the same
D. It will oscillate

Solution

The water will rise in the capillary tube due to capillary action, which is a result of surface tension.

Correct Answer: A — It will rise

Q. A capillary tube of radius 0.5 mm is dipped in water. What is the height of the water column raised in the tube? (Surface tension = 0.072 N/m, density of water = 1000 kg/m³)

A. 0.5 m
B. 0.1 m
C. 0.2 m
D. 0.3 m

Solution

Using the formula h = 2γ/(ρgr), h = 2 × 0.072 N/m / (1000 kg/m³ × 9.81 m/s² × 0.0005 m) = 0.2 m.

Correct Answer: C — 0.2 m

Q. A car accelerates from rest at a constant rate of 2 m/s². How far does it travel in 5 seconds? (2021)

A. 10 m
B. 20 m
C. 25 m
D. 50 m

Solution

Using the equation of motion: s = ut + (1/2)at². Here, u = 0, a = 2 m/s², t = 5 s. So, s = 0 + (1/2)(2)(5²) = 25 m.

Correct Answer: C — 25 m

Q. A car accelerates from rest at a rate of 2 m/s². How far does it travel in 10 seconds? (2020)

A. 50 m
B. 100 m
C. 150 m
D. 200 m

Solution

Using the formula s = ut + (1/2)at²; s = 0 + (1/2)(2)(10²) = 100 m.

Correct Answer: B — 100 m

Q. A car accelerates from rest at a rate of 2 m/s². What is its speed after 5 seconds? (2023)

A. 5 m/s
B. 10 m/s
C. 15 m/s
D. 20 m/s

Solution

Using the formula v = u + at, where u = 0, a = 2 m/s², and t = 5 s, we get v = 0 + 2 * 5 = 10 m/s.

Correct Answer: B — 10 m/s

Q. A car accelerates from rest at a rate of 2 m/s². What is the net force acting on the car if its mass is 1000 kg?

A. 200 N
B. 500 N
C. 1000 N
D. 2000 N

Solution

Using F = ma, F = 1000 kg * 2 m/s² = 2000 N.

Correct Answer: D — 2000 N

Q. A car accelerates from rest to a speed of 100 km/h in 10 seconds. What is its acceleration? (2023)

A. 5 m/s²
B. 10 m/s²
C. 15 m/s²
D. 20 m/s²

Solution

Acceleration = (Final Speed - Initial Speed)/Time = (100 km/h × (1000 m/3600 s))/10 s = 5 m/s²

Correct Answer: A — 5 m/s²

Q. A car accelerates from rest to a speed of 20 m/s in 10 seconds. What is the distance covered by the car during this time?

A. 50 m
B. 100 m
C. 200 m
D. 400 m

Solution

Using the formula d = ut + 0.5at², where u = 0, a = (20 m/s) / 10 s = 2 m/s², we get d = 0 + 0.5 * 2 * (10)² = 100 m.

Correct Answer: B — 100 m

Q. A car accelerates from rest to a speed of 20 m/s in 5 seconds. What is its acceleration?

A. 2 m/s²
B. 4 m/s²
C. 5 m/s²
D. 10 m/s²

Solution

Acceleration is calculated using the formula a = (final velocity - initial velocity) / time. Here, a = (20 m/s - 0 m/s) / 5 s = 4 m/s².

Correct Answer: B — 4 m/s²

Q. A car accelerates from rest to a speed of 20 m/s. If its mass is 1000 kg, what is the work done by the engine?

A. 200,000 J
B. 100,000 J
C. 50,000 J
D. 400,000 J

Solution

Work Done = Change in Kinetic Energy = 1/2 * m * (v^2) = 1/2 * 1000 * (20^2) = 200,000 J

Correct Answer: A — 200,000 J

Q. A car accelerates from rest to a speed of 20 m/s. If its mass is 1000 kg, what is the work done on the car? (2022)

A. 200,000 J
B. 100,000 J
C. 50,000 J
D. 400,000 J

Solution

Work Done = Change in Kinetic Energy = 1/2 * m * (v^2 - u^2) = 1/2 * 1000 kg * (20 m/s)^2 = 200,000 J

Correct Answer: A — 200,000 J

Q. A car accelerates from rest to a speed of 20 m/s. If its mass is 1000 kg, what is the kinetic energy of the car at this speed? (2000)

A. 200 J
B. 1000 J
C. 2000 J
D. 4000 J

Solution

Kinetic Energy (KE) = 0.5 × m × v² = 0.5 × 1000 kg × (20 m/s)² = 0.5 × 1000 × 400 = 200000 J.

Correct Answer: C — 2000 J

Q. A car accelerates from rest to a speed of 20 m/s. If its mass is 1000 kg, what is the kinetic energy of the car at that speed?

A. 200,000 J
B. 100,000 J
C. 50,000 J
D. 400,000 J

Solution

Kinetic Energy (KE) = 0.5 × m × v² = 0.5 × 1000 kg × (20 m/s)² = 0.5 × 1000 × 400 = 200,000 J.

Correct Answer: B — 100,000 J

Q. A car accelerates from rest to a speed of 20 m/s. If the mass of the car is 1000 kg, what is the work done by the engine?

A. 200,000 J
B. 100,000 J
C. 50,000 J
D. 400,000 J

Solution

Work Done = Change in Kinetic Energy = 1/2 * m * (v^2) = 1/2 * 1000 * (20^2) = 200,000 J

Correct Answer: A — 200,000 J

Q. A car accelerates from rest to a speed of 20 m/s. If the mass of the car is 1000 kg, what is the kinetic energy of the car at that speed? (2000)

A. 200 J
B. 1000 J
C. 2000 J
D. 4000 J

Solution

Kinetic Energy (KE) = 0.5 × m × v² = 0.5 × 1000 kg × (20 m/s)² = 0.5 × 1000 × 400 = 200000 J.

Correct Answer: D — 4000 J

Q. A car accelerates from rest to a speed of 25 m/s in 5 seconds. What is its acceleration?

A. 2 m/s²
B. 3 m/s²
C. 4 m/s²
D. 5 m/s²

Solution

Acceleration = (final speed - initial speed) / time = (25 m/s - 0) / 5 s = 5 m/s².

Correct Answer: B — 3 m/s²

Q. A car accelerates from rest to a speed of 30 m/s in 10 seconds. What is the acceleration of the car? (2022)

A. 3 m/s²
B. 2 m/s²
C. 1 m/s²
D. 4 m/s²

Solution

Acceleration (a) = (final velocity - initial velocity) / time = (30 m/s - 0) / 10 s = 3 m/s².

Correct Answer: A — 3 m/s²

Q. A car accelerates from rest to a speed of 30 m/s in 10 seconds. What is the distance covered by the car during this time?

A. 150 m
B. 300 m
C. 400 m
D. 600 m

Solution

Using the formula d = ut + 0.5at², where u = 0, a = (30 m/s) / 10 s = 3 m/s², we get d = 0 + 0.5 * 3 * (10)² = 150 m.

Correct Answer: B — 300 m

Q. A car accelerates from rest to a speed of 30 m/s. If the mass of the car is 800 kg, what is the work done on the car?

A. 360,000 J
B. 480,000 J
C. 600,000 J
D. 720,000 J

Solution

Work done = Change in Kinetic Energy = 0.5 × mass × (final speed² - initial speed²) = 0.5 × 800 kg × (30 m/s)² = 360,000 J.

Correct Answer: B — 480,000 J

Q. A car accelerates uniformly from rest to a speed of 20 m/s in 10 seconds. What is the distance covered by the car during this time?

A. 100 m
B. 200 m
C. 300 m
D. 400 m

Solution

Using the formula: distance = initial velocity * time + 0.5 * acceleration * time^2. Here, initial velocity = 0, final velocity = 20 m/s, time = 10 s. Acceleration = (final velocity - initial velocity) / time = 2 m/s². Distance = 0 + 0.5 * 2 * 10² = 100 m.

Correct Answer: B — 200 m

Q. A car accelerates uniformly from rest to a speed of 25 m/s in 10 seconds. What is the distance covered by the car during this time?

A. 100 m
B. 125 m
C. 150 m
D. 200 m

Solution

Distance (s) = ut + (1/2)at^2. Here, a = (v-u)/t = (25-0)/10 = 2.5 m/s². So, s = 0 + (1/2)*2.5*10^2 = 125 m.

Correct Answer: B — 125 m

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